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How can I invoke a thread multiple times in Python?
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I'm sorry if it is a stupid question. I am trying to use a number of classes of multi-threading to finish different jobs, which involves invoking these multi-threadings at different times for many times. But I am not sure which method to use. The code looks like this:
class workers1(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers2(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers3(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
WorkerList1=[workers1(i) for i in range(X)]
WorkerList2=[workers2(i) for i in range(XX)]
WorkerList2=[workers3(i) for i in range(XXX)]
while True:
for thread in WorkerList1:
thread.run (start? join? or?)
for thread in WorkerList2:
thread.run (start? join? or?)
for thread in WorkerList3:
thread.run (start? join? or?)
do sth .
I am trying to have all the threads in all the WorkerList to start functioning at the same time, or at least start around the same time. After sometime once they were all terminated, I would like to invoke all the threads again.
If there were no loop, I can just use .start; but since I can only start a thread once, start apparently does not fit here. If I use run, it seems that all the threads start sequentially, not only the threads in the same list, but also threads from different lists.
Can anyone please help?
python multithreading
add a comment |
I'm sorry if it is a stupid question. I am trying to use a number of classes of multi-threading to finish different jobs, which involves invoking these multi-threadings at different times for many times. But I am not sure which method to use. The code looks like this:
class workers1(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers2(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers3(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
WorkerList1=[workers1(i) for i in range(X)]
WorkerList2=[workers2(i) for i in range(XX)]
WorkerList2=[workers3(i) for i in range(XXX)]
while True:
for thread in WorkerList1:
thread.run (start? join? or?)
for thread in WorkerList2:
thread.run (start? join? or?)
for thread in WorkerList3:
thread.run (start? join? or?)
do sth .
I am trying to have all the threads in all the WorkerList to start functioning at the same time, or at least start around the same time. After sometime once they were all terminated, I would like to invoke all the threads again.
If there were no loop, I can just use .start; but since I can only start a thread once, start apparently does not fit here. If I use run, it seems that all the threads start sequentially, not only the threads in the same list, but also threads from different lists.
Can anyone please help?
python multithreading
When defining the Arrays shouldn't the second WorkerList2 be a WorkerList3 instead?
– Enak
Mar 22 at 11:18
add a comment |
I'm sorry if it is a stupid question. I am trying to use a number of classes of multi-threading to finish different jobs, which involves invoking these multi-threadings at different times for many times. But I am not sure which method to use. The code looks like this:
class workers1(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers2(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers3(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
WorkerList1=[workers1(i) for i in range(X)]
WorkerList2=[workers2(i) for i in range(XX)]
WorkerList2=[workers3(i) for i in range(XXX)]
while True:
for thread in WorkerList1:
thread.run (start? join? or?)
for thread in WorkerList2:
thread.run (start? join? or?)
for thread in WorkerList3:
thread.run (start? join? or?)
do sth .
I am trying to have all the threads in all the WorkerList to start functioning at the same time, or at least start around the same time. After sometime once they were all terminated, I would like to invoke all the threads again.
If there were no loop, I can just use .start; but since I can only start a thread once, start apparently does not fit here. If I use run, it seems that all the threads start sequentially, not only the threads in the same list, but also threads from different lists.
Can anyone please help?
python multithreading
I'm sorry if it is a stupid question. I am trying to use a number of classes of multi-threading to finish different jobs, which involves invoking these multi-threadings at different times for many times. But I am not sure which method to use. The code looks like this:
class workers1(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers2(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
class workers3(Thread):
def __init__(self):
Thread.__init__(self)
def run(self):
do some stuff
WorkerList1=[workers1(i) for i in range(X)]
WorkerList2=[workers2(i) for i in range(XX)]
WorkerList2=[workers3(i) for i in range(XXX)]
while True:
for thread in WorkerList1:
thread.run (start? join? or?)
for thread in WorkerList2:
thread.run (start? join? or?)
for thread in WorkerList3:
thread.run (start? join? or?)
do sth .
I am trying to have all the threads in all the WorkerList to start functioning at the same time, or at least start around the same time. After sometime once they were all terminated, I would like to invoke all the threads again.
If there were no loop, I can just use .start; but since I can only start a thread once, start apparently does not fit here. If I use run, it seems that all the threads start sequentially, not only the threads in the same list, but also threads from different lists.
Can anyone please help?
python multithreading
python multithreading
edited Jul 9 '12 at 13:40
Sergey K.
