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How to convert a string to binary code using list and dictionary
The order of keys in dictionariesHow to merge two dictionaries in a single expression?How do I check if a list is empty?How do I iterate over the words of a string?How do I read / convert an InputStream into a String in Java?How do I sort a dictionary by value?How do I make the first letter of a string uppercase in JavaScript?How to replace all occurrences of a string in JavaScriptHow to check whether a string contains a substring in JavaScript?How do I list all files of a directory?How do I convert a String to an int in Java?
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0
I am trying to convert a string to a char array then loop through each char in the array and compare against dictionary keys and then if they match print the key value and move to next char in array
I have gathered some examples and tried to work it out in my head. I am new to python and have come back to programming as a hobby after a long time to try and teach my 10 year old son. He was talking about binary and i said we could write a program in python that could for example take his name as input and print his name in binary code.
#binary table is formatted such i have shortened it for simplicity
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100"
word = input('please input a value to see its representation in Binary Code: ')
def split(letters):
return [char for char in letters]
def members(dictArg, keysListArg):
count = 0
for x in newArray:
if newArray[x] == binaryTable.keys():
value = binaryTable.keys()
print(newArray[x])
print(' : ')
print(value)
count += 1
return count
def printBinary(dictArg, keysListArg):
count = 0
for list_item in keysListArg:
if list_item in dictArg:
count+= 1
print(count)
print(list_item)
print(' : ')
#print(keysListArg)
#print(dictArg) #print dictArg.Key() How to do this
print('n')
return count
print('testing printBinary functionn')
newArray = split(word)
#members(newArray, binaryTable)
printBinary(newArray. binaryTable)
If i were to put say abcd i would like the output to be
a new dictionary with the chars in word with their binary key representatives or just to print the letter keys in the for loop iteration #next to the representative binary value eg
j : 0110101
a : 0101010
m : 0101010
e : 0101010
s : 0101010
output:
1
a
:
2
e
:
3
j
:
4
m
:
5
s
:
['j', 'a', 'm', 'e', 's']
>>>
*Why do the keys not come out in the same order?
python string binary converters
asked Mar 22 at 22:36
James DeanJames Dean
11
|
show 2 more comments
0
I am trying to convert a string to a char array then loop through each char in the array and compare against dictionary keys and then if they match print the key value and move to next char in array
I have gathered some examples and tried to work it out in my head. I am new to python and have come back to programming as a hobby after a long time to try and teach my 10 year old son. He was talking about binary and i said we could write a program in python that could for example take his name as input and print his name in binary code.
#binary table is formatted such i have shortened it for simplicity
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100"
word = input('please input a value to see its representation in Binary Code: ')
def split(letters):
return [char for char in letters]
def members(dictArg, keysListArg):
count = 0
for x in newArray:
if newArray[x] == binaryTable.keys():
value = binaryTable.keys()
print(newArray[x])
print(' : ')
print(value)
count += 1
return count
def printBinary(dictArg, keysListArg):
count = 0
for list_item in keysListArg:
if list_item in dictArg:
count+= 1
print(count)
print(list_item)
print(' : ')
#print(keysListArg)
#print(dictArg) #print dictArg.Key() How to do this
print('n')
return count
print('testing printBinary functionn')
newArray = split(word)
#members(newArray, binaryTable)
printBinary(newArray. binaryTable)
If i were to put say abcd i would like the output to be
a new dictionary with the chars in word with their binary key representatives or just to print the letter keys in the for loop iteration #next to the representative binary value eg
j : 0110101
a : 0101010
m : 0101010
e : 0101010
s : 0101010
output:
1
a
:
2
e
:
3
j
:
4
m
:
5
s
:
['j', 'a', 'm', 'e', 's']
>>>
*Why do the keys not come out in the same order?
python string binary converters
asked Mar 22 at 22:36
James DeanJames Dean
11
what version of python?dictused to not guarantee order of keys when iterating. not sure of the behavior now. stackoverflow.com/questions/5629023/…
– MFisherKDX
Mar 22 at 22:40
3.7 I edited the function as such but it still prints in the wrong order:
– James Dean
Mar 22 at 22:44
def printBinary(dictArg, keysListArg): count = 0 for list_item in keysListArg: if list_item in dictArg: count+= 1 print(count) print(list_item) print(' : ') x = keysListArg.get(list_item) print(x) return count
– James Dean
Mar 22 at 22:45
I'm having a hard time understanding what you are after ... but did you mean to call the functionprintBinaryasprintBinary(binaryTable, newArray)instead ofprintBinary(newArray, binaryTable)?
