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Is there a difference in break statement between C and Python?
What is the difference between #include <filename> and #include “filename”?Replacements for switch statement in Python?Calling an external command in PythonWhat are metaclasses in Python?What is the difference between @staticmethod and @classmethod?What is the difference between Python's list methods append and extend?Does Python have a ternary conditional operator?Difference between __str__ and __repr__?Improve INSERT-per-second performance of SQLite?Does Python have a string 'contains' substring method?
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I'm working on a python program and i'm still a beginner in python.
i've a c program that i'm trying to write in python, i'm facing a problem because in this program, break statement isn't performing the same way.
I've a loop and then a second inner loop and if condition where i need to break if the if condition is valid.
What i need is one break statement in the if condition.
in Python using this only break statement isn't giving me correct results while in c it's working.
I noticed that in C if i put a second break in the second loop after the if condition i'm getting same wrong results i'm getting in python.
for f in range(1,6):
for k in range(1,8):
if(x==y):
break
if ///// :
break
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
if /////
break
so these two codes aren't giving same result,
while if i change c code to this one, it will give me same pythong wrong results
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
break; <------------------------------- if i add this
if //////
break;
python c loops break
asked Mar 24 at 3:43
kotashakotasha
204
add a comment |
I'm working on a python program and i'm still a beginner in python.
i've a c program that i'm trying to write in python, i'm facing a problem because in this program, break statement isn't performing the same way.
I've a loop and then a second inner loop and if condition where i need to break if the if condition is valid.
What i need is one break statement in the if condition.
in Python using this only break statement isn't giving me correct results while in c it's working.
I noticed that in C if i put a second break in the second loop after the if condition i'm getting same wrong results i'm getting in python.
for f in range(1,6):
for k in range(1,8):
if(x==y):
break
if ///// :
break
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
if /////
break
so these two codes aren't giving same result,
while if i change c code to this one, it will give me same pythong wrong results
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
break; <------------------------------- if i add this
if //////
break;
python c loops break
asked Mar 24 at 3:43
kotashakotasha
204
2
I don't see a reason why those two code snippets would behave differently, unless your python program had an indentation issue where the interpreter thought your break statement was in the outer loop, not the inner one. I suggest you add some print statements to both pieces of code to verify the result you're getting. Also, you weren't very specific in your question about what result you saw that was different from what you were expecting. Please edit your question to fix that.
– Niayesh Isky
Mar 24 at 3:47
1
Also, are x and y supposed to be f and k? If not, where are they coming from? Are they being changed inside the loops?
– Niayesh Isky
Mar 24 at 3:48
no x and y aren't f and k, and actually it's a big program and i have results i'm waiting for, it's a cryptanalysis system that i'm trying to write in python.
– kotasha
Mar 24 at 3:52
You should always produce an example that is consistent: stackoverflow.com/help/mcve
– Klaus D.
Mar 24 at 4:19
add a comment |
I'm working on a python program and i'm still a beginner in python.
i've a c program that i'm trying to write in python, i'm facing a problem because in this program, break statement isn't performing the same way.
I've a loop and then a second inner loop and if condition where i need to break if the if condition is valid.
What i need is one break statement in the if condition.
in Python using this only break statement isn't giving me correct results while in c it's working.
I noticed that in C if i put a second break in the second loop after the if condition i'm getting same wrong results i'm getting in python.
for f in range(1,6):
for k in range(1,8):
if(x==y):
break
if ///// :
break
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
if /////
break
so these two codes aren't giving same result,
while if i change c code to this one, it will give me same pythong wrong results
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
break; <------------------------------- if i add this
if //////
break;
python c loops break
asked Mar 24 at 3:43
kotashakotasha
204
I'm working on a python program and i'm still a beginner in python.
i've a c program that i'm trying to write in python, i'm facing a problem because in this program, break statement isn't performing the same way.
I've a loop and then a second inner loop and if condition where i need to break if the if condition is valid.
What i need is one break statement in the if condition.
in Python using this only break statement isn't giving me correct results while in c it's working.
I noticed that in C if i put a second break in the second loop after the if condition i'm getting same wrong results i'm getting in python.
for f in range(1,6):
for k in range(1,8):
if(x==y):
break
if ///// :
break
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
if /////
break
so these two codes aren't giving same result,
while if i change c code to this one, it will give me same pythong wrong results
for (int f = 1; f < 6; f++)
for (int k = 1; k < 8; k++)
if(x==y)
break;
break; <------------------------------- if i add this
if //////
break;
python c loops break
python c loops break
asked Mar 24 at 3:43
kotashakotasha
204
asked Mar 24 at 3:43
kotashakotasha
204
asked Mar 24 at 3:43
kotashakotasha
204
asked Mar 24 at 3:43
kotashakotasha
204
asked Mar 24 at 3:43
kotashakotasha
204
204
2
I don't see a reason why those two code snippets would behave differently, unless your python program had an indentation issue where the interpreter thought your break statement was in the outer loop, not the inner one. I suggest you add some print statements to both pieces of code to verify the result you're getting. Also, you weren't very specific in your question about what result you saw that was different from what you were expecting. Please edit your question to fix that.
