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How to count tablets successfully?
Face recognition LibraryPeak detection in a 2D arraySimple and fast method to compare images for similarityHow do I find Waldo with Mathematica?Image Processing: Algorithm Improvement for 'Coca-Cola Can' RecognitionSegmentation for connected charactersImage Processing - Counting nucleiRobust image segmentation in OpenCVDistance Transform in OpenCV Python automatically converting CV_8UC3 to CV_32SC1 creating an assertion errorImage segmentation with watershed thresholding
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My last question on image recognition seemed to be too broad, so I would like to ask a more concrete question.
First the background. I have already developed a (round) pill counter. It uses something similar to this tutorial. After I made it I also found something similar with this other tutorial.
However my method fails for something like this image
Although the segmentation process is a bit complicated (because of the semi-transparency of the tablets) I have managed to get it
My problem is here. How can I count the elongated tablets, separating each one from the image, similar to the final results in the linked tutorials?
I would appreciate if someone can help me to find a solution.
So far I have applied distance transform and then my own version of watershed and I got
As you can see it fails in the adjacent tablets (distance transform usually does).
Take into account that the solution does have to work for this image and also for other arrangements of the tablets, the most difficult being for example
I am open to use OpenCV or if necessary implement on my own algorithms. So far I have tried both (used OpenCV functions and also programmed my own libraries) I am also open to use C++, or python or other. (personally I programmed them in C++ and I have done it on C# too)
Thanks again for the help.
opencv image-processing
|
show 1 more comment
My last question on image recognition seemed to be too broad, so I would like to ask a more concrete question.
First the background. I have already developed a (round) pill counter. It uses something similar to this tutorial. After I made it I also found something similar with this other tutorial.
However my method fails for something like this image
Although the segmentation process is a bit complicated (because of the semi-transparency of the tablets) I have managed to get it
My problem is here. How can I count the elongated tablets, separating each one from the image, similar to the final results in the linked tutorials?
I would appreciate if someone can help me to find a solution.
So far I have applied distance transform and then my own version of watershed and I got
As you can see it fails in the adjacent tablets (distance transform usually does).
Take into account that the solution does have to work for this image and also for other arrangements of the tablets, the most difficult being for example
I am open to use OpenCV or if necessary implement on my own algorithms. So far I have tried both (used OpenCV functions and also programmed my own libraries) I am also open to use C++, or python or other. (personally I programmed them in C++ and I have done it on C# too)
Thanks again for the help.
opencv image-processing
It can be easily done withcv::distanceTransform()
– Bahramdun Adil
Mar 25 at 2:33
@BahramdunAdil Could you provide an example? Asi I wrote I already tried distance transform and watershedoing with the results above. It fails. (Mainly when the tablets are next to each other)
– KansaiRobot
Mar 25 at 2:38
1
Didn't you ask that exact same question last week?
– T A
Mar 25 at 7:50
@TA It was argued my question was too general (well it involved pills and tablets of different sizes and characteristics) so I reduced the question to the first of my problems (in a much more concrete way) (and specifying that it should work for more than the same case)
– KansaiRobot
Mar 25 at 8:32
Have you tried eroding after using the distance transformation?
– T A
Mar 25 at 8:34
|
show 1 more comment
My last question on image recognition seemed to be too broad, so I would like to ask a more concrete question.
First the background. I have already developed a (round) pill counter. It uses something similar to this tutorial. After I made it I also found something similar with this other tutorial.
However my method fails for something like this image
Although the segmentation process is a bit complicated (because of the semi-transparency of the tablets) I have managed to get it
My problem is here. How can I count the elongated tablets, separating each one from the image, similar to the final results in the linked tutorials?
I would appreciate if someone can help me to find a solution.
So far I have applied distance transform and then my own version of watershed and I got
As you can see it fails in the adjacent tablets (distance transform usually does).
Take into account that the solution does have to work for this image and also for other arrangements of the tablets, the most difficult being for example
I am open to use OpenCV or if necessary implement on my own algorithms. So far I have tried both (used OpenCV functions and also programmed my own libraries) I am also open to use C++, or python or other. (personally I programmed them in C++ and I have done it on C# too)
Thanks again for the help.
opencv image-processing
My last question on image recognition seemed to be too broad, so I would like to ask a more concrete question.
First the background. I have already developed a (round) pill counter. It uses something similar to this tutorial. After I made it I also found something similar with this other tutorial.
However my method fails for something like this image
Although the segmentation process is a bit complicated (because of the semi-transparency of the tablets) I have managed to get it
My problem is here. How can I count the elongated tablets, separating each one from the image, similar to the final results in the linked tutorials?
I would appreciate if someone can help me to find a solution.
So far I have applied distance transform and then my own version of watershed and I got
As you can see it fails in the adjacent tablets (distance transform usually does).
Take into account that the solution does have to work for this image and also for other arrangements of the tablets, the most difficult being for example
I am open to use OpenCV or if necessary implement on my own algorithms. So far I have tried both (used OpenCV functions and also programmed my own libraries) I am also open to use C++, or python or other. (personally I programmed them in C++ and I have done it on C# too)
Thanks again for the help.
opencv image-processing
opencv image-processing
edited Mar 25 at 6:01
marc_s
593k13311351279
593k13311351279
asked Mar 25 at 1:53
KansaiRobotKansaiRobot
1,0241533
1,0241533
It can be easily done withcv::distanceTransform()
– Bahramdun Adil
Mar 25 at 2:33
@BahramdunAdil Could you provide an example? Asi I wrote I already tried distance transform and watershedoing with the results above. It fails. (Mainly when the tablets are next to each other)
– KansaiRobot
Mar 25 at 2:38
1
Didn't you ask that exact same question last week?
