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shell - display number of errors for best matches in agrep


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0















What I am trying to do is to get the best-matching word in a file and the number of errors for it using agrep. For now I am only able to get the word using this script:



array=(bla1 bla2 bla3)
for eachWord in "$array[@]"; do
result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt)
printf "$resultn"
done


Where bla1,2,3 are some words.



The output I have is the following:



agrep: 4 words match within 2 errors; search for them? (y/n)counting
first
and
should
agrep: 1 word matches within 1 error; search for it? (y/n)should
agrep: 2 words match within 4 errors; search for them? (y/n)must
must
agrep: 1 word matches within 2 errors; search for it? (y/n)should


Is there any way I can have the number of errors (2,1,4,2 in the output example above)?










share|improve this question
























  • What do you want with it?

    – Inian
    Mar 25 at 8:58











  • the Levenstein distance for mine and the best-matching word

    – Victoria
    Mar 25 at 9:24






  • 1





    As far as i've understood, you want the output to be: 2 1 4 2(i.e, number of errors). Can you try this: result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt|sed -E -n 's/.*s+withins+([0-9]+)s+errors;.*/1/p'). I'm pretty sure,this can be done using one sed or awk.

    – User123
    Mar 25 at 9:43











  • What I get after this is the following. Is there a way to extract only the second number? : agrep: 4 words match within 2 errors; search for them? (y/n) agrep: 1 word matches within 1 error; search for it? (y/n) agrep: 2 words match within 4 errors; search for them? (y/n) agrep: 1 word matches within 2 errors; search for it? (y/n)

    – Victoria
    Mar 25 at 10:02


















0















What I am trying to do is to get the best-matching word in a file and the number of errors for it using agrep. For now I am only able to get the word using this script:



array=(bla1 bla2 bla3)
for eachWord in "$array[@]"; do
result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt)
printf "$resultn"
done


Where bla1,2,3 are some words.



The output I have is the following:



agrep: 4 words match within 2 errors; search for them? (y/n)counting
first
and
should
agrep: 1 word matches within 1 error; search for it? (y/n)should
agrep: 2 words match within 4 errors; search for them? (y/n)must
must
agrep: 1 word matches within 2 errors; search for it? (y/n)should


Is there any way I can have the number of errors (2,1,4,2 in the output example above)?










share|improve this question
























  • What do you want with it?

    – Inian
    Mar 25 at 8:58











  • the Levenstein distance for mine and the best-matching word

    – Victoria
    Mar 25 at 9:24






  • 1





    As far as i've understood, you want the output to be: 2 1 4 2(i.e, number of errors). Can you try this: result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt|sed -E -n 's/.*s+withins+([0-9]+)s+errors;.*/1/p'). I'm pretty sure,this can be done using one sed or awk.

    – User123
    Mar 25 at 9:43











  • What I get after this is the following. Is there a way to extract only the second number? : agrep: 4 words match within 2 errors; search for them? (y/n) agrep: 1 word matches within 1 error; search for it? (y/n) agrep: 2 words match within 4 errors; search for them? (y/n) agrep: 1 word matches within 2 errors; search for it? (y/n)

    – Victoria
    Mar 25 at 10:02














0












0








0








What I am trying to do is to get the best-matching word in a file and the number of errors for it using agrep. For now I am only able to get the word using this script:



array=(bla1 bla2 bla3)
for eachWord in "$array[@]"; do
result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt)
printf "$resultn"
done


Where bla1,2,3 are some words.



The output I have is the following:



agrep: 4 words match within 2 errors; search for them? (y/n)counting
first
and
should
agrep: 1 word matches within 1 error; search for it? (y/n)should
agrep: 2 words match within 4 errors; search for them? (y/n)must
must
agrep: 1 word matches within 2 errors; search for it? (y/n)should


Is there any way I can have the number of errors (2,1,4,2 in the output example above)?










share|improve this question
















What I am trying to do is to get the best-matching word in a file and the number of errors for it using agrep. For now I am only able to get the word using this script:



array=(bla1 bla2 bla3)
for eachWord in "$array[@]"; do
result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt)
printf "$resultn"
done


Where bla1,2,3 are some words.



