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How do you echo content before the while loop?



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0















I’m trying to figure out how to echo out content above the while loop and underneath the check for num_rows, but I need to get the content from the while loop before doing that.



$sql = "SELECT * FROM table WHERE column = ?";
$stmt = $db->prepare($sql);
$stmt->bind_param('s', $test);
$result = $stmt->execute();
$stmt_result = $stmt->get_result();
if ($stmt_result->num_rows > 0)
echo "<div id='wrapper'>"; //I need to add HTML content here if $status === 2
while ($row = $stmt_result->fetch_assoc())
$title = $row['title'];
$description = $row['descript'];
$status = $row['status'];
if ($status === 2)
echo $status;
continue; //skip to the next iteration

echo $title;
echo $description;




Maybe I'm missing the obvious. How is it done?



To summarize, this is the output I'm looking for:



//if status !== 2: (i get 3 results)
<div id='wrapper'>
//title
//description

//title
//description

//title
//description
</div>
//if status === 2: (i get 1 result)
<div id='other_wrapper'>
//title
//description
</div>
//if status === 3: (i get 5 results)
<div id='yet_another_wrapper'>
//title
//description

//title
//description

//title
//description

//title
//description

//title
//description
</div>









share|improve this question



















  • 1





    You can't echo something that hasn't been loaded yet. You need to call that after fetch_assoc has retrieved the relevant data.

    – tadman
    Mar 21 at 17:16











  • Maybe i'm using the wrong approach. Is there a way to get a row using the echo $stmt_result->fetch_assoc()['status] before the while loop? Using it together with the while loop doesn't do anything.

    – BillWhickomb
    Mar 21 at 17:18











  • If you fetch and pluck out a single entry then it won't be available within the loop. Try fetching and saving to an array, then inspecting, echo as necessary, then loop again over the array.

    – tadman
    Mar 21 at 17:26

















0















I’m trying to figure out how to echo out content above the while loop and underneath the check for num_rows, but I need to get the content from the while loop before doing that.



$sql = "SELECT * FROM table WHERE column = ?";
$stmt = $db->prepare($sql);
$stmt->bind_param('s', $test);
$result = $stmt->execute();
$stmt_result = $stmt->get_result();
if ($stmt_result->num_rows > 0)
echo "<div id='wrapper'>"; //I need to add HTML content here if $status === 2
while ($row = $stmt_result->fetch_assoc())
$title = $row['title'];
$description = $row['descript'];
$status = $row['status'];
if ($status === 2)
echo $status;
continue; //skip to the next iteration

echo $title;
echo $description;




Maybe I'm missing the obvious. How is it done?



To summarize, this is the output I'm looking for:



//if status !== 2: (i get 3 results)
<div id='wrapper'>
//title
//description

//title
//description

//title
//description
</div>
//if status === 2: (i get 1 result)
<div id='other_wrapper'>
//title
//description
</div>
//if status === 3: (i get 5 results)
<div id='yet_another_wrapper'>
//title
//description

//title
//description

//title
//description

//title
//description

//title
//description
</div>









share|improve this question



















  • 1





    You can't echo something that hasn't been loaded yet. You need to call that after fetch_assoc has retrieved the relevant data.

    – tadman
    Mar 21 at 17:16











  • Maybe i'm using the wrong approach. Is there a way to get a row using the echo $stmt_result->fetch_assoc()['status] before the while loop? Using it together with the while loop doesn't do anything.

    – BillWhickomb
    Mar 21 at 17:18











  • If you fetch and pluck out a single entry then it won't be available within the loop. Try fetching and saving to an array, then inspecting, echo as necessary, then loop again over the array.

    – tadman
    Mar 21 at 17:26













0












0








0








I’m trying to figure out how to echo out content above the while loop and underneath the check for num_rows, but I need to get the content from the while loop before doing that.



$sql = "SELECT * FROM table WHERE column = ?";
$stmt = $db->prepare($sql);
$stmt->bind_param('s', $test);
$result = $stmt->execute();
$stmt_result = $stmt->get_result();
if ($stmt_result->num_rows > 0)
echo "<div id='wrapper'>"; //I need to add HTML content here if $status === 2
while ($row = $stmt_result->fetch_assoc())
$title = $row['title'];
$description = $row['descript'];
$status = $row['status'];
if ($status === 2)
echo $status;
continue; //skip to the next iteration

echo $title;
echo $description;




Maybe I'm missing the obvious. How is it done?



