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Sonata default filter value

Sonata admin bundle orderSymfony2 - Give a default filter in a list of elements of Sonata AdminCustomize the Sonata Admin Dashboard - Sonata and Symfony 2Creating custom form type using sonata form type as parentSonata Admin Filter: Invalid parameter number: number of bound variables does not match number of tokenssonata admin custom list field (not from entity)sonata admin add richhtml editor to block contentSonata sort admin list using a aggregate on a child fieldSonata form field - change a field based on the selection of another model fieldSonata admin: mosaic selected by default

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

0

I have a property in my method configureDatagridFilters() called assignee. When the list view of my admin is first loaded, I'd like to set the value of this property to the current user.

I have tried:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser(),
 ];

 return $parameters;

as well as an array_merge instead. None of them achieved what I'm after, it still just shows me the default/entire list.

I have tried adding a type, bit unclear as to what the type is as some examples I've seen are like EntityType::class and others just a number 3.

symfony sonata-admin sonata symfony-sonata

share|improve this question

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

add a comment | 

0

I have a property in my method configureDatagridFilters() called assignee. When the list view of my admin is first loaded, I'd like to set the value of this property to the current user.

I have tried:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser(),
 ];

 return $parameters;

as well as an array_merge instead. None of them achieved what I'm after, it still just shows me the default/entire list.

I have tried adding a type, bit unclear as to what the type is as some examples I've seen are like EntityType::class and others just a number 3.

symfony sonata-admin sonata symfony-sonata

share|improve this question

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

add a comment | 

I have a property in my method configureDatagridFilters() called assignee. When the list view of my admin is first loaded, I'd like to set the value of this property to the current user.

I have tried:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser(),
 ];

 return $parameters;

as well as an array_merge instead. None of them achieved what I'm after, it still just shows me the default/entire list.

I have tried adding a type, bit unclear as to what the type is as some examples I've seen are like EntityType::class and others just a number 3.

symfony sonata-admin sonata symfony-sonata

share|improve this question

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser(),
 ];

 return $parameters;

share|improve this question

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

share|improve this question

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

asked Mar 27 at 12:18

MylesKMylesK

2151212 bronze badges

1 Answer
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0

So I figured out how to set the filter by default to the current user.

My filter is an EntityType::class with the class of User::class. In order for the code snippet above to work, you must set the value to the user ID and not the user object like so: 'value' => $this->getUser()->getId().

So the full method would be:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser()->getId(),
 ];

 return $parameters;

share|improve this answer

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges

add a comment | 

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0

So I figured out how to set the filter by default to the current user.

My filter is an EntityType::class with the class of User::class. In order for the code snippet above to work, you must set the value to the user ID and not the user object like so: 'value' => $this->getUser()->getId().

So the full method would be:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser()->getId(),
 ];

 return $parameters;

share|improve this answer

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges

add a comment | 

0

So I figured out how to set the filter by default to the current user.

My filter is an EntityType::class with the class of User::class. In order for the code snippet above to work, you must set the value to the user ID and not the user object like so: 'value' => $this->getUser()->getId().

So the full method would be:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser()->getId(),
 ];

 return $parameters;

share|improve this answer

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges

add a comment | 

So I figured out how to set the filter by default to the current user.

My filter is an EntityType::class with the class of User::class. In order for the code snippet above to work, you must set the value to the user ID and not the user object like so: 'value' => $this->getUser()->getId().

So the full method would be:

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser()->getId(),
 ];

 return $parameters;

share|improve this answer

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges

public function getFilterParameters()

 $parameters = parent::getFilterParameters();

 $parameters['assignee'] = [
 'value' => $this->getUser()->getId(),
 ];

 return $parameters;

share|improve this answer

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges

answered Mar 28 at 15:27

MylesKMylesK

2151212 bronze badges