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How to replicate all rows of a dataframe for each ID of another dataframe in R?
The Next CEO of Stack OverflowHow to sort a dataframe by multiple column(s)?Remove rows with all or some NAs (missing values) in data.frameHow do I replace NA values with zeros in an R dataframe?How to delete rows from a dataframe that contain n*NAhow to take mean of a subset of a dataframe within for loop in rHow to create a new dataframe with summarized data in R?Consolidating duplicate rows in a dataframeHow to generate, populate and update a new dataframe based on an old dataframe?Reshaping a dataframe by moving part of an existing row to a new rowUse dplyr to change an R dataframe from second row across multiple columns
I have one dataframe (df_features) consisting of 32 rows and six columns that relate to potential features of a study and a second dataframe (df_participants) containing 10,000 unique (non-numeric) IDs of my participants. There are no common columns across the two dataframes.
I want to create a dataset that contains each of the 32 rows from df_features for every ID in df_participants (so 320,000 rows and 7 columns in total).
How do I do this? I feel like it should be straightforward but I just can't find anything anywhere!
r join
add a comment |
I have one dataframe (df_features) consisting of 32 rows and six columns that relate to potential features of a study and a second dataframe (df_participants) containing 10,000 unique (non-numeric) IDs of my participants. There are no common columns across the two dataframes.
I want to create a dataset that contains each of the 32 rows from df_features for every ID in df_participants (so 320,000 rows and 7 columns in total).
How do I do this? I feel like it should be straightforward but I just can't find anything anywhere!
r join
add a comment |
I have one dataframe (df_features) consisting of 32 rows and six columns that relate to potential features of a study and a second dataframe (df_participants) containing 10,000 unique (non-numeric) IDs of my participants. There are no common columns across the two dataframes.
I want to create a dataset that contains each of the 32 rows from df_features for every ID in df_participants (so 320,000 rows and 7 columns in total).
How do I do this? I feel like it should be straightforward but I just can't find anything anywhere!
r join
I have one dataframe (df_features) consisting of 32 rows and six columns that relate to potential features of a study and a second dataframe (df_participants) containing 10,000 unique (non-numeric) IDs of my participants. There are no common columns across the two dataframes.
I want to create a dataset that contains each of the 32 rows from df_features for every ID in df_participants (so 320,000 rows and 7 columns in total).
How do I do this? I feel like it should be straightforward but I just can't find anything anywhere!
r join
r join
asked Mar 21 at 17:03
MelMel
396
396
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
It sounds like you are looking to do a full outer join that will combine all features with all IDs. This can be done using several packages, and in base-R with the following:
features <- data.frame(f1=c("blue","geeen"),f2=c("young","old"))
participants <- data.frame(ID=c(1:10))
merge(features,participants,all=T)
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
add a comment |
You can do a full outer join. When you do a full outer join with no common columns across the two dataframes, you get the cartesian product of the two dataframes, which is what you're looking for. You can get this using the merge
function. If your only two arguments to merge
are the dataframes you want to perform the join on, you will get back the cartesian product of those dataframes.
Example:
df1 <- data.frame(y = 1:4)
df2 <- data.frame(z = 1:3)
df_merged <- merge(df1, df2)
print(df1)
# y
#1 1
#2 2
#3 3
#4 4
print(df2)
# z
#1 1
#2 2
#3 3
print(df_merged)
# y z
#1 1 1
#2 2 1
#3 3 1
#4 4 1
#5 1 2
#6 2 2
#7 3 2
#8 4 2
#9 1 3
#10 2 3
#11 3 3
#12 4 3
add a comment |
I found a fairly convoluted way around it in case anyone is looking to do something similar:
matching_1<- expand.grid(df_participants$ID, df_features$feature_rownumber) %>% arrange(Var1) %>%
rename("ID"=Var1, "feature_rownumber"=Var2)
matching_2 <- left_join(df_participants, matching_1, by="ID")
final_dataset <- left_join(matching_2, df_features, by="feature_rownumber")
However I'm fairly sure there must be a more concise method out there!
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
It sounds like you are looking to do a full outer join that will combine all features with all IDs. This can be done using several packages, and in base-R with the following:
features <- data.frame(f1=c("blue","geeen"),f2=c("young","old"))
participants <- data.frame(ID=c(1:10))
merge(features,participants,all=T)
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
add a comment |
It sounds like you are looking to do a full outer join that will combine all features with all IDs. This can be done using several packages, and in base-R with the following:
features <- data.frame(f1=c("blue","geeen"),f2=c("young","old"))
participants <- data.frame(ID=c(1:10))
merge(features,participants,all=T)
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
add a comment |
It sounds like you are looking to do a full outer join that will combine all features with all IDs. This can be done using several packages, and in base-R with the following:
features <- data.frame(f1=c("blue","geeen"),f2=c("young","old"))
participants <- data.frame(ID=c(1:10))
merge(features,participants,all=T)
It sounds like you are looking to do a full outer join that will combine all features with all IDs. This can be done using several packages, and in base-R with the following:
features <- data.frame(f1=c("blue","geeen"),f2=c("young","old"))
participants <- data.frame(ID=c(1:10))
merge(features,participants,all=T)
answered Mar 21 at 17:17
SorenSoren
1,2431711
1,2431711
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
add a comment |
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
Thanks, that's much better than the ridiculous method I initially used!