To summarize, this is the output I'm looking for:



//if status !== 2: (i get 3 results)
<div id='wrapper'>
//title
//description

//title
//description

//title
//description
</div>
//if status === 2: (i get 1 result)
<div id='other_wrapper'>
//title
//description
</div>
//if status === 3: (i get 5 results)
<div id='yet_another_wrapper'>
//title
//description

//title
//description

//title
//description

//title
//description

//title
//description
</div>









share|improve this question
















I’m trying to figure out how to echo out content above the while loop and underneath the check for num_rows, but I need to get the content from the while loop before doing that.



$sql = "SELECT * FROM table WHERE column = ?";
$stmt = $db->prepare($sql);
$stmt->bind_param('s', $test);
$result = $stmt->execute();
$stmt_result = $stmt->get_result();
if ($stmt_result->num_rows > 0)
echo "<div id='wrapper'>"; //I need to add HTML content here if $status === 2
while ($row = $stmt_result->fetch_assoc())
$title = $row['title'];
$description = $row['descript'];
$status = $row['status'];
if ($status === 2)
echo $status;
continue; //skip to the next iteration

echo $title;
echo $description;




Maybe I'm missing the obvious. How is it done?



To summarize, this is the output I'm looking for:



//if status !== 2: (i get 3 results)
<div id='wrapper'>
//title
//description

//title
//description

//title
//description
</div>
//if status === 2: (i get 1 result)
<div id='other_wrapper'>
//title
//description
</div>
//if status === 3: (i get 5 results)
<div id='yet_another_wrapper'>
//title
//description

//title
//description

//title
//description

//title
//description

//title
//description
</div>






php mysql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 21 at 17:22







BillWhickomb

















asked Mar 21 at 17:14









BillWhickombBillWhickomb

66110




66110







  • 1





    You can't echo something that hasn't been loaded yet. You need to call that after fetch_assoc has retrieved the relevant data.

    – tadman
    Mar 21 at 17:16











  • Maybe i'm using the wrong approach. Is there a way to get a row using the echo $stmt_result->fetch_assoc()['status] before the while loop? Using it together with the while loop doesn't do anything.

    – BillWhickomb
    Mar 21 at 17:18











  • If you fetch and pluck out a single entry then it won't be available within the loop. Try fetching and saving to an array, then inspecting, echo as necessary, then loop again over the array.

    – tadman
    Mar 21 at 17:26












  • 1





    You can't echo something that hasn't been loaded yet. You need to call that after fetch_assoc has retrieved the relevant data.

    – tadman
    Mar 21 at 17:16











  • Maybe i'm using the wrong approach. Is there a way to get a row using the echo $stmt_result->fetch_assoc()['status] before the while loop? Using it together with the while loop doesn't do anything.

    – BillWhickomb
    Mar 21 at 17:18











  • If you fetch and pluck out a single entry then it won't be available within the loop. Try fetching and saving to an array, then inspecting, echo as necessary, then loop again over the array.

    – tadman
    Mar 21 at 17:26







1




1





You can't echo something that hasn't been loaded yet. You need to call that after fetch_assoc has retrieved the relevant data.

– tadman
Mar 21 at 17:16





You can't echo something that hasn't been loaded yet. You need to call that after fetch_assoc has retrieved the relevant data.

– tadman
Mar 21 at 17:16













Maybe i'm using the wrong approach. Is there a way to get a row using the echo $stmt_result->fetch_assoc()['status] before the while loop? Using it together with the while loop doesn't do anything.

– BillWhickomb
Mar 21 at 17:18





Maybe i'm using the wrong approach. Is there a way to get a row using the echo $stmt_result->fetch_assoc()['status] before the while loop? Using it together with the while loop doesn't do anything.

– BillWhickomb
Mar 21 at 17:18













If you fetch and pluck out a single entry then it won't be available within the loop. Try fetching and saving to an array, then inspecting, echo as necessary, then loop again over the array.

– tadman
Mar 21 at 17:26





If you fetch and pluck out a single entry then it won't be available within the loop. Try fetching and saving to an array, then inspecting, echo as necessary, then loop again over the array.

– tadman
Mar 21 at 17:26












3 Answers
3






active

oldest

votes


















3














Maybe something like this could work for you.