– T A
Mar 25 at 7:50
@TA It was argued my question was too general (well it involved pills and tablets of different sizes and characteristics) so I reduced the question to the first of my problems (in a much more concrete way) (and specifying that it should work for more than the same case)
– KansaiRobot
Mar 25 at 8:32
Have you tried eroding after using the distance transformation?
– T A
Mar 25 at 8:34
|
show 1 more comment
It can be easily done withcv::distanceTransform()
– Bahramdun Adil
Mar 25 at 2:33
@BahramdunAdil Could you provide an example? Asi I wrote I already tried distance transform and watershedoing with the results above. It fails. (Mainly when the tablets are next to each other)
– KansaiRobot
Mar 25 at 2:38
1
Didn't you ask that exact same question last week?
– T A
Mar 25 at 7:50
@TA It was argued my question was too general (well it involved pills and tablets of different sizes and characteristics) so I reduced the question to the first of my problems (in a much more concrete way) (and specifying that it should work for more than the same case)
– KansaiRobot
Mar 25 at 8:32
Have you tried eroding after using the distance transformation?
– T A
Mar 25 at 8:34
It can be easily done with
cv::distanceTransform()
– Bahramdun Adil
Mar 25 at 2:33
It can be easily done with
cv::distanceTransform()
– Bahramdun Adil
Mar 25 at 2:33
@BahramdunAdil Could you provide an example? Asi I wrote I already tried distance transform and watershedoing with the results above. It fails. (Mainly when the tablets are next to each other)
– KansaiRobot
Mar 25 at 2:38
@BahramdunAdil Could you provide an example? Asi I wrote I already tried distance transform and watershedoing with the results above. It fails. (Mainly when the tablets are next to each other)
– KansaiRobot
Mar 25 at 2:38
1
1
Didn't you ask that exact same question last week?
– T A
Mar 25 at 7:50
Didn't you ask that exact same question last week?
– T A
Mar 25 at 7:50
@TA It was argued my question was too general (well it involved pills and tablets of different sizes and characteristics) so I reduced the question to the first of my problems (in a much more concrete way) (and specifying that it should work for more than the same case)
– KansaiRobot
Mar 25 at 8:32
@TA It was argued my question was too general (well it involved pills and tablets of different sizes and characteristics) so I reduced the question to the first of my problems (in a much more concrete way) (and specifying that it should work for more than the same case)
– KansaiRobot
Mar 25 at 8:32
Have you tried eroding after using the distance transformation?
– T A
Mar 25 at 8:34
Have you tried eroding after using the distance transformation?
– T A
Mar 25 at 8:34
|
show 1 more comment
1 Answer
1
active
oldest
votes
Given that the pills are all identical and don’t overlap, simply divide the total pill area by the area of a single pill.
The area is estimated simply counting the number of “pill” pixels.
You do need to calibrate the method by giving it the area of a single pill. This can be trivially obtained by giving the correct solution to one of the images (manual counting), then all the other images can be counted automatically.
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
add a comment |
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1 Answer
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1 Answer
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votes
Given that the pills are all identical and don’t overlap, simply divide the total pill area by the area of a single pill.
The area is estimated simply counting the number of “pill” pixels.
You do need to calibrate the method by giving it the area of a single pill. This can be trivially obtained by giving the correct solution to one of the images (manual counting), then all the other images can be counted automatically.
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
add a comment |
Given that the pills are all identical and don’t overlap, simply divide the total pill area by the area of a single pill.
The area is estimated simply counting the number of “pill” pixels.
You do need to calibrate the method by giving it the area of a single pill. This can be trivially obtained by giving the correct solution to one of the images (manual counting), then all the other images can be counted automatically.
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
add a comment |
Given that the pills are all identical and don’t overlap, simply divide the total pill area by the area of a single pill.
The area is estimated simply counting the number of “pill” pixels.
You do need to calibrate the method by giving it the area of a single pill. This can be trivially obtained by giving the correct solution to one of the images (manual counting), then all the other images can be counted automatically.
Given that the pills are all identical and don’t overlap, simply divide the total pill area by the area of a single pill.
The area is estimated simply counting the number of “pill” pixels.
You do need to calibrate the method by giving it the area of a single pill. This can be trivially obtained by giving the correct solution to one of the images (manual counting), then all the other images can be counted automatically.
answered Mar 25 at 13:19
Cris LuengoCris Luengo
25.7k62457
25.7k62457
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
add a comment |
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
Ideally I would like to have them marked as in pyimagesearch.com/wp-content/uploads/2015/10/… (the pic is for round coins, but similar for tablets)
– KansaiRobot
Mar 26 at 1:50
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
@KansaiRobot: Sure, you can try doing it the hard way if you want. Good luck with that!
– Cris Luengo
Mar 26 at 1:53
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
Unfortunatelly it is a requirement.
– KansaiRobot
Mar 26 at 1:56
add a comment |
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It can be easily done with
cv::distanceTransform()
– Bahramdun Adil
Mar 25 at 2:33
@BahramdunAdil Could you provide an example? Asi I wrote I already tried distance transform and watershedoing with the results above. It fails. (Mainly when the tablets are next to each other)
– KansaiRobot
Mar 25 at 2:38
1
Didn't you ask that exact same question last week?
– T A
Mar 25 at 7:50
@TA It was argued my question was too general (well it involved pills and tablets of different sizes and characteristics) so I reduced the question to the first of my problems (in a much more concrete way) (and specifying that it should work for more than the same case)
– KansaiRobot
Mar 25 at 8:32
Have you tried eroding after using the distance transformation?
– T A
Mar 25 at 8:34