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mutableListOf(mutableListOf()) return an array of array with a size equal to 1 when it's first declared
How do I determine the size of my array in C?What’s the difference between “Array()” and “[]” while declaring a JavaScript array?Getting a sub-array from an existing arrayGet first key in a (possibly) associative array?Grab a segment of an array in Java without creating a new array on heapAny way to declare an array in-line?How do I declare and initialize an array in Java?How to extend an existing JavaScript array with another array, without creating a new arrayGet the first element of an arrayHow to initialize an array's length in javascript?
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When I create a matrix (Array of Array) with the following declaration the returned size is 1 instead of 0 :
var matrix: MutableList<MutableList<Cell>> = mutableListOf(mutableListOf())
which lead to having a size equal to 2 when I add the first array to the matrix :
matrix.add(lineOfCells)
matrix now contain a first empty array at index 0 and lineOfCells array at index 1, but what I'm looking for is just to have lineOfCells at index 0.
arrays kotlin
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
add a comment |
When I create a matrix (Array of Array) with the following declaration the returned size is 1 instead of 0 :
var matrix: MutableList<MutableList<Cell>> = mutableListOf(mutableListOf())
which lead to having a size equal to 2 when I add the first array to the matrix :
matrix.add(lineOfCells)
matrix now contain a first empty array at index 0 and lineOfCells array at index 1, but what I'm looking for is just to have lineOfCells at index 0.
arrays kotlin
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
4
Well, yes, since mutableListOf() creates and returns a List, and you're thus creatng a list containing a list. Just don't:var matrix: MutableList<MutableList<Cell>> = mutableListOf()
– JB Nizet
Mar 26 at 22:48
add a comment |
When I create a matrix (Array of Array) with the following declaration the returned size is 1 instead of 0 :
var matrix: MutableList<MutableList<Cell>> = mutableListOf(mutableListOf())
which lead to having a size equal to 2 when I add the first array to the matrix :
matrix.add(lineOfCells)
matrix now contain a first empty array at index 0 and lineOfCells array at index 1, but what I'm looking for is just to have lineOfCells at index 0.
arrays kotlin
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
When I create a matrix (Array of Array) with the following declaration the returned size is 1 instead of 0 :
var matrix: MutableList<MutableList<Cell>> = mutableListOf(mutableListOf())
which lead to having a size equal to 2 when I add the first array to the matrix :
matrix.add(lineOfCells)
matrix now contain a first empty array at index 0 and lineOfCells array at index 1, but what I'm looking for is just to have lineOfCells at index 0.
arrays kotlin
arrays kotlin
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
asked Mar 26 at 21:23
ChuloChulo
5,83911 gold badges47 silver badges67 bronze badges
5,83911 gold badges47 silver badges67 bronze badges
4
Well, yes, since mutableListOf() creates and returns a List, and you're thus creatng a list containing a list. Just don't:var matrix: MutableList<MutableList<Cell>> = mutableListOf()
– JB Nizet
Mar 26 at 22:48
add a comment |
4
Well, yes, since mutableListOf() creates and returns a List, and you're thus creatng a list containing a list. Just don't:var matrix: MutableList<MutableList<Cell>> = mutableListOf()
– JB Nizet
Mar 26 at 22:48
4
4
Well, yes, since mutableListOf() creates and returns a List, and you're thus creatng a list containing a list. Just don't:
var matrix: MutableList<MutableList<Cell>> = mutableListOf()– JB Nizet
Mar 26 at 22:48
Well, yes, since mutableListOf() creates and returns a List, and you're thus creatng a list containing a list. Just don't:
var matrix: MutableList<MutableList<Cell>> = mutableListOf()– JB Nizet
Mar 26 at 22:48
add a comment |
1 Answer
1
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oldest
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You have an [0][0] cell, what looks like[[]] this, from the beginning so it means when you are adding one you have a second line of cells.
Or try
var matrix: MutableList> = mutableListOf()
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
add a comment |
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1 Answer
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1 Answer
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You have an [0][0] cell, what looks like[[]] this, from the beginning so it means when you are adding one you have a second line of cells.
Or try
var matrix: MutableList> = mutableListOf()
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
add a comment |
You have an [0][0] cell, what looks like[[]] this, from the beginning so it means when you are adding one you have a second line of cells.
Or try
var matrix: MutableList> = mutableListOf()
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
add a comment |
You have an [0][0] cell, what looks like[[]] this, from the beginning so it means when you are adding one you have a second line of cells.
Or try
var matrix: MutableList> = mutableListOf()
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
You have an [0][0] cell, what looks like[[]] this, from the beginning so it means when you are adding one you have a second line of cells.
Or try
var matrix: MutableList> = mutableListOf()
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
answered Mar 27 at 10:25
SuperSaiyanJSTNSuperSaiyanJSTN
284 bronze badges
284 bronze badges
add a comment |
add a comment |
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4
Well, yes, since mutableListOf() creates and returns a List, and you're thus creatng a list containing a list. Just don't:
var matrix: MutableList<MutableList<Cell>> = mutableListOf()– JB Nizet
Mar 26 at 22:48