SQL recursive query with multiple references to same tableAdd a column with a default value to an existing table in SQL ServerHow to concatenate text from multiple rows into a single text string in SQL server?SQL update from one Table to another based on a ID matchInserting multiple rows in a single SQL query?SQL multiple column orderingFinding duplicate values in a SQL tableWhat are the options for storing hierarchical data in a relational database?Find all tables containing column with specified name - MS SQL ServerHow to drop a table if it exists in SQL Server?SQL query return data from multiple tables

Three Dots in Center Page

Applications of pure mathematics in operations research

What would the United Kingdom's "optimal" Brexit deal look like?

What are the cons of stateless password generators?

Can I attune a Circlet of Human Perfection to my animated skeletons to allow them to blend in and speak?

Why would anyone ever invest in a cash-only etf?

Can a US President, after impeachment and removal, be re-elected or re-appointed?

What force enables us to walk? Friction or normal reaction?

Antonym of "Megalomania"

Are all French verb conjugation tenses and moods practical and efficient?

Unknown indication below upper stave

Is it okay for me to decline a project on ethical grounds?

Word for giving preference to the oldest child

What are the closest international airports in different countries?

Just how much information should you share with a former client?

Why would an invisible personal shield be necessary?

Correct word for a little toy that always stands up?

How to innovate in OR

Word for soundtrack music which is part of the action of the movie

How can flights operated by the same company have such different prices when marketed by another?

How to choose using Collection<Id> rather than Collection<String>, or the opposite?

How to prevent a single-element caster from being useless against immune foes?

Why does calling cout.operator<<(const char*) print the address instead of the character string?

Can you continue the movement of a Bonus Action Dash granted by Expeditious Retreat if your Concentration is broken mid-move?



SQL recursive query with multiple references to same table


Add a column with a default value to an existing table in SQL ServerHow to concatenate text from multiple rows into a single text string in SQL server?SQL update from one Table to another based on a ID matchInserting multiple rows in a single SQL query?SQL multiple column orderingFinding duplicate values in a SQL tableWhat are the options for storing hierarchical data in a relational database?Find all tables containing column with specified name - MS SQL ServerHow to drop a table if it exists in SQL Server?SQL query return data from multiple tables






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















Is there way to solve this problem with some sort of recursive SQL query (MySQL) rather than programmatically doing it.



I have two tables, one contains packages id and name, the other one contains id of package and parent_id which is also reference to id of some other package. What I need to achieve is to get list of all id of packages which contain some specific package.



Below is an example of tables and desired output if I'm looking for package with id 8. Package 8 is part of package 5 and 6, but package 6 is part of package 1 and 4. So, I need all of that ids as array(1,4,5,6).



packages table:



+----+-----------+
| id | name |
+----+-----------+
| 1 | package 1 |
| 2 | package 2 |
| 3 | package 3 |
| 4 | package 4 |
| 5 | package 5 |
| 6 | package 6 |
| 7 | package 7 |
| 8 | package 8 |
+----+-----------+


part_of table:



+----+-----------+
| id | parent_id |
+----+-----------+
| 6 | 1 |
| 6 | 4 |
| 8 | 5 |
| 8 | 6 |
+----+-----------+


output:



+----+
| id |
+----+
| 1 |
| 4 |
| 5 |
| 6 |
+----+


EDIT: To explain a bit better what this all was about. This packages table is actually car parts table, which also includes price and many more fields. If we look for "timing belt" part, it can be standalone, can be part of some bundle, we call it "timing belt set" or can be part of "full service" at workshop. All of them, "timing belt", "timing belt set", "full service" are stored in same table. Now, when customer comes asking for "timing belt", I can offer him standalone for 50$ or in set for 150$ or I can offer full service for 250$. All of them includes "timing belt" he asked for.










share|improve this question


























  • Have you tried to write a query? Post what you have tried and what you have difficulties with and we can try to help.

    – clinomaniac
    Mar 26 at 21:40











  • No, I didn't because I'm not quite familiar with sql querying. So I wrote in php recursive function which uses more simple query. Get all parent_id for id 8, then foreach parent_id call function again. Results of all function calls are merged into one master array.

