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3D plot of the CONE using matplotlib
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!How do you change the size of figures drawn with matplotlib?Plot logarithmic axes with matplotlib in pythonHiding axis text in matplotlib plotsHow to change the font size on a matplotlib plotHow to put the legend out of the plotWhen to use cla(), clf() or close() for clearing a plot in matplotlib?Save plot to image file instead of displaying it using MatplotlibHow to make IPython notebook matplotlib plot inlineInstallation Issue with matplotlib PythonPython Matplotlib - how to set values on y axis in barchart
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I'm looking for help to draw a 3D cone using matplotlib.
My goal is to draw a HSL cone, then base on the vertex coordinats i will select the color.
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
theta1 = np.linspace(0, 2*np.pi, 100)
r1 = np.linspace(-2, 0, 100)
t1, R1 = np.meshgrid(theta1, r1)
X1 = R1*np.cos(t1)
Y1 = R1*np.sin(t1)
Z1 = 5+R1*2.5
theta2 = np.linspace(0, 2*np.pi, 100)
r2 = np.linspace(0, 2, 100)
t2, R2 = np.meshgrid(theta2, r2)
X2 = R2*np.cos(t2)
Y2 = R2*np.sin(t2)
Z2 = -5+R2*2.5
ax.set_xlabel('x axis')
ax.set_ylabel('y axis')
ax.set_zlabel('z axis')
# ax.set_xlim(-2.5, 2.5)
# ax.set_ylim(-2.5, 2.5)
# ax.set_zlim(0, 5)
ax.set_aspect('equal')
ax.plot_surface(X1, Y1, Z1, alpha=0.8, color="blue")
ax.plot_surface(X2, Y2, Z2, alpha=0.8, color="blue")
# ax.plot_surface(X, Y, Z, alpha=0.8)
#fig. savefig ("Cone.png", dpi=100, transparent = False)
plt.show()
HSL CONE
My cone
So my question now is how to define color of each element.
python matplotlib 3d
add a comment |
I'm looking for help to draw a 3D cone using matplotlib.
My goal is to draw a HSL cone, then base on the vertex coordinats i will select the color.
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
theta1 = np.linspace(0, 2*np.pi, 100)
r1 = np.linspace(-2, 0, 100)
t1, R1 = np.meshgrid(theta1, r1)
X1 = R1*np.cos(t1)
Y1 = R1*np.sin(t1)
Z1 = 5+R1*2.5
theta2 = np.linspace(0, 2*np.pi, 100)
r2 = np.linspace(0, 2, 100)
t2, R2 = np.meshgrid(theta2, r2)
X2 = R2*np.cos(t2)
Y2 = R2*np.sin(t2)
Z2 = -5+R2*2.5
ax.set_xlabel('x axis')
ax.set_ylabel('y axis')
ax.set_zlabel('z axis')
# ax.set_xlim(-2.5, 2.5)
# ax.set_ylim(-2.5, 2.5)
# ax.set_zlim(0, 5)
ax.set_aspect('equal')
ax.plot_surface(X1, Y1, Z1, alpha=0.8, color="blue")
ax.plot_surface(X2, Y2, Z2, alpha=0.8, color="blue")
# ax.plot_surface(X, Y, Z, alpha=0.8)
#fig. savefig ("Cone.png", dpi=100, transparent = False)
plt.show()
HSL CONE
My cone
So my question now is how to define color of each element.
python matplotlib 3d
Hello! Did you try anything? Please share your efforts and explain where you are struck. As it is, It seems that you are expenting people do the work for you. See how to ask.
– Valentino
Mar 22 at 11:04
Hi, sorry, I did'n mean that. The thing is, I know how to build a 3d cone, but now I'm looking for the method how to define the vertex color base on the vertex coordinats.
– kking
Mar 22 at 11:45
An example here: matplotlib.org/gallery/mplot3d/… may be helpful.
