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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

-1

1

I'm listing data with Foreach and I'm trying to print it as 1 if all of this data is active and 1 is active, but there is a problem with the code

foreach($veri as $data) 

 if($data['status']==1)

 echo 'active';

 else if($data['status']==2)

 echo 'not active'; 

 

Result:

1active1active1active2not active

trying to do

active or not active

php

share|improve this question

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  there's nothing wrong with your loop. i think the issue could be from the code before the loop runs
  
  – Festus Yuma
  Mar 25 at 1:44
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  There is literally no way the PHP code shown produces "1active1active1active2not active". Where do the numbers come from? Can you also please explain clearly what "print it as 1 if all of this data is active and 1 is active" means?
  
  – Phil
  Mar 25 at 1:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can you add the code where you declared the array you're looping through
  
  – Festus Yuma
  Mar 25 at 1:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Phil I'm holding a json data in the database. There are a lot of data here and they have a situation. If the status of each data is 1 get active. If the status of each data is not 1 I am trying not to be not active.
  
  – Berkay Kara
  Mar 25 at 1:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @FestusYuma I get the s status of the data that I have saved json in the database.
  
  – Berkay Kara
  Mar 25 at 1:54
  

  
  
  
  

 | 
show 1 more comment

-1

1

I'm listing data with Foreach and I'm trying to print it as 1 if all of this data is active and 1 is active, but there is a problem with the code

foreach($veri as $data) 

 if($data['status']==1)

 echo 'active';

 else if($data['status']==2)

 echo 'not active'; 

 

Result:

1active1active1active2not active

trying to do

active or not active

php

share|improve this question

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  there's nothing wrong with your loop. i think the issue could be from the code before the loop runs
  
  – Festus Yuma
  Mar 25 at 1:44
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  There is literally no way the PHP code shown produces "1active1active1active2not active". Where do the numbers come from? Can you also please explain clearly what "print it as 1 if all of this data is active and 1 is active" means?
  
  – Phil
  Mar 25 at 1:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can you add the code where you declared the array you're looping through
  
  – Festus Yuma
  Mar 25 at 1:45
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Phil I'm holding a json data in the database. There are a lot of data here and they have a situation. If the status of each data is 1 get active. If the status of each data is not 1 I am trying not to be not active.
  
  – Berkay Kara
  Mar 25 at 1:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @FestusYuma I get the s status of the data that I have saved json in the database.
  
  – Berkay Kara
  Mar 25 at 1:54
  

  
  
  
  

 | 
show 1 more comment

I'm listing data with Foreach and I'm trying to print it as 1 if all of this data is active and 1 is active, but there is a problem with the code

foreach($veri as $data) 

 if($data['status']==1)

 echo 'active';

 else if($data['status']==2)

 echo 'not active'; 

 

Result:

1active1active1active2not active

trying to do

active or not active

php

share|improve this question

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

foreach($veri as $data) 

 if($data['status']==1)

 echo 'active';

 else if($data['status']==2)

 echo 'not active'; 

 

1active1active1active2not active

active or not active

share|improve this question

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

share|improve this question

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

asked Mar 25 at 1:38

Berkay KaraBerkay Kara

204

1 Answer
1

active

oldest

votes

0

Sounds like you want to only print "active" if all entries have status equal to 1 and "not active" otherwise.

You can use array_reduce() to reduce the array to a single boolean

$allActive = array_reduce($ver1, function($active, $data) 
 return $active && $data['status'] === 1;
, true);

echo $allActive ? 'active' : 'not active';

Demo ~ https://3v4l.org/5Ve9d

---

The above is somewhat inefficient as it will iterate over the entire array, even after it finds a value other than 1.

This is slightly more verbose but optimally exits early

$allActive = true;
forEach($ver1 as $data) 
 if (!($allActive = $data['status'] === 1)) 
 break;
 

Demo ~ https://3v4l.org/UDSpt

share|improve this answer

edited Mar 25 at 2:06

answered Mar 25 at 1:55

PhilPhil

102k13152171

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thank you for your help
  
  – Berkay Kara
  Mar 25 at 2:26
  

  
  
  
  

add a comment | 

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0

Sounds like you want to only print "active" if all entries have status equal to 1 and "not active" otherwise.

You can use array_reduce() to reduce the array to a single boolean

$allActive = array_reduce($ver1, function($active, $data) 
 return $active && $data['status'] === 1;
, true);

echo $allActive ? 'active' : 'not active';

Demo ~ https://3v4l.org/5Ve9d

---

The above is somewhat inefficient as it will iterate over the entire array, even after it finds a value other than 1.

This is slightly more verbose but optimally exits early

$allActive = true;
forEach($ver1 as $data) 
 if (!($allActive = $data['status'] === 1)) 
 break;
 

Demo ~ https://3v4l.org/UDSpt

share|improve this answer

edited Mar 25 at 2:06

answered Mar 25 at 1:55

PhilPhil

102k13152171

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thank you for your help
  
  – Berkay Kara
  Mar 25 at 2:26
  

  
  
  
  

add a comment | 

0

Sounds like you want to only print "active" if all entries have status equal to 1 and "not active" otherwise.

You can use array_reduce() to reduce the array to a single boolean

$allActive = array_reduce($ver1, function($active, $data) 
 return $active && $data['status'] === 1;
, true);

echo $allActive ? 'active' : 'not active';

Demo ~ https://3v4l.org/5Ve9d

---

The above is somewhat inefficient as it will iterate over the entire array, even after it finds a value other than 1.

This is slightly more verbose but optimally exits early

$allActive = true;
forEach($ver1 as $data) 
 if (!($allActive = $data['status'] === 1)) 
 break;
 

Demo ~ https://3v4l.org/UDSpt

share|improve this answer

edited Mar 25 at 2:06

answered Mar 25 at 1:55

PhilPhil

102k13152171

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thank you for your help
  
  – Berkay Kara
  Mar 25 at 2:26
  

  
  
  
  

add a comment | 

Sounds like you want to only print "active" if all entries have status equal to 1 and "not active" otherwise.

You can use array_reduce() to reduce the array to a single boolean

$allActive = array_reduce($ver1, function($active, $data) 
 return $active && $data['status'] === 1;
, true);

echo $allActive ? 'active' : 'not active';

Demo ~ https://3v4l.org/5Ve9d

---

The above is somewhat inefficient as it will iterate over the entire array, even after it finds a value other than 1.

This is slightly more verbose but optimally exits early

$allActive = true;
forEach($ver1 as $data) 
 if (!($allActive = $data['status'] === 1)) 
 break;
 

Demo ~ https://3v4l.org/UDSpt

share|improve this answer

edited Mar 25 at 2:06

answered Mar 25 at 1:55

PhilPhil

102k13152171

$allActive = array_reduce($ver1, function($active, $data) 
 return $active && $data['status'] === 1;
, true);

echo $allActive ? 'active' : 'not active';

$allActive = true;
forEach($ver1 as $data) 
 if (!($allActive = $data['status'] === 1)) 
 break;
 

share|improve this answer

edited Mar 25 at 2:06

answered Mar 25 at 1:55

PhilPhil

102k13152171

answered Mar 25 at 1:55

PhilPhil

102k13152171

answered Mar 25 at 1:55

PhilPhil

102k13152171