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How to fix tribonacci series function when using generators

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0

Following is my approach to return the n element in Tribonacci series

def tri(n,seq = [1, 1, 1]):
 for i in range(n-2):
 seq = seq[1:] + [sum(seq)]
 return seq[-1]

I get the correct result when passing argument through print().

print(tri(10))

Output : 193

However, when using generator(using repl.it), I get error of can only concatenate tuple (not"list") to tuple

I am using below for generator

def tri_generator(): 
for i in range(1000): 
 yield (i, (1, 1, 1))
 yield (i, (1, 0, 1))
 yield (i, (1, 2, 3))

Not sure what I am missing? Any help is appreciated.

python-3.x

share|improve this question

edited Mar 27 at 3:58

N997

asked Mar 27 at 3:50

N997N997

6555 bronze badges

add a comment | 

0

Following is my approach to return the n element in Tribonacci series

def tri(n,seq = [1, 1, 1]):
 for i in range(n-2):
 seq = seq[1:] + [sum(seq)]
 return seq[-1]

I get the correct result when passing argument through print().

print(tri(10))

Output : 193

However, when using generator(using repl.it), I get error of can only concatenate tuple (not"list") to tuple

I am using below for generator

def tri_generator(): 
for i in range(1000): 
 yield (i, (1, 1, 1))
 yield (i, (1, 0, 1))
 yield (i, (1, 2, 3))

Not sure what I am missing? Any help is appreciated.

python-3.x

share|improve this question

edited Mar 27 at 3:58

N997

asked Mar 27 at 3:50

N997N997

6555 bronze badges

add a comment | 

Following is my approach to return the n element in Tribonacci series

def tri(n,seq = [1, 1, 1]):
 for i in range(n-2):
 seq = seq[1:] + [sum(seq)]
 return seq[-1]

I get the correct result when passing argument through print().

print(tri(10))

Output : 193

However, when using generator(using repl.it), I get error of can only concatenate tuple (not"list") to tuple

I am using below for generator

def tri_generator(): 
for i in range(1000): 
 yield (i, (1, 1, 1))
 yield (i, (1, 0, 1))
 yield (i, (1, 2, 3))

Not sure what I am missing? Any help is appreciated.

python-3.x

share|improve this question

edited Mar 27 at 3:58

N997

asked Mar 27 at 3:50

N997N997

6555 bronze badges

def tri(n,seq = [1, 1, 1]):
 for i in range(n-2):
 seq = seq[1:] + [sum(seq)]
 return seq[-1]

print(tri(10))

def tri_generator(): 
for i in range(1000): 
 yield (i, (1, 1, 1))
 yield (i, (1, 0, 1))
 yield (i, (1, 2, 3))

share|improve this question

edited Mar 27 at 3:58

N997

asked Mar 27 at 3:50

N997N997

6555 bronze badges

share|improve this question

edited Mar 27 at 3:58

N997

asked Mar 27 at 3:50

N997N997

6555 bronze badges

asked Mar 27 at 3:50

N997N997

6555 bronze badges

asked Mar 27 at 3:50

N997N997

6555 bronze badges

1 Answer
1

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1

Here's a simple generator (you can clean up the code as you may like):

def tri_generator():
 i = 0
 seq = [1, 1, 1]
 while True:
 seq = [seq[1], seq[2], seq[0] + seq[1] + seq[2]]
 yield i, seq
 i += 1 

 n = 10
 xx = tri_generator()
 for i in range(n - 2):
 print(next(xx)) 

## Output:
## (0, [1, 1, 3])
## (1, [1, 3, 5])
## (2, [3, 5, 9])
## (3, [5, 9, 17])
## (4, [9, 17, 31])
## (5, [17, 31, 57])
## (6, [31, 57, 105])
## (7, [57, 105, 193])

share|improve this answer

answered Mar 27 at 6:12

SanVSanV

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1

Here's a simple generator (you can clean up the code as you may like):

def tri_generator():
 i = 0
 seq = [1, 1, 1]
 while True:
 seq = [seq[1], seq[2], seq[0] + seq[1] + seq[2]]
 yield i, seq
 i += 1 

 n = 10
 xx = tri_generator()
 for i in range(n - 2):
 print(next(xx)) 

## Output:
## (0, [1, 1, 3])
## (1, [1, 3, 5])
## (2, [3, 5, 9])
## (3, [5, 9, 17])
## (4, [9, 17, 31])
## (5, [17, 31, 57])
## (6, [31, 57, 105])
## (7, [57, 105, 193])

share|improve this answer

answered Mar 27 at 6:12

SanVSanV

53911 silver badge1111 bronze badges

add a comment | 

1

Here's a simple generator (you can clean up the code as you may like):

def tri_generator():
 i = 0
 seq = [1, 1, 1]
 while True:
 seq = [seq[1], seq[2], seq[0] + seq[1] + seq[2]]
 yield i, seq
 i += 1 

 n = 10
 xx = tri_generator()
 for i in range(n - 2):
 print(next(xx)) 

## Output:
## (0, [1, 1, 3])
## (1, [1, 3, 5])
## (2, [3, 5, 9])
## (3, [5, 9, 17])
## (4, [9, 17, 31])
## (5, [17, 31, 57])
## (6, [31, 57, 105])
## (7, [57, 105, 193])

share|improve this answer

answered Mar 27 at 6:12

SanVSanV

53911 silver badge1111 bronze badges

add a comment | 

Here's a simple generator (you can clean up the code as you may like):

def tri_generator():
 i = 0
 seq = [1, 1, 1]
 while True:
 seq = [seq[1], seq[2], seq[0] + seq[1] + seq[2]]
 yield i, seq
 i += 1 

 n = 10
 xx = tri_generator()
 for i in range(n - 2):
 print(next(xx)) 

## Output:
## (0, [1, 1, 3])
## (1, [1, 3, 5])
## (2, [3, 5, 9])
## (3, [5, 9, 17])
## (4, [9, 17, 31])
## (5, [17, 31, 57])
## (6, [31, 57, 105])
## (7, [57, 105, 193])

share|improve this answer

answered Mar 27 at 6:12

SanVSanV

53911 silver badge1111 bronze badges

def tri_generator():
 i = 0
 seq = [1, 1, 1]
 while True:
 seq = [seq[1], seq[2], seq[0] + seq[1] + seq[2]]
 yield i, seq
 i += 1 

 n = 10
 xx = tri_generator()
 for i in range(n - 2):
 print(next(xx)) 

## Output:
## (0, [1, 1, 3])
## (1, [1, 3, 5])
## (2, [3, 5, 9])
## (3, [5, 9, 17])
## (4, [9, 17, 31])
## (5, [17, 31, 57])
## (6, [31, 57, 105])
## (7, [57, 105, 193])

share|improve this answer

answered Mar 27 at 6:12

SanVSanV

53911 silver badge1111 bronze badges

answered Mar 27 at 6:12

SanVSanV

53911 silver badge1111 bronze badges

answered Mar 27 at 6:12

SanVSanV

53911 silver badge1111 bronze badges