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INSERT INTO or Update


Can I concatenate multiple MySQL rows into one field?“INSERT IGNORE” vs “INSERT … ON DUPLICATE KEY UPDATE”How to 'insert if not exists' in MySQL?INSERT INTO … SELECT FROM … ON DUPLICATE KEY UPDATEHow to import CSV file to MySQL tableInsert into a MySQL table or update if existsmysql -> insert into tbl (select from another table) and some default valuesSQL query return data from multiple tablesInsert if DNE else update Mysql rowHow get selected rows where user id is not in table record mysql






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















My code updates same row multiple times in one query with values from another table. How to update or create a new record in one query? How to do that if there is no record "forum_users_posts_in" with matching data



userid 
idcat
idcustom
create a new record (t.posts = 1)


If such a record exists then update it only (t.posts = t2.sum_total)



UPDATE #__forum_users_posts_in AS t
JOIN (
SELECT
userid, count(*) AS sum_total
FROM
#__forum_messages AS t2
WHERE
T2.thread = '.$topicId.' and hold = 0
GROUP BY
t2.userid
) AS t2 ON t.userid = t2.userid and (idcat = '.$cat->id.' or idcustom = '.$selectcustom1.')
SET t.posts = t.posts + t2.sum_total









share|improve this question






























    0















    My code updates same row multiple times in one query with values from another table. How to update or create a new record in one query? How to do that if there is no record "forum_users_posts_in" with matching data



    userid 
    idcat
    idcustom
    create a new record (t.posts = 1)


    If such a record exists then update it only (t.posts = t2.sum_total)



    UPDATE #__forum_users_posts_in AS t
    JOIN (
    SELECT
    userid, count(*) AS sum_total
    FROM
    #__forum_messages AS t2
    WHERE
    T2.thread = '.$topicId.' and hold = 0
    GROUP BY
    t2.userid
    ) AS t2 ON t.userid = t2.userid and (idcat = '.$cat->id.' or idcustom = '.$selectcustom1.')
    SET t.posts = t.posts + t2.sum_total









    share|improve this question


























      0












      0








      0








      My code updates same row multiple times in one query with values from another table. How to update or create a new record in one query? How to do that if there is no record "forum_users_posts_in" with matching data



      userid 
      idcat
      idcustom
      create a new record (t.posts = 1)


      If such a record exists then update it only (t.posts = t2.sum_total)



      UPDATE #__forum_users_posts_in AS t
      JOIN (
      SELECT
      userid, count(*) AS sum_total
      FROM
      #__forum_messages AS t2
      WHERE
      T2.thread = '.$topicId.' and hold = 0
      GROUP BY
      t2.userid
      ) AS t2 ON t.userid = t2.userid and (idcat = '.$cat->id.' or idcustom = '.$selectcustom1.')
      SET t.posts = t.posts + t2.sum_total









      share|improve this question
















      My code updates same row multiple times in one query with values from another table. How to update or create a new record in one query? How to do that if there is no record "forum_users_posts_in" with matching data



      userid 
      idcat
      idcustom
      create a new record (t.posts = 1)


      If such a record exists then update it only (t.posts = t2.sum_total)



      UPDATE #__forum_users_posts_in AS t
      JOIN (
      SELECT
      userid, count(*) AS sum_total
      FROM
      #__forum_messages AS t2
      WHERE
      T2.thread = '.$topicId.' and hold = 0
      GROUP BY
      t2.userid
      ) AS t2 ON t.userid = t2.userid and (idcat = '.$cat->id.' or idcustom = '.$selectcustom1.')
      SET t.posts = t.posts + t2.sum_total






      php mysql insert-into






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 26 at 10:57









      Jay Blanchard

      36.4k12 gold badges57 silver badges100 bronze badges




      36.4k12 gold badges57 silver badges100 bronze badges










      asked Mar 26 at 10:52









      waxmanwaxman

      31 bronze badge




      31 bronze badge






















          1 Answer
          1






          active

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          0














          You can try this method to create or edit row



          INSERT INTO `table` (`columns`) VALUES
          (...)
          ON DUPLICATE KEY UPDATE
          `column` = VALUES (`column`);





          share|improve this answer






















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            1 Answer
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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            You can try this method to create or edit row



            INSERT INTO `table` (`columns`) VALUES
            (...)
            ON DUPLICATE KEY UPDATE
            `column` = VALUES (`column`);





            share|improve this answer



























              0














              You can try this method to create or edit row



              INSERT INTO `table` (`columns`) VALUES
              (...)
              ON DUPLICATE KEY UPDATE
              `column` = VALUES (`column`);





              share|improve this answer

























                0












                0








                0







                You can try this method to create or edit row



                INSERT INTO `table` (`columns`) VALUES
                (...)
                ON DUPLICATE KEY UPDATE
                `column` = VALUES (`column`);





                share|improve this answer













                You can try this method to create or edit row



                INSERT INTO `table` (`columns`) VALUES
                (...)
                ON DUPLICATE KEY UPDATE
                `column` = VALUES (`column`);






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 26 at 11:00









                SonOfWinterSonOfWinter

                336 bronze badges




                336 bronze badges
















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