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how to format a a url to return something like this “product/4/improved-led-lamp” in the template

Django blows up with 1.1, Can't find urls moduleHaving trouble with getting URL config to work% url % not work in DjangoDjango 1.8.3 urlsHow to link my css, js and image file link in djangoextends not working in Django 1.9NoReverseMatch error: Split URL and Views into multiple files to link and reverse them from a single REST Api RootDjango - Slug field for model object not being applied to URLWhy is Django template pattern matching with wrong view and causing a NoReverseMatch error?urls.py django 2.0.2 need parameters

1

I'm trying to return a formatted url that will look like this "edit-book/4/improved-led-lamp" using the % url % tag

I've tried % url 'dashboard:editbook' 4 slug %

here is the root url.py

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
 path('', include('home.urls')),
 path('dashboard/', include('dashboard.urls')),
 path('admin/', admin.site.urls),
]

here is my dashboard app's urls,py

from django.urls import path
from . import views

app_name = 'dashboard'
urlpatterns = [
 path('edit-book/<int:id>/<slug:title>', views.BookView.as_view(), name='editbook'),
]

if I visit "edit-book/4/improved-led-lamp" in my browser, it resolves, but when I try to reproduce this in the view using % url % tag, it throws noReverseMatch error

this is the error
screenshot of error

python django django-templates

share|improve this question

edited Mar 25 at 16:13

dmoxy

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please show the full error.
  
  – Daniel Roseman
  Mar 25 at 15:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @DanielRoseman, I just uploaded a screenshot of the error, plus i've edited the code to provide more details
  
  – dmoxy
  Mar 25 at 16:11
  

  
  
  
  

add a comment | 

1

I'm trying to return a formatted url that will look like this "edit-book/4/improved-led-lamp" using the % url % tag

I've tried % url 'dashboard:editbook' 4 slug %

here is the root url.py

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
 path('', include('home.urls')),
 path('dashboard/', include('dashboard.urls')),
 path('admin/', admin.site.urls),
]

here is my dashboard app's urls,py

from django.urls import path
from . import views

app_name = 'dashboard'
urlpatterns = [
 path('edit-book/<int:id>/<slug:title>', views.BookView.as_view(), name='editbook'),
]

if I visit "edit-book/4/improved-led-lamp" in my browser, it resolves, but when I try to reproduce this in the view using % url % tag, it throws noReverseMatch error

this is the error
screenshot of error

python django django-templates

share|improve this question

edited Mar 25 at 16:13

dmoxy

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please show the full error.
  
  – Daniel Roseman
  Mar 25 at 15:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @DanielRoseman, I just uploaded a screenshot of the error, plus i've edited the code to provide more details
  
  – dmoxy
  Mar 25 at 16:11
  

  
  
  
  

add a comment | 

I'm trying to return a formatted url that will look like this "edit-book/4/improved-led-lamp" using the % url % tag

I've tried % url 'dashboard:editbook' 4 slug %

here is the root url.py

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
 path('', include('home.urls')),
 path('dashboard/', include('dashboard.urls')),
 path('admin/', admin.site.urls),
]

here is my dashboard app's urls,py

from django.urls import path
from . import views

app_name = 'dashboard'
urlpatterns = [
 path('edit-book/<int:id>/<slug:title>', views.BookView.as_view(), name='editbook'),
]

if I visit "edit-book/4/improved-led-lamp" in my browser, it resolves, but when I try to reproduce this in the view using % url % tag, it throws noReverseMatch error

this is the error
screenshot of error

python django django-templates

share|improve this question

edited Mar 25 at 16:13

dmoxy

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
 path('', include('home.urls')),
 path('dashboard/', include('dashboard.urls')),
 path('admin/', admin.site.urls),
]

from django.urls import path
from . import views

app_name = 'dashboard'
urlpatterns = [
 path('edit-book/<int:id>/<slug:title>', views.BookView.as_view(), name='editbook'),
]

share|improve this question

edited Mar 25 at 16:13

dmoxy

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

share|improve this question

edited Mar 25 at 16:13

dmoxy

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

asked Mar 25 at 15:47

dmoxydmoxy

1855 bronze badges

1 Answer
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2

Your syntax looks correct and if slug variable consists of slug ([-a-zA-Z0-9_]+) it should be working.

Look into contents of slug. Error screenshot shows that it's an empty string.

share|improve this answer

edited Mar 25 at 16:13

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I've updated the question
  
  – dmoxy
  Mar 25 at 16:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  screenshot shows that slug variable is empty string. You need an actual slug there.
  
  – Kyryl Havrylenko
  Mar 25 at 16:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thanks mate, you were right
  
  – dmoxy
  Mar 25 at 16:17
  

  
  
  
  

add a comment | 

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2

Your syntax looks correct and if slug variable consists of slug ([-a-zA-Z0-9_]+) it should be working.

Look into contents of slug. Error screenshot shows that it's an empty string.

share|improve this answer

edited Mar 25 at 16:13

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I've updated the question
  
  – dmoxy
  Mar 25 at 16:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  screenshot shows that slug variable is empty string. You need an actual slug there.
  
  – Kyryl Havrylenko
  Mar 25 at 16:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thanks mate, you were right
  
  – dmoxy
  Mar 25 at 16:17
  

  
  
  
  

add a comment | 

2

Your syntax looks correct and if slug variable consists of slug ([-a-zA-Z0-9_]+) it should be working.

Look into contents of slug. Error screenshot shows that it's an empty string.

share|improve this answer

edited Mar 25 at 16:13

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I've updated the question
  
  – dmoxy
  Mar 25 at 16:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  screenshot shows that slug variable is empty string. You need an actual slug there.
  
  – Kyryl Havrylenko
  Mar 25 at 16:14
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thanks mate, you were right
  
  – dmoxy
  Mar 25 at 16:17
  

  
  
  
  

add a comment | 

Your syntax looks correct and if slug variable consists of slug ([-a-zA-Z0-9_]+) it should be working.

Look into contents of slug. Error screenshot shows that it's an empty string.

share|improve this answer

edited Mar 25 at 16:13

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges

share|improve this answer

edited Mar 25 at 16:13

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges

answered Mar 25 at 16:03

Kyryl HavrylenkoKyryl Havrylenko

45922 silver badges99 bronze badges