20.9k1385162
20.9k1385162
asked Nov 8 '10 at 8:13
user500432user500432
31113
31113
When defining the Arrays shouldn't the second WorkerList2 be a WorkerList3 instead?
– Enak
Mar 22 at 11:18
add a comment |
When defining the Arrays shouldn't the second WorkerList2 be a WorkerList3 instead?
– Enak
Mar 22 at 11:18
When defining the Arrays shouldn't the second WorkerList2 be a WorkerList3 instead?
– Enak
Mar 22 at 11:18
When defining the Arrays shouldn't the second WorkerList2 be a WorkerList3 instead?
– Enak
Mar 22 at 11:18
add a comment |
3 Answers
3
active
oldest
votes
there are a lot of misconceptions here:
you can only start a specific instance of a thread once. but in your case, the for loop is looping over different instances of a thread, each instance being assigned to the variable
thread
in the loop, so there is no problem at all in calling thestart()
method over each thread. (you can think of it as if the variablethread
is an alias of theThread()
object instantiated in your list)run()
is not the same asjoin()
: callingrun()
performs as if you were programming sequentially. therun()
method does not start a new thread, it simply execute the statements in in the method, as for any other function call.join()
does not start executing anything: it only waits for a thread to finish. in order forjoin()
to work properly for a thread, you have to callstart()
on this thread first.
additionally, you should note that you cannot restart a thread once it has finished execution: you have to recreate the thread object for it to be started again. one workaround to get this working is to call Thread.__init__()
at the end of the run()
method. however, i would not recommend doing this since this will disallow the use of the join()
method to detect the end of execution of the thread.
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
add a comment |
If you would call thread.start()
in the loops, you would actually start every thread only once, because all the entries in your list are distinct thread objects (it does not matter they belong to the same class). You should never call the run()
method of a thread directly -- it is meant to be called by the start()
method. Calling it directly would not call it in a separate thread.
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
Therun()
method of every thread is only invoked once. Write a loop insiderun()
, or use some producer-consumer pattern using thequeue
module.
– Sven Marnach
Nov 8 '10 at 9:04
add a comment |
I had this same dilemma and came up with this solution which has worked perfectly for me. It also allows a thread-killing decorator to be used efficiently.
The key feature is the use of a thread refresher which is instantiated and .start
ed in main
. This thread-refreshing thread will run a function that instantiates and starts all other (real, task-performing) threads. Decorating the thread-refreshing function with a thread-killer allows you to kill all threads when a certain condition is met, such as main
terminating.
@ThreadKiller(arg) #qu'est-ce que c'est
def RefreshThreads():
threadTask1 = threading.Thread(name = "Task1", target = Task1, args = (anyArguments))
threadTask2 = threading.Thread(name = "Task2", target = Task2, args = (anyArguments))
threadTask1.start()
threadTask2.start()
#Main
while True:
#do stuff
threadRefreshThreads = threading.Thread(name = "RefreshThreads", target = RefreshThreads, args = ())
threadRefreshThreads.start()
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
there are a lot of misconceptions here:
you can only start a specific instance of a thread once. but in your case, the for loop is looping over different instances of a thread, each instance being assigned to the variable
thread
in the loop, so there is no problem at all in calling thestart()
method over each thread. (you can think of it as if the variablethread
is an alias of theThread()
object instantiated in your list)run()
is not the same asjoin()
: callingrun()
performs as if you were programming sequentially. therun()
method does not start a new thread, it simply execute the statements in in the method, as for any other function call.join()
does not start executing anything: it only waits for a thread to finish. in order forjoin()
to work properly for a thread, you have to callstart()
on this thread first.
additionally, you should note that you cannot restart a thread once it has finished execution: you have to recreate the thread object for it to be started again. one workaround to get this working is to call Thread.__init__()
at the end of the run()
method. however, i would not recommend doing this since this will disallow the use of the join()
method to detect the end of execution of the thread.
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
add a comment |
there are a lot of misconceptions here:
you can only start a specific instance of a thread once. but in your case, the for loop is looping over different instances of a thread, each instance being assigned to the variable
thread
in the loop, so there is no problem at all in calling thestart()
method over each thread. (you can think of it as if the variablethread
is an alias of theThread()
object instantiated in your list)run()
is not the same asjoin()
: callingrun()
performs as if you were programming sequentially. therun()
method does not start a new thread, it simply execute the statements in in the method, as for any other function call.join()
does not start executing anything: it only waits for a thread to finish. in order forjoin()
to work properly for a thread, you have to callstart()
on this thread first.
additionally, you should note that you cannot restart a thread once it has finished execution: you have to recreate the thread object for it to be started again. one workaround to get this working is to call Thread.__init__()
at the end of the run()
method. however, i would not recommend doing this since this will disallow the use of the join()
method to detect the end of execution of the thread.
