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Generate a string representing the decimal value of a given binary number
Add 2 numbers and print the result using Assembly x86print number to screen assemblyPrint out register in decimal without printfNASM Guessing Number Game Gone WrongHelp on VGA and putpixel intel x86 asm AT&T syntaxBase pointer and stack pointerHow to get window proc parameters?Calling C function from assembly, segfaultAssembly code for converting hex to dec is not workingFloating point exceptions in x86 NASM assembly using div instruction(VC++) Runtime Check for Uninitialized Variables: How is the test Implemented?NASM on linux: Using sys_read adds extra line at the endSafely Searching Virtual Address Space using NASM
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I'm trying to do an assignment linking c and nasm. The C program sends me a string representing a 32-bit number (e.g. "000...0011"). I need to print its value, as a string (the string "3" for the example above), using C's printf with %s.
Note: to make life easier, I'll ignore the case of negative numbers for now.
I'm new to nasm and so I pretty much have no clue what goes wrong where. I tried converting the given string to a number, store it somewhere, and then have it printed, but this simply prints the binary representation.
Here's my code:
.rodata section
format_string: db "%s", 10, 0 ; format string
.bss section
an: resb 12 ; enough to store integer in [-2,147,483,648 (-2^31) : 2,147,483,647 (2^31-1)]
convertor:
push ebp
mov ebp, esp
pushad
mov ecx, dword [ebp+8] ; get function argument (pointer to string)
mov eax, 1 ; initialize eax with 1 - this will serve as a multiplier
mov dword [an], 0 ; initialize an with 0
ecx_To_an:
cmp eax, 0 ; while eax != 0
jz done ; do :
shr dword [ecx], 1 ;
jnc carry_flag_not_set ; if carry isn't set, lsb was 0
add [an], eax ; else - lsb was 1 - an += eax
carry_flag_not_set:
shl eax, 1 ; eax = eax*2
jmp ecx_To_an ; go to the loop
done:
push an ; call printf with 2 arguments -
push format_string ; pointer to str and pointer to format string
call printf
I don't see how it can be possible to print the int value, given that I can't change the %s argument that is given to printf.
Help will be much appreciated.
assembly x86 nasm
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
|
show 28 more comments
I'm trying to do an assignment linking c and nasm. The C program sends me a string representing a 32-bit number (e.g. "000...0011"). I need to print its value, as a string (the string "3" for the example above), using C's printf with %s.
Note: to make life easier, I'll ignore the case of negative numbers for now.
I'm new to nasm and so I pretty much have no clue what goes wrong where. I tried converting the given string to a number, store it somewhere, and then have it printed, but this simply prints the binary representation.
Here's my code:
.rodata section
format_string: db "%s", 10, 0 ; format string
.bss section
an: resb 12 ; enough to store integer in [-2,147,483,648 (-2^31) : 2,147,483,647 (2^31-1)]
convertor:
push ebp
mov ebp, esp
pushad
mov ecx, dword [ebp+8] ; get function argument (pointer to string)
mov eax, 1 ; initialize eax with 1 - this will serve as a multiplier
mov dword [an], 0 ; initialize an with 0
ecx_To_an:
cmp eax, 0 ; while eax != 0
jz done ; do :
shr dword [ecx], 1 ;
jnc carry_flag_not_set ; if carry isn't set, lsb was 0
add [an], eax ; else - lsb was 1 - an += eax
carry_flag_not_set:
shl eax, 1 ; eax = eax*2
jmp ecx_To_an ; go to the loop
done:
push an ; call printf with 2 arguments -
push format_string ; pointer to str and pointer to format string
call printf
I don't see how it can be possible to print the int value, given that I can't change the %s argument that is given to printf.
Help will be much appreciated.
assembly x86 nasm
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
1
You will need to convert to decimal digits. Plenty of examples for that.
– Jester
Mar 26 at 0:50
3
Sample decimal conversion codes: 1 2 3 You can find plenty more.
– Jester
Mar 26 at 1:11
3
You never increment ecx, so you are only looking at the first 4 bytes of the string.
– prl
Mar 26 at 1:11
1
Well, can you write it in C? Obviously without using standard library functions. The logic is just repeated division by 10. PS: the first one I linked literally says in the comments ... "Convert EAX to ASCII and store it onto the stack" and "Pointer to the first ASCII digit" Heck, it even prints the string although usingwrite()notprintf("%s", ...)but those are basically equivalent.
– Jester
Mar 26 at 1:48
1
Keeping your data in registers is simpler, as well as more efficient. Since string->integer will leave the result in a register, you should keep it there instead of storing to memory. (Also, finding ways to use fewer instructions and/or cheaper instructions is the fun part of writing in asm.) But anyway, I think my answer that I linked about base10string-> integer is pretty understandable, and easy to adapt for base2string -> integer. Then you feed that integer to an integer->base10string function. Jester linked 3 existing Q&As about that part.
