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How to make new line in Gmail using “SMPTLIB PYTHON”?


How do I check whether a file exists without exceptions?Calling an external command in PythonWhat are metaclasses in Python?Hidden features of PythonHow can I safely create a nested directory?Does Python have a ternary conditional operator?How can I make a time delay in Python?How to make a chain of function decorators?How to make a flat list out of list of listsDoes Python have a string 'contains' substring method?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















Here's the code:



print "type END to send the message"
while(True):
message = raw_input("> Message : ")
if message != 'END':
msg.attach(MIMEText(message, 'plain'))
else:
break


It doesn't make a new line in the gmail message... so what's the code to make a new line for smtplib python?










share|improve this question


























  • Where are you expecting to see this newline, and why? This code will produce a valid multipart message, assuming msg is a MIMEMultipart instance.

    – snakecharmerb
    Mar 29 at 13:57

















0















Here's the code:



print "type END to send the message"
while(True):
message = raw_input("> Message : ")
if message != 'END':
msg.attach(MIMEText(message, 'plain'))
else:
break


It doesn't make a new line in the gmail message... so what's the code to make a new line for smtplib python?










share|improve this question


























  • Where are you expecting to see this newline, and why? This code will produce a valid multipart message, assuming msg is a MIMEMultipart instance.

    – snakecharmerb
    Mar 29 at 13:57













0












0








0








Here's the code:



print "type END to send the message"
while(True):
message = raw_input("> Message : ")
if message != 'END':
msg.attach(MIMEText(message, 'plain'))
else:
break


It doesn't make a new line in the gmail message... so what's the code to make a new line for smtplib python?










share|improve this question
















Here's the code:



print "type END to send the message"
while(True):
message = raw_input("> Message : ")
if message != 'END':
msg.attach(MIMEText(message, 'plain'))
else:
break


It doesn't make a new line in the gmail message... so what's the code to make a new line for smtplib python?







python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 28 at 4:37









jkdev

5,8836 gold badges39 silver badges69 bronze badges




5,8836 gold badges39 silver badges69 bronze badges










asked Mar 28 at 4:08









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1




1















  • Where are you expecting to see this newline, and why? This code will produce a valid multipart message, assuming msg is a MIMEMultipart instance.

    – snakecharmerb
    Mar 29 at 13:57

















  • Where are you expecting to see this newline, and why? This code will produce a valid multipart message, assuming msg is a MIMEMultipart instance.

    – snakecharmerb
    Mar 29 at 13:57
















Where are you expecting to see this newline, and why? This code will produce a valid multipart message, assuming msg is a MIMEMultipart instance.

– snakecharmerb
Mar 29 at 13:57





Where are you expecting to see this newline, and why? This code will produce a valid multipart message, assuming msg is a MIMEMultipart instance.

– snakecharmerb
Mar 29 at 13:57












0






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