    – Igor Pejašinović
    Mar 26 at 21:48











  • MySQL only supports recursive CTEs in v8+. What version are you using?

    – Gordon Linoff
    Mar 26 at 21:50






  • 1





    MySQL 8.0 and MariaDB 10.2+ have recursive CTEs which will make this answer quite easy.

    – danblack
    Mar 26 at 21:52











  • mysql Ver 8.0.15 for Linux on x86_64 (MySQL Community Server - GPL)

    – Igor Pejašinović
    Mar 26 at 22:00

















2















Is there way to solve this problem with some sort of recursive SQL query (MySQL) rather than programmatically doing it.



I have two tables, one contains packages id and name, the other one contains id of package and parent_id which is also reference to id of some other package. What I need to achieve is to get list of all id of packages which contain some specific package.



Below is an example of tables and desired output if I'm looking for package with id 8. Package 8 is part of package 5 and 6, but package 6 is part of package 1 and 4. So, I need all of that ids as array(1,4,5,6).



packages table:



+----+-----------+
| id | name |
+----+-----------+
| 1 | package 1 |
| 2 | package 2 |
| 3 | package 3 |
| 4 | package 4 |
| 5 | package 5 |
| 6 | package 6 |
| 7 | package 7 |
| 8 | package 8 |
+----+-----------+


part_of table:



+----+-----------+
| id | parent_id |
+----+-----------+
| 6 | 1 |
| 6 | 4 |
| 8 | 5 |
| 8 | 6 |
+----+-----------+


output:



+----+
| id |
+----+
| 1 |
| 4 |
| 5 |
| 6 |
+----+


EDIT: To explain a bit better what this all was about. This packages table is actually car parts table, which also includes price and many more fields. If we look for "timing belt" part, it can be standalone, can be part of some bundle, we call it "timing belt set" or can be part of "full service" at workshop. All of them, "timing belt", "timing belt set", "full service" are stored in same table. Now, when customer comes asking for "timing belt", I can offer him standalone for 50$ or in set for 150$ or I can offer full service for 250$. All of them includes "timing belt" he asked for.










share|improve this question


























  • Have you tried to write a query? Post what you have tried and what you have difficulties with and we can try to help.

    – clinomaniac
    Mar 26 at 21:40











  • No, I didn't because I'm not quite familiar with sql querying. So I wrote in php recursive function which uses more simple query. Get all parent_id for id 8, then foreach parent_id call function again. Results of all function calls are merged into one master array.

    – Igor Pejašinović
    Mar 26 at 21:48











  • MySQL only supports recursive CTEs in v8+. What version are you using?

    – Gordon Linoff
    Mar 26 at 21:50






  • 1





    MySQL 8.0 and MariaDB 10.2+ have recursive CTEs which will make this answer quite easy.

    – danblack
    Mar 26 at 21:52











  • mysql Ver 8.0.15 for Linux on x86_64 (MySQL Community Server - GPL)

    – Igor Pejašinović
    Mar 26 at 22:00













2












2








2








Is there way to solve this problem with some sort of recursive SQL query (MySQL) rather than programmatically doing it.



I have two tables, one contains packages id and name, the other one contains id of package and parent_id which is also reference to id of some other package. What I need to achieve is to get list of all id of packages which contain some specific package.



Below is an example of tables and desired output if I'm looking for package with id 8. Package 8 is part of package 5 and 6, but package 6 is part of package 1 and 4. So, I need all of that ids as array(1,4,5,6).



packages table:



+----+-----------+
| id | name |
+----+-----------+
| 1 | package 1 |
| 2 | package 2 |
| 3 | package 3 |
| 4 | package 4 |
| 5 | package 5 |
| 6 | package 6 |
| 7 | package 7 |
| 8 | package 8 |
+----+-----------+


part_of table:



+----+-----------+
| id | parent_id |
+----+-----------+
| 6 | 1 |
| 6 | 4 |
| 8 | 5 |
| 8 | 6 |
+----+-----------+


output:



