How do you shift a signal to reference a virtual ground in an instrumentation amplifier? [closed]New to Embedded Development. Working on digital KVMSend/Capture Radio Wave signals with .NETProgrammable power supplyThermocouple signal amplification using INA126PMax485 chip not working on 3v3 logic but able to work on 5v arduino pin even if only connected through my fingerConnecting I2C Device to Labview using NI-845x74LS148 circuit output remains constant regardless to inputMultithreaded Graph TraversalConvert 0 v-5 v voltage to 0-1 V for ADC (for ESP8266 12F)How can I convert a 24V relay signal (closed circuit/open circuit) to a 5V/0V binary signal?
Make 24 using exactly three 3s
Manager questioning my time estimates for a project
Mysterious procedure calls without parameters - but no exceptions generated
Why is the Eisenstein ideal paper so great?
Python program to take in two strings and print the larger string
Beginner looking to learn/master musical theory and instrumental ability. Where should I begin?
Should there be an "a" before "ten years imprisonment"?
Must a warlock replace spells with new spells of exactly their Pact Magic spell slot level?
Time complexity of an algorithm: Is it important to state the base of the logarithm?
Best material to absorb as much light as possible
Gravitational effects of a single human body on the motion of planets
WordPress 5.2.1 deactivated my jQuery
Why does Bran want to find Drogon?
Why do Russians almost not use verbs of possession akin to "have"?
What could a self-sustaining lunar colony slowly lose that would ultimately prove fatal?
Shorten or merge multiple lines of `&> /dev/null &`
Why didn't Thanos use the Time Stone to stop the Avengers' plan?
How to politely tell someone they did not hit "reply to all" in an email?
What does kpsewhich stand for?
Why isn't 'chemically-strengthened glass' made with potassium carbonate to begin with?
Of strange atmospheres - the survivable but unbreathable
How can I tell if I'm being too picky as a referee?
Why did Drogon spare this character?
Need to read my home electrical Meter
How do you shift a signal to reference a virtual ground in an instrumentation amplifier? [closed]
New to Embedded Development. Working on digital KVMSend/Capture Radio Wave signals with .NETProgrammable power supplyThermocouple signal amplification using INA126PMax485 chip not working on 3v3 logic but able to work on 5v arduino pin even if only connected through my fingerConnecting I2C Device to Labview using NI-845x74LS148 circuit output remains constant regardless to inputMultithreaded Graph TraversalConvert 0 v-5 v voltage to 0-1 V for ADC (for ESP8266 12F)How can I convert a 24V relay signal (closed circuit/open circuit) to a 5V/0V binary signal?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I'm working on a circuit that needs to amplify a signal based on a changing resistance. The hardware that I have to work with can only make an offset square wave, but I need an input that is centered around 0V. I have tried using an instrumentation amplifier with one voltage set as the excitation signal and the other is the virtual ground, but it still fails to center the signal.
Any ideas of what to do to shift the signal?
electronics circuit-diagram
asked Mar 24 at 1:04
FrontskyFrontsky
164
closed as off-topic by Dijkgraaf, JumpingJezza, Martijn Pieters♦ Mar 25 at 1:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions about general computing hardware and software are off-topic for Stack Overflow unless they directly involve tools used primarily for programming. You may be able to get help on Super User." – Dijkgraaf, Martijn Pieters
add a comment |
I'm working on a circuit that needs to amplify a signal based on a changing resistance. The hardware that I have to work with can only make an offset square wave, but I need an input that is centered around 0V. I have tried using an instrumentation amplifier with one voltage set as the excitation signal and the other is the virtual ground, but it still fails to center the signal.
Any ideas of what to do to shift the signal?
electronics circuit-diagram
asked Mar 24 at 1:04
FrontskyFrontsky
164
closed as off-topic by Dijkgraaf, JumpingJezza, Martijn Pieters♦ Mar 25 at 1:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions about general computing hardware and software are off-topic for Stack Overflow unless they directly involve tools used primarily for programming. You may be able to get help on Super User." – Dijkgraaf, Martijn Pieters
I'm voting to close this question because the development of electronic devices is off-topic for Stack Overflow: consider asking these questions on Electronics.SE
– JumpingJezza
Mar 25 at 0:47
My bad. I'm still learning all the nuances of these sites
– Frontsky
Mar 26 at 23:47
add a comment |
I'm working on a circuit that needs to amplify a signal based on a changing resistance. The hardware that I have to work with can only make an offset square wave, but I need an input that is centered around 0V. I have tried using an instrumentation amplifier with one voltage set as the excitation signal and the other is the virtual ground, but it still fails to center the signal.