– Niayesh Isky
Mar 24 at 3:47
1
Also, are x and y supposed to be f and k? If not, where are they coming from? Are they being changed inside the loops?
– Niayesh Isky
Mar 24 at 3:48
no x and y aren't f and k, and actually it's a big program and i have results i'm waiting for, it's a cryptanalysis system that i'm trying to write in python.
– kotasha
Mar 24 at 3:52
You should always produce an example that is consistent: stackoverflow.com/help/mcve
– Klaus D.
Mar 24 at 4:19
add a comment |
2
I don't see a reason why those two code snippets would behave differently, unless your python program had an indentation issue where the interpreter thought your break statement was in the outer loop, not the inner one. I suggest you add some print statements to both pieces of code to verify the result you're getting. Also, you weren't very specific in your question about what result you saw that was different from what you were expecting. Please edit your question to fix that.
– Niayesh Isky
Mar 24 at 3:47
1
Also, are x and y supposed to be f and k? If not, where are they coming from? Are they being changed inside the loops?
– Niayesh Isky
Mar 24 at 3:48
no x and y aren't f and k, and actually it's a big program and i have results i'm waiting for, it's a cryptanalysis system that i'm trying to write in python.
– kotasha
Mar 24 at 3:52
You should always produce an example that is consistent: stackoverflow.com/help/mcve
– Klaus D.
Mar 24 at 4:19
2
2
I don't see a reason why those two code snippets would behave differently, unless your python program had an indentation issue where the interpreter thought your break statement was in the outer loop, not the inner one. I suggest you add some print statements to both pieces of code to verify the result you're getting. Also, you weren't very specific in your question about what result you saw that was different from what you were expecting. Please edit your question to fix that.
– Niayesh Isky
Mar 24 at 3:47
I don't see a reason why those two code snippets would behave differently, unless your python program had an indentation issue where the interpreter thought your break statement was in the outer loop, not the inner one. I suggest you add some print statements to both pieces of code to verify the result you're getting. Also, you weren't very specific in your question about what result you saw that was different from what you were expecting. Please edit your question to fix that.
– Niayesh Isky
Mar 24 at 3:47
1
1
Also, are x and y supposed to be f and k? If not, where are they coming from? Are they being changed inside the loops?
– Niayesh Isky
Mar 24 at 3:48
Also, are x and y supposed to be f and k? If not, where are they coming from? Are they being changed inside the loops?
– Niayesh Isky
Mar 24 at 3:48
no x and y aren't f and k, and actually it's a big program and i have results i'm waiting for, it's a cryptanalysis system that i'm trying to write in python.
– kotasha
Mar 24 at 3:52
no x and y aren't f and k, and actually it's a big program and i have results i'm waiting for, it's a cryptanalysis system that i'm trying to write in python.
– kotasha
Mar 24 at 3:52
You should always produce an example that is consistent: stackoverflow.com/help/mcve
– Klaus D.
Mar 24 at 4:19
You should always produce an example that is consistent: stackoverflow.com/help/mcve
– Klaus D.
Mar 24 at 4:19
add a comment |
1 Answer
1
active
oldest
votes
break behaves the same in both languages. Check the indentation in your Python program. Your first two samples shpuld behave the same.
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
add a comment |
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break behaves the same in both languages. Check the indentation in your Python program. Your first two samples shpuld behave the same.
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
add a comment |
break behaves the same in both languages. Check the indentation in your Python program. Your first two samples shpuld behave the same.
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
add a comment |
break behaves the same in both languages. Check the indentation in your Python program. Your first two samples shpuld behave the same.
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
break behaves the same in both languages. Check the indentation in your Python program. Your first two samples shpuld behave the same.
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
answered Mar 24 at 3:49
CoffeeTableEspressoCoffeeTableEspresso
905418
905418
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I don't see a reason why those two code snippets would behave differently, unless your python program had an indentation issue where the interpreter thought your break statement was in the outer loop, not the inner one. I suggest you add some print statements to both pieces of code to verify the result you're getting. Also, you weren't very specific in your question about what result you saw that was different from what you were expecting. Please edit your question to fix that.
– Niayesh Isky
Mar 24 at 3:47
1
Also, are x and y supposed to be f and k? If not, where are they coming from? Are they being changed inside the loops?
– Niayesh Isky
Mar 24 at 3:48
no x and y aren't f and k, and actually it's a big program and i have results i'm waiting for, it's a cryptanalysis system that i'm trying to write in python.
– kotasha
Mar 24 at 3:52
You should always produce an example that is consistent: stackoverflow.com/help/mcve
– Klaus D.
Mar 24 at 4:19