+----+
| id |
+----+
| 1 |
| 4 |
| 5 |
| 6 |
+----+


EDIT: To explain a bit better what this all was about. This packages table is actually car parts table, which also includes price and many more fields. If we look for "timing belt" part, it can be standalone, can be part of some bundle, we call it "timing belt set" or can be part of "full service" at workshop. All of them, "timing belt", "timing belt set", "full service" are stored in same table. Now, when customer comes asking for "timing belt", I can offer him standalone for 50$ or in set for 150$ or I can offer full service for 250$. All of them includes "timing belt" he asked for.










share|improve this question
















Is there way to solve this problem with some sort of recursive SQL query (MySQL) rather than programmatically doing it.



I have two tables, one contains packages id and name, the other one contains id of package and parent_id which is also reference to id of some other package. What I need to achieve is to get list of all id of packages which contain some specific package.



Below is an example of tables and desired output if I'm looking for package with id 8. Package 8 is part of package 5 and 6, but package 6 is part of package 1 and 4. So, I need all of that ids as array(1,4,5,6).



packages table:



+----+-----------+
| id | name |
+----+-----------+
| 1 | package 1 |
| 2 | package 2 |
| 3 | package 3 |
| 4 | package 4 |
| 5 | package 5 |
| 6 | package 6 |
| 7 | package 7 |
| 8 | package 8 |
+----+-----------+


part_of table:



+----+-----------+
| id | parent_id |
+----+-----------+
| 6 | 1 |
| 6 | 4 |
| 8 | 5 |
| 8 | 6 |
+----+-----------+


output:



+----+
| id |
+----+
| 1 |
| 4 |
| 5 |
| 6 |
+----+


EDIT: To explain a bit better what this all was about. This packages table is actually car parts table, which also includes price and many more fields. If we look for "timing belt" part, it can be standalone, can be part of some bundle, we call it "timing belt set" or can be part of "full service" at workshop. All of them, "timing belt", "timing belt set", "full service" are stored in same table. Now, when customer comes asking for "timing belt", I can offer him standalone for 50$ or in set for 150$ or I can offer full service for 250$. All of them includes "timing belt" he asked for.







mysql sql recursive-query






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 27 at 0:28







Igor Pejašinović

















asked Mar 26 at 21:36









Igor PejašinovićIgor Pejašinović

187 bronze badges




187 bronze badges















  • Have you tried to write a query? Post what you have tried and what you have difficulties with and we can try to help.

    – clinomaniac
    Mar 26 at 21:40











  • No, I didn't because I'm not quite familiar with sql querying. So I wrote in php recursive function which uses more simple query. Get all parent_id for id 8, then foreach parent_id call function again. Results of all function calls are merged into one master array.

    – Igor Pejašinović
    Mar 26 at 21:48











  • MySQL only supports recursive CTEs in v8+. What version are you using?

    – Gordon Linoff
    Mar 26 at 21:50






  • 1





    MySQL 8.0 and MariaDB 10.2+ have recursive CTEs which will make this answer quite easy.

    – danblack
    Mar 26 at 21:52











  • mysql Ver 8.0.15 for Linux on x86_64 (MySQL Community Server - GPL)

    – Igor Pejašinović
    Mar 26 at 22:00

















  • Have you tried to write a query? Post what you have tried and what you have difficulties with and we can try to help.

    – clinomaniac
    Mar 26 at 21:40











  • No, I didn't because I'm not quite familiar with sql querying. So I wrote in php recursive function which uses more simple query. Get all parent_id for id 8, then foreach parent_id call function again. Results of all function calls are merged into one master array.

    – Igor Pejašinović
    Mar 26 at 21:48











  • MySQL only supports recursive CTEs in v8+. What version are you using?

    – Gordon Linoff
    Mar 26 at 21:50






  • 1





    MySQL 8.0 and MariaDB 10.2+ have recursive CTEs which will make this answer quite easy.

    – danblack
    Mar 26 at 21:52











  • mysql Ver 8.0.15 for Linux on x86_64 (MySQL Community Server - GPL)

    – Igor Pejašinović
    Mar 26 at 22:00
















Have you tried to write a query? Post what you have tried and what you have difficulties with and we can try to help.

