Argument labels '(stringInterpolationSegment:)' do not match any available overloadsGMStepper - Argument labels '(stringInterpolationSegment:)' do not match any available overloads@selector() in Swift?swift 3 error : Argument labels '(_:)' do not match any available overloadsSwift CGPoint Argument labels '(_:, _:)' do not match any available overloadsNumberFormatter Argument labels '(_:)' do not match any available overloadsArgument labels '(_:)' do not match any available overloadsArgument labels '(UUIDString)' do not match any available overloadsArgument labels '(_:, _:)' do not match any available overloadsArgument Labels '(collectionviewlayout:)' do not match any available overloadsError: Argument labels '(_:, _:)' do not match any available overloadsswift cgsize error Argument labels '(_:, _:)' do not match any available overloads
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Argument labels '(stringInterpolationSegment:)' do not match any available overloads
GMStepper - Argument labels '(stringInterpolationSegment:)' do not match any available overloads@selector() in Swift?swift 3 error : Argument labels '(_:)' do not match any available overloadsSwift CGPoint Argument labels '(_:, _:)' do not match any available overloadsNumberFormatter Argument labels '(_:)' do not match any available overloadsArgument labels '(_:)' do not match any available overloadsArgument labels '(UUIDString)' do not match any available overloadsArgument labels '(_:, _:)' do not match any available overloadsArgument Labels '(collectionviewlayout:)' do not match any available overloadsError: Argument labels '(_:, _:)' do not match any available overloadsswift cgsize error Argument labels '(_:, _:)' do not match any available overloads
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
After updating the latest Xcode Version 10.2 (10E125), I am getting this error :
Argument labels '(stringInterpolationSegment:)' do not match any available overloads
Could not find any solution yet, any idea please ?
let interpolation1 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.latitude)
let interpolation2 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.longitude)
let coordinate:String = interpolation1 + "," + interpolation2
swift xcode10.2
add a comment |
After updating the latest Xcode Version 10.2 (10E125), I am getting this error :
Argument labels '(stringInterpolationSegment:)' do not match any available overloads
Could not find any solution yet, any idea please ?
let interpolation1 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.latitude)
let interpolation2 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.longitude)
let coordinate:String = interpolation1 + "," + interpolation2
swift xcode10.2
Can you provide the line of code, or lines, where this error is occurring?
– Mike Taverne
Mar 27 at 4:38
Its an existing app and there are lots of place where its been used. One of them is like this:let coordinate:String = String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude) + "," + String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
– Arafin Russell
Mar 27 at 4:50
1
ReplacestringInterpolationSegmentwithstringInterpolation.
– Sachin Vas
Mar 27 at 5:17
add a comment |
After updating the latest Xcode Version 10.2 (10E125), I am getting this error :
Argument labels '(stringInterpolationSegment:)' do not match any available overloads
Could not find any solution yet, any idea please ?
let interpolation1 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.latitude)
let interpolation2 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.longitude)
let coordinate:String = interpolation1 + "," + interpolation2
swift xcode10.2
After updating the latest Xcode Version 10.2 (10E125), I am getting this error :
Argument labels '(stringInterpolationSegment:)' do not match any available overloads
Could not find any solution yet, any idea please ?
let interpolation1 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.latitude)
let interpolation2 = String(stringInterpolationSegment:self.addSpotAnnotation!.coordinate.longitude)
let coordinate:String = interpolation1 + "," + interpolation2
swift xcode10.2
swift xcode10.2
edited Mar 27 at 9:10
Sachin Vas
1,5468 silver badges15 bronze badges
1,5468 silver badges15 bronze badges
asked Mar 27 at 3:39
Arafin RussellArafin Russell
5477 silver badges21 bronze badges
5477 silver badges21 bronze badges
Can you provide the line of code, or lines, where this error is occurring?
– Mike Taverne
Mar 27 at 4:38
Its an existing app and there are lots of place where its been used. One of them is like this:let coordinate:String = String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude) + "," + String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
– Arafin Russell
Mar 27 at 4:50
1
ReplacestringInterpolationSegmentwithstringInterpolation.
