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Concatinate part of two columns
Add a column with a default value to an existing table in SQL ServerFetch the row which has the Max value for a columnSQL Server: How to Join to first rowUsing group by on multiple columnsMySQL - Get row number on selectUsing union and order by clause in mysqlSQL select only rows with max value on a columnconcatenate sqlQuery regarding NVL in SQL
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
select name,(name,1,3||phone_no,1,3)from users order by (name);
I'm writing a query for the above problem and it is showing error.
Write a to display user name and password. The password should be generated by concatenating first three characters of user name and first three numbers in the phone number and give an alias name as the password. Sort the result based on user name
sql oracle
edited Mar 25 at 10:43
DJo
1,3651936
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
add a comment |
select name,(name,1,3||phone_no,1,3)from users order by (name);
I'm writing a query for the above problem and it is showing error.
Write a to display user name and password. The password should be generated by concatenating first three characters of user name and first three numbers in the phone number and give an alias name as the password. Sort the result based on user name
sql oracle
edited Mar 25 at 10:43
DJo
1,3651936
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
add a comment |
select name,(name,1,3||phone_no,1,3)from users order by (name);
I'm writing a query for the above problem and it is showing error.
Write a to display user name and password. The password should be generated by concatenating first three characters of user name and first three numbers in the phone number and give an alias name as the password. Sort the result based on user name
sql oracle
edited Mar 25 at 10:43
DJo
1,3651936
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
select name,(name,1,3||phone_no,1,3)from users order by (name);
I'm writing a query for the above problem and it is showing error.
Write a to display user name and password. The password should be generated by concatenating first three characters of user name and first three numbers in the phone number and give an alias name as the password. Sort the result based on user name
sql oracle
sql oracle
edited Mar 25 at 10:43
DJo
1,3651936
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
edited Mar 25 at 10:43
DJo
1,3651936
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
edited Mar 25 at 10:43
DJo
1,3651936
edited Mar 25 at 10:43
DJo
1,3651936
edited Mar 25 at 10:43
DJo
1,3651936
1,3651936
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
asked Mar 25 at 5:11
Anu RadhaAnu Radha
94
94
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
remove extra parenthesis and use substring function
select name,substr(name,1,3)|| substr(phone_no,1,3) from users order by name
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
remove extra parenthesis and use substring function
select name,substr(name,1,3)|| substr(phone_no,1,3) from users order by name
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
add a comment |
remove extra parenthesis and use substring function
select name,substr(name,1,3)|| substr(phone_no,1,3) from users order by name
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
add a comment |
remove extra parenthesis and use substring function
select name,substr(name,1,3)|| substr(phone_no,1,3) from users order by name
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
remove extra parenthesis and use substring function
select name,substr(name,1,3)|| substr(phone_no,1,3) from users order by name
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
answered Mar 25 at 5:14
Zaynul Abadin TuhinZaynul Abadin Tuhin
20.8k31338
20.8k31338
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
add a comment |
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
select Schedule_id, travel_date (date format('yyyy/mm/dd')) as FormattedDate from schedule order by (Schedule_id);
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
can uh please correct this one also
– Anu Radha
Mar 25 at 8:33
add a comment |
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