– clinomaniac
Mar 26 at 21:40





Have you tried to write a query? Post what you have tried and what you have difficulties with and we can try to help.

– clinomaniac
Mar 26 at 21:40













No, I didn't because I'm not quite familiar with sql querying. So I wrote in php recursive function which uses more simple query. Get all parent_id for id 8, then foreach parent_id call function again. Results of all function calls are merged into one master array.

– Igor Pejašinović
Mar 26 at 21:48





No, I didn't because I'm not quite familiar with sql querying. So I wrote in php recursive function which uses more simple query. Get all parent_id for id 8, then foreach parent_id call function again. Results of all function calls are merged into one master array.

– Igor Pejašinović
Mar 26 at 21:48













MySQL only supports recursive CTEs in v8+. What version are you using?

– Gordon Linoff
Mar 26 at 21:50





MySQL only supports recursive CTEs in v8+. What version are you using?

– Gordon Linoff
Mar 26 at 21:50




1




1





MySQL 8.0 and MariaDB 10.2+ have recursive CTEs which will make this answer quite easy.

– danblack
Mar 26 at 21:52





MySQL 8.0 and MariaDB 10.2+ have recursive CTEs which will make this answer quite easy.

– danblack
Mar 26 at 21:52













mysql Ver 8.0.15 for Linux on x86_64 (MySQL Community Server - GPL)

– Igor Pejašinović
Mar 26 at 22:00





mysql Ver 8.0.15 for Linux on x86_64 (MySQL Community Server - GPL)

– Igor Pejašinović
Mar 26 at 22:00












3 Answers
3






active

oldest

votes


















2














You should be able to achieve this using a MySQL recursive common table expression:



WITH RECURSIVE cte AS (
SELECT id, parent_id FROM part_of WHERE id = 8
UNION ALL
SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
)
SELECT parent_id FROM cte


Demo on DB fiddle:



| parent_id |
| --------- |
| 5 |
| 6 |
| 1 |
| 4 |



You can JOIN the results with the products table to show the name of each parent product:



WITH RECURSIVE cte AS (
SELECT id, parent_id FROM part_of WHERE id = 8
UNION ALL
SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
)
SELECT cte.parent_id, p.name
FROM cte
INNER JOIN packages p on cte.parent_id = p.id


Demo on DB Fiddle:



| parent_id | name |
| --------- | --------- |
| 1 | package 1 |
| 4 | package 4 |
| 5 | package 5 |
| 6 | package 6 |





share|improve this answer



























  • I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

    – MhQ-6
    Mar 26 at 22:58







  • 1





    @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

    – Igor Pejašinović
    Mar 27 at 0:09


















0














Why not use part_of table twice ? join the part-of table itself self join and then query for the id ? it really depends on what level of recursion you are looking for i guess.






share|improve this answer
































    0














    I writing this answer assuming that you will need the packages tables to get the ID, which will then be used to get the parent_id from the part_of table. This part was a bit unclear in your question. If I am wrong in assuming this, then @GBM answer will work as well, as well as mine.



    WITH PACKAGES_CTE AS (
    SELECT PACKAGES.ID, PACKAGES.NAME
    FROM PACKAGES
    ), PACKAGES2_CTE AS
    (
    SELECT *
    FROM PACKAGES2
    )

    SELECT P2.PARENT_ID
    FROM PACKAGES2_CTE P2
    LEFT JOIN PACKAGES2_CTE P3 ON P3.PARENT_ID = P2.ID
    WHERE P3.ID = 8

    UNION ALL

    SELECT P2.PARENT_ID
    FROM PACKAGES_CTE P
    LEFT JOIN PACKAGES2_CTE P2 ON P.ID = P2.ID
    WHERE P2.ID = P2.PARENT_ID OR P.ID = 8


    If you have any questions feel free to ask. I did test this using the sample data you provided. Since I already knew the ID, I did not need to use the Packages.Name. I assume you will want to use Packages.Name = 'Package 8' instead of P.ID = 8.