– Sachin Vas
Mar 27 at 5:17
add a comment |
Can you provide the line of code, or lines, where this error is occurring?
– Mike Taverne
Mar 27 at 4:38
Its an existing app and there are lots of place where its been used. One of them is like this:let coordinate:String = String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude) + "," + String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
– Arafin Russell
Mar 27 at 4:50
1
ReplacestringInterpolationSegmentwithstringInterpolation.
– Sachin Vas
Mar 27 at 5:17
Can you provide the line of code, or lines, where this error is occurring?
– Mike Taverne
Mar 27 at 4:38
Can you provide the line of code, or lines, where this error is occurring?
– Mike Taverne
Mar 27 at 4:38
Its an existing app and there are lots of place where its been used. One of them is like this:
let coordinate:String = String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude) + "," + String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)– Arafin Russell
Mar 27 at 4:50
Its an existing app and there are lots of place where its been used. One of them is like this:
let coordinate:String = String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude) + "," + String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)– Arafin Russell
Mar 27 at 4:50
1
1
Replace
stringInterpolationSegment with stringInterpolation.– Sachin Vas
Mar 27 at 5:17
Replace
stringInterpolationSegment with stringInterpolation.– Sachin Vas
Mar 27 at 5:17
add a comment |
3 Answers
3
active
oldest
votes
The error is due to changes to how string interpolation works in Swift 5.
The solution is not to replace String(stringInterpolationSegment:) with String(stringInterpolation:):
We do not propose preserving existing init(stringInterpolation:) or init(stringInterpolationSegment:) initializers, since they have always been documented as calls that should not be used directly. [emphasis added]
The example you gave:
coordinate:String =
String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude)
+ ","
+ String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
can much more easily be written as:
let coordinate = "(self.addSpotAnnotation!.coordinate.latitude),(self.addSpotAnnotation!.coordinate.longitude)"
add a comment |
String Interpolation Updates
Swift 4.2 implements string interpolation by interpolating segments:
let language = "Swift"
let languageSegment = String(stringInterpolationSegment: language)
let space = " "
let spaceSegment = String(stringInterpolationSegment: space)
let version = 4.2
let versionSegment = String(stringInterpolationSegment: version)
let string = String(stringInterpolation: languageSegment, spaceSegment, versionSegment)
In this code, the compiler first wraps each literal segment and then interpolates one with init(stringInterpolationSegment:) . Then, it wraps all segments together with init(stringInterpolation:)
Swift 5 takes a completely different approach
// 1
var interpolation = DefaultStringInterpolation(
literalCapacity: 7,
interpolationCount: 1)
// 2
let language = "Swift"
interpolation.appendLiteral(language)
let space = " "
interpolation.appendLiteral(space)
let version = 5
interpolation.appendInterpolation(version)
// 3
let string = String(stringInterpolation: interpolation)
Here’s what this code does:
Define a DefaultStringInterpolation instance with a certain capacity and interpolation count.
Call appendLiteral(:) or appendInterpolation(:) to add literals and interpolated values to interpolation.
Produce the final interpolated string by calling init(stringInterpolation:)
credit: raywenderlich
add a comment |
public func == <T>(lhs: ResultTest<T>, rhs: ResultTest<T>) -> Bool
return "(lhs)" == "(rhs)"
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The error is due to changes to how string interpolation works in Swift 5.
The solution is not to replace String(stringInterpolationSegment:) with String(stringInterpolation:):
We do not propose preserving existing init(stringInterpolation:) or init(stringInterpolationSegment:) initializers, since they have always been documented as calls that should not be used directly. [emphasis added]
The example you gave:
coordinate:String =
String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude)
+ ","
+ String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
can much more easily be written as:
let coordinate = "(self.addSpotAnnotation!.coordinate.latitude),(self.addSpotAnnotation!.coordinate.longitude)"
add a comment |
The error is due to changes to how string interpolation works in Swift 5.
