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Getting a byte out of a given String of 1s and 0s

0

I am looking for a fast way to get a byte out of a String, if the string consists of 1s and 0s. For example: String a="101010" . How do I get the Byte b ="101010"?

I looked at some other posts but they usually consist of how to get the byte value of a String. I am interested in basically switching the format.

Edit:

to make it more clear, I am looking for this

String a = "101010"
byte b = //What to do?
System.out.print(b)

--> 0b101010

java

share|improve this question

edited Mar 22 at 6:53

Tricker Macedonia

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Some more context would be helpful here. Using your examples, why can't you treat String a as an array and search if it contains Byte b in it. Are you looking for a function that does that?
  
  – Jerry M.
  Mar 21 at 20:03
  

  
  
  
  


• 
  
  
  

  
  12
  

  
  
  
  
  
  

  
  
  Are you looking for byte b = Byte.parseByte(a, 2);
  
  – Elliott Frisch
  Mar 21 at 20:03
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Nope, I have put an extra example to explain what I am looking for
  
  – Tricker Macedonia
  Mar 22 at 6:59
  

  
  
  
  

add a comment | 

0

I am looking for a fast way to get a byte out of a String, if the string consists of 1s and 0s. For example: String a="101010" . How do I get the Byte b ="101010"?

I looked at some other posts but they usually consist of how to get the byte value of a String. I am interested in basically switching the format.

Edit:

to make it more clear, I am looking for this

String a = "101010"
byte b = //What to do?
System.out.print(b)

--> 0b101010

java

share|improve this question

edited Mar 22 at 6:53

Tricker Macedonia

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Some more context would be helpful here. Using your examples, why can't you treat String a as an array and search if it contains Byte b in it. Are you looking for a function that does that?
  
  – Jerry M.
  Mar 21 at 20:03
  

  
  
  
  


• 
  
  
  

  
  12
  

  
  
  
  
  
  

  
  
  Are you looking for byte b = Byte.parseByte(a, 2);
  
  – Elliott Frisch
  Mar 21 at 20:03
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Nope, I have put an extra example to explain what I am looking for
  
  – Tricker Macedonia
  Mar 22 at 6:59
  

  
  
  
  

add a comment | 

I am looking for a fast way to get a byte out of a String, if the string consists of 1s and 0s. For example: String a="101010" . How do I get the Byte b ="101010"?

I looked at some other posts but they usually consist of how to get the byte value of a String. I am interested in basically switching the format.

Edit:

to make it more clear, I am looking for this

String a = "101010"
byte b = //What to do?
System.out.print(b)

--> 0b101010

java

share|improve this question

edited Mar 22 at 6:53

Tricker Macedonia

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

String a = "101010"
byte b = //What to do?
System.out.print(b)

share|improve this question

edited Mar 22 at 6:53

Tricker Macedonia

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

share|improve this question

edited Mar 22 at 6:53

Tricker Macedonia

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

asked Mar 21 at 19:58

Tricker MacedoniaTricker Macedonia

286

2 Answers
2

active

oldest

votes

2

The Byte class and other integral types like Integer can parse numbers in a range of radices from 2 to 36 (encoded using digits 0-9 and letters A-Z).

String a = "101010";
byte b = Byte.parseByte(a, 2);
String c = Integer.toBinaryString(b & 0xFF);
String d = "0b" + c;

Remember, a Java byte is signed, so we need to mask out any high-order bits that would be introduced when used in a way that promotes the value to a signed int.

share|improve this answer

edited Mar 23 at 1:33

answered Mar 21 at 20:44

ericksonerickson

224k42334431

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  String a= "1010"; byte b = Byte.parseByte(a,2); System.out.println(b); printed the decimal value of a. I want it to print the same as "a" 1010... I am not sure if I am clear enough in my post, I just want to get a byte with the same form.
  
  – Tricker Macedonia
  Mar 22 at 6:49
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @TrickerMacedonia it is not the decimal value that you getting
  
  – paradox
  Mar 22 at 7:14
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @TrickerMacedonia I added some detail about conversion back to a String.
  
  – erickson
  Mar 23 at 1:33
  

  
  
  
  

add a comment | 

0

A byte is a signed primitive value in Java, when you print it you will get a decimal representation of that value (by default). You need to perform two steps; first, parse the String into a byte; second, display the byte with your desired formatting (as a binary String with leading 0b). That can be done simply enough, something like

String a = "101010";
byte b = Byte.parseByte(a, 2);
System.out.printf("0b%s%n", Integer.toBinaryString(b));

Which outputs (as requested)

0b101010

share|improve this answer

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191

add a comment | 

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2

The Byte class and other integral types like Integer can parse numbers in a range of radices from 2 to 36 (encoded using digits 0-9 and letters A-Z).