    This was an interesting problem!






    share|improve this answer

























    • packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

      – Igor Pejašinović
      Mar 27 at 0:11













    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55366572%2fsql-recursive-query-with-multiple-references-to-same-table%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    You should be able to achieve this using a MySQL recursive common table expression:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT parent_id FROM cte


    Demo on DB fiddle:



    | parent_id |
    | --------- |
    | 5 |
    | 6 |
    | 1 |
    | 4 |



    You can JOIN the results with the products table to show the name of each parent product:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT cte.parent_id, p.name
    FROM cte
    INNER JOIN packages p on cte.parent_id = p.id


    Demo on DB Fiddle:



    | parent_id | name |
    | --------- | --------- |
    | 1 | package 1 |
    | 4 | package 4 |
    | 5 | package 5 |
    | 6 | package 6 |





    share|improve this answer



























    • I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

      – MhQ-6
      Mar 26 at 22:58







    • 1





      @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

      – Igor Pejašinović
      Mar 27 at 0:09















    2














    You should be able to achieve this using a MySQL recursive common table expression:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT parent_id FROM cte


    Demo on DB fiddle:



    | parent_id |
    | --------- |
    | 5 |
    | 6 |
    | 1 |
    | 4 |



    You can JOIN the results with the products table to show the name of each parent product:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT cte.parent_id, p.name
    FROM cte
    INNER JOIN packages p on cte.parent_id = p.id


    Demo on DB Fiddle:



    | parent_id | name |
    | --------- | --------- |
    | 1 | package 1 |
    | 4 | package 4 |
    | 5 | package 5 |
    | 6 | package 6 |





    share|improve this answer



























    • I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

      – MhQ-6
      Mar 26 at 22:58







    • 1





      @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

      – Igor Pejašinović
      Mar 27 at 0:09













    2












    2








    2







    You should be able to achieve this using a MySQL recursive common table expression:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT parent_id FROM cte


    Demo on DB fiddle:



    | parent_id |
    | --------- |
    | 5 |
    | 6 |
    | 1 |
    | 4 |



    You can JOIN the results with the products table to show the name of each parent product:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT cte.parent_id, p.name
    FROM cte
    INNER JOIN packages p on cte.parent_id = p.id


    Demo on DB Fiddle:



    | parent_id | name |
    | --------- | --------- |
    | 1 | package 1 |
    | 4 | package 4 |
    | 5 | package 5 |
    | 6 | package 6 |





    share|improve this answer















    You should be able to achieve this using a MySQL recursive common table expression:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT parent_id FROM cte


    Demo on DB fiddle:



    | parent_id |
    | --------- |
    | 5 |
    | 6 |
    | 1 |
    | 4 |



    You can JOIN the results with the products table to show the name of each parent product:



    WITH RECURSIVE cte AS (
    SELECT id, parent_id FROM part_of WHERE id = 8
    UNION ALL
    SELECT po.id, po.parent_id FROM part_of po INNER JOIN cte ON cte.parent_id = po.id
    )
    SELECT cte.parent_id, p.name
    FROM cte
    INNER JOIN packages p on cte.parent_id = p.id


    Demo on DB Fiddle:



    | parent_id | name |
    | --------- | --------- |
    | 1 | package 1 |
    | 4 | package 4 |
    | 5 | package 5 |
    | 6 | package 6 |






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 26 at 23:21

























    answered Mar 26 at 22:56









    GMBGMB

    22.3k6 gold badges11 silver badges28 bronze badges




    22.3k6 gold badges11 silver badges28 bronze badges















    • I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

      – MhQ-6
      Mar 26 at 22:58







    • 1





      @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

      – Igor Pejašinović
      Mar 27 at 0:09

















    • I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

      – MhQ-6
      Mar 26 at 22:58







    • 1





      @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

      – Igor Pejašinović
      Mar 27 at 0:09
















    I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

    – MhQ-6
    Mar 26 at 22:58






    I am pretty sure he will still need to the packages table. I his example, he uses package 8. I assume he wants to get the ID for package 8 and then join onto the part_of table. I could be wrong, hopefully @IgorPejašinović will provide some insight.