– swatchai
Mar 22 at 12:36
add a comment |
I'm looking for help to draw a 3D cone using matplotlib.
My goal is to draw a HSL cone, then base on the vertex coordinats i will select the color.
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
theta1 = np.linspace(0, 2*np.pi, 100)
r1 = np.linspace(-2, 0, 100)
t1, R1 = np.meshgrid(theta1, r1)
X1 = R1*np.cos(t1)
Y1 = R1*np.sin(t1)
Z1 = 5+R1*2.5
theta2 = np.linspace(0, 2*np.pi, 100)
r2 = np.linspace(0, 2, 100)
t2, R2 = np.meshgrid(theta2, r2)
X2 = R2*np.cos(t2)
Y2 = R2*np.sin(t2)
Z2 = -5+R2*2.5
ax.set_xlabel('x axis')
ax.set_ylabel('y axis')
ax.set_zlabel('z axis')
# ax.set_xlim(-2.5, 2.5)
# ax.set_ylim(-2.5, 2.5)
# ax.set_zlim(0, 5)
ax.set_aspect('equal')
ax.plot_surface(X1, Y1, Z1, alpha=0.8, color="blue")
ax.plot_surface(X2, Y2, Z2, alpha=0.8, color="blue")
# ax.plot_surface(X, Y, Z, alpha=0.8)
#fig. savefig ("Cone.png", dpi=100, transparent = False)
plt.show()
HSL CONE
My cone
So my question now is how to define color of each element.
python matplotlib 3d
I'm looking for help to draw a 3D cone using matplotlib.
My goal is to draw a HSL cone, then base on the vertex coordinats i will select the color.
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
theta1 = np.linspace(0, 2*np.pi, 100)
r1 = np.linspace(-2, 0, 100)
t1, R1 = np.meshgrid(theta1, r1)
X1 = R1*np.cos(t1)
Y1 = R1*np.sin(t1)
Z1 = 5+R1*2.5
theta2 = np.linspace(0, 2*np.pi, 100)
r2 = np.linspace(0, 2, 100)
t2, R2 = np.meshgrid(theta2, r2)
X2 = R2*np.cos(t2)
Y2 = R2*np.sin(t2)
Z2 = -5+R2*2.5
ax.set_xlabel('x axis')
ax.set_ylabel('y axis')
ax.set_zlabel('z axis')
# ax.set_xlim(-2.5, 2.5)
# ax.set_ylim(-2.5, 2.5)
# ax.set_zlim(0, 5)
ax.set_aspect('equal')
ax.plot_surface(X1, Y1, Z1, alpha=0.8, color="blue")
ax.plot_surface(X2, Y2, Z2, alpha=0.8, color="blue")
# ax.plot_surface(X, Y, Z, alpha=0.8)
#fig. savefig ("Cone.png", dpi=100, transparent = False)
plt.show()
HSL CONE
My cone
So my question now is how to define color of each element.
python matplotlib 3d
python matplotlib 3d
edited Mar 22 at 12:05
kking
asked Mar 22 at 10:58
kkingkking
11
11
Hello! Did you try anything? Please share your efforts and explain where you are struck. As it is, It seems that you are expenting people do the work for you. See how to ask.
– Valentino
Mar 22 at 11:04
Hi, sorry, I did'n mean that. The thing is, I know how to build a 3d cone, but now I'm looking for the method how to define the vertex color base on the vertex coordinats.
– kking
Mar 22 at 11:45
An example here: matplotlib.org/gallery/mplot3d/… may be helpful.
– swatchai
Mar 22 at 12:36
add a comment |
Hello! Did you try anything? Please share your efforts and explain where you are struck. As it is, It seems that you are expenting people do the work for you. See how to ask.
– Valentino
Mar 22 at 11:04
Hi, sorry, I did'n mean that. The thing is, I know how to build a 3d cone, but now I'm looking for the method how to define the vertex color base on the vertex coordinats.
