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1

I am trying to retrieve a field from a JsonObject as String. This field "agentid" sometimes come as long and sometimes as String. When it comes as a long, I get an exception

java.lang.ClassCastException: java.lang.Double cannot be cast to
java.lang.CharSequence

Following is the statement which hits this exception:

// get agent ID
String agentID = parameterJson.getString("agentid");

How to safely get the content of this field "agentid" and store it as String in Java?

java json

share|improve this question

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use Double.toString(parameterJson.getDouble("agentid"); to store this as a String. However, you'll have to fit the method the the type of the object you want to parse.
  
  – Maxouille
  Mar 25 at 14:02
  

  
  
  
  

add a comment | 

1

I am trying to retrieve a field from a JsonObject as String. This field "agentid" sometimes come as long and sometimes as String. When it comes as a long, I get an exception

java.lang.ClassCastException: java.lang.Double cannot be cast to
java.lang.CharSequence

Following is the statement which hits this exception:

// get agent ID
String agentID = parameterJson.getString("agentid");

How to safely get the content of this field "agentid" and store it as String in Java?

java json

share|improve this question

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use Double.toString(parameterJson.getDouble("agentid"); to store this as a String. However, you'll have to fit the method the the type of the object you want to parse.
  
  – Maxouille
  Mar 25 at 14:02
  

  
  
  
  

add a comment | 

I am trying to retrieve a field from a JsonObject as String. This field "agentid" sometimes come as long and sometimes as String. When it comes as a long, I get an exception

java.lang.ClassCastException: java.lang.Double cannot be cast to
java.lang.CharSequence

Following is the statement which hits this exception:

// get agent ID
String agentID = parameterJson.getString("agentid");

How to safely get the content of this field "agentid" and store it as String in Java?

java json

share|improve this question

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

// get agent ID
String agentID = parameterJson.getString("agentid");

share|improve this question

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

share|improve this question

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

asked Mar 25 at 14:00

user3243499user3243499

97922 gold badges1313 silver badges2929 bronze badges

3 Answers
3

active

oldest

votes

1

Depnding on which JsonObject class you are using, I'm assuming it has a get() or getObject() method that returns an Object. You can call that method followed by .toString().

For example:

String agentID = parameterJson.getObject("agentid").toString();

share|improve this answer

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It am getting java.lang.Double cannot be cast to io.vertx.core.json.JsonObject. Used code as you have suggested String agentID = parameterJson.getJsonObject("agentid").toString();
  
  – user3243499
  Mar 25 at 14:25
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @user3243499 Perhaps you are not calling the right method. I don't know which class you are using, so I can't check it myself, but see if there's a method that returns an Object (not JsonObject).
  
  – Eran
  Mar 25 at 14:27
  

  
  
  
  

add a comment | 

1

There are different things you can do:

For the first you can do Double.toString(...) because the Exception tells you why the error appears.

Also you can do String.valueOf(Object) that can also handle every object you pass in there or you just use the toString method when you get an Object from the JSON.

You also are able to just use the getDouble instead of getString and use the type double.

share|improve this answer

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

add a comment | 

0

you can use this to convert it to string.

String agentID = String.valueOf(parameterJson.getString("agentid"));

share|improve this answer

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  parameterJson.getString("agentid") already returns a String, and throws an exception if the value of the given key is not a String.
  
  – Eran
  Mar 25 at 14:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This wouldn't work as you're doing a getString(Double), it will still throw the exception, either String.valueOf(Object) or Object.toString() are the way to go
  
  – Oscar Arranz
  Mar 25 at 14:07
  

  
  
  
  

add a comment | 

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1

Depnding on which JsonObject class you are using, I'm assuming it has a get() or getObject() method that returns an Object. You can call that method followed by .toString().