    – MhQ-6
    Mar 26 at 22:58





    1




    1





    @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

    – Igor Pejašinović
    Mar 27 at 0:09





    @GMB first solution is right answer. packages table is just about feeling what this is all about. I'm using it just to find starting id.

    – Igor Pejašinović
    Mar 27 at 0:09













    0














    Why not use part_of table twice ? join the part-of table itself self join and then query for the id ? it really depends on what level of recursion you are looking for i guess.






    share|improve this answer





























      0














      Why not use part_of table twice ? join the part-of table itself self join and then query for the id ? it really depends on what level of recursion you are looking for i guess.






      share|improve this answer



























        0












        0








        0







        Why not use part_of table twice ? join the part-of table itself self join and then query for the id ? it really depends on what level of recursion you are looking for i guess.






        share|improve this answer













        Why not use part_of table twice ? join the part-of table itself self join and then query for the id ? it really depends on what level of recursion you are looking for i guess.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 26 at 22:07









        user3342678user3342678

        113 bronze badges




        113 bronze badges
























            0














            I writing this answer assuming that you will need the packages tables to get the ID, which will then be used to get the parent_id from the part_of table. This part was a bit unclear in your question. If I am wrong in assuming this, then @GBM answer will work as well, as well as mine.



            WITH PACKAGES_CTE AS (
            SELECT PACKAGES.ID, PACKAGES.NAME
            FROM PACKAGES
            ), PACKAGES2_CTE AS
            (
            SELECT *
            FROM PACKAGES2
            )

            SELECT P2.PARENT_ID
            FROM PACKAGES2_CTE P2
            LEFT JOIN PACKAGES2_CTE P3 ON P3.PARENT_ID = P2.ID
            WHERE P3.ID = 8

            UNION ALL

            SELECT P2.PARENT_ID
            FROM PACKAGES_CTE P
            LEFT JOIN PACKAGES2_CTE P2 ON P.ID = P2.ID
            WHERE P2.ID = P2.PARENT_ID OR P.ID = 8


            If you have any questions feel free to ask. I did test this using the sample data you provided. Since I already knew the ID, I did not need to use the Packages.Name. I assume you will want to use Packages.Name = 'Package 8' instead of P.ID = 8.



            This was an interesting problem!






            share|improve this answer

























            • packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

              – Igor Pejašinović
              Mar 27 at 0:11















            0














            I writing this answer assuming that you will need the packages tables to get the ID, which will then be used to get the parent_id from the part_of table. This part was a bit unclear in your question. If I am wrong in assuming this, then @GBM answer will work as well, as well as mine.



            WITH PACKAGES_CTE AS (
            SELECT PACKAGES.ID, PACKAGES.NAME
            FROM PACKAGES
            ), PACKAGES2_CTE AS
            (
            SELECT *
            FROM PACKAGES2
            )

            SELECT P2.PARENT_ID
            FROM PACKAGES2_CTE P2
            LEFT JOIN PACKAGES2_CTE P3 ON P3.PARENT_ID = P2.ID
            WHERE P3.ID = 8

            UNION ALL

            SELECT P2.PARENT_ID
            FROM PACKAGES_CTE P
            LEFT JOIN PACKAGES2_CTE P2 ON P.ID = P2.ID
            WHERE P2.ID = P2.PARENT_ID OR P.ID = 8


            If you have any questions feel free to ask. I did test this using the sample data you provided. Since I already knew the ID, I did not need to use the Packages.Name. I assume you will want to use Packages.Name = 'Package 8' instead of P.ID = 8.



            This was an interesting problem!






            share|improve this answer

























            • packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

              – Igor Pejašinović
              Mar 27 at 0:11













            0












            0








            0







            I writing this answer assuming that you will need the packages tables to get the ID, which will then be used to get the parent_id from the part_of table. This part was a bit unclear in your question. If I am wrong in assuming this, then @GBM answer will work as well, as well as mine.