– kking
Mar 22 at 11:45
An example here: matplotlib.org/gallery/mplot3d/… may be helpful.
– swatchai
Mar 22 at 12:36
Hello! Did you try anything? Please share your efforts and explain where you are struck. As it is, It seems that you are expenting people do the work for you. See how to ask.
– Valentino
Mar 22 at 11:04
Hello! Did you try anything? Please share your efforts and explain where you are struck. As it is, It seems that you are expenting people do the work for you. See how to ask.
– Valentino
Mar 22 at 11:04
Hi, sorry, I did'n mean that. The thing is, I know how to build a 3d cone, but now I'm looking for the method how to define the vertex color base on the vertex coordinats.
– kking
Mar 22 at 11:45
Hi, sorry, I did'n mean that. The thing is, I know how to build a 3d cone, but now I'm looking for the method how to define the vertex color base on the vertex coordinats.
– kking
Mar 22 at 11:45
An example here: matplotlib.org/gallery/mplot3d/… may be helpful.
– swatchai
Mar 22 at 12:36
An example here: matplotlib.org/gallery/mplot3d/… may be helpful.
– swatchai
Mar 22 at 12:36
add a comment |
1 Answer
1
active
oldest
votes
i have found a solution, maybe it will be usefull for others.
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
import colorsys
from matplotlib.tri import Triangulation
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
n_angles = 80
n_radii = 20
# An array of radii
# Does not include radius r=0, this is to eliminate duplicate points
radii = np.linspace(0.0, 0.5, n_radii)
# An array of angles
angles = np.linspace(0, 2*np.pi, n_angles, endpoint=False)
# Repeat all angles for each radius
angles = np.repeat(angles[..., np.newaxis], n_radii, axis=1)
# Convert polar (radii, angles) coords to cartesian (x, y) coords
# (0, 0) is added here. There are no duplicate points in the (x, y) plane
x = np.append(0, (radii*np.cos(angles)).flatten())
y = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z = 1+-np.sqrt(x**2+y**2)*2
print(x.shape, y.shape, angles.shape, radii.shape, z.shape)
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri = Triangulation(x, y)
triangle_vertices = np.array([np.array([[x[T[0]], y[T[0]], z[T[0]]],
[x[T[1]], y[T[1]], z[T[1]]],
[x[T[2]], y[T[2]], z[T[2]]]]) for T in tri.triangles])
x2 = np.append(0, (radii*np.cos(angles)).flatten())
y2 = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z2 = -1+np.sqrt(x**2+y**2)*2
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri2 = Triangulation(x2, y2)
triangle_vertices2 = np.array([np.array([[x2[T[0]], y2[T[0]], z2[T[0]]],
[x2[T[1]], y2[T[1]], z2[T[1]]],
[x2[T[2]], y2[T[2]], z2[T[2]]]]) for T in tri2.triangles])
triangle_vertices = np.concatenate([triangle_vertices, triangle_vertices2])
midpoints = np.average(triangle_vertices, axis=1)
def find_color_for_point(pt):
c_x, c_y, c_z = pt
angle = np.arctan2(c_x, c_y)*180/np.pi
if (angle < 0):
angle = angle + 360
if c_z < 0:
l = 0.5 - abs(c_z)/2
#l=0
if c_z == 0:
l = 0.5
if c_z > 0:
l = (1 - (1-c_z)/2)
if c_z > 0.97:
l = (1 - (1-c_z)/2)
col = colorsys.hls_to_rgb(angle/360, l, 1)
return col
facecolors = [find_color_for_point(pt) for pt in midpoints] # smooth gradient
# facecolors = [np.random.random(3) for pt in midpoints] # random colors
coll = Poly3DCollection(
triangle_vertices, facecolors=facecolors, edgecolors=None)
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.add_collection(coll)
ax.set_xlim(-1, 1)
ax.set_ylim(-1, 1)
ax.set_zlim(-1, 1)
ax.elev = 50
plt.show()
add a comment |
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1 Answer
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active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
i have found a solution, maybe it will be usefull for others.