– Peter Cordes
Mar 26 at 20:10
|
show 28 more comments
I'm trying to do an assignment linking c and nasm. The C program sends me a string representing a 32-bit number (e.g. "000...0011"). I need to print its value, as a string (the string "3" for the example above), using C's printf with %s.
Note: to make life easier, I'll ignore the case of negative numbers for now.
I'm new to nasm and so I pretty much have no clue what goes wrong where. I tried converting the given string to a number, store it somewhere, and then have it printed, but this simply prints the binary representation.
Here's my code:
.rodata section
format_string: db "%s", 10, 0 ; format string
.bss section
an: resb 12 ; enough to store integer in [-2,147,483,648 (-2^31) : 2,147,483,647 (2^31-1)]
convertor:
push ebp
mov ebp, esp
pushad
mov ecx, dword [ebp+8] ; get function argument (pointer to string)
mov eax, 1 ; initialize eax with 1 - this will serve as a multiplier
mov dword [an], 0 ; initialize an with 0
ecx_To_an:
cmp eax, 0 ; while eax != 0
jz done ; do :
shr dword [ecx], 1 ;
jnc carry_flag_not_set ; if carry isn't set, lsb was 0
add [an], eax ; else - lsb was 1 - an += eax
carry_flag_not_set:
shl eax, 1 ; eax = eax*2
jmp ecx_To_an ; go to the loop
done:
push an ; call printf with 2 arguments -
push format_string ; pointer to str and pointer to format string
call printf
I don't see how it can be possible to print the int value, given that I can't change the %s argument that is given to printf.
Help will be much appreciated.
assembly x86 nasm
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
I'm trying to do an assignment linking c and nasm. The C program sends me a string representing a 32-bit number (e.g. "000...0011"). I need to print its value, as a string (the string "3" for the example above), using C's printf with %s.
Note: to make life easier, I'll ignore the case of negative numbers for now.
I'm new to nasm and so I pretty much have no clue what goes wrong where. I tried converting the given string to a number, store it somewhere, and then have it printed, but this simply prints the binary representation.
Here's my code:
.rodata section
format_string: db "%s", 10, 0 ; format string
.bss section
an: resb 12 ; enough to store integer in [-2,147,483,648 (-2^31) : 2,147,483,647 (2^31-1)]
convertor:
push ebp
mov ebp, esp
pushad
mov ecx, dword [ebp+8] ; get function argument (pointer to string)
mov eax, 1 ; initialize eax with 1 - this will serve as a multiplier
mov dword [an], 0 ; initialize an with 0
ecx_To_an:
cmp eax, 0 ; while eax != 0
jz done ; do :
shr dword [ecx], 1 ;
jnc carry_flag_not_set ; if carry isn't set, lsb was 0
add [an], eax ; else - lsb was 1 - an += eax
carry_flag_not_set:
shl eax, 1 ; eax = eax*2
jmp ecx_To_an ; go to the loop
done:
push an ; call printf with 2 arguments -
push format_string ; pointer to str and pointer to format string
call printf
I don't see how it can be possible to print the int value, given that I can't change the %s argument that is given to printf.
Help will be much appreciated.
assembly x86 nasm
assembly x86 nasm
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
edited Mar 26 at 0:50
Jester
47.5k4 gold badges50 silver badges87 bronze badges
47.5k4 gold badges50 silver badges87 bronze badges
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
asked Mar 26 at 0:49
J. DoeJ. Doe
11 bronze badge
11 bronze badge
1
You will need to convert to decimal digits. Plenty of examples for that.
– Jester
Mar 26 at 0:50
3
Sample decimal conversion codes: 1 2 3 You can find plenty more.
– Jester
Mar 26 at 1:11
3
You never increment ecx, so you are only looking at the first 4 bytes of the string.
– prl
Mar 26 at 1:11
1
Well, can you write it in C? Obviously without using standard library functions. The logic is just repeated division by 10. PS: the first one I linked literally says in the comments ... "Convert EAX to ASCII and store it onto the stack" and "Pointer to the first ASCII digit" Heck, it even prints the string although usingwrite()notprintf("%s", ...)but those are basically equivalent.
– Jester
Mar 26 at 1:48
1
Keeping your data in registers is simpler, as well as more efficient. Since string->integer will leave the result in a register, you should keep it there instead of storing to memory. (Also, finding ways to use fewer instructions and/or cheaper instructions is the fun part of writing in asm.) But anyway, I think my answer that I linked about base10string-> integer is pretty understandable, and easy to adapt for base2string -> integer. Then you feed that integer to an integer->base10string function. Jester linked 3 existing Q&As about that part.
– Peter Cordes
Mar 26 at 20:10
|
show 28 more comments
1
You will need to convert to decimal digits. Plenty of examples for that.
