Why is a method body filled with semicolons acceptable syntax?Why are exclamation marks used in Ruby methods?Is it possible to write a plain old java program that runs on android?java compilation: classname Vs classname with file-extensionCompile all files in src?Eclipse Plugin Get Code from Current Open FileIs it possible to write a program in Java without main() using JDK 1.7 or higher?Why the main method should be in staticError: Main method not found in class MovieDatabaseJava - Method executed prior to Default Constructor
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Why is a method body filled with semicolons acceptable syntax?
Why are exclamation marks used in Ruby methods?Is it possible to write a plain old java program that runs on android?java compilation: classname Vs classname with file-extensionCompile all files in src?Eclipse Plugin Get Code from Current Open FileIs it possible to write a program in Java without main() using JDK 1.7 or higher?Why the main method should be in staticError: Main method not found in class MovieDatabaseJava - Method executed prior to Default Constructor
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
public static void main(String[] args)
System.out.println("World Hello!");;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;
;;;;;;;;;
;;;;;;;
;;;;;;;;;;;;;;
;;;;;
The normal person is me wants to say: "What are all of those semicolons doing there!?"
java methods
edited Mar 24 at 20:36
double-beep
3,14251632
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
add a comment |
public static void main(String[] args)
System.out.println("World Hello!");;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;
;;;;;;;;;
;;;;;;;
;;;;;;;;;;;;;;
;;;;;
The normal person is me wants to say: "What are all of those semicolons doing there!?"
java methods
edited Mar 24 at 20:36
double-beep
3,14251632
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
add a comment |
public static void main(String[] args)
System.out.println("World Hello!");;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;
;;;;;;;;;
;;;;;;;
;;;;;;;;;;;;;;
;;;;;
The normal person is me wants to say: "What are all of those semicolons doing there!?"
java methods
edited Mar 24 at 20:36
double-beep
3,14251632
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
public static void main(String[] args)
System.out.println("World Hello!");;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;;;;;
;;;;;;;;;
;;;;;;;
;;;;;;;;;;;;;;
;;;;;
The normal person is me wants to say: "What are all of those semicolons doing there!?"
java methods
java methods
edited Mar 24 at 20:36
double-beep
3,14251632
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
edited Mar 24 at 20:36
double-beep
3,14251632
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
edited Mar 24 at 20:36
double-beep
3,14251632
edited Mar 24 at 20:36
double-beep
3,14251632
edited Mar 24 at 20:36
double-beep
3,14251632
3,14251632
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
asked Apr 1 '14 at 23:01
ZeratasZeratas
4952931
4952931
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Because a simple semicolon next to another semicolon is an empty statement. So, lot of semi colons next to each other are lot of empty statements. It compiles and runs with no problems.
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
2
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
2
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
1
@peter.petrovwhile(true)?
– Luiggi Mendoza
Apr 1 '14 at 23:05
|
show 3 more comments
According to Oracle Java Language Specification:
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally.
Since the language it self allows consecutive semicolons, the compiler will not produce an error.
You could also check the bytecode to see what is happening, the code with a lot of ";" :
// Stack: 1, Locals: 1
public Duh1();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 15]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
and the code with only 1 ";" :
// Method descriptor #6 ()V
// Stack: 1, Locals: 1
public Duh2();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh2
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
As you can check the bytecode is exactly the same for both version with single ";" and consecutive multiple ";".
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
add a comment |
Because a semi-colon only symbolises a newline. This means that we can simpily write:
cout << "Hello Worldn"; return 0;
Without even writing on a newline. Keep in mind its more tidy to write on seperate lines.
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Because a simple semicolon next to another semicolon is an empty statement. So, lot of semi colons next to each other are lot of empty statements. It compiles and runs with no problems.
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
2
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
2
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
1
@peter.petrovwhile(true)?
– Luiggi Mendoza
Apr 1 '14 at 23:05
|
show 3 more comments
Because a simple semicolon next to another semicolon is an empty statement. So, lot of semi colons next to each other are lot of empty statements. It compiles and runs with no problems.
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
2
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
2
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
1
@peter.petrovwhile(true)?
– Luiggi Mendoza
Apr 1 '14 at 23:05
|
show 3 more comments
Because a simple semicolon next to another semicolon is an empty statement. So, lot of semi colons next to each other are lot of empty statements. It compiles and runs with no problems.
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
Because a simple semicolon next to another semicolon is an empty statement. So, lot of semi colons next to each other are lot of empty statements. It compiles and runs with no problems.
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
answered Apr 1 '14 at 23:02
Luiggi MendozaLuiggi Mendoza
75.2k10109232
75.2k10109232
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
2
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
2
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
1
@peter.petrovwhile(true)?
