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0

I have an array of numbers b[2, 1, 1, 1, 2, 0]. The goal is to find the mode of the array. However, before I can do that I have to create an intermediate array that stores the count of each number. To do this I need to use the element value from the input array as the index number for the intermediate array.
The first part of my if statement works. I'm having a problem with my code in the else statement which is used to count for all numbers that aren't 0. If I print(newArr) It should be printing an array that is [1,3,2] but what it is currently printing is [1,4,5].

 import print from "";

 export let main = async () => {

 let input = [2, 1, 1, 1, 2, 0];
 print(input);

 export let mode = (b: number[]): number => 
 let newArr: number[] = [];
 let current = 0;
 let count = 0;
 
 for (let i = 0; i < b.length; i++) 
 if (b[i] === 0) 
 newArr[b[i]] = count + 1;
 count = newArr[b[i]];
 else 
 newArr[a[i]] = current + 1;
 current = newArr[a[i]];
 
 
 print(newArr)

If the array is b[2,1,1,2,1,0] then 1 should be returned as the mode, and if we printed the array we created it should print newArr[1,3,2] because element 0 has 1 occurrence, element 1 has 3 occurrences, and element 2 has 2 occurrences. The idea is to go from 0 as an element in our input array to it 0 being an index in our intermediate array. so lastly we see which is our max occurrences ( or max element in our intermediate array) which is 3 at index 1, so the mode is 1.

arrays typescript for-loop

share|improve this question

asked Mar 25 at 2:48

B19B19

112

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  stackoverflow.com/questions/53398035/… may be duplicate of
  
  – Syed Mehtab Hassan
  Mar 25 at 5:34
  

  
  
  
  

add a comment | 

0

I have an array of numbers b[2, 1, 1, 1, 2, 0]. The goal is to find the mode of the array. However, before I can do that I have to create an intermediate array that stores the count of each number. To do this I need to use the element value from the input array as the index number for the intermediate array.
The first part of my if statement works. I'm having a problem with my code in the else statement which is used to count for all numbers that aren't 0. If I print(newArr) It should be printing an array that is [1,3,2] but what it is currently printing is [1,4,5].

 import print from "";

 export let main = async () => {

 let input = [2, 1, 1, 1, 2, 0];
 print(input);

 export let mode = (b: number[]): number => 
 let newArr: number[] = [];
 let current = 0;
 let count = 0;
 
 for (let i = 0; i < b.length; i++) 
 if (b[i] === 0) 
 newArr[b[i]] = count + 1;
 count = newArr[b[i]];
 else 
 newArr[a[i]] = current + 1;
 current = newArr[a[i]];
 
 
 print(newArr)

If the array is b[2,1,1,2,1,0] then 1 should be returned as the mode, and if we printed the array we created it should print newArr[1,3,2] because element 0 has 1 occurrence, element 1 has 3 occurrences, and element 2 has 2 occurrences. The idea is to go from 0 as an element in our input array to it 0 being an index in our intermediate array. so lastly we see which is our max occurrences ( or max element in our intermediate array) which is 3 at index 1, so the mode is 1.

arrays typescript for-loop

share|improve this question

asked Mar 25 at 2:48

B19B19

112

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  stackoverflow.com/questions/53398035/… may be duplicate of
  
  – Syed Mehtab Hassan
  Mar 25 at 5:34
  

  
  
  
  

add a comment | 

I have an array of numbers b[2, 1, 1, 1, 2, 0]. The goal is to find the mode of the array. However, before I can do that I have to create an intermediate array that stores the count of each number. To do this I need to use the element value from the input array as the index number for the intermediate array.
The first part of my if statement works. I'm having a problem with my code in the else statement which is used to count for all numbers that aren't 0. If I print(newArr) It should be printing an array that is [1,3,2] but what it is currently printing is [1,4,5].

 import print from "";

 export let main = async () => {

 let input = [2, 1, 1, 1, 2, 0];
 print(input);

 export let mode = (b: number[]): number => 
 let newArr: number[] = [];
 let current = 0;
 let count = 0;
 
 for (let i = 0; i < b.length; i++) 
 if (b[i] === 0) 
 newArr[b[i]] = count + 1;
 count = newArr[b[i]];
 else 
 newArr[a[i]] = current + 1;
 current = newArr[a[i]];
 
 
 print(newArr)

If the array is b[2,1,1,2,1,0] then 1 should be returned as the mode, and if we printed the array we created it should print newArr[1,3,2] because element 0 has 1 occurrence, element 1 has 3 occurrences, and element 2 has 2 occurrences. The idea is to go from 0 as an element in our input array to it 0 being an index in our intermediate array. so lastly we see which is our max occurrences ( or max element in our intermediate array) which is 3 at index 1, so the mode is 1.

arrays typescript for-loop

share|improve this question

asked Mar 25 at 2:48

B19B19

112

 import print from "";

 export let main = async () => {

 let input = [2, 1, 1, 1, 2, 0];
 print(input);

 export let mode = (b: number[]): number => 
 let newArr: number[] = [];
 let current = 0;
 let count = 0;
 
 for (let i = 0; i < b.length; i++) 
 if (b[i] === 0) 
 newArr[b[i]] = count + 1;
 count = newArr[b[i]];
 else 
 newArr[a[i]] = current + 1;
 current = newArr[a[i]];
 
 
 print(newArr)

share|improve this question

asked Mar 25 at 2:48

B19B19

112

share|improve this question

asked Mar 25 at 2:48

B19B19

112

asked Mar 25 at 2:48

B19B19

112

asked Mar 25 at 2:48

B19B19

112