Convert Format Of Date using /How to return only the Date from a SQL Server DateTime datatypeHow to print a date in a regular format?Compare two dates with JavaScriptWhere can I find documentation on formatting a date in JavaScript?Detecting an “invalid date” Date instance in JavaScriptYYYY-MM-DD format date in shell scriptHow do I get the current date in JavaScript?Calculate difference between two dates (number of days)?How to format a JavaScript dateGet current time and date on Android
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Convert Format Of Date using /
How to return only the Date from a SQL Server DateTime datatypeHow to print a date in a regular format?Compare two dates with JavaScriptWhere can I find documentation on formatting a date in JavaScript?Detecting an “invalid date” Date instance in JavaScriptYYYY-MM-DD format date in shell scriptHow do I get the current date in JavaScript?Calculate difference between two dates (number of days)?How to format a JavaScript dateGet current time and date on Android
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
Sample data
sasq=c(-5844, 0, 7121)
d2=as.Date(sasq, '1960-01-01')
>d2
"1944-01-01" "1960-01-01" "1979-07-01"
But I try to obtain:
"1/1944" "1/1960" "1/1970"
with just MONTH/YEAR and no lead zeros on month
r date sas
asked Mar 22 at 22:21
bvowebvowe
40019
add a comment |
Sample data
sasq=c(-5844, 0, 7121)
d2=as.Date(sasq, '1960-01-01')
>d2
"1944-01-01" "1960-01-01" "1979-07-01"
But I try to obtain:
"1/1944" "1/1960" "1/1970"
with just MONTH/YEAR and no lead zeros on month
r date sas
asked Mar 22 at 22:21
bvowebvowe
40019
Your example is not reproducible. Have you tried usingformat()function? E.g.format(Sys.time(), format = "%m/%Y").
– Roman Luštrik
Mar 22 at 22:29
add a comment |
Sample data
sasq=c(-5844, 0, 7121)
d2=as.Date(sasq, '1960-01-01')
>d2
"1944-01-01" "1960-01-01" "1979-07-01"
But I try to obtain:
"1/1944" "1/1960" "1/1970"
with just MONTH/YEAR and no lead zeros on month
r date sas
asked Mar 22 at 22:21
bvowebvowe
40019
Sample data
sasq=c(-5844, 0, 7121)
d2=as.Date(sasq, '1960-01-01')
>d2
"1944-01-01" "1960-01-01" "1979-07-01"
But I try to obtain:
"1/1944" "1/1960" "1/1970"
with just MONTH/YEAR and no lead zeros on month
r date sas
r date sas
asked Mar 22 at 22:21
bvowebvowe
40019
asked Mar 22 at 22:21
bvowebvowe
40019
edited Mar 22 at 22:32
bvowe
asked Mar 22 at 22:21
bvowebvowe
40019
asked Mar 22 at 22:21
bvowebvowe
40019
asked Mar 22 at 22:21
bvowebvowe
40019
40019
Your example is not reproducible. Have you tried usingformat()function? E.g.format(Sys.time(), format = "%m/%Y").
– Roman Luštrik
Mar 22 at 22:29
add a comment |
Your example is not reproducible. Have you tried usingformat()function? E.g.format(Sys.time(), format = "%m/%Y").
– Roman Luštrik
Mar 22 at 22:29
Your example is not reproducible. Have you tried using
format() function? E.g. format(Sys.time(), format = "%m/%Y").– Roman Luštrik
Mar 22 at 22:29
Your example is not reproducible. Have you tried using
format() function? E.g. format(Sys.time(), format = "%m/%Y").– Roman Luštrik
Mar 22 at 22:29
add a comment |
1 Answer
1
active
oldest
votes
d2=format(as.Date(sasq, '1960-01-01'),'%e/%Y')
answered Mar 22 at 22:29
WilWil
1,4681217
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
@bvowe try%e.
– Roman Luštrik
Mar 22 at 22:33
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
d2=format(as.Date(sasq, '1960-01-01'),'%e/%Y')
answered Mar 22 at 22:29
WilWil
1,4681217
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
@bvowe try%e.
– Roman Luštrik
Mar 22 at 22:33
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
add a comment |
d2=format(as.Date(sasq, '1960-01-01'),'%e/%Y')
answered Mar 22 at 22:29
WilWil
1,4681217
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
@bvowe try%e.
– Roman Luštrik
Mar 22 at 22:33
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
add a comment |
d2=format(as.Date(sasq, '1960-01-01'),'%e/%Y')
answered Mar 22 at 22:29
WilWil
1,4681217
d2=format(as.Date(sasq, '1960-01-01'),'%e/%Y')
answered Mar 22 at 22:29
WilWil
1,4681217
edited Mar 22 at 22:47
answered Mar 22 at 22:29
WilWil
1,4681217
answered Mar 22 at 22:29
WilWil
1,4681217
answered Mar 22 at 22:29
WilWil
1,4681217
1,4681217
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
@bvowe try%e.
– Roman Luštrik
Mar 22 at 22:33
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
add a comment |
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
@bvowe try%e.
– Roman Luštrik
Mar 22 at 22:33
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
perfecto! how do i remove leading zero for example instead of 01/ to get 1
– bvowe
Mar 22 at 22:31
@bvowe try
%e.– Roman Luštrik
Mar 22 at 22:33
@bvowe try
%e.– Roman Luštrik
Mar 22 at 22:33
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
As @RomanLuštrik stated it is %e. I have updated my answer.
– Wil
Mar 22 at 22:47
add a comment |
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Your example is not reproducible. Have you tried using
format()function? E.g.format(Sys.time(), format = "%m/%Y").– Roman Luštrik
Mar 22 at 22:29