– MFisherKDX
Mar 22 at 22:52
I have solved it:
– James Dean
Mar 22 at 22:56
|
show 2 more comments
0
0
0
I am trying to convert a string to a char array then loop through each char in the array and compare against dictionary keys and then if they match print the key value and move to next char in array
I have gathered some examples and tried to work it out in my head. I am new to python and have come back to programming as a hobby after a long time to try and teach my 10 year old son. He was talking about binary and i said we could write a program in python that could for example take his name as input and print his name in binary code.
#binary table is formatted such i have shortened it for simplicity
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100"
word = input('please input a value to see its representation in Binary Code: ')
def split(letters):
return [char for char in letters]
def members(dictArg, keysListArg):
count = 0
for x in newArray:
if newArray[x] == binaryTable.keys():
value = binaryTable.keys()
print(newArray[x])
print(' : ')
print(value)
count += 1
return count
def printBinary(dictArg, keysListArg):
count = 0
for list_item in keysListArg:
if list_item in dictArg:
count+= 1
print(count)
print(list_item)
print(' : ')
#print(keysListArg)
#print(dictArg) #print dictArg.Key() How to do this
print('n')
return count
print('testing printBinary functionn')
newArray = split(word)
#members(newArray, binaryTable)
printBinary(newArray. binaryTable)
If i were to put say abcd i would like the output to be
a new dictionary with the chars in word with their binary key representatives or just to print the letter keys in the for loop iteration #next to the representative binary value eg
j : 0110101
a : 0101010
m : 0101010
e : 0101010
s : 0101010
output:
1
a
:
2
e
:
3
j
:
4
m
:
5
s
:
['j', 'a', 'm', 'e', 's']
>>>
*Why do the keys not come out in the same order?
python string binary converters
asked Mar 22 at 22:36
James DeanJames Dean
11
I am trying to convert a string to a char array then loop through each char in the array and compare against dictionary keys and then if they match print the key value and move to next char in array
I have gathered some examples and tried to work it out in my head. I am new to python and have come back to programming as a hobby after a long time to try and teach my 10 year old son. He was talking about binary and i said we could write a program in python that could for example take his name as input and print his name in binary code.
#binary table is formatted such i have shortened it for simplicity
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100"
word = input('please input a value to see its representation in Binary Code: ')
def split(letters):
return [char for char in letters]
def members(dictArg, keysListArg):
count = 0
for x in newArray:
if newArray[x] == binaryTable.keys():
value = binaryTable.keys()
print(newArray[x])
print(' : ')
print(value)
count += 1
return count
def printBinary(dictArg, keysListArg):
count = 0
for list_item in keysListArg:
if list_item in dictArg:
count+= 1
print(count)
print(list_item)
print(' : ')
#print(keysListArg)
#print(dictArg) #print dictArg.Key() How to do this
print('n')
return count
print('testing printBinary functionn')
newArray = split(word)
#members(newArray, binaryTable)
printBinary(newArray. binaryTable)
If i were to put say abcd i would like the output to be
a new dictionary with the chars in word with their binary key representatives or just to print the letter keys in the for loop iteration #next to the representative binary value eg
j : 0110101
a : 0101010
m : 0101010
e : 0101010
s : 0101010
output:
1
a
:
2
e
:
3
j
:
4
m
:
5
s
:
['j', 'a', 'm', 'e', 's']
>>>
*Why do the keys not come out in the same order?