For example:

String agentID = parameterJson.getObject("agentid").toString();

share|improve this answer

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It am getting java.lang.Double cannot be cast to io.vertx.core.json.JsonObject. Used code as you have suggested String agentID = parameterJson.getJsonObject("agentid").toString();
  
  – user3243499
  Mar 25 at 14:25
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @user3243499 Perhaps you are not calling the right method. I don't know which class you are using, so I can't check it myself, but see if there's a method that returns an Object (not JsonObject).
  
  – Eran
  Mar 25 at 14:27
  

  
  
  
  

add a comment | 

1

Depnding on which JsonObject class you are using, I'm assuming it has a get() or getObject() method that returns an Object. You can call that method followed by .toString().

For example:

String agentID = parameterJson.getObject("agentid").toString();

share|improve this answer

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It am getting java.lang.Double cannot be cast to io.vertx.core.json.JsonObject. Used code as you have suggested String agentID = parameterJson.getJsonObject("agentid").toString();
  
  – user3243499
  Mar 25 at 14:25
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @user3243499 Perhaps you are not calling the right method. I don't know which class you are using, so I can't check it myself, but see if there's a method that returns an Object (not JsonObject).
  
  – Eran
  Mar 25 at 14:27
  

  
  
  
  

add a comment | 

Depnding on which JsonObject class you are using, I'm assuming it has a get() or getObject() method that returns an Object. You can call that method followed by .toString().

For example:

String agentID = parameterJson.getObject("agentid").toString();

share|improve this answer

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

String agentID = parameterJson.getObject("agentid").toString();

share|improve this answer

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

answered Mar 25 at 14:02

EranEran

301k3939 gold badges512512 silver badges586586 bronze badges

1

There are different things you can do:

For the first you can do Double.toString(...) because the Exception tells you why the error appears.

Also you can do String.valueOf(Object) that can also handle every object you pass in there or you just use the toString method when you get an Object from the JSON.

You also are able to just use the getDouble instead of getString and use the type double.

share|improve this answer

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

add a comment | 

1

There are different things you can do:

For the first you can do Double.toString(...) because the Exception tells you why the error appears.

Also you can do String.valueOf(Object) that can also handle every object you pass in there or you just use the toString method when you get an Object from the JSON.

You also are able to just use the getDouble instead of getString and use the type double.

share|improve this answer

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

add a comment | 

There are different things you can do:

For the first you can do Double.toString(...) because the Exception tells you why the error appears.

Also you can do String.valueOf(Object) that can also handle every object you pass in there or you just use the toString method when you get an Object from the JSON.

You also are able to just use the getDouble instead of getString and use the type double.

share|improve this answer

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

share|improve this answer

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

answered Mar 25 at 14:04

CodeMatrixCodeMatrix

1,85411 gold badge1111 silver badges2222 bronze badges

0

you can use this to convert it to string.

String agentID = String.valueOf(parameterJson.getString("agentid"));

share|improve this answer

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  parameterJson.getString("agentid") already returns a String, and throws an exception if the value of the given key is not a String.
  
  – Eran
  Mar 25 at 14:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This wouldn't work as you're doing a getString(Double), it will still throw the exception, either String.valueOf(Object) or Object.toString() are the way to go
  
  – Oscar Arranz
  Mar 25 at 14:07
  

  
  
  
  

add a comment | 

0

you can use this to convert it to string.

String agentID = String.valueOf(parameterJson.getString("agentid"));

share|improve this answer

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  parameterJson.getString("agentid") already returns a String, and throws an exception if the value of the given key is not a String.
  
  – Eran
  Mar 25 at 14:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This wouldn't work as you're doing a getString(Double), it will still throw the exception, either String.valueOf(Object) or Object.toString() are the way to go
  
  – Oscar Arranz
  Mar 25 at 14:07
  

  
  
  
  

add a comment | 

you can use this to convert it to string.

String agentID = String.valueOf(parameterJson.getString("agentid"));

share|improve this answer

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges

String agentID = String.valueOf(parameterJson.getString("agentid"));

share|improve this answer

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges

answered Mar 25 at 14:03

Onkar MusaleOnkar Musale

73144 silver badges2121 bronze badges