Put these lines in place of the while loop



$rows = $stmt_result->fetch_all(MYSQLI_ASSOC);
foreach ($rows as $row)
if ($row['status'] === 2)
$title = $row['title'];
$description = $row['descript'];
$status = $row['status'];
if ($status === 2)
echo $status;
continue; //skip to the next iteration

echo $title;
echo $description;







share|improve this answer























  • That's pretty brilliant, I'll give it a try :)

    – BillWhickomb
    Mar 21 at 17:27


















1














Try this:



$idv =0;
if ($stmt_result->num_rows > 0)
while ($row = $stmt_result->fetch_assoc())
if($row['status'] ==2 && $idv==0)
$idv =1;
echo "<div id='wrapper'>"; //adds div once only if status is 2

$title = $row['title'];
$description = $row['descript'];
$status = $row['status'];
if ($status === 2)
echo $status;
continue; //skip to the next iteration

echo $title;
echo $description;







share|improve this answer























  • Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

    – BillWhickomb
    Mar 21 at 17:29


















0














The above answers a great, but someone provided the perfect solution:



$wrappers = [
'wrapper' => [/* items from db with status not 2 or 3 */]
'other_wrapper' => [/* items from db with status 2 */]
'yet_another_wrapper' => [/* items from db with status 3 */]
];
function getWrapperNameForStatus($status)
if($status === 2)
return 'other_wrapper';


if($status === 3)
return 'yet_another_wrapper';


return 'wrapper';


$wrappers = [];
while ($row = $stmt_result->fetch_assoc())
$wrapperName = getWrapperNameForStatus($row['status']);

$wrappers[$wrapperName][] = [
'title' => $row['title'],
'description' => $row['description'],
'status' => $row['status']
];



Credit goes to https://www.phphelp.com/u/JimL for this solution. It's clean, gives you the ability to post unlimited content within unlimited wrappers, and it prevents code duplication. Thanks Jim.






share|improve this answer























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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3














    Maybe something like this could work for you.



    Put these lines in place of the while loop



    $rows = $stmt_result->fetch_all(MYSQLI_ASSOC);
    foreach ($rows as $row)
    if ($row['status'] === 2)
    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;







    share|improve this answer























    • That's pretty brilliant, I'll give it a try :)

      – BillWhickomb
      Mar 21 at 17:27















    3














    Maybe something like this could work for you.



    Put these lines in place of the while loop



    $rows = $stmt_result->fetch_all(MYSQLI_ASSOC);
    foreach ($rows as $row)
    if ($row['status'] === 2)
    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;







    share|improve this answer























    • That's pretty brilliant, I'll give it a try :)

      – BillWhickomb
      Mar 21 at 17:27













    3












    3








    3







    Maybe something like this could work for you.



    Put these lines in place of the while loop



    $rows = $stmt_result->fetch_all(MYSQLI_ASSOC);
    foreach ($rows as $row)
    if ($row['status'] === 2)
    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;







    share|improve this answer













    Maybe something like this could work for you.



    Put these lines in place of the while loop



    $rows = $stmt_result->fetch_all(MYSQLI_ASSOC);
    foreach ($rows as $row)
    if ($row['status'] === 2)
    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;








    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 21 at 17:25









    Giovanni BarcaGiovanni Barca

    337




    337












    • That's pretty brilliant, I'll give it a try :)

      – BillWhickomb
      Mar 21 at 17:27

















    • That's pretty brilliant, I'll give it a try :)

      – BillWhickomb
      Mar 21 at 17:27
















    That's pretty brilliant, I'll give it a try :)

    – BillWhickomb
    Mar 21 at 17:27





    That's pretty brilliant, I'll give it a try :)

    – BillWhickomb
    Mar 21 at 17:27













    1














    Try this:



    $idv =0;
    if ($stmt_result->num_rows > 0)
    while ($row = $stmt_result->fetch_assoc())
    if($row['status'] ==2 && $idv==0)
    $idv =1;
    echo "<div id='wrapper'>"; //adds div once only if status is 2

    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;







    share|improve this answer























    • Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

      – BillWhickomb
      Mar 21 at 17:29















    1














    Try this:



    $idv =0;
    if ($stmt_result->num_rows > 0)
    while ($row = $stmt_result->fetch_assoc())
    if($row['status'] ==2 && $idv==0)
    $idv =1;
    echo "<div id='wrapper'>"; //adds div once only if status is 2

    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;







    share|improve this answer























    • Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

      – BillWhickomb
      Mar 21 at 17:29













    1












    1








    1







    Try this:



    $idv =0;
    if ($stmt_result->num_rows > 0)
    while ($row = $stmt_result->fetch_assoc())
    if($row['status'] ==2 && $idv==0)
    $idv =1;
    echo "<div id='wrapper'>"; //adds div once only if status is 2

    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;







    share|improve this answer













    Try this:



    $idv =0;
    if ($stmt_result->num_rows > 0)
    while ($row = $stmt_result->fetch_assoc())
    if($row['status'] ==2 && $idv==0)
    $idv =1;
    echo "<div id='wrapper'>"; //adds div once only if status is 2