python string binary converters
python string binary converters
asked Mar 22 at 22:36
James DeanJames Dean
11
asked Mar 22 at 22:36
James DeanJames Dean
11
asked Mar 22 at 22:36
James DeanJames Dean
11
asked Mar 22 at 22:36
James DeanJames Dean
11
asked Mar 22 at 22:36
James DeanJames Dean
11
11
what version of python?dictused to not guarantee order of keys when iterating. not sure of the behavior now. stackoverflow.com/questions/5629023/…
– MFisherKDX
Mar 22 at 22:40
3.7 I edited the function as such but it still prints in the wrong order:
– James Dean
Mar 22 at 22:44
def printBinary(dictArg, keysListArg): count = 0 for list_item in keysListArg: if list_item in dictArg: count+= 1 print(count) print(list_item) print(' : ') x = keysListArg.get(list_item) print(x) return count
– James Dean
Mar 22 at 22:45
I'm having a hard time understanding what you are after ... but did you mean to call the functionprintBinaryasprintBinary(binaryTable, newArray)instead ofprintBinary(newArray, binaryTable)?
– MFisherKDX
Mar 22 at 22:52
I have solved it:
– James Dean
Mar 22 at 22:56
|
show 2 more comments
what version of python?dictused to not guarantee order of keys when iterating. not sure of the behavior now. stackoverflow.com/questions/5629023/…
– MFisherKDX
Mar 22 at 22:40
3.7 I edited the function as such but it still prints in the wrong order:
– James Dean
Mar 22 at 22:44
def printBinary(dictArg, keysListArg): count = 0 for list_item in keysListArg: if list_item in dictArg: count+= 1 print(count) print(list_item) print(' : ') x = keysListArg.get(list_item) print(x) return count
– James Dean
Mar 22 at 22:45
I'm having a hard time understanding what you are after ... but did you mean to call the functionprintBinaryasprintBinary(binaryTable, newArray)instead ofprintBinary(newArray, binaryTable)?
– MFisherKDX
Mar 22 at 22:52
I have solved it:
– James Dean
Mar 22 at 22:56
what version of python?
dict used to not guarantee order of keys when iterating. not sure of the behavior now. stackoverflow.com/questions/5629023/…– MFisherKDX
Mar 22 at 22:40
what version of python?
dict used to not guarantee order of keys when iterating. not sure of the behavior now. stackoverflow.com/questions/5629023/…– MFisherKDX
Mar 22 at 22:40
3.7 I edited the function as such but it still prints in the wrong order:
– James Dean
Mar 22 at 22:44
3.7 I edited the function as such but it still prints in the wrong order:
– James Dean
Mar 22 at 22:44
def printBinary(dictArg, keysListArg): count = 0 for list_item in keysListArg: if list_item in dictArg: count+= 1 print(count) print(list_item) print(' : ') x = keysListArg.get(list_item) print(x) return count
– James Dean
Mar 22 at 22:45
def printBinary(dictArg, keysListArg): count = 0 for list_item in keysListArg: if list_item in dictArg: count+= 1 print(count) print(list_item) print(' : ') x = keysListArg.get(list_item) print(x) return count
– James Dean
Mar 22 at 22:45
I'm having a hard time understanding what you are after ... but did you mean to call the function
printBinary as printBinary(binaryTable, newArray) instead of printBinary(newArray, binaryTable) ?– MFisherKDX
Mar 22 at 22:52
I'm having a hard time understanding what you are after ... but did you mean to call the function
printBinary as printBinary(binaryTable, newArray) instead of printBinary(newArray, binaryTable) ?– MFisherKDX
Mar 22 at 22:52
I have solved it:
– James Dean
Mar 22 at 22:56
I have solved it:
– James Dean
Mar 22 at 22:56
|
show 2 more comments
1 Answer
1
active
oldest
votes
0
#program to take a string and show the binary representation of all the letters
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100",
"e" : "01100101",
"f" : "01100110",
"g" : "01100111",
"h" : "01101000",
"i" : "01101001",
"j" : "01101010",
"k" : "01101011",
"l" : "01101100",
"m" : "01101101",
"n" : "01101110",
"o" : "01101111",
"p" : "01110000",
"q" : "01110001",
"r" : "01110010",
"s" : "01110011",
"t" : "01110100",
"u" : "01110101",
"v" : "01110110",
"w" : "01110111",
"x" : "01111000",
"y" : "01111001",
"z" : "01111010",
"A" : "01000001",
"B" : "01000010",
"C" : "01000011",
"D" : "01000100",
"E" : "01000101",
"F" : "01000110",
"G" : "01000111",
"H" : "01001000",
"I" : "01001001",
"J" : "01001010",
"K" : "01001011",
"L" : "01001100",
"M" : "01001101",
"N" : "01001110",
"O" : "01001111",
"P" : "01010000",
"Q" : "01001111",
"R" : "01010010",
"S" : "01010011",
"T" : "01010100",
"U" : "01010101",
"V" : "01010110",
"W" : "01010111",
"X" : "01011000",
"Y" : "01011001",
"Z" : "01011010"
print('Hello there! I am a binary translator. Add some text to see it in binary!')