The solution is not to replace String(stringInterpolationSegment:) with String(stringInterpolation:):
We do not propose preserving existing init(stringInterpolation:) or init(stringInterpolationSegment:) initializers, since they have always been documented as calls that should not be used directly. [emphasis added]
The example you gave:
coordinate:String =
String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude)
+ ","
+ String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
can much more easily be written as:
let coordinate = "(self.addSpotAnnotation!.coordinate.latitude),(self.addSpotAnnotation!.coordinate.longitude)"
add a comment |
The error is due to changes to how string interpolation works in Swift 5.
The solution is not to replace String(stringInterpolationSegment:) with String(stringInterpolation:):
We do not propose preserving existing init(stringInterpolation:) or init(stringInterpolationSegment:) initializers, since they have always been documented as calls that should not be used directly. [emphasis added]
The example you gave:
coordinate:String =
String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude)
+ ","
+ String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
can much more easily be written as:
let coordinate = "(self.addSpotAnnotation!.coordinate.latitude),(self.addSpotAnnotation!.coordinate.longitude)"
The error is due to changes to how string interpolation works in Swift 5.
The solution is not to replace String(stringInterpolationSegment:) with String(stringInterpolation:):
We do not propose preserving existing init(stringInterpolation:) or init(stringInterpolationSegment:) initializers, since they have always been documented as calls that should not be used directly. [emphasis added]
The example you gave:
coordinate:String =
String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude)
+ ","
+ String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)
can much more easily be written as:
let coordinate = "(self.addSpotAnnotation!.coordinate.latitude),(self.addSpotAnnotation!.coordinate.longitude)"
answered Mar 27 at 5:43
Mike TaverneMike Taverne
6,6482 gold badges24 silver badges42 bronze badges
6,6482 gold badges24 silver badges42 bronze badges
add a comment |
add a comment |
String Interpolation Updates
Swift 4.2 implements string interpolation by interpolating segments:
let language = "Swift"
let languageSegment = String(stringInterpolationSegment: language)
let space = " "
let spaceSegment = String(stringInterpolationSegment: space)
let version = 4.2
let versionSegment = String(stringInterpolationSegment: version)
let string = String(stringInterpolation: languageSegment, spaceSegment, versionSegment)
In this code, the compiler first wraps each literal segment and then interpolates one with init(stringInterpolationSegment:) . Then, it wraps all segments together with init(stringInterpolation:)
Swift 5 takes a completely different approach
// 1
var interpolation = DefaultStringInterpolation(
literalCapacity: 7,
interpolationCount: 1)
// 2
let language = "Swift"
interpolation.appendLiteral(language)
let space = " "
interpolation.appendLiteral(space)
let version = 5
interpolation.appendInterpolation(version)
// 3
let string = String(stringInterpolation: interpolation)
Here’s what this code does:
Define a DefaultStringInterpolation instance with a certain capacity and interpolation count.
Call appendLiteral(:) or appendInterpolation(:) to add literals and interpolated values to interpolation.
Produce the final interpolated string by calling init(stringInterpolation:)
credit: raywenderlich
add a comment |
String Interpolation Updates
Swift 4.2 implements string interpolation by interpolating segments:
let language = "Swift"
let languageSegment = String(stringInterpolationSegment: language)
let space = " "
let spaceSegment = String(stringInterpolationSegment: space)
let version = 4.2
let versionSegment = String(stringInterpolationSegment: version)
let string = String(stringInterpolation: languageSegment, spaceSegment, versionSegment)
In this code, the compiler first wraps each literal segment and then interpolates one with init(stringInterpolationSegment:) . Then, it wraps all segments together with init(stringInterpolation:)
Swift 5 takes a completely different approach
// 1
var interpolation = DefaultStringInterpolation(
literalCapacity: 7,
interpolationCount: 1)
// 2
let language = "Swift"
interpolation.appendLiteral(language)
let space = " "
interpolation.appendLiteral(space)
let version = 5
interpolation.appendInterpolation(version)
// 3
let string = String(stringInterpolation: interpolation)
Here’s what this code does:
Define a DefaultStringInterpolation instance with a certain capacity and interpolation count.
Call appendLiteral(:) or appendInterpolation(:) to add literals and interpolated values to interpolation.
