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0

I made a beer matching dating app for a school assignment. Unfortunately am I having a bit of trouble finding out how to search in my database on a template injected number as object.

I've tried this I read on MongoDB docs

The database looks like this :

beerProfile: Object
 ↳24589: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

So beerProfile is an object and has the object 24589 inside it. Inside the 24589 object are name, imd, description and bid.

I tried to use the find() function. ( the collection is called users )

db.collection('users').find( [24589]: [name: [Heineken]] , name: 1, bid: 1 , done);

And I also tried :

db.collection('users').find( $text: $search: 24589 , done);

I would like to make it return the object values of the 24589 object. Does anyone how I can achieve this ?

mongodb

share|improve this question

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

add a comment | 

0

I made a beer matching dating app for a school assignment. Unfortunately am I having a bit of trouble finding out how to search in my database on a template injected number as object.

I've tried this I read on MongoDB docs

The database looks like this :

beerProfile: Object
 ↳24589: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

So beerProfile is an object and has the object 24589 inside it. Inside the 24589 object are name, imd, description and bid.

I tried to use the find() function. ( the collection is called users )

db.collection('users').find( [24589]: [name: [Heineken]] , name: 1, bid: 1 , done);

And I also tried :

db.collection('users').find( $text: $search: 24589 , done);

I would like to make it return the object values of the 24589 object. Does anyone how I can achieve this ?

mongodb

share|improve this question

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

add a comment | 

I made a beer matching dating app for a school assignment. Unfortunately am I having a bit of trouble finding out how to search in my database on a template injected number as object.

I've tried this I read on MongoDB docs

The database looks like this :

beerProfile: Object
 ↳24589: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

So beerProfile is an object and has the object 24589 inside it. Inside the 24589 object are name, imd, description and bid.

I tried to use the find() function. ( the collection is called users )

db.collection('users').find( [24589]: [name: [Heineken]] , name: 1, bid: 1 , done);

And I also tried :

db.collection('users').find( $text: $search: 24589 , done);

I would like to make it return the object values of the 24589 object. Does anyone how I can achieve this ?

mongodb

share|improve this question

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

beerProfile: Object
 ↳24589: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

db.collection('users').find( [24589]: [name: [Heineken]] , name: 1, bid: 1 , done);

db.collection('users').find( $text: $search: 24589 , done);

share|improve this question

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

share|improve this question

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

asked Mar 27 at 0:36

Root_ishRoot_ish

444 bronze badges

1 Answer
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oldest

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0

I think your "schema" became unnecessarily complex by using a variable (24589) as a key. You should change it to something like this:

beerProfile: Object
 ↳beer: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

Then you can use a simple find():

db.collection('users').find( "beer.bid": "24589")

share|improve this answer

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you for your response. This is a really good solution thank you! How would you add a second beer to the beer profile ? As duplicates aren't allowed. Or is there a workaround ?
  
  – Root_ish
  Mar 27 at 18:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Root_ish, then you have to make it an array which can hold multiple beer objects. beer: [ name: "Heineken" bid: 24589 , name: "Bud" bid: 24590 ], etc.
  
  – Zolbayar
  Mar 27 at 22:59
  

  
  
  
  

add a comment | 

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0

I think your "schema" became unnecessarily complex by using a variable (24589) as a key. You should change it to something like this:

beerProfile: Object
 ↳beer: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

Then you can use a simple find():

db.collection('users').find( "beer.bid": "24589")

share|improve this answer

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you for your response. This is a really good solution thank you! How would you add a second beer to the beer profile ? As duplicates aren't allowed. Or is there a workaround ?
  
  – Root_ish
  Mar 27 at 18:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Root_ish, then you have to make it an array which can hold multiple beer objects. beer: [ name: "Heineken" bid: 24589 , name: "Bud" bid: 24590 ], etc.
  
  – Zolbayar
  Mar 27 at 22:59
  

  
  
  
  

add a comment | 

0

I think your "schema" became unnecessarily complex by using a variable (24589) as a key. You should change it to something like this:

beerProfile: Object
 ↳beer: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

Then you can use a simple find():

db.collection('users').find( "beer.bid": "24589")

share|improve this answer

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you for your response. This is a really good solution thank you! How would you add a second beer to the beer profile ? As duplicates aren't allowed. Or is there a workaround ?
  
  – Root_ish
  Mar 27 at 18:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Root_ish, then you have to make it an array which can hold multiple beer objects. beer: [ name: "Heineken" bid: 24589 , name: "Bud" bid: 24590 ], etc.
  
  – Zolbayar
  Mar 27 at 22:59
  

  
  
  
  

add a comment | 

I think your "schema" became unnecessarily complex by using a variable (24589) as a key. You should change it to something like this:

beerProfile: Object
 ↳beer: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

Then you can use a simple find():

db.collection('users').find( "beer.bid": "24589")

share|improve this answer

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges

beerProfile: Object
 ↳beer: Object 
 ↳name: "Heineken"
 img: "https://untappd.akamaized.net/site/beer_logos/beer94130_52756_sm.jpeg"
 description: "Heinken is a beer"
 bid:"24589"

db.collection('users').find( "beer.bid": "24589")

share|improve this answer

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges

answered Mar 27 at 3:27

ZolbayarZolbayar

46655 silver badges1515 bronze badges