print('Below is a binary table for all characters of the Alphabet. Remember, upper and lower case characters have different binary values!')
print(
'''
Letter Binary Letter Binary
a 01100001 A 01000001
b 01100010 B 01000010
c 01100011 C 01000011
d 01100100 D 01000100
e 01100101 E 01000101
f 01100110 F 01000110
g 01100111 G 01000111
h 01101000 H 01001000
i 01101001 I 01001001
j 01101010 J 01001010
k 01101011 K 01001011
l 01101100 L 01001100
m 01101101 M 01001101
n 01101110 N 01001110
o 01101111 O 01001111
p 01110000 P 01010000
q 01110001 Q 01010001
r 01110010 R 01010010
s 01110011 S 01010011
t 01110100 T 01010100
u 01110101 U 01010101
v 01110110 V 01010110
w 01110111 W 01010111
x 01111000 X 01011000
y 01111001 Y 01011001
z 01111010 Z 01011010''')
word = input('please input a value to see its representation in Binary Code: ')
#splits the word into single letters and stores in a list aka newArray
def split(letters):
return [char for char in letters]
#takes the parameters of newArray and binaryTable.
#new array is the input word split into letters
def printBinary(dictArg, keysListArg):
for list_item in dictArg:
if list_item in keysListArg:
#grabs the binary value linked to its key and stores in x
x = keysListArg.get(list_item)
#prints list item along side its binary key
print(list_item + ' : ' + x)
#splits the word
newArray = split(word)
#prints each letter next to its binary code representation
printBinary(newArray, binaryTable)
sample output:
please input a value to see its representation in Binary Code: louis
l : 01101100
o : 01101111
u : 01110101
i : 01101001
s : 01110011
>>>
answered Mar 22 at 23:54
James DeanJames Dean
11
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1 Answer
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active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
#program to take a string and show the binary representation of all the letters
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100",
"e" : "01100101",
"f" : "01100110",
"g" : "01100111",
"h" : "01101000",
"i" : "01101001",
"j" : "01101010",
"k" : "01101011",
"l" : "01101100",
"m" : "01101101",
"n" : "01101110",
"o" : "01101111",
"p" : "01110000",
"q" : "01110001",
"r" : "01110010",
"s" : "01110011",
"t" : "01110100",
"u" : "01110101",
"v" : "01110110",
"w" : "01110111",
"x" : "01111000",
"y" : "01111001",
"z" : "01111010",
"A" : "01000001",
"B" : "01000010",
"C" : "01000011",
"D" : "01000100",
"E" : "01000101",
"F" : "01000110",
"G" : "01000111",
"H" : "01001000",
"I" : "01001001",
"J" : "01001010",
"K" : "01001011",
"L" : "01001100",
"M" : "01001101",
"N" : "01001110",
"O" : "01001111",
"P" : "01010000",
"Q" : "01001111",
"R" : "01010010",
"S" : "01010011",
"T" : "01010100",
"U" : "01010101",
"V" : "01010110",
"W" : "01010111",
"X" : "01011000",
"Y" : "01011001",
"Z" : "01011010"
print('Hello there! I am a binary translator. Add some text to see it in binary!')
print('Below is a binary table for all characters of the Alphabet. Remember, upper and lower case characters have different binary values!')