Produce the final interpolated string by calling init(stringInterpolation:)
credit: raywenderlich
add a comment |
String Interpolation Updates
Swift 4.2 implements string interpolation by interpolating segments:
let language = "Swift"
let languageSegment = String(stringInterpolationSegment: language)
let space = " "
let spaceSegment = String(stringInterpolationSegment: space)
let version = 4.2
let versionSegment = String(stringInterpolationSegment: version)
let string = String(stringInterpolation: languageSegment, spaceSegment, versionSegment)
In this code, the compiler first wraps each literal segment and then interpolates one with init(stringInterpolationSegment:) . Then, it wraps all segments together with init(stringInterpolation:)
Swift 5 takes a completely different approach
// 1
var interpolation = DefaultStringInterpolation(
literalCapacity: 7,
interpolationCount: 1)
// 2
let language = "Swift"
interpolation.appendLiteral(language)
let space = " "
interpolation.appendLiteral(space)
let version = 5
interpolation.appendInterpolation(version)
// 3
let string = String(stringInterpolation: interpolation)
Here’s what this code does:
Define a DefaultStringInterpolation instance with a certain capacity and interpolation count.
Call appendLiteral(:) or appendInterpolation(:) to add literals and interpolated values to interpolation.
Produce the final interpolated string by calling init(stringInterpolation:)
credit: raywenderlich
String Interpolation Updates
Swift 4.2 implements string interpolation by interpolating segments:
let language = "Swift"
let languageSegment = String(stringInterpolationSegment: language)
let space = " "
let spaceSegment = String(stringInterpolationSegment: space)
let version = 4.2
let versionSegment = String(stringInterpolationSegment: version)
let string = String(stringInterpolation: languageSegment, spaceSegment, versionSegment)
In this code, the compiler first wraps each literal segment and then interpolates one with init(stringInterpolationSegment:) . Then, it wraps all segments together with init(stringInterpolation:)
Swift 5 takes a completely different approach
// 1
var interpolation = DefaultStringInterpolation(
literalCapacity: 7,
interpolationCount: 1)
// 2
let language = "Swift"
interpolation.appendLiteral(language)
let space = " "
interpolation.appendLiteral(space)
let version = 5
interpolation.appendInterpolation(version)
// 3
let string = String(stringInterpolation: interpolation)
Here’s what this code does:
Define a DefaultStringInterpolation instance with a certain capacity and interpolation count.
Call appendLiteral(:) or appendInterpolation(:) to add literals and interpolated values to interpolation.
Produce the final interpolated string by calling init(stringInterpolation:)
credit: raywenderlich
edited Mar 27 at 5:50
answered Mar 27 at 5:39
Arafin RussellArafin Russell
5477 silver badges21 bronze badges
5477 silver badges21 bronze badges
add a comment |
add a comment |
public func == <T>(lhs: ResultTest<T>, rhs: ResultTest<T>) -> Bool
return "(lhs)" == "(rhs)"
add a comment |
public func == <T>(lhs: ResultTest<T>, rhs: ResultTest<T>) -> Bool
return "(lhs)" == "(rhs)"
add a comment |
public func == <T>(lhs: ResultTest<T>, rhs: ResultTest<T>) -> Bool
return "(lhs)" == "(rhs)"
public func == <T>(lhs: ResultTest<T>, rhs: ResultTest<T>) -> Bool
return "(lhs)" == "(rhs)"
edited Jun 13 at 7:15
answered Jun 13 at 5:37
GiangGiang
2,03417 silver badges20 bronze badges
2,03417 silver badges20 bronze badges
add a comment |
add a comment |
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Can you provide the line of code, or lines, where this error is occurring?
– Mike Taverne
Mar 27 at 4:38
Its an existing app and there are lots of place where its been used. One of them is like this:
let coordinate:String = String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.latitude) + "," + String(stringInterpolationSegment: self.addSpotAnnotation!.coordinate.longitude)– Arafin Russell
Mar 27 at 4:50
1
Replace
stringInterpolationSegmentwithstringInterpolation.– Sachin Vas
Mar 27 at 5:17