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Fetch MyQL Data into the Jvector Map Using JSON


Safely turning a JSON string into an objectSerializing to JSON in jQueryShould I use the datetime or timestamp data type in MySQL?Convert form data to JavaScript object with jQueryWhy does Google prepend while(1); to their JSON responses?How can I pretty-print JSON using JavaScript?Parse JSON in JavaScript?How does data binding work in AngularJS?The “right” JSON date formatFetch: POST json data






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0















I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.



Here is my PHP code :



$json_data=array(); 

foreach($result as $rec)

$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];

array_push($json_data,$json_array);
echo json_encode($json_data) ;


The JSON That I am recieving is :



[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]


The Script that I am using is :



<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);

$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);


);
);​
</script>


But I am getting the error :




" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "











share|improve this question
























  • there've been no characters. this code is really bothering me now. is there any other method ?

    – Abnit Chauhan
    Mar 25 at 6:42











  • As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data

    – Abnit Chauhan
    Mar 25 at 7:20












  • I have updated the questions with the current Error : please have a look. @JaromandaX

    – Abnit Chauhan
    Mar 25 at 7:31











  • Please have a look into the issue @JaromandaX

    – Abnit Chauhan
    Mar 25 at 10:49

















0















I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.



Here is my PHP code :



$json_data=array(); 

foreach($result as $rec)

$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];

array_push($json_data,$json_array);
echo json_encode($json_data) ;


The JSON That I am recieving is :



[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]


The Script that I am using is :



<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);

$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);


);
);​
</script>


But I am getting the error :




" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "











share|improve this question
























  • there've been no characters. this code is really bothering me now. is there any other method ?

    – Abnit Chauhan
    Mar 25 at 6:42











  • As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data

    – Abnit Chauhan
    Mar 25 at 7:20












  • I have updated the questions with the current Error : please have a look. @JaromandaX

    – Abnit Chauhan
    Mar 25 at 7:31











  • Please have a look into the issue @JaromandaX

    – Abnit Chauhan
    Mar 25 at 10:49













0












0








0








I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.



Here is my PHP code :



$json_data=array(); 

foreach($result as $rec)

$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];

array_push($json_data,$json_array);
echo json_encode($json_data) ;


The JSON That I am recieving is :



[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]


The Script that I am using is :



<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);

$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);


);
);​
</script>


But I am getting the error :




" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "











share|improve this question
















I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.



Here is my PHP code :



$json_data=array(); 

foreach($result as $rec)

$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];

array_push($json_data,$json_array);
echo json_encode($json_data) ;


The JSON That I am recieving is :



[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]


The Script that I am using is :



<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);

$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);


);
);​
</script>


But I am getting the error :




" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "








javascript php mysql jvectormap






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 25 at 7:30







Abnit Chauhan

















asked Mar 25 at 5:10









Abnit ChauhanAbnit Chauhan

4210




4210












  • there've been no characters. this code is really bothering me now. is there any other method ?

    – Abnit Chauhan
    Mar 25 at 6:42











  • As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data

    – Abnit Chauhan
    Mar 25 at 7:20












  • I have updated the questions with the current Error : please have a look. @JaromandaX

    – Abnit Chauhan
    Mar 25 at 7:31











  • Please have a look into the issue @JaromandaX

    – Abnit Chauhan
    Mar 25 at 10:49

















  • there've been no characters. this code is really bothering me now. is there any other method ?

    – Abnit Chauhan
    Mar 25 at 6:42











  • As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data

    – Abnit Chauhan
    Mar 25 at 7:20












  • I have updated the questions with the current Error : please have a look. @JaromandaX

    – Abnit Chauhan
    Mar 25 at 7:31











  • Please have a look into the issue @JaromandaX

    – Abnit Chauhan
    Mar 25 at 10:49
















there've been no characters. this code is really bothering me now. is there any other method ?

– Abnit Chauhan
Mar 25 at 6:42





there've been no characters. this code is really bothering me now. is there any other method ?

– Abnit Chauhan
Mar 25 at 6:42













As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data

– Abnit Chauhan
Mar 25 at 7:20






As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data

– Abnit Chauhan
Mar 25 at 7:20














I have updated the questions with the current Error : please have a look. @JaromandaX

– Abnit Chauhan
Mar 25 at 7:31





I have updated the questions with the current Error : please have a look. @JaromandaX

– Abnit Chauhan
Mar 25 at 7:31













Please have a look into the issue @JaromandaX

– Abnit Chauhan
Mar 25 at 10:49





Please have a look into the issue @JaromandaX

– Abnit Chauhan
Mar 25 at 10:49












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