The output I have is the following:



agrep: 4 words match within 2 errors; search for them? (y/n)counting
first
and
should
agrep: 1 word matches within 1 error; search for it? (y/n)should
agrep: 2 words match within 4 errors; search for them? (y/n)must
must
agrep: 1 word matches within 2 errors; search for it? (y/n)should


Is there any way I can have the number of errors (2,1,4,2 in the output example above)?







linux bash shell grep agrep






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 25 at 12:16









agc

5,2091539




5,2091539










asked Mar 25 at 8:34









VictoriaVictoria

49118




49118












  • What do you want with it?

    – Inian
    Mar 25 at 8:58











  • the Levenstein distance for mine and the best-matching word

    – Victoria
    Mar 25 at 9:24






  • 1





    As far as i've understood, you want the output to be: 2 1 4 2(i.e, number of errors). Can you try this: result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt|sed -E -n 's/.*s+withins+([0-9]+)s+errors;.*/1/p'). I'm pretty sure,this can be done using one sed or awk.

    – User123
    Mar 25 at 9:43











  • What I get after this is the following. Is there a way to extract only the second number? : agrep: 4 words match within 2 errors; search for them? (y/n) agrep: 1 word matches within 1 error; search for it? (y/n) agrep: 2 words match within 4 errors; search for them? (y/n) agrep: 1 word matches within 2 errors; search for it? (y/n)

    – Victoria
    Mar 25 at 10:02


















  • What do you want with it?

    – Inian
    Mar 25 at 8:58











  • the Levenstein distance for mine and the best-matching word

    – Victoria
    Mar 25 at 9:24






  • 1





    As far as i've understood, you want the output to be: 2 1 4 2(i.e, number of errors). Can you try this: result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt|sed -E -n 's/.*s+withins+([0-9]+)s+errors;.*/1/p'). I'm pretty sure,this can be done using one sed or awk.

    – User123
    Mar 25 at 9:43











  • What I get after this is the following. Is there a way to extract only the second number? : agrep: 4 words match within 2 errors; search for them? (y/n) agrep: 1 word matches within 1 error; search for it? (y/n) agrep: 2 words match within 4 errors; search for them? (y/n) agrep: 1 word matches within 2 errors; search for it? (y/n)

    – Victoria
    Mar 25 at 10:02

















What do you want with it?

– Inian
Mar 25 at 8:58





What do you want with it?

– Inian
Mar 25 at 8:58













the Levenstein distance for mine and the best-matching word

– Victoria
Mar 25 at 9:24





the Levenstein distance for mine and the best-matching word

– Victoria
Mar 25 at 9:24




1




1





As far as i've understood, you want the output to be: 2 1 4 2(i.e, number of errors). Can you try this: result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt|sed -E -n 's/.*s+withins+([0-9]+)s+errors;.*/1/p'). I'm pretty sure,this can be done using one sed or awk.

– User123
Mar 25 at 9:43





As far as i've understood, you want the output to be: 2 1 4 2(i.e, number of errors). Can you try this: result=$(yes "yes" | agrep -B $eachWord /home/victoria/file.txt|sed -E -n 's/.*s+withins+([0-9]+)s+errors;.*/1/p'). I'm pretty sure,this can be done using one sed or awk.

– User123
Mar 25 at 9:43













What I get after this is the following. Is there a way to extract only the second number? : agrep: 4 words match within 2 errors; search for them? (y/n) agrep: 1 word matches within 1 error; search for it? (y/n) agrep: 2 words match within 4 errors; search for them? (y/n) agrep: 1 word matches within 2 errors; search for it? (y/n)

– Victoria
Mar 25 at 10:02






What I get after this is the following. Is there a way to extract only the second number? : agrep: 4 words match within 2 errors; search for them? (y/n) agrep: 1 word matches within 1 error; search for it? (y/n) agrep: 2 words match within 4 errors; search for them? (y/n) agrep: 1 word matches within 2 errors; search for it? (y/n)

– Victoria
Mar 25 at 10:02













1 Answer
1






active

oldest

votes


















0














The main problem is, that agrep reports the errors to standard error (file descriptor 2) and not to standard out (file descriptor 1). In order to throw away stdout and return stderr, you have to redirect stdout to /dev/null and redirect stderr to stdout:



2>&1 1>/dev/null


The minor problem is, that agrep does not output proper line endings, if you feed it by yes. You have to write a newline it stderr:



echo >&2


Finally, as User123 told you, you need a sed command to extract the number of errors.



