If I try to do the following:

things = 5
print("You have " + things + " things.")

I get the following error in Python 3.x:

Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
TypeError: must be str, not int

... and a similar error in Python 2.x:

Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
TypeError: cannot concatenate 'str' and 'int' objects

How can I get around this problem?

The problem here is that the + operator has (at least) two different meanings in Python: for numeric types, it means "add the numbers together":

>>> 1 + 2
3
>>> 3.4 + 5.6
9.0

... and for sequence types, it means "concatenate the sequences":

>>> [1, 2, 3] + [4, 5, 6]
[1, 2, 3, 4, 5, 6]
>>> 'abc' + 'def'
'abcdef'

As a rule, Python doesn't implicitly convert objects from one type to another¹ in order to make operations "make sense", because that would be confusing: for instance, you might think that '3' + 5 should mean '35', but someone else might think it should mean 8 or even '8'.

Similarly, Python won't let you concatenate two different types of sequence:

>>> [7, 8, 9] + 'ghi'
Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
TypeError: can only concatenate list (not "str") to list

Because of this, you need to do the conversion explicitly, whether what you want is concatenation or addition:

>>> 'Total: ' + str(123)
'Total: 123'
>>> int('456') + 789
1245

However, there is a better way. Depending on which version of Python you use, there are three different kinds of string formatting available², which not only allow you to avoid multiple + operations:

>>> things = 5

>>> 'You have %d things.' % things # % interpolation
'You have 5 things.'

>>> 'You have things.'.format(things) # str.format()
'You have 5 things.'

>>> f'You have things things.' # f-string (since Python 3.6)
'You have 5 things.'

... but also allow you to control how values are displayed:

>>> value = 5
>>> sq_root = value ** 0.5
>>> sq_root
2.23606797749979

>>> 'The square root of %d is %.2f (roughly).' % (value, sq_root)
'The square root of 5 is 2.24 (roughly).'

>>> 'The square root of v is sr:.2f (roughly).'.format(v=value, sr=sq_root)
'The square root of 5 is 2.24 (roughly).'

>>> f'The square root of value is sq_root:.2f (roughly).'
'The square root of 5 is 2.24 (roughly).'

Whether you use % interpolation, str.format(), or f-strings is up to you: % interpolation has been around the longest (and is familiar to people with a background in C), str.format() is often more powerful, and f-strings are more powerful still (but available only in Python 3.6 and later).

Another alternative is to use the fact that if you give print multiple positional arguments, it will join their string representations together using the sep keyword argument (which defaults to ' '):

>>> things = 5
>>> print('you have', things, 'things.')
you have 5 things.
>>> print('you have', things, 'things.', sep=' ... ')
you have ... 5 ... things.

... but that's usually not as flexible as using Python's built-in string formatting abilities.

¹ Although it makes an exception for numeric types, where most people would agree on the 'right' thing to do:

>>> 1 + 2.3
3.3
>>> 4.5 + (5.6+7j)
(10.1+7j)

² Actually four ... but template strings are rarely used and somewhat awkward.

TL;DR

1. either: print("You have " + str(things) + " things.") (the old
   school way)




2. or: print("You have things.".format(things)) (the new pythonic
   and recommended way)

A bit more verbal explanation:

Although there is anything not covered from the excellent @Zero Piraeus answer above, I will try to "minify" it a bit:

You cannot concatenate a string and a number (of any kind) in python because those objects have different definitions of the plus(+) operator which are not compatible with each other (In the str case + is used for concatenation, in the number case it is used to add two numbers together).
So in order to solve this "misunderstanding" between objects:

1. The old school way is to cast the number to string with the
   str(anything) method and then concatenate the result with another
   string.


2. The more pythonic and recommended way is to use the format method which is very versatile (you don't have to take my word on it, read the documentation and this article)

Have fun and do read the @Zero Piraeus answer it surely worth your time!

Python 2.x

1. 
   'You have %d things.' % things [1]


2. 
   'You have things.'.format(things) [2]

Python 3.6+

1. 
   'You have %d things.' % things [1]


2. 
   'You have things.'.format(things) [2]


3. 
   f'You have things things.' [3]

Reference

1. printf-style String Formatting


2. Built-in types -> str.format


3. Formatted string literals

str.format()

Another alternative is using str.format() method to concatenate an int into a String.

In your case:

Replace

print("You have " + things + " things.")

With

print("You have things".format(things))

Bonus: for multiple concatenation

if you have

first = 'rohit'
last = 'singh'
age = '5'
print("My Username is ".format(first,age,last))