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Python - MatPlotLib - How can I set two ticks on my x axis, one at the far left and one at the far right?

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2

So I am trying to display some analytics in my python web-app. I want to display the date-time for the first and last entries on the x axis.

I have attempted to set the ticks as a two entry list but it gave a bad result.

plt.scatter(x_data, y_data)
 plt.grid(True)
 plt.xticks(x_data, [x_data[0], x_data[-1]])
 fig = plt.gcf()

Where the x_data is:

['10:59:44 27-03-2019', '11:00:07 27-03-2019', '11:00:09 27-03-2019', '11:00:12 27-03-2019', '11:30:23 27-03-2019', '11:30:29 27-03-2019', '11:30:30 27-03-2019', '11:30:31 27-03-2019', '11:30:32 27-03-2019', '11:32:44 27-03-2019', '11:33:21 27-03-2019', '11:35:50 27-03-2019', '12:16:12 27-03-2019', '12:16:39 27-03-2019', '12:17:36 27-03-2019', '12:19:40 27-03-2019', '12:23:50 27-03-2019']

I expected the output to place one on the far left and the other on the far right. Instead the first two ticks simply showed the times overlapping.

I am unsure what the proper way of doing it is.

python matplotlib

share|improve this question

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  have you tried plt.xticks without the second argument? for setting axis limits there is plt.xlim funtion
  
  – alexey
  Mar 27 at 12:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If I understand correctly you want all the ticks to show but only display the label for the first and last?
  
  – Gio
  Mar 27 at 12:39
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, I do want the other ticks to show but for the first and last to be labelled.
  
  – Thomas Coll
  Mar 27 at 12:41
  

  
  
  
  

add a comment | 

2

So I am trying to display some analytics in my python web-app. I want to display the date-time for the first and last entries on the x axis.

I have attempted to set the ticks as a two entry list but it gave a bad result.

plt.scatter(x_data, y_data)
 plt.grid(True)
 plt.xticks(x_data, [x_data[0], x_data[-1]])
 fig = plt.gcf()

Where the x_data is:

['10:59:44 27-03-2019', '11:00:07 27-03-2019', '11:00:09 27-03-2019', '11:00:12 27-03-2019', '11:30:23 27-03-2019', '11:30:29 27-03-2019', '11:30:30 27-03-2019', '11:30:31 27-03-2019', '11:30:32 27-03-2019', '11:32:44 27-03-2019', '11:33:21 27-03-2019', '11:35:50 27-03-2019', '12:16:12 27-03-2019', '12:16:39 27-03-2019', '12:17:36 27-03-2019', '12:19:40 27-03-2019', '12:23:50 27-03-2019']

I expected the output to place one on the far left and the other on the far right. Instead the first two ticks simply showed the times overlapping.

I am unsure what the proper way of doing it is.

python matplotlib

share|improve this question

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  have you tried plt.xticks without the second argument? for setting axis limits there is plt.xlim funtion
  
  – alexey
  Mar 27 at 12:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If I understand correctly you want all the ticks to show but only display the label for the first and last?
  
  – Gio
  Mar 27 at 12:39
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, I do want the other ticks to show but for the first and last to be labelled.
  
  – Thomas Coll
  Mar 27 at 12:41
  

  
  
  
  

add a comment | 

So I am trying to display some analytics in my python web-app. I want to display the date-time for the first and last entries on the x axis.

I have attempted to set the ticks as a two entry list but it gave a bad result.

plt.scatter(x_data, y_data)
 plt.grid(True)
 plt.xticks(x_data, [x_data[0], x_data[-1]])
 fig = plt.gcf()

Where the x_data is:

['10:59:44 27-03-2019', '11:00:07 27-03-2019', '11:00:09 27-03-2019', '11:00:12 27-03-2019', '11:30:23 27-03-2019', '11:30:29 27-03-2019', '11:30:30 27-03-2019', '11:30:31 27-03-2019', '11:30:32 27-03-2019', '11:32:44 27-03-2019', '11:33:21 27-03-2019', '11:35:50 27-03-2019', '12:16:12 27-03-2019', '12:16:39 27-03-2019', '12:17:36 27-03-2019', '12:19:40 27-03-2019', '12:23:50 27-03-2019']

I expected the output to place one on the far left and the other on the far right. Instead the first two ticks simply showed the times overlapping.

