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SCILAB Adding legend in a plot generated by a loop
Accessing the index in 'for' loops?How do I loop through or enumerate a JavaScript object?JavaScript closure inside loops – simple practical exampleHow do I break out of nested loops in Java?Looping through the content of a file in BashLoop through an array in JavaScriptHow to put the legend out of the plotSave plot to image file instead of displaying it using MatplotlibDraw legend on a plot using different colorsggplot2 legends: Adding items not in plot code to the legend & changing shapes in legend
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I´d like to know how to add legend in a plot generated by a loop in SciLab. There are 4 loops and each loop has a different legend (and colors).
I tried the code bellow. However, gives me the 4 legends but with the same color (in the case red).
inta=read("H_intacta_num.txt",-1,1500)
d1=read("H_dano1_num.txt",-1,1500)
d2=read("H_dano2_num.txt",-1,1500)
d3=read("H_dano3_num.txt",-1,1500)
leia1=read("Dados_MagN1.txt",-1,3);
frequ=leia1(:,1)
\loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
\loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
\loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
\loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
loops plot legend scilab
asked Mar 23 at 14:27
LVoltzLVoltz
114
add a comment |
I´d like to know how to add legend in a plot generated by a loop in SciLab. There are 4 loops and each loop has a different legend (and colors).
I tried the code bellow. However, gives me the 4 legends but with the same color (in the case red).
inta=read("H_intacta_num.txt",-1,1500)
d1=read("H_dano1_num.txt",-1,1500)
d2=read("H_dano2_num.txt",-1,1500)
d3=read("H_dano3_num.txt",-1,1500)
leia1=read("Dados_MagN1.txt",-1,3);
frequ=leia1(:,1)
\loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
\loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
\loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
\loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
loops plot legend scilab
asked Mar 23 at 14:27
LVoltzLVoltz
114
add a comment |
I´d like to know how to add legend in a plot generated by a loop in SciLab. There are 4 loops and each loop has a different legend (and colors).
I tried the code bellow. However, gives me the 4 legends but with the same color (in the case red).
inta=read("H_intacta_num.txt",-1,1500)
d1=read("H_dano1_num.txt",-1,1500)
d2=read("H_dano2_num.txt",-1,1500)
d3=read("H_dano3_num.txt",-1,1500)
leia1=read("Dados_MagN1.txt",-1,3);
frequ=leia1(:,1)
\loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
\loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
\loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
\loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
loops plot legend scilab
asked Mar 23 at 14:27
LVoltzLVoltz
114
I´d like to know how to add legend in a plot generated by a loop in SciLab. There are 4 loops and each loop has a different legend (and colors).
I tried the code bellow. However, gives me the 4 legends but with the same color (in the case red).
inta=read("H_intacta_num.txt",-1,1500)
d1=read("H_dano1_num.txt",-1,1500)
d2=read("H_dano2_num.txt",-1,1500)
d3=read("H_dano3_num.txt",-1,1500)
leia1=read("Dados_MagN1.txt",-1,3);
frequ=leia1(:,1)
\loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
\loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
\loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
\loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
loops plot legend scilab
loops plot legend scilab
asked Mar 23 at 14:27
LVoltzLVoltz
114
asked Mar 23 at 14:27
LVoltzLVoltz
114
asked Mar 23 at 14:27
LVoltzLVoltz
114
asked Mar 23 at 14:27
LVoltzLVoltz
114
asked Mar 23 at 14:27
LVoltzLVoltz
114
114
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Here legend will consider the first 4 polylines in the stack, hence red ones. You can change the links this way (btw line comment is // not \)
//loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
h(1)=gce()
//loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
h(2)=gce()
//loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
h(3)=gce()
//loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
h(4)=gce()
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(h, ['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
add a comment |
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1 Answer
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oldest
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oldest
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oldest
votes
Here legend will consider the first 4 polylines in the stack, hence red ones. You can change the links this way (btw line comment is // not \)
//loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
h(1)=gce()
//loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
h(2)=gce()
//loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
h(3)=gce()
//loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
h(4)=gce()
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(h, ['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
add a comment |
Here legend will consider the first 4 polylines in the stack, hence red ones. You can change the links this way (btw line comment is // not \)
//loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
h(1)=gce()
//loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
h(2)=gce()
//loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
h(3)=gce()
//loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
h(4)=gce()
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(h, ['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
add a comment |
Here legend will consider the first 4 polylines in the stack, hence red ones. You can change the links this way (btw line comment is // not \)
//loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
h(1)=gce()
//loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
h(2)=gce()
//loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
h(3)=gce()
//loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
h(4)=gce()
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(h, ['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
Here legend will consider the first 4 polylines in the stack, hence red ones. You can change the links this way (btw line comment is // not \)
//loop1 - red (label: healthy)
for i=48:94
plot(frequ,inta(i,:),'r')
end
h(1)=gce()
//loop 2 - blue (label: Damaged_L1)
for j=48:94
plot(frequ,d1(j,:),'b')
end
h(2)=gce()
//loop 3 - black (label: Damaged_L2)
for j=37:72
plot(frequ,d2(j,:),'k')
end
h(3)=gce()
//loop 4 - ciano (label: Damaged_L3)
for j=36:70
plot(frequ,d3(j,:),'c')
end
h(4)=gce()
ylabel("Amplitude (m/s^2)/N")
xlabel("Frequency (Hz)")
p=legend(h, ['Healthy';'Damaged_L1';'Damaged_L2';'Damaged_L3'],[2])
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
answered Mar 24 at 16:44
Stéphane MotteletStéphane Mottelet
545113
545113
add a comment |
add a comment |
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