print(
'''
Letter Binary Letter Binary
a 01100001 A 01000001
b 01100010 B 01000010
c 01100011 C 01000011
d 01100100 D 01000100
e 01100101 E 01000101
f 01100110 F 01000110
g 01100111 G 01000111
h 01101000 H 01001000
i 01101001 I 01001001
j 01101010 J 01001010
k 01101011 K 01001011
l 01101100 L 01001100
m 01101101 M 01001101
n 01101110 N 01001110
o 01101111 O 01001111
p 01110000 P 01010000
q 01110001 Q 01010001
r 01110010 R 01010010
s 01110011 S 01010011
t 01110100 T 01010100
u 01110101 U 01010101
v 01110110 V 01010110
w 01110111 W 01010111
x 01111000 X 01011000
y 01111001 Y 01011001
z 01111010 Z 01011010''')
word = input('please input a value to see its representation in Binary Code: ')
#splits the word into single letters and stores in a list aka newArray
def split(letters):
return [char for char in letters]
#takes the parameters of newArray and binaryTable.
#new array is the input word split into letters
def printBinary(dictArg, keysListArg):
for list_item in dictArg:
if list_item in keysListArg:
#grabs the binary value linked to its key and stores in x
x = keysListArg.get(list_item)
#prints list item along side its binary key
print(list_item + ' : ' + x)
#splits the word
newArray = split(word)
#prints each letter next to its binary code representation
printBinary(newArray, binaryTable)
sample output:
please input a value to see its representation in Binary Code: louis
l : 01101100
o : 01101111
u : 01110101
i : 01101001
s : 01110011
>>>
answered Mar 22 at 23:54
James DeanJames Dean
11
add a comment |
0
#program to take a string and show the binary representation of all the letters
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100",
"e" : "01100101",
"f" : "01100110",
"g" : "01100111",
"h" : "01101000",
"i" : "01101001",
"j" : "01101010",
"k" : "01101011",
"l" : "01101100",
"m" : "01101101",
"n" : "01101110",
"o" : "01101111",
"p" : "01110000",
"q" : "01110001",
"r" : "01110010",
"s" : "01110011",
"t" : "01110100",
"u" : "01110101",
"v" : "01110110",
"w" : "01110111",
"x" : "01111000",
"y" : "01111001",
"z" : "01111010",
"A" : "01000001",
"B" : "01000010",
"C" : "01000011",
"D" : "01000100",
"E" : "01000101",
"F" : "01000110",
"G" : "01000111",
"H" : "01001000",
"I" : "01001001",
"J" : "01001010",
"K" : "01001011",
"L" : "01001100",
"M" : "01001101",
"N" : "01001110",
"O" : "01001111",
"P" : "01010000",
"Q" : "01001111",
"R" : "01010010",
"S" : "01010011",
"T" : "01010100",
"U" : "01010101",
"V" : "01010110",
"W" : "01010111",
"X" : "01011000",
"Y" : "01011001",
"Z" : "01011010"
print('Hello there! I am a binary translator. Add some text to see it in binary!')
print('Below is a binary table for all characters of the Alphabet. Remember, upper and lower case characters have different binary values!')
print(
'''
Letter Binary Letter Binary
a 01100001 A 01000001
b 01100010 B 01000010
c 01100011 C 01000011
d 01100100 D 01000100
e 01100101 E 01000101
f 01100110 F 01000110
g 01100111 G 01000111
h 01101000 H 01001000
i 01101001 I 01001001
j 01101010 J 01001010
k 01101011 K 01001011
l 01101100 L 01001100
m 01101101 M 01001101
n 01101110 N 01001110
o 01101111 O 01001111
p 01110000 P 01010000
q 01110001 Q 01010001
r 01110010 R 01010010
s 01110011 S 01010011
t 01110100 T 01010100
u 01110101 U 01010101
v 01110110 V 01010110
w 01110111 W 01010111
x 01111000 X 01011000
y 01111001 Y 01011001
z 01111010 Z 01011010''')
word = input('please input a value to see its representation in Binary Code: ')
#splits the word into single letters and stores in a list aka newArray
def split(letters):
return [char for char in letters]
#takes the parameters of newArray and binaryTable.