            WITH PACKAGES_CTE AS (
            SELECT PACKAGES.ID, PACKAGES.NAME
            FROM PACKAGES
            ), PACKAGES2_CTE AS
            (
            SELECT *
            FROM PACKAGES2
            )

            SELECT P2.PARENT_ID
            FROM PACKAGES2_CTE P2
            LEFT JOIN PACKAGES2_CTE P3 ON P3.PARENT_ID = P2.ID
            WHERE P3.ID = 8

            UNION ALL

            SELECT P2.PARENT_ID
            FROM PACKAGES_CTE P
            LEFT JOIN PACKAGES2_CTE P2 ON P.ID = P2.ID
            WHERE P2.ID = P2.PARENT_ID OR P.ID = 8


            If you have any questions feel free to ask. I did test this using the sample data you provided. Since I already knew the ID, I did not need to use the Packages.Name. I assume you will want to use Packages.Name = 'Package 8' instead of P.ID = 8.



            This was an interesting problem!






            share|improve this answer













            I writing this answer assuming that you will need the packages tables to get the ID, which will then be used to get the parent_id from the part_of table. This part was a bit unclear in your question. If I am wrong in assuming this, then @GBM answer will work as well, as well as mine.



            WITH PACKAGES_CTE AS (
            SELECT PACKAGES.ID, PACKAGES.NAME
            FROM PACKAGES
            ), PACKAGES2_CTE AS
            (
            SELECT *
            FROM PACKAGES2
            )

            SELECT P2.PARENT_ID
            FROM PACKAGES2_CTE P2
            LEFT JOIN PACKAGES2_CTE P3 ON P3.PARENT_ID = P2.ID
            WHERE P3.ID = 8

            UNION ALL

            SELECT P2.PARENT_ID
            FROM PACKAGES_CTE P
            LEFT JOIN PACKAGES2_CTE P2 ON P.ID = P2.ID
            WHERE P2.ID = P2.PARENT_ID OR P.ID = 8


            If you have any questions feel free to ask. I did test this using the sample data you provided. Since I already knew the ID, I did not need to use the Packages.Name. I assume you will want to use Packages.Name = 'Package 8' instead of P.ID = 8.



            This was an interesting problem!







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 26 at 23:13









            MhQ-6MhQ-6

            1688 bronze badges




            1688 bronze badges















            • packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

              – Igor Pejašinović
              Mar 27 at 0:11

















            • packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

              – Igor Pejašinović
              Mar 27 at 0:11
















            packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

            – Igor Pejašinović
            Mar 27 at 0:11





            packages table is just there to get some feeling about what this is. Im using it just to find starting id. With your solution, I get result I want for this example in first post, but if I add new row in part_of, lets say package 4 has parent 2, it stops working. that's why i think, it must be some recursive query.

            – Igor Pejašinović
            Mar 27 at 0:11

















            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55366572%2fsql-recursive-query-with-multiple-references-to-same-table%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Kamusi Yaliyomo Aina za kamusi | Muundo wa kamusi | Faida za kamusi | Dhima ya picha katika kamusi | Marejeo | Tazama pia | Viungo vya nje | UrambazajiKuhusu kamusiGo-SwahiliWiki-KamusiKamusi ya Kiswahili na Kiingerezakuihariri na kuongeza habari

            SQL error code 1064 with creating Laravel foreign keysForeign key constraints: When to use ON UPDATE and ON DELETEDropping column with foreign key Laravel error: General error: 1025 Error on renameLaravel SQL Can't create tableLaravel Migration foreign key errorLaravel php artisan migrate:refresh giving a syntax errorSQLSTATE[42S01]: Base table or view already exists or Base table or view already exists: 1050 Tableerror in migrating laravel file to xampp serverSyntax error or access violation: 1064:syntax to use near 'unsigned not null, modelName varchar(191) not null, title varchar(191) not nLaravel cannot create new table field in mysqlLaravel 5.7:Last migration creates table but is not registered in the migration table

            은진 송씨 목차 역사 본관 분파 인물 조선 왕실과의 인척 관계 집성촌 항렬자 인구 같이 보기 각주 둘러보기 메뉴은진 송씨세종실록 149권, 지리지 충청도 공주목 은진현