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Fetch MyQL Data into the Jvector Map Using JSON
Safely turning a JSON string into an objectSerializing to JSON in jQueryShould I use the datetime or timestamp data type in MySQL?Convert form data to JavaScript object with jQueryWhy does Google prepend while(1); to their JSON responses?How can I pretty-print JSON using JavaScript?Parse JSON in JavaScript?How does data binding work in AngularJS?The “right” JSON date formatFetch: POST json data
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.
Here is my PHP code :
$json_data=array();
foreach($result as $rec)
$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];
array_push($json_data,$json_array);
echo json_encode($json_data) ;
The JSON That I am recieving is :
[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]
The Script that I am using is :
<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);
$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);
);
);
</script>
But I am getting the error :
" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "
javascript php mysql jvectormap
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
add a comment |
I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.
Here is my PHP code :
$json_data=array();
foreach($result as $rec)
$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];
array_push($json_data,$json_array);
echo json_encode($json_data) ;
The JSON That I am recieving is :
[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]
The Script that I am using is :
<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);
$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);
);
);
</script>
But I am getting the error :
" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "
javascript php mysql jvectormap
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
there've been no characters. this code is really bothering me now. is there any other method ?
– Abnit Chauhan
Mar 25 at 6:42
As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data
– Abnit Chauhan
Mar 25 at 7:20
I have updated the questions with the current Error : please have a look. @JaromandaX
– Abnit Chauhan
Mar 25 at 7:31
Please have a look into the issue @JaromandaX
– Abnit Chauhan
Mar 25 at 10:49
add a comment |
I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.
Here is my PHP code :
$json_data=array();
foreach($result as $rec)
$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];
array_push($json_data,$json_array);
echo json_encode($json_data) ;
The JSON That I am recieving is :
[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]
The Script that I am using is :
<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);
$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);
);
);
</script>
But I am getting the error :
" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "
javascript php mysql jvectormap
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
I have fetched values From my MySQL Database and stored it in JSON Format. Now What I am trying to do is that I need to show those values on the JvectorMap.
but I am not able to do it.
Here is my PHP code :
$json_data=array();
foreach($result as $rec)
$json_array['Country']=$rec['user_country'];
$json_array['CountryCode']=$rec['country_code'];
$json_array['persons']=$rec['usercountry'];
array_push($json_data,$json_array);
echo json_encode($json_data) ;
The JSON That I am recieving is :
[
"Country":"Australia","CountryCode":"AU","persons":"5",
"Country":"Spain","CountryCode":"ES","persons":"2",
"Country":"India","CountryCode":"IN","persons":"8",
"Country":"Mexico","CountryCode":"MX","persons":"4",
"Country":"United States","CountryCode":"US","persons":"4"
]
The Script that I am using is :
<script type="text/javascript">
var dataC = '<?php echo $data ; ?>' ;
var countryData = ;
$.each(dataC, function()
countryData[this.CountryCode] = this.persons;
);
$(function()
$('#world-map').vectorMap(
map: 'world_mill_en',
series:
regions: [
values: countryData, //load the data
scale: ['#C8EEFF', '#0071A4'],
normalizeFunction: 'polynomial']
,
//-----------------------------------------------
// changed to onRegionLabelShow from onLabelShow
//-----------------------------------------------
onRegionLabelShow: function(e, el, code)
//search through dataC to find the selected country by it's code
var country =$.grep(dataC, function(obj, index)
return obj.CountryCode == code;
)[0]; //snag the first one
//only if selected country was found in dataC
if (country != undefined)
el.html(el.html() +
"<br/><b>Code: </b>" +country.CountryCode +
"<br/><b>Name: </b>" + country.Country +
"<br/><b>persons: </b>" + country.persons);
);
);
</script>
But I am getting the error :
" jquery.min.js:2 Uncaught TypeError: Cannot use 'in' operator to search for 'length' in ["Country":"Australia","CountryCode":"AU","persons":"5","Country":"Spain","CountryCode":"ES","persons":"2","Country":"India","CountryCode":"IN","persons":"8","Country":"Mexico","CountryCode":"MX","persons":"4","Country":"United States","CountryCode":"US","persons":"4"] "
javascript php mysql jvectormap
javascript php mysql jvectormap
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
edited Mar 25 at 7:30
Abnit Chauhan
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
asked Mar 25 at 5:10
Abnit ChauhanAbnit Chauhan
4210
4210
there've been no characters. this code is really bothering me now. is there any other method ?
– Abnit Chauhan
Mar 25 at 6:42
As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data
– Abnit Chauhan
Mar 25 at 7:20
I have updated the questions with the current Error : please have a look. @JaromandaX
– Abnit Chauhan
Mar 25 at 7:31
Please have a look into the issue @JaromandaX
– Abnit Chauhan
Mar 25 at 10:49
add a comment |
there've been no characters. this code is really bothering me now. is there any other method ?
– Abnit Chauhan
Mar 25 at 6:42
As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data
– Abnit Chauhan
Mar 25 at 7:20
I have updated the questions with the current Error : please have a look. @JaromandaX
– Abnit Chauhan
Mar 25 at 7:31
Please have a look into the issue @JaromandaX
– Abnit Chauhan
Mar 25 at 10:49
there've been no characters. this code is really bothering me now. is there any other method ?
– Abnit Chauhan
Mar 25 at 6:42
there've been no characters. this code is really bothering me now. is there any other method ?
– Abnit Chauhan
Mar 25 at 6:42
As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data
– Abnit Chauhan
Mar 25 at 7:20
As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data
– Abnit Chauhan
Mar 25 at 7:20
I have updated the questions with the current Error : please have a look. @JaromandaX
– Abnit Chauhan
Mar 25 at 7:31
I have updated the questions with the current Error : please have a look. @JaromandaX
– Abnit Chauhan
Mar 25 at 7:31
Please have a look into the issue @JaromandaX
– Abnit Chauhan
Mar 25 at 10:49
Please have a look into the issue @JaromandaX
– Abnit Chauhan
Mar 25 at 10:49
add a comment |
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there've been no characters. this code is really bothering me now. is there any other method ?
– Abnit Chauhan
Mar 25 at 6:42
As a matter of fact , there was a space in my Code. thanks for mentioning that. I removed the spaces but the main problem now I am facing is that how can I fetch the values in dataC object from php myql data
– Abnit Chauhan
Mar 25 at 7:20
I have updated the questions with the current Error : please have a look. @JaromandaX
– Abnit Chauhan
Mar 25 at 7:31
Please have a look into the issue @JaromandaX
– Abnit Chauhan
Mar 25 at 10:49