Any ideas of what to do to shift the signal?
electronics circuit-diagram
asked Mar 24 at 1:04
FrontskyFrontsky
164
I'm working on a circuit that needs to amplify a signal based on a changing resistance. The hardware that I have to work with can only make an offset square wave, but I need an input that is centered around 0V. I have tried using an instrumentation amplifier with one voltage set as the excitation signal and the other is the virtual ground, but it still fails to center the signal.
Any ideas of what to do to shift the signal?
electronics circuit-diagram
electronics circuit-diagram
asked Mar 24 at 1:04
FrontskyFrontsky
164
asked Mar 24 at 1:04
FrontskyFrontsky
164
asked Mar 24 at 1:04
FrontskyFrontsky
164
asked Mar 24 at 1:04
FrontskyFrontsky
164
asked Mar 24 at 1:04
FrontskyFrontsky
164
164
closed as off-topic by Dijkgraaf, JumpingJezza, Martijn Pieters♦ Mar 25 at 1:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions about general computing hardware and software are off-topic for Stack Overflow unless they directly involve tools used primarily for programming. You may be able to get help on Super User." – Dijkgraaf, Martijn Pieters
closed as off-topic by Dijkgraaf, JumpingJezza, Martijn Pieters♦ Mar 25 at 1:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions about general computing hardware and software are off-topic for Stack Overflow unless they directly involve tools used primarily for programming. You may be able to get help on Super User." – Dijkgraaf, Martijn Pieters
I'm voting to close this question because the development of electronic devices is off-topic for Stack Overflow: consider asking these questions on Electronics.SE
– JumpingJezza
Mar 25 at 0:47
My bad. I'm still learning all the nuances of these sites
– Frontsky
Mar 26 at 23:47
add a comment |
I'm voting to close this question because the development of electronic devices is off-topic for Stack Overflow: consider asking these questions on Electronics.SE
– JumpingJezza
Mar 25 at 0:47
My bad. I'm still learning all the nuances of these sites
– Frontsky
Mar 26 at 23:47
I'm voting to close this question because the development of electronic devices is off-topic for Stack Overflow: consider asking these questions on Electronics.SE
– JumpingJezza
Mar 25 at 0:47
I'm voting to close this question because the development of electronic devices is off-topic for Stack Overflow: consider asking these questions on Electronics.SE
– JumpingJezza
Mar 25 at 0:47
My bad. I'm still learning all the nuances of these sites
– Frontsky
Mar 26 at 23:47
My bad. I'm still learning all the nuances of these sites
– Frontsky
Mar 26 at 23:47
add a comment |
1 Answer
1
active
oldest
votes
I understand you need to balance the signal, for example, +/-5V. from a 0-10V. positive (unbalanced) signal (maybe values are wrong but check if I got the idea right, please).
Have you tried to make a SUMMING amplifier with an OPAMP? By the same example above, if you input GND (0V) into a resistor R that goes to non-inverting input (+), then there is another resistor R connected to the same + input but to -5V on the other terminal, the result is -5V. If your input now gets out of GND and receives 5V, the result is 0V on the output. If you input 10V, you will get 5V on the output. Pretty straightforward. This is a single gain non-inverting amplifier with two positive inputs being added up. But one of them has the negative boundary. Everything on output is the input referenced to this negative boundary now. You have just made a level shifter... Sorry if I got you wrong, please clarify if the case. Of course you know that inverting input is shorted to output and your power must be symmetric and at least 2V bigger than your desired span @ output, right? Resistor R should be something inside the 100k-10M field. If you negative boundary is not -VCC please make a voltage divider with 1-10k resistors (in order for impedances not to interact with your summing circuitry) to obtain the very exact voltage you need to be this boundary. Hope it helps.
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I understand you need to balance the signal, for example, +/-5V. from a 0-10V. positive (unbalanced) signal (maybe values are wrong but check if I got the idea right, please).