– Mel
Mar 21 at 17:30
add a comment |
You can do a full outer join. When you do a full outer join with no common columns across the two dataframes, you get the cartesian product of the two dataframes, which is what you're looking for. You can get this using the merge
function. If your only two arguments to merge
are the dataframes you want to perform the join on, you will get back the cartesian product of those dataframes.
Example:
df1 <- data.frame(y = 1:4)
df2 <- data.frame(z = 1:3)
df_merged <- merge(df1, df2)
print(df1)
# y
#1 1
#2 2
#3 3
#4 4
print(df2)
# z
#1 1
#2 2
#3 3
print(df_merged)
# y z
#1 1 1
#2 2 1
#3 3 1
#4 4 1
#5 1 2
#6 2 2
#7 3 2
#8 4 2
#9 1 3
#10 2 3
#11 3 3
#12 4 3
add a comment |
You can do a full outer join. When you do a full outer join with no common columns across the two dataframes, you get the cartesian product of the two dataframes, which is what you're looking for. You can get this using the merge
function. If your only two arguments to merge
are the dataframes you want to perform the join on, you will get back the cartesian product of those dataframes.
Example:
df1 <- data.frame(y = 1:4)
df2 <- data.frame(z = 1:3)
df_merged <- merge(df1, df2)
print(df1)
# y
#1 1
#2 2
#3 3
#4 4
print(df2)
# z
#1 1
#2 2
#3 3
print(df_merged)
# y z
#1 1 1
#2 2 1
#3 3 1
#4 4 1
#5 1 2
#6 2 2
#7 3 2
#8 4 2
#9 1 3
#10 2 3
#11 3 3
#12 4 3
add a comment |
You can do a full outer join. When you do a full outer join with no common columns across the two dataframes, you get the cartesian product of the two dataframes, which is what you're looking for. You can get this using the merge
function. If your only two arguments to merge
are the dataframes you want to perform the join on, you will get back the cartesian product of those dataframes.
Example:
df1 <- data.frame(y = 1:4)
df2 <- data.frame(z = 1:3)
df_merged <- merge(df1, df2)
print(df1)
# y
#1 1
#2 2
#3 3
#4 4
print(df2)
# z
#1 1
#2 2
#3 3
print(df_merged)
# y z
#1 1 1
#2 2 1
#3 3 1
#4 4 1
#5 1 2
#6 2 2
#7 3 2
#8 4 2
#9 1 3
#10 2 3
#11 3 3
#12 4 3
You can do a full outer join. When you do a full outer join with no common columns across the two dataframes, you get the cartesian product of the two dataframes, which is what you're looking for. You can get this using the merge
function. If your only two arguments to merge
are the dataframes you want to perform the join on, you will get back the cartesian product of those dataframes.
Example:
df1 <- data.frame(y = 1:4)
df2 <- data.frame(z = 1:3)
df_merged <- merge(df1, df2)
print(df1)
# y
#1 1
#2 2
#3 3
#4 4
print(df2)
# z
#1 1
#2 2
#3 3
print(df_merged)
# y z
#1 1 1
#2 2 1
#3 3 1
#4 4 1
#5 1 2
#6 2 2
#7 3 2
#8 4 2
#9 1 3
#10 2 3
#11 3 3
#12 4 3
edited Mar 21 at 17:20
answered Mar 21 at 17:14
David RosenmanDavid Rosenman
63239
63239
add a comment |
add a comment |
I found a fairly convoluted way around it in case anyone is looking to do something similar:
matching_1<- expand.grid(df_participants$ID, df_features$feature_rownumber) %>% arrange(Var1) %>%
rename("ID"=Var1, "feature_rownumber"=Var2)
matching_2 <- left_join(df_participants, matching_1, by="ID")
final_dataset <- left_join(matching_2, df_features, by="feature_rownumber")
However I'm fairly sure there must be a more concise method out there!
add a comment |
I found a fairly convoluted way around it in case anyone is looking to do something similar:
matching_1<- expand.grid(df_participants$ID, df_features$feature_rownumber) %>% arrange(Var1) %>%
rename("ID"=Var1, "feature_rownumber"=Var2)
matching_2 <- left_join(df_participants, matching_1, by="ID")
final_dataset <- left_join(matching_2, df_features, by="feature_rownumber")
However I'm fairly sure there must be a more concise method out there!
add a comment |
I found a fairly convoluted way around it in case anyone is looking to do something similar:
matching_1<- expand.grid(df_participants$ID, df_features$feature_rownumber) %>% arrange(Var1) %>%
rename("ID"=Var1, "feature_rownumber"=Var2)
matching_2 <- left_join(df_participants, matching_1, by="ID")
final_dataset <- left_join(matching_2, df_features, by="feature_rownumber")
However I'm fairly sure there must be a more concise method out there!
I found a fairly convoluted way around it in case anyone is looking to do something similar:
matching_1<- expand.grid(df_participants$ID, df_features$feature_rownumber) %>% arrange(Var1) %>%
rename("ID"=Var1, "feature_rownumber"=Var2)
matching_2 <- left_join(df_participants, matching_1, by="ID")
final_dataset <- left_join(matching_2, df_features, by="feature_rownumber")
However I'm fairly sure there must be a more concise method out there!
answered Mar 21 at 17:27
MelMel
396
396
add a comment |
add a comment |
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