#new array is the input word split into letters
def printBinary(dictArg, keysListArg):
for list_item in dictArg:
if list_item in keysListArg:
#grabs the binary value linked to its key and stores in x
x = keysListArg.get(list_item)
#prints list item along side its binary key
print(list_item + ' : ' + x)
#splits the word
newArray = split(word)
#prints each letter next to its binary code representation
printBinary(newArray, binaryTable)
sample output:
please input a value to see its representation in Binary Code: louis
l : 01101100
o : 01101111
u : 01110101
i : 01101001
s : 01110011
>>>
answered Mar 22 at 23:54
James DeanJames Dean
11
add a comment |
0
0
0
#program to take a string and show the binary representation of all the letters
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100",
"e" : "01100101",
"f" : "01100110",
"g" : "01100111",
"h" : "01101000",
"i" : "01101001",
"j" : "01101010",
"k" : "01101011",
"l" : "01101100",
"m" : "01101101",
"n" : "01101110",
"o" : "01101111",
"p" : "01110000",
"q" : "01110001",
"r" : "01110010",
"s" : "01110011",
"t" : "01110100",
"u" : "01110101",
"v" : "01110110",
"w" : "01110111",
"x" : "01111000",
"y" : "01111001",
"z" : "01111010",
"A" : "01000001",
"B" : "01000010",
"C" : "01000011",
"D" : "01000100",
"E" : "01000101",
"F" : "01000110",
"G" : "01000111",
"H" : "01001000",
"I" : "01001001",
"J" : "01001010",
"K" : "01001011",
"L" : "01001100",
"M" : "01001101",
"N" : "01001110",
"O" : "01001111",
"P" : "01010000",
"Q" : "01001111",
"R" : "01010010",
"S" : "01010011",
"T" : "01010100",
"U" : "01010101",
"V" : "01010110",
"W" : "01010111",
"X" : "01011000",
"Y" : "01011001",
"Z" : "01011010"
print('Hello there! I am a binary translator. Add some text to see it in binary!')
print('Below is a binary table for all characters of the Alphabet. Remember, upper and lower case characters have different binary values!')
print(
'''
Letter Binary Letter Binary
a 01100001 A 01000001
b 01100010 B 01000010
c 01100011 C 01000011
d 01100100 D 01000100
e 01100101 E 01000101
f 01100110 F 01000110
g 01100111 G 01000111
h 01101000 H 01001000
i 01101001 I 01001001
j 01101010 J 01001010
k 01101011 K 01001011
l 01101100 L 01001100
m 01101101 M 01001101
n 01101110 N 01001110
o 01101111 O 01001111
p 01110000 P 01010000
q 01110001 Q 01010001
r 01110010 R 01010010
s 01110011 S 01010011
t 01110100 T 01010100
u 01110101 U 01010101
v 01110110 V 01010110
w 01110111 W 01010111
x 01111000 X 01011000
y 01111001 Y 01011001
z 01111010 Z 01011010''')
word = input('please input a value to see its representation in Binary Code: ')
#splits the word into single letters and stores in a list aka newArray
def split(letters):
return [char for char in letters]
#takes the parameters of newArray and binaryTable.