String a = "101010";
byte b = Byte.parseByte(a, 2);
String c = Integer.toBinaryString(b & 0xFF);
String d = "0b" + c;

Remember, a Java byte is signed, so we need to mask out any high-order bits that would be introduced when used in a way that promotes the value to a signed int.

share|improve this answer

edited Mar 23 at 1:33

answered Mar 21 at 20:44

ericksonerickson

224k42334431

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  String a= "1010"; byte b = Byte.parseByte(a,2); System.out.println(b); printed the decimal value of a. I want it to print the same as "a" 1010... I am not sure if I am clear enough in my post, I just want to get a byte with the same form.
  
  – Tricker Macedonia
  Mar 22 at 6:49
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @TrickerMacedonia it is not the decimal value that you getting
  
  – paradox
  Mar 22 at 7:14
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @TrickerMacedonia I added some detail about conversion back to a String.
  
  – erickson
  Mar 23 at 1:33
  

  
  
  
  

add a comment | 

2

The Byte class and other integral types like Integer can parse numbers in a range of radices from 2 to 36 (encoded using digits 0-9 and letters A-Z).

String a = "101010";
byte b = Byte.parseByte(a, 2);
String c = Integer.toBinaryString(b & 0xFF);
String d = "0b" + c;

Remember, a Java byte is signed, so we need to mask out any high-order bits that would be introduced when used in a way that promotes the value to a signed int.

share|improve this answer

edited Mar 23 at 1:33

answered Mar 21 at 20:44

ericksonerickson

224k42334431

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  String a= "1010"; byte b = Byte.parseByte(a,2); System.out.println(b); printed the decimal value of a. I want it to print the same as "a" 1010... I am not sure if I am clear enough in my post, I just want to get a byte with the same form.
  
  – Tricker Macedonia
  Mar 22 at 6:49
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @TrickerMacedonia it is not the decimal value that you getting
  
  – paradox
  Mar 22 at 7:14
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @TrickerMacedonia I added some detail about conversion back to a String.
  
  – erickson
  Mar 23 at 1:33
  

  
  
  
  

add a comment | 

The Byte class and other integral types like Integer can parse numbers in a range of radices from 2 to 36 (encoded using digits 0-9 and letters A-Z).

String a = "101010";
byte b = Byte.parseByte(a, 2);
String c = Integer.toBinaryString(b & 0xFF);
String d = "0b" + c;

Remember, a Java byte is signed, so we need to mask out any high-order bits that would be introduced when used in a way that promotes the value to a signed int.

share|improve this answer

edited Mar 23 at 1:33

answered Mar 21 at 20:44

ericksonerickson

224k42334431

String a = "101010";
byte b = Byte.parseByte(a, 2);
String c = Integer.toBinaryString(b & 0xFF);
String d = "0b" + c;

share|improve this answer

edited Mar 23 at 1:33

answered Mar 21 at 20:44

ericksonerickson

224k42334431

answered Mar 21 at 20:44

ericksonerickson

224k42334431

answered Mar 21 at 20:44

ericksonerickson

224k42334431

0

A byte is a signed primitive value in Java, when you print it you will get a decimal representation of that value (by default). You need to perform two steps; first, parse the String into a byte; second, display the byte with your desired formatting (as a binary String with leading 0b). That can be done simply enough, something like

String a = "101010";
byte b = Byte.parseByte(a, 2);
System.out.printf("0b%s%n", Integer.toBinaryString(b));

Which outputs (as requested)

0b101010

share|improve this answer

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191

add a comment | 

0

A byte is a signed primitive value in Java, when you print it you will get a decimal representation of that value (by default). You need to perform two steps; first, parse the String into a byte; second, display the byte with your desired formatting (as a binary String with leading 0b). That can be done simply enough, something like

String a = "101010";
byte b = Byte.parseByte(a, 2);
System.out.printf("0b%s%n", Integer.toBinaryString(b));

Which outputs (as requested)

0b101010

share|improve this answer

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191

add a comment | 

A byte is a signed primitive value in Java, when you print it you will get a decimal representation of that value (by default). You need to perform two steps; first, parse the String into a byte; second, display the byte with your desired formatting (as a binary String with leading 0b). That can be done simply enough, something like

String a = "101010";
byte b = Byte.parseByte(a, 2);
System.out.printf("0b%s%n", Integer.toBinaryString(b));

Which outputs (as requested)

0b101010

share|improve this answer

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191

String a = "101010";
byte b = Byte.parseByte(a, 2);
System.out.printf("0b%s%n", Integer.toBinaryString(b));

0b101010

share|improve this answer

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191

answered Mar 23 at 20:00

Elliott FrischElliott Frisch

156k1396191