I am unsure what the proper way of doing it is.

python matplotlib

share|improve this question

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

plt.scatter(x_data, y_data)
 plt.grid(True)
 plt.xticks(x_data, [x_data[0], x_data[-1]])
 fig = plt.gcf()

['10:59:44 27-03-2019', '11:00:07 27-03-2019', '11:00:09 27-03-2019', '11:00:12 27-03-2019', '11:30:23 27-03-2019', '11:30:29 27-03-2019', '11:30:30 27-03-2019', '11:30:31 27-03-2019', '11:30:32 27-03-2019', '11:32:44 27-03-2019', '11:33:21 27-03-2019', '11:35:50 27-03-2019', '12:16:12 27-03-2019', '12:16:39 27-03-2019', '12:17:36 27-03-2019', '12:19:40 27-03-2019', '12:23:50 27-03-2019']

share|improve this question

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

share|improve this question

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

asked Mar 27 at 12:34

Thomas CollThomas Coll

1544 bronze badges

2 Answers
2

active

oldest

votes

2

Here is a workaround solution using some random data because you did not specify what the y_data is. The idea is to loop through the existing default tick labels and then replace all the tick labels by empty strings except the first and the last one.

fig, ax = plt.subplots()

plt.scatter(x_data, range(len(x_data)))
plt.grid(True)

fig.canvas.draw()
xticks = ax.get_xticklabels()
labels_new = [lab.get_text() if i in [0, len(xticks)-1] else "" 
 for i, lab in enumerate(xticks) ]

ax.set_xticklabels(labels_new)

plt.show()

share|improve this answer

edited Mar 27 at 14:27

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's a good workaround. If there is no official way then this will do. Thank you!
  
  – Thomas Coll
  Mar 27 at 14:44
  

  
  
  
  

add a comment | 

1

I suspect your problem is that you are defining a vector of ticks and then assigning two labels (in position 0 and 1).

import numpy as np
import matplotlib.pyplot as plt

x_data=np.array([1,2,3,4,5,6,7,8])
y_data=np.random.normal(0, 1, (8, 1))

# create an array for your labels 
new_labels=[''] * (len(x_data)-2)
new_labels.insert(0,x_data[0])
new_labels.append(x_data[-1])

plt.scatter(x_data, y_data)
plt.grid(True)
plt.xticks(x_data, new_labels) #use the new tick labels
fig = plt.gcf()

share|improve this answer

edited Mar 27 at 16:54

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  No this leads to an messed up output (oi65.tinypic.com/2j5qm9.jpg)
  
  – Thomas Coll
  Mar 27 at 14:17
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes, of course. I added a list as second label =). Now it should work
  
  – Gio
  Mar 27 at 16:54
  

  
  
  
  

add a comment | 

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2

Here is a workaround solution using some random data because you did not specify what the y_data is. The idea is to loop through the existing default tick labels and then replace all the tick labels by empty strings except the first and the last one.

fig, ax = plt.subplots()

plt.scatter(x_data, range(len(x_data)))
plt.grid(True)

fig.canvas.draw()
xticks = ax.get_xticklabels()
labels_new = [lab.get_text() if i in [0, len(xticks)-1] else "" 
 for i, lab in enumerate(xticks) ]

ax.set_xticklabels(labels_new)

plt.show()

share|improve this answer

edited Mar 27 at 14:27

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's a good workaround. If there is no official way then this will do. Thank you!
  
  – Thomas Coll
  Mar 27 at 14:44
  

  
  
  
  

add a comment | 

2

Here is a workaround solution using some random data because you did not specify what the y_data is. The idea is to loop through the existing default tick labels and then replace all the tick labels by empty strings except the first and the last one.

fig, ax = plt.subplots()

plt.scatter(x_data, range(len(x_data)))
plt.grid(True)

fig.canvas.draw()
xticks = ax.get_xticklabels()
labels_new = [lab.get_text() if i in [0, len(xticks)-1] else "" 
 for i, lab in enumerate(xticks) ]

ax.set_xticklabels(labels_new)

plt.show()

share|improve this answer

edited Mar 27 at 14:27

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's a good workaround. If there is no official way then this will do. Thank you!
  