– Jester
Mar 26 at 0:50
3
Sample decimal conversion codes: 1 2 3 You can find plenty more.
– Jester
Mar 26 at 1:11
3
You never increment ecx, so you are only looking at the first 4 bytes of the string.
– prl
Mar 26 at 1:11
1
Well, can you write it in C? Obviously without using standard library functions. The logic is just repeated division by 10. PS: the first one I linked literally says in the comments ... "Convert EAX to ASCII and store it onto the stack" and "Pointer to the first ASCII digit" Heck, it even prints the string although usingwrite()notprintf("%s", ...)but those are basically equivalent.
– Jester
Mar 26 at 1:48
1
Keeping your data in registers is simpler, as well as more efficient. Since string->integer will leave the result in a register, you should keep it there instead of storing to memory. (Also, finding ways to use fewer instructions and/or cheaper instructions is the fun part of writing in asm.) But anyway, I think my answer that I linked about base10string-> integer is pretty understandable, and easy to adapt for base2string -> integer. Then you feed that integer to an integer->base10string function. Jester linked 3 existing Q&As about that part.
– Peter Cordes
Mar 26 at 20:10
1
1
You will need to convert to decimal digits. Plenty of examples for that.
– Jester
Mar 26 at 0:50
You will need to convert to decimal digits. Plenty of examples for that.
– Jester
Mar 26 at 0:50
3
3
Sample decimal conversion codes: 1 2 3 You can find plenty more.
– Jester
Mar 26 at 1:11
Sample decimal conversion codes: 1 2 3 You can find plenty more.
– Jester
Mar 26 at 1:11
3
3
You never increment ecx, so you are only looking at the first 4 bytes of the string.
– prl
Mar 26 at 1:11
You never increment ecx, so you are only looking at the first 4 bytes of the string.
– prl
Mar 26 at 1:11
1
1
Well, can you write it in C? Obviously without using standard library functions. The logic is just repeated division by 10. PS: the first one I linked literally says in the comments ... "Convert EAX to ASCII and store it onto the stack" and "Pointer to the first ASCII digit" Heck, it even prints the string although using
write() not printf("%s", ...) but those are basically equivalent.– Jester
Mar 26 at 1:48
Well, can you write it in C? Obviously without using standard library functions. The logic is just repeated division by 10. PS: the first one I linked literally says in the comments ... "Convert EAX to ASCII and store it onto the stack" and "Pointer to the first ASCII digit" Heck, it even prints the string although using
write() not printf("%s", ...) but those are basically equivalent.– Jester
Mar 26 at 1:48
1
1
Keeping your data in registers is simpler, as well as more efficient. Since string->integer will leave the result in a register, you should keep it there instead of storing to memory. (Also, finding ways to use fewer instructions and/or cheaper instructions is the fun part of writing in asm.) But anyway, I think my answer that I linked about base10string-> integer is pretty understandable, and easy to adapt for base2string -> integer. Then you feed that integer to an integer->base10string function. Jester linked 3 existing Q&As about that part.
– Peter Cordes
Mar 26 at 20:10
Keeping your data in registers is simpler, as well as more efficient. Since string->integer will leave the result in a register, you should keep it there instead of storing to memory. (Also, finding ways to use fewer instructions and/or cheaper instructions is the fun part of writing in asm.) But anyway, I think my answer that I linked about base10string-> integer is pretty understandable, and easy to adapt for base2string -> integer. Then you feed that integer to an integer->base10string function. Jester linked 3 existing Q&As about that part.
– Peter Cordes
Mar 26 at 20:10
|
show 28 more comments
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1
You will need to convert to decimal digits. Plenty of examples for that.
– Jester
Mar 26 at 0:50
3
Sample decimal conversion codes: 1 2 3 You can find plenty more.
– Jester
Mar 26 at 1:11
3
You never increment ecx, so you are only looking at the first 4 bytes of the string.
– prl
Mar 26 at 1:11
1
Well, can you write it in C? Obviously without using standard library functions. The logic is just repeated division by 10. PS: the first one I linked literally says in the comments ... "Convert EAX to ASCII and store it onto the stack" and "Pointer to the first ASCII digit" Heck, it even prints the string although using
write()notprintf("%s", ...)but those are basically equivalent.– Jester
Mar 26 at 1:48
1
Keeping your data in registers is simpler, as well as more efficient. Since string->integer will leave the result in a register, you should keep it there instead of storing to memory. (Also, finding ways to use fewer instructions and/or cheaper instructions is the fun part of writing in asm.) But anyway, I think my answer that I linked about base10string-> integer is pretty understandable, and easy to adapt for base2string -> integer. Then you feed that integer to an integer->base10string function. Jester linked 3 existing Q&As about that part.
– Peter Cordes
Mar 26 at 20:10