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
import colorsys
from matplotlib.tri import Triangulation
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
n_angles = 80
n_radii = 20
# An array of radii
# Does not include radius r=0, this is to eliminate duplicate points
radii = np.linspace(0.0, 0.5, n_radii)
# An array of angles
angles = np.linspace(0, 2*np.pi, n_angles, endpoint=False)
# Repeat all angles for each radius
angles = np.repeat(angles[..., np.newaxis], n_radii, axis=1)
# Convert polar (radii, angles) coords to cartesian (x, y) coords
# (0, 0) is added here. There are no duplicate points in the (x, y) plane
x = np.append(0, (radii*np.cos(angles)).flatten())
y = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z = 1+-np.sqrt(x**2+y**2)*2
print(x.shape, y.shape, angles.shape, radii.shape, z.shape)
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri = Triangulation(x, y)
triangle_vertices = np.array([np.array([[x[T[0]], y[T[0]], z[T[0]]],
[x[T[1]], y[T[1]], z[T[1]]],
[x[T[2]], y[T[2]], z[T[2]]]]) for T in tri.triangles])
x2 = np.append(0, (radii*np.cos(angles)).flatten())
y2 = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z2 = -1+np.sqrt(x**2+y**2)*2
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri2 = Triangulation(x2, y2)
triangle_vertices2 = np.array([np.array([[x2[T[0]], y2[T[0]], z2[T[0]]],
[x2[T[1]], y2[T[1]], z2[T[1]]],
[x2[T[2]], y2[T[2]], z2[T[2]]]]) for T in tri2.triangles])
triangle_vertices = np.concatenate([triangle_vertices, triangle_vertices2])
midpoints = np.average(triangle_vertices, axis=1)
def find_color_for_point(pt):
c_x, c_y, c_z = pt
angle = np.arctan2(c_x, c_y)*180/np.pi
if (angle < 0):
angle = angle + 360
if c_z < 0:
l = 0.5 - abs(c_z)/2
#l=0
if c_z == 0:
l = 0.5
if c_z > 0:
l = (1 - (1-c_z)/2)
if c_z > 0.97:
l = (1 - (1-c_z)/2)
col = colorsys.hls_to_rgb(angle/360, l, 1)
return col
facecolors = [find_color_for_point(pt) for pt in midpoints] # smooth gradient
# facecolors = [np.random.random(3) for pt in midpoints] # random colors
coll = Poly3DCollection(
triangle_vertices, facecolors=facecolors, edgecolors=None)
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.add_collection(coll)
ax.set_xlim(-1, 1)
ax.set_ylim(-1, 1)
ax.set_zlim(-1, 1)
ax.elev = 50
plt.show()
add a comment |
i have found a solution, maybe it will be usefull for others.