  – Thomas Coll
  Mar 27 at 14:44
  

  
  
  
  

add a comment | 

Here is a workaround solution using some random data because you did not specify what the y_data is. The idea is to loop through the existing default tick labels and then replace all the tick labels by empty strings except the first and the last one.

fig, ax = plt.subplots()

plt.scatter(x_data, range(len(x_data)))
plt.grid(True)

fig.canvas.draw()
xticks = ax.get_xticklabels()
labels_new = [lab.get_text() if i in [0, len(xticks)-1] else "" 
 for i, lab in enumerate(xticks) ]

ax.set_xticklabels(labels_new)

plt.show()

share|improve this answer

edited Mar 27 at 14:27

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

fig, ax = plt.subplots()

plt.scatter(x_data, range(len(x_data)))
plt.grid(True)

fig.canvas.draw()
xticks = ax.get_xticklabels()
labels_new = [lab.get_text() if i in [0, len(xticks)-1] else "" 
 for i, lab in enumerate(xticks) ]

ax.set_xticklabels(labels_new)

plt.show()

share|improve this answer

edited Mar 27 at 14:27

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

answered Mar 27 at 14:18

SheldoreSheldore

21.9k55 gold badges1515 silver badges3737 bronze badges

1

I suspect your problem is that you are defining a vector of ticks and then assigning two labels (in position 0 and 1).

import numpy as np
import matplotlib.pyplot as plt

x_data=np.array([1,2,3,4,5,6,7,8])
y_data=np.random.normal(0, 1, (8, 1))

# create an array for your labels 
new_labels=[''] * (len(x_data)-2)
new_labels.insert(0,x_data[0])
new_labels.append(x_data[-1])

plt.scatter(x_data, y_data)
plt.grid(True)
plt.xticks(x_data, new_labels) #use the new tick labels
fig = plt.gcf()

share|improve this answer

edited Mar 27 at 16:54

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  No this leads to an messed up output (oi65.tinypic.com/2j5qm9.jpg)
  
  – Thomas Coll
  Mar 27 at 14:17
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes, of course. I added a list as second label =). Now it should work
  
  – Gio
  Mar 27 at 16:54
  

  
  
  
  

add a comment | 

1

I suspect your problem is that you are defining a vector of ticks and then assigning two labels (in position 0 and 1).

import numpy as np
import matplotlib.pyplot as plt

x_data=np.array([1,2,3,4,5,6,7,8])
y_data=np.random.normal(0, 1, (8, 1))

# create an array for your labels 
new_labels=[''] * (len(x_data)-2)
new_labels.insert(0,x_data[0])
new_labels.append(x_data[-1])

plt.scatter(x_data, y_data)
plt.grid(True)
plt.xticks(x_data, new_labels) #use the new tick labels
fig = plt.gcf()

share|improve this answer

edited Mar 27 at 16:54

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  No this leads to an messed up output (oi65.tinypic.com/2j5qm9.jpg)
  
  – Thomas Coll
  Mar 27 at 14:17
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes, of course. I added a list as second label =). Now it should work
  
  – Gio
  Mar 27 at 16:54
  

  
  
  
  

add a comment | 

I suspect your problem is that you are defining a vector of ticks and then assigning two labels (in position 0 and 1).

import numpy as np
import matplotlib.pyplot as plt

x_data=np.array([1,2,3,4,5,6,7,8])
y_data=np.random.normal(0, 1, (8, 1))

# create an array for your labels 
new_labels=[''] * (len(x_data)-2)
new_labels.insert(0,x_data[0])
new_labels.append(x_data[-1])

plt.scatter(x_data, y_data)
plt.grid(True)
plt.xticks(x_data, new_labels) #use the new tick labels
fig = plt.gcf()

share|improve this answer

edited Mar 27 at 16:54

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges

import numpy as np
import matplotlib.pyplot as plt

x_data=np.array([1,2,3,4,5,6,7,8])
y_data=np.random.normal(0, 1, (8, 1))

# create an array for your labels 
new_labels=[''] * (len(x_data)-2)
new_labels.insert(0,x_data[0])
new_labels.append(x_data[-1])

plt.scatter(x_data, y_data)
plt.grid(True)
plt.xticks(x_data, new_labels) #use the new tick labels
fig = plt.gcf()

share|improve this answer

edited Mar 27 at 16:54

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges

answered Mar 27 at 12:52

GioGio

1,91811 gold badge1313 silver badges2424 bronze badges