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
add a comment |
there are a lot of misconceptions here:
you can only start a specific instance of a thread once. but in your case, the for loop is looping over different instances of a thread, each instance being assigned to the variable
thread
in the loop, so there is no problem at all in calling thestart()
method over each thread. (you can think of it as if the variablethread
is an alias of theThread()
object instantiated in your list)run()
is not the same asjoin()
: callingrun()
performs as if you were programming sequentially. therun()
method does not start a new thread, it simply execute the statements in in the method, as for any other function call.join()
does not start executing anything: it only waits for a thread to finish. in order forjoin()
to work properly for a thread, you have to callstart()
on this thread first.
additionally, you should note that you cannot restart a thread once it has finished execution: you have to recreate the thread object for it to be started again. one workaround to get this working is to call Thread.__init__()
at the end of the run()
method. however, i would not recommend doing this since this will disallow the use of the join()
method to detect the end of execution of the thread.
there are a lot of misconceptions here:
you can only start a specific instance of a thread once. but in your case, the for loop is looping over different instances of a thread, each instance being assigned to the variable
thread
in the loop, so there is no problem at all in calling thestart()
method over each thread. (you can think of it as if the variablethread
is an alias of theThread()
object instantiated in your list)run()
is not the same asjoin()
: callingrun()
performs as if you were programming sequentially. therun()
method does not start a new thread, it simply execute the statements in in the method, as for any other function call.join()
does not start executing anything: it only waits for a thread to finish. in order forjoin()
to work properly for a thread, you have to callstart()
on this thread first.
additionally, you should note that you cannot restart a thread once it has finished execution: you have to recreate the thread object for it to be started again. one workaround to get this working is to call Thread.__init__()
at the end of the run()
method. however, i would not recommend doing this since this will disallow the use of the join()
method to detect the end of execution of the thread.
edited Mar 22 at 11:01
answered Nov 8 '10 at 8:21
Adrien PlissonAdrien Plisson
16.5k43669
16.5k43669
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
add a comment |
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
but it I am using the start() method in the loop, my program may actually give me a runtime error, saying that the thread is already started. So I am not able to invoke the run method within each thread again.
– user500432
Nov 8 '10 at 8:54
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
right, i edited my answer...
– Adrien Plisson
Nov 8 '10 at 9:13
add a comment |
If you would call thread.start()
in the loops, you would actually start every thread only once, because all the entries in your list are distinct thread objects (it does not matter they belong to the same class). You should never call the run()
method of a thread directly -- it is meant to be called by the start()
method. Calling it directly would not call it in a separate thread.
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
Therun()
method of every thread is only invoked once. Write a loop insiderun()
, or use some producer-consumer pattern using thequeue
module.
– Sven Marnach
Nov 8 '10 at 9:04
add a comment |
If you would call thread.start()
in the loops, you would actually start every thread only once, because all the entries in your list are distinct thread objects (it does not matter they belong to the same class). You should never call the run()
method of a thread directly -- it is meant to be called by the start()
method. Calling it directly would not call it in a separate thread.
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
Therun()
method of every thread is only invoked once. Write a loop insiderun()
, or use some producer-consumer pattern using thequeue
module.
– Sven Marnach
Nov 8 '10 at 9:04
add a comment |
If you would call thread.start()
in the loops, you would actually start every thread only once, because all the entries in your list are distinct thread objects (it does not matter they belong to the same class). You should never call the run()
method of a thread directly -- it is meant to be called by the start()
method. Calling it directly would not call it in a separate thread.
If you would call thread.start()
in the loops, you would actually start every thread only once, because all the entries in your list are distinct thread objects (it does not matter they belong to the same class). You should never call the run()
method of a thread directly -- it is meant to be called by the start()
method. Calling it directly would not call it in a separate thread.
answered Nov 8 '10 at 8:24
Sven MarnachSven Marnach
362k80759703
362k80759703
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
Therun()
method of every thread is only invoked once. Write a loop insiderun()
, or use some producer-consumer pattern using thequeue
module.
– Sven Marnach
Nov 8 '10 at 9:04
add a comment |
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
Therun()
method of every thread is only invoked once. Write a loop insiderun()
, or use some producer-consumer pattern using thequeue
module.