Have you tried to make a SUMMING amplifier with an OPAMP? By the same example above, if you input GND (0V) into a resistor R that goes to non-inverting input (+), then there is another resistor R connected to the same + input but to -5V on the other terminal, the result is -5V. If your input now gets out of GND and receives 5V, the result is 0V on the output. If you input 10V, you will get 5V on the output. Pretty straightforward. This is a single gain non-inverting amplifier with two positive inputs being added up. But one of them has the negative boundary. Everything on output is the input referenced to this negative boundary now. You have just made a level shifter... Sorry if I got you wrong, please clarify if the case. Of course you know that inverting input is shorted to output and your power must be symmetric and at least 2V bigger than your desired span @ output, right? Resistor R should be something inside the 100k-10M field. If you negative boundary is not -VCC please make a voltage divider with 1-10k resistors (in order for impedances not to interact with your summing circuitry) to obtain the very exact voltage you need to be this boundary. Hope it helps.
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
add a comment |
I understand you need to balance the signal, for example, +/-5V. from a 0-10V. positive (unbalanced) signal (maybe values are wrong but check if I got the idea right, please).
Have you tried to make a SUMMING amplifier with an OPAMP? By the same example above, if you input GND (0V) into a resistor R that goes to non-inverting input (+), then there is another resistor R connected to the same + input but to -5V on the other terminal, the result is -5V. If your input now gets out of GND and receives 5V, the result is 0V on the output. If you input 10V, you will get 5V on the output. Pretty straightforward. This is a single gain non-inverting amplifier with two positive inputs being added up. But one of them has the negative boundary. Everything on output is the input referenced to this negative boundary now. You have just made a level shifter... Sorry if I got you wrong, please clarify if the case. Of course you know that inverting input is shorted to output and your power must be symmetric and at least 2V bigger than your desired span @ output, right? Resistor R should be something inside the 100k-10M field. If you negative boundary is not -VCC please make a voltage divider with 1-10k resistors (in order for impedances not to interact with your summing circuitry) to obtain the very exact voltage you need to be this boundary. Hope it helps.
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
add a comment |
I understand you need to balance the signal, for example, +/-5V. from a 0-10V. positive (unbalanced) signal (maybe values are wrong but check if I got the idea right, please).
Have you tried to make a SUMMING amplifier with an OPAMP? By the same example above, if you input GND (0V) into a resistor R that goes to non-inverting input (+), then there is another resistor R connected to the same + input but to -5V on the other terminal, the result is -5V. If your input now gets out of GND and receives 5V, the result is 0V on the output. If you input 10V, you will get 5V on the output. Pretty straightforward. This is a single gain non-inverting amplifier with two positive inputs being added up. But one of them has the negative boundary. Everything on output is the input referenced to this negative boundary now. You have just made a level shifter... Sorry if I got you wrong, please clarify if the case. Of course you know that inverting input is shorted to output and your power must be symmetric and at least 2V bigger than your desired span @ output, right? Resistor R should be something inside the 100k-10M field. If you negative boundary is not -VCC please make a voltage divider with 1-10k resistors (in order for impedances not to interact with your summing circuitry) to obtain the very exact voltage you need to be this boundary. Hope it helps.
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
I understand you need to balance the signal, for example, +/-5V. from a 0-10V. positive (unbalanced) signal (maybe values are wrong but check if I got the idea right, please).
Have you tried to make a SUMMING amplifier with an OPAMP? By the same example above, if you input GND (0V) into a resistor R that goes to non-inverting input (+), then there is another resistor R connected to the same + input but to -5V on the other terminal, the result is -5V. If your input now gets out of GND and receives 5V, the result is 0V on the output. If you input 10V, you will get 5V on the output. Pretty straightforward. This is a single gain non-inverting amplifier with two positive inputs being added up. But one of them has the negative boundary. Everything on output is the input referenced to this negative boundary now. You have just made a level shifter... Sorry if I got you wrong, please clarify if the case. Of course you know that inverting input is shorted to output and your power must be symmetric and at least 2V bigger than your desired span @ output, right? Resistor R should be something inside the 100k-10M field. If you negative boundary is not -VCC please make a voltage divider with 1-10k resistors (in order for impedances not to interact with your summing circuitry) to obtain the very exact voltage you need to be this boundary. Hope it helps.
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
answered Mar 24 at 23:19
Mario CarvalhoMario Carvalho
262
262
add a comment |
add a comment |
I'm voting to close this question because the development of electronic devices is off-topic for Stack Overflow: consider asking these questions on Electronics.SE
– JumpingJezza
Mar 25 at 0:47
My bad. I'm still learning all the nuances of these sites
– Frontsky
Mar 26 at 23:47