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Where is the C++ operators are initially defined?


What are the differences between a pointer variable and a reference variable in C++?The Definitive C++ Book Guide and ListC++ Singleton design patternWhat is the “-->” operator in C++?What is the copy-and-swap idiom?What are the basic rules and idioms for operator overloading?C++11 introduced a standardized memory model. What does it mean? And how is it going to affect C++ programming?Why should C++ programmers minimize use of 'new'?Why are elementwise additions much faster in separate loops than in a combined loop?Can code that is valid in both C and C++ produce different behavior when compiled in each language?






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0















The topic we covered operator overloaded. They say the defined operators of C++ have already different meaning then you should create another ones. My question is where the initial C++ operators are defined, I mean which library have these operator implementation for default?










share|improve this question



















  • 2





    They are not part of a library, they are built in to the compiler.

    – Neil Butterworth
    Mar 25 at 21:41












  • How can reach that the compiler information?

    – Tahir Furkan Kizir Student
    Mar 26 at 22:03

















0















The topic we covered operator overloaded. They say the defined operators of C++ have already different meaning then you should create another ones. My question is where the initial C++ operators are defined, I mean which library have these operator implementation for default?










share|improve this question



















  • 2





    They are not part of a library, they are built in to the compiler.

    – Neil Butterworth
    Mar 25 at 21:41












  • How can reach that the compiler information?

    – Tahir Furkan Kizir Student
    Mar 26 at 22:03













0












0








0








The topic we covered operator overloaded. They say the defined operators of C++ have already different meaning then you should create another ones. My question is where the initial C++ operators are defined, I mean which library have these operator implementation for default?










share|improve this question














The topic we covered operator overloaded. They say the defined operators of C++ have already different meaning then you should create another ones. My question is where the initial C++ operators are defined, I mean which library have these operator implementation for default?







c++ operator-overloading






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 25 at 21:40









Tahir Furkan Kizir StudentTahir Furkan Kizir Student

11




11










  • 2





    They are not part of a library, they are built in to the compiler.

    – Neil Butterworth
    Mar 25 at 21:41












  • How can reach that the compiler information?

    – Tahir Furkan Kizir Student
    Mar 26 at 22:03












  • 2





    They are not part of a library, they are built in to the compiler.

    – Neil Butterworth
    Mar 25 at 21:41












  • How can reach that the compiler information?

    – Tahir Furkan Kizir Student
    Mar 26 at 22:03







2




2





They are not part of a library, they are built in to the compiler.

– Neil Butterworth
Mar 25 at 21:41






They are not part of a library, they are built in to the compiler.

– Neil Butterworth
Mar 25 at 21:41














How can reach that the compiler information?

– Tahir Furkan Kizir Student
Mar 26 at 22:03





How can reach that the compiler information?

– Tahir Furkan Kizir Student
Mar 26 at 22:03












1 Answer
1






active

oldest

votes


















0














The standard operators are not defined in any library, they are built into the language and implemented by the compiler. Libraries and user code can then overload them as needed.






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    0














    The standard operators are not defined in any library, they are built into the language and implemented by the compiler. Libraries and user code can then overload them as needed.






    share|improve this answer





























      0














      The standard operators are not defined in any library, they are built into the language and implemented by the compiler. Libraries and user code can then overload them as needed.






      share|improve this answer



























        0












        0








        0







        The standard operators are not defined in any library, they are built into the language and implemented by the compiler. Libraries and user code can then overload them as needed.






        share|improve this answer













        The standard operators are not defined in any library, they are built into the language and implemented by the compiler. Libraries and user code can then overload them as needed.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 25 at 21:42









        Remy LebeauRemy Lebeau

        357k19 gold badges286 silver badges483 bronze badges




        357k19 gold badges286 silver badges483 bronze badges



















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