– Luiggi Mendoza
Apr 1 '14 at 23:05
|
show 3 more comments
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
2
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
2
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
1
@peter.petrovwhile(true)?
– Luiggi Mendoza
Apr 1 '14 at 23:05
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
So if you wanted to, you could have an infinite amount of empty statements?
– Zeratas
Apr 1 '14 at 23:03
2
2
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
@Sempus yes, you can. But as you noted in your question content, it is kinda ridiculous.
– Luiggi Mendoza
Apr 1 '14 at 23:03
2
2
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
There's nothing infinite in computing and in computers.
– peter.petrov
Apr 1 '14 at 23:03
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
@Sempus I think there's a limit to how long a method can be.
– Daniel Kaplan
Apr 1 '14 at 23:04
1
1
@peter.petrov
while(true)?– Luiggi Mendoza
Apr 1 '14 at 23:05
@peter.petrov
while(true)?– Luiggi Mendoza
Apr 1 '14 at 23:05
|
show 3 more comments
According to Oracle Java Language Specification:
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally.
Since the language it self allows consecutive semicolons, the compiler will not produce an error.
You could also check the bytecode to see what is happening, the code with a lot of ";" :
// Stack: 1, Locals: 1
public Duh1();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 15]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
and the code with only 1 ";" :
// Method descriptor #6 ()V
// Stack: 1, Locals: 1
public Duh2();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh2
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
As you can check the bytecode is exactly the same for both version with single ";" and consecutive multiple ";".
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
add a comment |
According to Oracle Java Language Specification:
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally.
Since the language it self allows consecutive semicolons, the compiler will not produce an error.
You could also check the bytecode to see what is happening, the code with a lot of ";" :
// Stack: 1, Locals: 1
public Duh1();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 15]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
and the code with only 1 ";" :
// Method descriptor #6 ()V
// Stack: 1, Locals: 1
public Duh2();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh2
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
As you can check the bytecode is exactly the same for both version with single ";" and consecutive multiple ";".
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
add a comment |
According to Oracle Java Language Specification:
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally.
Since the language it self allows consecutive semicolons, the compiler will not produce an error.
You could also check the bytecode to see what is happening, the code with a lot of ";" :
// Stack: 1, Locals: 1
public Duh1();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 15]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
and the code with only 1 ";" :
// Method descriptor #6 ()V
// Stack: 1, Locals: 1
public Duh2();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh2
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
As you can check the bytecode is exactly the same for both version with single ";" and consecutive multiple ";".
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
According to Oracle Java Language Specification:
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally.
Since the language it self allows consecutive semicolons, the compiler will not produce an error.
You could also check the bytecode to see what is happening, the code with a lot of ";" :
// Stack: 1, Locals: 1
public Duh1();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 15]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
and the code with only 1 ";" :
// Method descriptor #6 ()V
// Stack: 1, Locals: 1
public Duh2();
0 aload_0 [this]
1 invokespecial java.lang.Object() [8]
4 return
Line numbers:
[pc: 0, line: 3]
Local variable table:
[pc: 0, pc: 5] local: this index: 0 type: Duh2
// Method descriptor #15 ([Ljava/lang/String;)V
// Stack: 2, Locals: 1
public static void main(java.lang.String[] args);
0 getstatic java.lang.System.out : java.io.PrintStream [16]
3 ldc <String "World Hello!"> [22]
5 invokevirtual java.io.PrintStream.println(java.lang.String) : void [24]
8 return
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
Local variable table:
[pc: 0, pc: 9] local: args index: 0 type: java.lang.String[]
Line numbers:
[pc: 0, line: 5]
[pc: 8, line: 6]
As you can check the bytecode is exactly the same for both version with single ";" and consecutive multiple ";".
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
edited Apr 5 '14 at 16:52
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
answered Apr 1 '14 at 23:05
dreamcrashdreamcrash
13.9k134569
13.9k134569
add a comment |
add a comment |
Because a semi-colon only symbolises a newline. This means that we can simpily write:
cout << "Hello Worldn"; return 0;
Without even writing on a newline. Keep in mind its more tidy to write on seperate lines.
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
add a comment |
Because a semi-colon only symbolises a newline. This means that we can simpily write:
cout << "Hello Worldn"; return 0;
Without even writing on a newline. Keep in mind its more tidy to write on seperate lines.
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
add a comment |
Because a semi-colon only symbolises a newline. This means that we can simpily write:
cout << "Hello Worldn"; return 0;
Without even writing on a newline. Keep in mind its more tidy to write on seperate lines.
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
Because a semi-colon only symbolises a newline. This means that we can simpily write:
cout << "Hello Worldn"; return 0;
Without even writing on a newline. Keep in mind its more tidy to write on seperate lines.
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
answered Apr 2 '14 at 0:59
KinggadinoKinggadino
349
349
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