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
import colorsys
from matplotlib.tri import Triangulation
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
n_angles = 80
n_radii = 20
# An array of radii
# Does not include radius r=0, this is to eliminate duplicate points
radii = np.linspace(0.0, 0.5, n_radii)
# An array of angles
angles = np.linspace(0, 2*np.pi, n_angles, endpoint=False)
# Repeat all angles for each radius
angles = np.repeat(angles[..., np.newaxis], n_radii, axis=1)
# Convert polar (radii, angles) coords to cartesian (x, y) coords
# (0, 0) is added here. There are no duplicate points in the (x, y) plane
x = np.append(0, (radii*np.cos(angles)).flatten())
y = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z = 1+-np.sqrt(x**2+y**2)*2
print(x.shape, y.shape, angles.shape, radii.shape, z.shape)
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri = Triangulation(x, y)
triangle_vertices = np.array([np.array([[x[T[0]], y[T[0]], z[T[0]]],
[x[T[1]], y[T[1]], z[T[1]]],
[x[T[2]], y[T[2]], z[T[2]]]]) for T in tri.triangles])
x2 = np.append(0, (radii*np.cos(angles)).flatten())
y2 = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z2 = -1+np.sqrt(x**2+y**2)*2
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri2 = Triangulation(x2, y2)
triangle_vertices2 = np.array([np.array([[x2[T[0]], y2[T[0]], z2[T[0]]],
[x2[T[1]], y2[T[1]], z2[T[1]]],
[x2[T[2]], y2[T[2]], z2[T[2]]]]) for T in tri2.triangles])
triangle_vertices = np.concatenate([triangle_vertices, triangle_vertices2])
midpoints = np.average(triangle_vertices, axis=1)
def find_color_for_point(pt):
c_x, c_y, c_z = pt
angle = np.arctan2(c_x, c_y)*180/np.pi
if (angle < 0):
angle = angle + 360
if c_z < 0:
l = 0.5 - abs(c_z)/2
#l=0
if c_z == 0:
l = 0.5
if c_z > 0:
l = (1 - (1-c_z)/2)
if c_z > 0.97:
l = (1 - (1-c_z)/2)
col = colorsys.hls_to_rgb(angle/360, l, 1)
return col
facecolors = [find_color_for_point(pt) for pt in midpoints] # smooth gradient
# facecolors = [np.random.random(3) for pt in midpoints] # random colors
coll = Poly3DCollection(
triangle_vertices, facecolors=facecolors, edgecolors=None)
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.add_collection(coll)
ax.set_xlim(-1, 1)
ax.set_ylim(-1, 1)
ax.set_zlim(-1, 1)
ax.elev = 50
plt.show()
add a comment |
i have found a solution, maybe it will be usefull for others.
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
import colorsys
from matplotlib.tri import Triangulation
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
n_angles = 80
n_radii = 20
# An array of radii
# Does not include radius r=0, this is to eliminate duplicate points
radii = np.linspace(0.0, 0.5, n_radii)
# An array of angles
angles = np.linspace(0, 2*np.pi, n_angles, endpoint=False)
# Repeat all angles for each radius
angles = np.repeat(angles[..., np.newaxis], n_radii, axis=1)
# Convert polar (radii, angles) coords to cartesian (x, y) coords
# (0, 0) is added here. There are no duplicate points in the (x, y) plane
x = np.append(0, (radii*np.cos(angles)).flatten())
y = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z = 1+-np.sqrt(x**2+y**2)*2
print(x.shape, y.shape, angles.shape, radii.shape, z.shape)
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri = Triangulation(x, y)
triangle_vertices = np.array([np.array([[x[T[0]], y[T[0]], z[T[0]]],
[x[T[1]], y[T[1]], z[T[1]]],
[x[T[2]], y[T[2]], z[T[2]]]]) for T in tri.triangles])
x2 = np.append(0, (radii*np.cos(angles)).flatten())
y2 = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z2 = -1+np.sqrt(x**2+y**2)*2
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri2 = Triangulation(x2, y2)
triangle_vertices2 = np.array([np.array([[x2[T[0]], y2[T[0]], z2[T[0]]],
[x2[T[1]], y2[T[1]], z2[T[1]]],
[x2[T[2]], y2[T[2]], z2[T[2]]]]) for T in tri2.triangles])
triangle_vertices = np.concatenate([triangle_vertices, triangle_vertices2])
midpoints = np.average(triangle_vertices, axis=1)
def find_color_for_point(pt):
c_x, c_y, c_z = pt
angle = np.arctan2(c_x, c_y)*180/np.pi
if (angle < 0):
angle = angle + 360
if c_z < 0:
l = 0.5 - abs(c_z)/2
#l=0
if c_z == 0:
l = 0.5
if c_z > 0:
l = (1 - (1-c_z)/2)
if c_z > 0.97:
l = (1 - (1-c_z)/2)
col = colorsys.hls_to_rgb(angle/360, l, 1)
return col
facecolors = [find_color_for_point(pt) for pt in midpoints] # smooth gradient
# facecolors = [np.random.random(3) for pt in midpoints] # random colors
coll = Poly3DCollection(
triangle_vertices, facecolors=facecolors, edgecolors=None)
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.add_collection(coll)
ax.set_xlim(-1, 1)
ax.set_ylim(-1, 1)
ax.set_zlim(-1, 1)
ax.elev = 50
plt.show()
i have found a solution, maybe it will be usefull for others.
