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Unable to determine object's concavity in OpenCV


How to determine a Python variable's type?In Python, how do I determine if an object is iterable?Determine the type of an object?Why drawcontours in OpenCV doesn´t fill contours in the edge of the image?General contour detectionTriangle detection using OpenCVopenCV: cannot detect small shapes using findContoursOpenCV Convex Hull coordinatesOpenCV 3.4.0 video contours/arclength error(s)how to join nearby contours in a opencv motion detection






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0















I am attempting to detect convex pentagons in an image using OpenCV. I am using the following image:



enter image description here



I first find the contours in the image and then do this:



approx = cv2.approxPolyDP(c, 0.04 * perimeter, True)
isPentagon = len(approx) == 5


When I ran this on the image, I got this result:



enter image description here



This white part in the image is being detected. I thought that checking the concavity would solve it. Here is what I attempted:



isPentagon = len(approx) == 5 and cv2.isContourConvex(c)


However, for all the pentagons I tried, isContourConvex returned False. I am not sure why. I tried other images as well and the same happened. Variable c is the contour.



Is there a way to fix this? Maybe a better way to check if a polygon is regular?










share|improve this question




























    0















    I am attempting to detect convex pentagons in an image using OpenCV. I am using the following image:



    enter image description here



    I first find the contours in the image and then do this:



    approx = cv2.approxPolyDP(c, 0.04 * perimeter, True)
    isPentagon = len(approx) == 5


    When I ran this on the image, I got this result:



    enter image description here



    This white part in the image is being detected. I thought that checking the concavity would solve it. Here is what I attempted:



    isPentagon = len(approx) == 5 and cv2.isContourConvex(c)


    However, for all the pentagons I tried, isContourConvex returned False. I am not sure why. I tried other images as well and the same happened. Variable c is the contour.



    Is there a way to fix this? Maybe a better way to check if a polygon is regular?










    share|improve this question
























      0












      0








      0








      I am attempting to detect convex pentagons in an image using OpenCV. I am using the following image:



      enter image description here



      I first find the contours in the image and then do this:



      approx = cv2.approxPolyDP(c, 0.04 * perimeter, True)
      isPentagon = len(approx) == 5


      When I ran this on the image, I got this result:



      enter image description here



      This white part in the image is being detected. I thought that checking the concavity would solve it. Here is what I attempted:



      isPentagon = len(approx) == 5 and cv2.isContourConvex(c)


      However, for all the pentagons I tried, isContourConvex returned False. I am not sure why. I tried other images as well and the same happened. Variable c is the contour.



      Is there a way to fix this? Maybe a better way to check if a polygon is regular?










      share|improve this question














      I am attempting to detect convex pentagons in an image using OpenCV. I am using the following image:



      enter image description here



      I first find the contours in the image and then do this:



      approx = cv2.approxPolyDP(c, 0.04 * perimeter, True)
      isPentagon = len(approx) == 5


      When I ran this on the image, I got this result:



      enter image description here



      This white part in the image is being detected. I thought that checking the concavity would solve it. Here is what I attempted:



      isPentagon = len(approx) == 5 and cv2.isContourConvex(c)


      However, for all the pentagons I tried, isContourConvex returned False. I am not sure why. I tried other images as well and the same happened. Variable c is the contour.



      Is there a way to fix this? Maybe a better way to check if a polygon is regular?







      python opencv object-detection






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Mar 24 at 20:33









      Nick SolonkoNick Solonko

      294318




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          The issues was that I was passing in the original contour found by cv2.findContours into the cv2.isContourConvex. That original contour has a ton of points, some of which give the shape a concave characteristic.



          To fix this, I had to call cv2.isContourConvex(approx). This would evaluate the approximation of the pentagon that has exactly five sides and five vertices. Although I would later draw the initial contour, evaluating the contourConvex function on the approximation yielded the correct result.






          share|improve this answer























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            The issues was that I was passing in the original contour found by cv2.findContours into the cv2.isContourConvex. That original contour has a ton of points, some of which give the shape a concave characteristic.



            To fix this, I had to call cv2.isContourConvex(approx). This would evaluate the approximation of the pentagon that has exactly five sides and five vertices. Although I would later draw the initial contour, evaluating the contourConvex function on the approximation yielded the correct result.






            share|improve this answer



























              0














              The issues was that I was passing in the original contour found by cv2.findContours into the cv2.isContourConvex. That original contour has a ton of points, some of which give the shape a concave characteristic.



              To fix this, I had to call cv2.isContourConvex(approx). This would evaluate the approximation of the pentagon that has exactly five sides and five vertices. Although I would later draw the initial contour, evaluating the contourConvex function on the approximation yielded the correct result.






              share|improve this answer

























                0












                0








                0







                The issues was that I was passing in the original contour found by cv2.findContours into the cv2.isContourConvex. That original contour has a ton of points, some of which give the shape a concave characteristic.



                To fix this, I had to call cv2.isContourConvex(approx). This would evaluate the approximation of the pentagon that has exactly five sides and five vertices. Although I would later draw the initial contour, evaluating the contourConvex function on the approximation yielded the correct result.






                share|improve this answer













                The issues was that I was passing in the original contour found by cv2.findContours into the cv2.isContourConvex. That original contour has a ton of points, some of which give the shape a concave characteristic.



                To fix this, I had to call cv2.isContourConvex(approx). This would evaluate the approximation of the pentagon that has exactly five sides and five vertices. Although I would later draw the initial contour, evaluating the contourConvex function on the approximation yielded the correct result.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 24 at 22:50









                Nick SolonkoNick Solonko

                294318




                294318



























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