– Sven Marnach
Nov 8 '10 at 9:04
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
If my thread is already started, and finished execution, how can I invoke the run method embedded within the thread again? My point was to call the run method within each thread multiple times
– user500432
Nov 8 '10 at 8:57
The
run()
method of every thread is only invoked once. Write a loop inside run()
, or use some producer-consumer pattern using the queue
module.– Sven Marnach
Nov 8 '10 at 9:04
The
run()
method of every thread is only invoked once. Write a loop inside run()
, or use some producer-consumer pattern using the queue
module.– Sven Marnach
Nov 8 '10 at 9:04
add a comment |
I had this same dilemma and came up with this solution which has worked perfectly for me. It also allows a thread-killing decorator to be used efficiently.
The key feature is the use of a thread refresher which is instantiated and .start
ed in main
. This thread-refreshing thread will run a function that instantiates and starts all other (real, task-performing) threads. Decorating the thread-refreshing function with a thread-killer allows you to kill all threads when a certain condition is met, such as main
terminating.
@ThreadKiller(arg) #qu'est-ce que c'est
def RefreshThreads():
threadTask1 = threading.Thread(name = "Task1", target = Task1, args = (anyArguments))
threadTask2 = threading.Thread(name = "Task2", target = Task2, args = (anyArguments))
threadTask1.start()
threadTask2.start()
#Main
while True:
#do stuff
threadRefreshThreads = threading.Thread(name = "RefreshThreads", target = RefreshThreads, args = ())
threadRefreshThreads.start()
add a comment |
I had this same dilemma and came up with this solution which has worked perfectly for me. It also allows a thread-killing decorator to be used efficiently.
The key feature is the use of a thread refresher which is instantiated and .start
ed in main
. This thread-refreshing thread will run a function that instantiates and starts all other (real, task-performing) threads. Decorating the thread-refreshing function with a thread-killer allows you to kill all threads when a certain condition is met, such as main
terminating.
@ThreadKiller(arg) #qu'est-ce que c'est
def RefreshThreads():
threadTask1 = threading.Thread(name = "Task1", target = Task1, args = (anyArguments))
threadTask2 = threading.Thread(name = "Task2", target = Task2, args = (anyArguments))
threadTask1.start()
threadTask2.start()
#Main
while True:
#do stuff
threadRefreshThreads = threading.Thread(name = "RefreshThreads", target = RefreshThreads, args = ())
threadRefreshThreads.start()
add a comment |
I had this same dilemma and came up with this solution which has worked perfectly for me. It also allows a thread-killing decorator to be used efficiently.
The key feature is the use of a thread refresher which is instantiated and .start
ed in main
. This thread-refreshing thread will run a function that instantiates and starts all other (real, task-performing) threads. Decorating the thread-refreshing function with a thread-killer allows you to kill all threads when a certain condition is met, such as main
terminating.
@ThreadKiller(arg) #qu'est-ce que c'est
def RefreshThreads():
threadTask1 = threading.Thread(name = "Task1", target = Task1, args = (anyArguments))
threadTask2 = threading.Thread(name = "Task2", target = Task2, args = (anyArguments))
threadTask1.start()
threadTask2.start()
#Main
while True:
#do stuff
threadRefreshThreads = threading.Thread(name = "RefreshThreads", target = RefreshThreads, args = ())
threadRefreshThreads.start()
I had this same dilemma and came up with this solution which has worked perfectly for me. It also allows a thread-killing decorator to be used efficiently.
The key feature is the use of a thread refresher which is instantiated and .start
ed in main
. This thread-refreshing thread will run a function that instantiates and starts all other (real, task-performing) threads. Decorating the thread-refreshing function with a thread-killer allows you to kill all threads when a certain condition is met, such as main
terminating.
@ThreadKiller(arg) #qu'est-ce que c'est
def RefreshThreads():
threadTask1 = threading.Thread(name = "Task1", target = Task1, args = (anyArguments))
threadTask2 = threading.Thread(name = "Task2", target = Task2, args = (anyArguments))
threadTask1.start()
threadTask2.start()
#Main
while True:
#do stuff
threadRefreshThreads = threading.Thread(name = "RefreshThreads", target = RefreshThreads, args = ())
threadRefreshThreads.start()
edited Apr 19 '18 at 16:25
answered Apr 19 '18 at 14:45
Ctrl SCtrl S
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When defining the Arrays shouldn't the second WorkerList2 be a WorkerList3 instead?
– Enak
Mar 22 at 11:18