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
import numpy as np
import colorsys
from matplotlib.tri import Triangulation
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
n_angles = 80
n_radii = 20
# An array of radii
# Does not include radius r=0, this is to eliminate duplicate points
radii = np.linspace(0.0, 0.5, n_radii)
# An array of angles
angles = np.linspace(0, 2*np.pi, n_angles, endpoint=False)
# Repeat all angles for each radius
angles = np.repeat(angles[..., np.newaxis], n_radii, axis=1)
# Convert polar (radii, angles) coords to cartesian (x, y) coords
# (0, 0) is added here. There are no duplicate points in the (x, y) plane
x = np.append(0, (radii*np.cos(angles)).flatten())
y = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z = 1+-np.sqrt(x**2+y**2)*2
print(x.shape, y.shape, angles.shape, radii.shape, z.shape)
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri = Triangulation(x, y)
triangle_vertices = np.array([np.array([[x[T[0]], y[T[0]], z[T[0]]],
[x[T[1]], y[T[1]], z[T[1]]],
[x[T[2]], y[T[2]], z[T[2]]]]) for T in tri.triangles])
x2 = np.append(0, (radii*np.cos(angles)).flatten())
y2 = np.append(0, (radii*np.sin(angles)).flatten())
# Pringle surface
z2 = -1+np.sqrt(x**2+y**2)*2
# NOTE: This assumes that there is a nice projection of the surface into the x/y-plane!
tri2 = Triangulation(x2, y2)
triangle_vertices2 = np.array([np.array([[x2[T[0]], y2[T[0]], z2[T[0]]],
[x2[T[1]], y2[T[1]], z2[T[1]]],
[x2[T[2]], y2[T[2]], z2[T[2]]]]) for T in tri2.triangles])
triangle_vertices = np.concatenate([triangle_vertices, triangle_vertices2])
midpoints = np.average(triangle_vertices, axis=1)
def find_color_for_point(pt):
c_x, c_y, c_z = pt
angle = np.arctan2(c_x, c_y)*180/np.pi
if (angle < 0):
angle = angle + 360
if c_z < 0:
l = 0.5 - abs(c_z)/2
#l=0
if c_z == 0:
l = 0.5
if c_z > 0:
l = (1 - (1-c_z)/2)
if c_z > 0.97:
l = (1 - (1-c_z)/2)
col = colorsys.hls_to_rgb(angle/360, l, 1)
return col
facecolors = [find_color_for_point(pt) for pt in midpoints] # smooth gradient
# facecolors = [np.random.random(3) for pt in midpoints] # random colors
coll = Poly3DCollection(
triangle_vertices, facecolors=facecolors, edgecolors=None)
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.add_collection(coll)
ax.set_xlim(-1, 1)
ax.set_ylim(-1, 1)
ax.set_zlim(-1, 1)
ax.elev = 50
plt.show()
answered Mar 22 at 12:40
kkingkking
11
11
add a comment |
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Hello! Did you try anything? Please share your efforts and explain where you are struck. As it is, It seems that you are expenting people do the work for you. See how to ask.
– Valentino
Mar 22 at 11:04
Hi, sorry, I did'n mean that. The thing is, I know how to build a 3d cone, but now I'm looking for the method how to define the vertex color base on the vertex coordinats.
– kking
Mar 22 at 11:45
An example here: matplotlib.org/gallery/mplot3d/… may be helpful.
– swatchai
Mar 22 at 12:36