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multiplication in dataframe


Catch multiple exceptions in one line (except block)Filter dataframe rows if value in column is in a set list of valuesAdding new column to existing DataFrame in Python pandasSet value for particular cell in pandas DataFrame using indexSkip the headers when editing a csv file using Python“Large data” work flows using pandasChange data type of columns in PandasHow to iterate over rows in a DataFrame in Pandas?Combine two columns of text in dataframe in pandas/pythonConvert list of dictionaries to a pandas DataFrame






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








-1















I have these two pandas dataframes and I want to multiply first row to shares with whole 1st column of Log_Return dataframe, similarly the 2nd row of first dataframe with 2nd column of Log_Returns and so on. kindly help me to solve this problem with the help of a loop.



enter image description here










share|improve this question


























  • you should post the code here.

    – mauve
    Mar 20 at 19:24











  • I m just asking for idea that how can I do it

    – Hussnain Akbar
    Mar 20 at 19:33






  • 1





    Please see this link on create a minimal reproducible example

    – G. Anderson
    Mar 20 at 19:38











  • @HussnainAkbar How is this related to requests? You tagged the question with that...

    – Ralf
    Mar 20 at 20:17


















-1















I have these two pandas dataframes and I want to multiply first row to shares with whole 1st column of Log_Return dataframe, similarly the 2nd row of first dataframe with 2nd column of Log_Returns and so on. kindly help me to solve this problem with the help of a loop.



enter image description here










share|improve this question


























  • you should post the code here.

    – mauve
    Mar 20 at 19:24











  • I m just asking for idea that how can I do it

    – Hussnain Akbar
    Mar 20 at 19:33






  • 1





    Please see this link on create a minimal reproducible example

    – G. Anderson
    Mar 20 at 19:38











  • @HussnainAkbar How is this related to requests? You tagged the question with that...

    – Ralf
    Mar 20 at 20:17














-1












-1








-1








I have these two pandas dataframes and I want to multiply first row to shares with whole 1st column of Log_Return dataframe, similarly the 2nd row of first dataframe with 2nd column of Log_Returns and so on. kindly help me to solve this problem with the help of a loop.



enter image description here










share|improve this question
















I have these two pandas dataframes and I want to multiply first row to shares with whole 1st column of Log_Return dataframe, similarly the 2nd row of first dataframe with 2nd column of Log_Returns and so on. kindly help me to solve this problem with the help of a loop.



enter image description here







python python-3.x python-2.7 python-requests






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 20 at 19:27









James Coyle

6,2451 gold badge23 silver badges39 bronze badges




6,2451 gold badge23 silver badges39 bronze badges










asked Mar 20 at 19:23









Hussnain AkbarHussnain Akbar

194 bronze badges




194 bronze badges















  • you should post the code here.

    – mauve
    Mar 20 at 19:24











  • I m just asking for idea that how can I do it

    – Hussnain Akbar
    Mar 20 at 19:33






  • 1





    Please see this link on create a minimal reproducible example

    – G. Anderson
    Mar 20 at 19:38











  • @HussnainAkbar How is this related to requests? You tagged the question with that...

    – Ralf
    Mar 20 at 20:17


















  • you should post the code here.

    – mauve
    Mar 20 at 19:24











  • I m just asking for idea that how can I do it

    – Hussnain Akbar
    Mar 20 at 19:33






  • 1





    Please see this link on create a minimal reproducible example

    – G. Anderson
    Mar 20 at 19:38











  • @HussnainAkbar How is this related to requests? You tagged the question with that...

    – Ralf
    Mar 20 at 20:17

















you should post the code here.

– mauve
Mar 20 at 19:24





you should post the code here.

– mauve
Mar 20 at 19:24













I m just asking for idea that how can I do it

– Hussnain Akbar
Mar 20 at 19:33





I m just asking for idea that how can I do it

– Hussnain Akbar
Mar 20 at 19:33




1




1





Please see this link on create a minimal reproducible example

– G. Anderson
Mar 20 at 19:38





Please see this link on create a minimal reproducible example

– G. Anderson
Mar 20 at 19:38













@HussnainAkbar How is this related to requests? You tagged the question with that...

– Ralf
Mar 20 at 20:17






@HussnainAkbar How is this related to requests? You tagged the question with that...

– Ralf
Mar 20 at 20:17













1 Answer
1






active

oldest

votes


















0














This code can help you:



i=0
for j in range(Log_return.shape[1]):
#j chooses the column of Log dataframe
#shape[1] gives number of columns
for k in range(len(Log_return)):
# k chooses the rows one by one of jth column

shares.iloc[i,0]*Log_return.iloc[k,j]
#you can multiply and even store the values or do any operations you want
i+=1
#i determines the row of shares dataframe





share|improve this answer



























  • I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

    – Hussnain Akbar
    Mar 26 at 22:30












  • Try the code now I have edited

    – Tojrah
    Mar 27 at 0:29










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














This code can help you:



i=0
for j in range(Log_return.shape[1]):
#j chooses the column of Log dataframe
#shape[1] gives number of columns
for k in range(len(Log_return)):
# k chooses the rows one by one of jth column

shares.iloc[i,0]*Log_return.iloc[k,j]
#you can multiply and even store the values or do any operations you want
i+=1
#i determines the row of shares dataframe





share|improve this answer



























  • I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

    – Hussnain Akbar
    Mar 26 at 22:30












  • Try the code now I have edited

    – Tojrah
    Mar 27 at 0:29















0














This code can help you:



i=0
for j in range(Log_return.shape[1]):
#j chooses the column of Log dataframe
#shape[1] gives number of columns
for k in range(len(Log_return)):
# k chooses the rows one by one of jth column

shares.iloc[i,0]*Log_return.iloc[k,j]
#you can multiply and even store the values or do any operations you want
i+=1
#i determines the row of shares dataframe





share|improve this answer



























  • I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

    – Hussnain Akbar
    Mar 26 at 22:30












  • Try the code now I have edited

    – Tojrah
    Mar 27 at 0:29













0












0








0







This code can help you:



i=0
for j in range(Log_return.shape[1]):
#j chooses the column of Log dataframe
#shape[1] gives number of columns
for k in range(len(Log_return)):
# k chooses the rows one by one of jth column

shares.iloc[i,0]*Log_return.iloc[k,j]
#you can multiply and even store the values or do any operations you want
i+=1
#i determines the row of shares dataframe





share|improve this answer















This code can help you:



i=0
for j in range(Log_return.shape[1]):
#j chooses the column of Log dataframe
#shape[1] gives number of columns
for k in range(len(Log_return)):
# k chooses the rows one by one of jth column

shares.iloc[i,0]*Log_return.iloc[k,j]
#you can multiply and even store the values or do any operations you want
i+=1
#i determines the row of shares dataframe






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 27 at 0:28

























answered Mar 21 at 6:24









TojrahTojrah

5281 silver badge16 bronze badges




5281 silver badge16 bronze badges















  • I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

    – Hussnain Akbar
    Mar 26 at 22:30












  • Try the code now I have edited

    – Tojrah
    Mar 27 at 0:29

















  • I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

    – Hussnain Akbar
    Mar 26 at 22:30












  • Try the code now I have edited

    – Tojrah
    Mar 27 at 0:29
















I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

– Hussnain Akbar
Mar 26 at 22:30






I have tried this code but getting error but no output. Kindly help me out I m stuck here IndexError: single positional indexer is out-of-bounds

– Hussnain Akbar
Mar 26 at 22:30














Try the code now I have edited

– Tojrah
Mar 27 at 0:29





Try the code now I have edited

– Tojrah
Mar 27 at 0:29






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