This is an example:



for a in r1234t rot ruht rood; do
yes y | agrep -B "$a" /etc/passwd
echo >&2
done 2>&1 1>/dev/null |
sed -n 's/.* ([0-9]+) error.*/1/p'


Output is:



4
1
2
1





share|improve this answer























  • I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

    – User123
    Mar 26 at 5:30













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1 Answer
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oldest

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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









0














The main problem is, that agrep reports the errors to standard error (file descriptor 2) and not to standard out (file descriptor 1). In order to throw away stdout and return stderr, you have to redirect stdout to /dev/null and redirect stderr to stdout:



2>&1 1>/dev/null


The minor problem is, that agrep does not output proper line endings, if you feed it by yes. You have to write a newline it stderr:



echo >&2


Finally, as User123 told you, you need a sed command to extract the number of errors.



This is an example:



for a in r1234t rot ruht rood; do
yes y | agrep -B "$a" /etc/passwd
echo >&2
done 2>&1 1>/dev/null |
sed -n 's/.* ([0-9]+) error.*/1/p'


Output is:



4
1
2
1





share|improve this answer























  • I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

    – User123
    Mar 26 at 5:30















0














The main problem is, that agrep reports the errors to standard error (file descriptor 2) and not to standard out (file descriptor 1). In order to throw away stdout and return stderr, you have to redirect stdout to /dev/null and redirect stderr to stdout:



2>&1 1>/dev/null


The minor problem is, that agrep does not output proper line endings, if you feed it by yes. You have to write a newline it stderr:



echo >&2


Finally, as User123 told you, you need a sed command to extract the number of errors.



This is an example:



for a in r1234t rot ruht rood; do
yes y | agrep -B "$a" /etc/passwd
echo >&2
done 2>&1 1>/dev/null |
sed -n 's/.* ([0-9]+) error.*/1/p'


Output is:



4
1
2
1





share|improve this answer























  • I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

    – User123
    Mar 26 at 5:30













0












0








0







The main problem is, that agrep reports the errors to standard error (file descriptor 2) and not to standard out (file descriptor 1). In order to throw away stdout and return stderr, you have to redirect stdout to /dev/null and redirect stderr to stdout:



2>&1 1>/dev/null


The minor problem is, that agrep does not output proper line endings, if you feed it by yes. You have to write a newline it stderr:



echo >&2


Finally, as User123 told you, you need a sed command to extract the number of errors.



This is an example:



for a in r1234t rot ruht rood; do
yes y | agrep -B "$a" /etc/passwd
echo >&2
done 2>&1 1>/dev/null |
sed -n 's/.* ([0-9]+) error.*/1/p'


Output is:



4
1
2
1





share|improve this answer













The main problem is, that agrep reports the errors to standard error (file descriptor 2) and not to standard out (file descriptor 1). In order to throw away stdout and return stderr, you have to redirect stdout to /dev/null and redirect stderr to stdout:



2>&1 1>/dev/null


The minor problem is, that agrep does not output proper line endings, if you feed it by yes. You have to write a newline it stderr:



echo >&2


Finally, as User123 told you, you need a sed command to extract the number of errors.



This is an example:



for a in r1234t rot ruht rood; do
yes y | agrep -B "$a" /etc/passwd
echo >&2
done 2>&1 1>/dev/null |
sed -n 's/.* ([0-9]+) error.*/1/p'


Output is:



4
1
2
1






share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 25 at 13:10









cevingceving

10.8k360108




10.8k360108












  • I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

    – User123
    Mar 26 at 5:30

















  • I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

    – User123
    Mar 26 at 5:30
















I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

– User123
Mar 26 at 5:30





I guess the OP only wants the second number (i.e more precisely, the number of errors: the number before the string 'errorrs'), so sed command could be modified a bit: 's/.*s+withins+([0-9]+)s+errors;.*/1/p'

– User123
Mar 26 at 5:30



















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