#new array is the input word split into letters
def printBinary(dictArg, keysListArg):
for list_item in dictArg:
if list_item in keysListArg:
#grabs the binary value linked to its key and stores in x
x = keysListArg.get(list_item)
#prints list item along side its binary key
print(list_item + ' : ' + x)
#splits the word
newArray = split(word)
#prints each letter next to its binary code representation
printBinary(newArray, binaryTable)
sample output:
please input a value to see its representation in Binary Code: louis
l : 01101100
o : 01101111
u : 01110101
i : 01101001
s : 01110011
>>>
answered Mar 22 at 23:54
James DeanJames Dean
11
#program to take a string and show the binary representation of all the letters
binaryTable =
"a" : "01100001",
"b" : "01100010",
"c" : "01100011",
"d" : "01100100",
"e" : "01100101",
"f" : "01100110",
"g" : "01100111",
"h" : "01101000",
"i" : "01101001",
"j" : "01101010",
"k" : "01101011",
"l" : "01101100",
"m" : "01101101",
"n" : "01101110",
"o" : "01101111",
"p" : "01110000",
"q" : "01110001",
"r" : "01110010",
"s" : "01110011",
"t" : "01110100",
"u" : "01110101",
"v" : "01110110",
"w" : "01110111",
"x" : "01111000",
"y" : "01111001",
"z" : "01111010",
"A" : "01000001",
"B" : "01000010",
"C" : "01000011",
"D" : "01000100",
"E" : "01000101",
"F" : "01000110",
"G" : "01000111",
"H" : "01001000",
"I" : "01001001",
"J" : "01001010",
"K" : "01001011",
"L" : "01001100",
"M" : "01001101",
"N" : "01001110",
"O" : "01001111",
"P" : "01010000",
"Q" : "01001111",
"R" : "01010010",
"S" : "01010011",
"T" : "01010100",
"U" : "01010101",
"V" : "01010110",
"W" : "01010111",
"X" : "01011000",
"Y" : "01011001",
"Z" : "01011010"
print('Hello there! I am a binary translator. Add some text to see it in binary!')
print('Below is a binary table for all characters of the Alphabet. Remember, upper and lower case characters have different binary values!')
print(
'''
Letter Binary Letter Binary
a 01100001 A 01000001
b 01100010 B 01000010
c 01100011 C 01000011
d 01100100 D 01000100
e 01100101 E 01000101
f 01100110 F 01000110
g 01100111 G 01000111
h 01101000 H 01001000
i 01101001 I 01001001
j 01101010 J 01001010
k 01101011 K 01001011
l 01101100 L 01001100
m 01101101 M 01001101
n 01101110 N 01001110
o 01101111 O 01001111
p 01110000 P 01010000
q 01110001 Q 01010001
r 01110010 R 01010010
s 01110011 S 01010011
t 01110100 T 01010100
u 01110101 U 01010101
v 01110110 V 01010110
w 01110111 W 01010111
x 01111000 X 01011000
y 01111001 Y 01011001
z 01111010 Z 01011010''')
word = input('please input a value to see its representation in Binary Code: ')
#splits the word into single letters and stores in a list aka newArray
def split(letters):
return [char for char in letters]
#takes the parameters of newArray and binaryTable.
#new array is the input word split into letters
def printBinary(dictArg, keysListArg):
for list_item in dictArg:
if list_item in keysListArg:
#grabs the binary value linked to its key and stores in x
x = keysListArg.get(list_item)
#prints list item along side its binary key
print(list_item + ' : ' + x)
#splits the word
newArray = split(word)
#prints each letter next to its binary code representation
printBinary(newArray, binaryTable)
sample output:
please input a value to see its representation in Binary Code: louis
l : 01101100
o : 01101111
u : 01110101
i : 01101001
s : 01110011
>>>
answered Mar 22 at 23:54
James DeanJames Dean
11
answered Mar 22 at 23:54
James DeanJames Dean
11
answered Mar 22 at 23:54
James DeanJames Dean
11
answered Mar 22 at 23:54
James DeanJames Dean
11
11
add a comment |
add a comment |
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what version of python?
dictused to not guarantee order of keys when iterating. not sure of the behavior now. stackoverflow.com/questions/5629023/…– MFisherKDX
Mar 22 at 22:40
3.7 I edited the function as such but it still prints in the wrong order:
– James Dean
Mar 22 at 22:44
def printBinary(dictArg, keysListArg): count = 0 for list_item in keysListArg: if list_item in dictArg: count+= 1 print(count) print(list_item) print(' : ') x = keysListArg.get(list_item) print(x) return count
– James Dean
Mar 22 at 22:45
I'm having a hard time understanding what you are after ... but did you mean to call the function
printBinaryasprintBinary(binaryTable, newArray)instead ofprintBinary(newArray, binaryTable)?– MFisherKDX
Mar 22 at 22:52
I have solved it:
– James Dean
Mar 22 at 22:56