    $title = $row['title'];
    $description = $row['descript'];
    $status = $row['status'];
    if ($status === 2)
    echo $status;
    continue; //skip to the next iteration

    echo $title;
    echo $description;








    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 21 at 17:27









    CoursesWebCoursesWeb

    3,38931522




    3,38931522












    • Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

      – BillWhickomb
      Mar 21 at 17:29

















    • Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

      – BillWhickomb
      Mar 21 at 17:29
















    Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

    – BillWhickomb
    Mar 21 at 17:29





    Also a good solution, plus it lets me keep the while loop. Give me a moment while i try the solutions

    – BillWhickomb
    Mar 21 at 17:29











    0














    The above answers a great, but someone provided the perfect solution:



    $wrappers = [
    'wrapper' => [/* items from db with status not 2 or 3 */]
    'other_wrapper' => [/* items from db with status 2 */]
    'yet_another_wrapper' => [/* items from db with status 3 */]
    ];
    function getWrapperNameForStatus($status)
    if($status === 2)
    return 'other_wrapper';


    if($status === 3)
    return 'yet_another_wrapper';


    return 'wrapper';


    $wrappers = [];
    while ($row = $stmt_result->fetch_assoc())
    $wrapperName = getWrapperNameForStatus($row['status']);

    $wrappers[$wrapperName][] = [
    'title' => $row['title'],
    'description' => $row['description'],
    'status' => $row['status']
    ];



    Credit goes to https://www.phphelp.com/u/JimL for this solution. It's clean, gives you the ability to post unlimited content within unlimited wrappers, and it prevents code duplication. Thanks Jim.






    share|improve this answer



























      0














      The above answers a great, but someone provided the perfect solution:



      $wrappers = [
      'wrapper' => [/* items from db with status not 2 or 3 */]
      'other_wrapper' => [/* items from db with status 2 */]
      'yet_another_wrapper' => [/* items from db with status 3 */]
      ];
      function getWrapperNameForStatus($status)
      if($status === 2)
      return 'other_wrapper';


      if($status === 3)
      return 'yet_another_wrapper';


      return 'wrapper';


      $wrappers = [];
      while ($row = $stmt_result->fetch_assoc())
      $wrapperName = getWrapperNameForStatus($row['status']);

      $wrappers[$wrapperName][] = [
      'title' => $row['title'],
      'description' => $row['description'],
      'status' => $row['status']
      ];



      Credit goes to https://www.phphelp.com/u/JimL for this solution. It's clean, gives you the ability to post unlimited content within unlimited wrappers, and it prevents code duplication. Thanks Jim.






      share|improve this answer

























        0












        0








        0







        The above answers a great, but someone provided the perfect solution:



        $wrappers = [
        'wrapper' => [/* items from db with status not 2 or 3 */]
        'other_wrapper' => [/* items from db with status 2 */]
        'yet_another_wrapper' => [/* items from db with status 3 */]
        ];
        function getWrapperNameForStatus($status)
        if($status === 2)
        return 'other_wrapper';


        if($status === 3)
        return 'yet_another_wrapper';


        return 'wrapper';


        $wrappers = [];
        while ($row = $stmt_result->fetch_assoc())
        $wrapperName = getWrapperNameForStatus($row['status']);

        $wrappers[$wrapperName][] = [
        'title' => $row['title'],
        'description' => $row['description'],
        'status' => $row['status']
        ];



        Credit goes to https://www.phphelp.com/u/JimL for this solution. It's clean, gives you the ability to post unlimited content within unlimited wrappers, and it prevents code duplication. Thanks Jim.






        share|improve this answer













        The above answers a great, but someone provided the perfect solution:



        $wrappers = [
        'wrapper' => [/* items from db with status not 2 or 3 */]
        'other_wrapper' => [/* items from db with status 2 */]
        'yet_another_wrapper' => [/* items from db with status 3 */]
        ];
        function getWrapperNameForStatus($status)
        if($status === 2)
        return 'other_wrapper';


        if($status === 3)
        return 'yet_another_wrapper';


        return 'wrapper';


        $wrappers = [];
        while ($row = $stmt_result->fetch_assoc())
        $wrapperName = getWrapperNameForStatus($row['status']);

        $wrappers[$wrapperName][] = [
        'title' => $row['title'],
        'description' => $row['description'],
        'status' => $row['status']
        ];



        Credit goes to https://www.phphelp.com/u/JimL for this solution. It's clean, gives you the ability to post unlimited content within unlimited wrappers, and it prevents code duplication. Thanks Jim.







        share|improve this answer












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        answered Mar 22 at 10:12









        BillWhickombBillWhickomb

        66110




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