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Convert line endings [duplicate]

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49

19

This question already has an answer here:

• 
  How to convert DOS/Windows newline (CRLF) to Unix newline (LF) in a Bash script?
  
  23 answers
  
  

I have been using d2u to convert line endings. After installing Puppy Linux I
noticed that it does not come with d2u, but dos2unix. Then I noticed that
Ubuntu is missing both by default.

What is another way to convert line endings?

bash shell sed command-line dos2unix

share|improve this question

edited Nov 3 '16 at 22:33

Steven Penny

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

marked as duplicate by Adrian Frühwirth, Steven Penny, laalto, Micha, Howli Apr 30 '14 at 10:40

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

49

19

This question already has an answer here:

• 
  How to convert DOS/Windows newline (CRLF) to Unix newline (LF) in a Bash script?
  
  23 answers
  
  

I have been using d2u to convert line endings. After installing Puppy Linux I
noticed that it does not come with d2u, but dos2unix. Then I noticed that
Ubuntu is missing both by default.

What is another way to convert line endings?

bash shell sed command-line dos2unix

share|improve this question

edited Nov 3 '16 at 22:33

Steven Penny

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

marked as duplicate by Adrian Frühwirth, Steven Penny, laalto, Micha, Howli Apr 30 '14 at 10:40

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

add a comment | 

This question already has an answer here:

• 
  How to convert DOS/Windows newline (CRLF) to Unix newline (LF) in a Bash script?
  
  23 answers
  
  

I have been using d2u to convert line endings. After installing Puppy Linux I
noticed that it does not come with d2u, but dos2unix. Then I noticed that
Ubuntu is missing both by default.

What is another way to convert line endings?

bash shell sed command-line dos2unix

share|improve this question

edited Nov 3 '16 at 22:33

Steven Penny

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

share|improve this question

edited Nov 3 '16 at 22:33

Steven Penny

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

share|improve this question

edited Nov 3 '16 at 22:33

Steven Penny

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

asked May 27 '13 at 8:01

Steven PennySteven Penny

1

2 Answers
2

active

oldest

votes

84

Some options:

Using tr

tr -d '1532' < windows.txt > unix.txt

OR

tr -d 'r' < windows.txt > unix.txt 

Using perl

perl -p -e 's/r$//' < windows.txt > unix.txt

Using sed

sed 's/^M$//' windows.txt > unix.txt

OR

sed 's/r$//' windows.txt > unix.txt

To obtain ^M, you have to type CTRL-V and then CTRL-M.

share|improve this answer

edited Jun 7 '17 at 23:01

B T

29.2k26139169

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  
  on my mac only this works: tr -d 'r' < windows.txt > unix.txt
  
  – Davoud Taghawi-Nejad
  Sep 4 '15 at 21:22
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  I learned on mac you cannot use tr to open and write to the same file. That results in a blank file, but writing to a different name works great!
  
  – Loren
  Jul 28 '16 at 0:59
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Loren i think that should be your assumption with any redirection. The destination file is opened before the reading of the source. Some commands let you do "in-place" like sed's -i but use intermediate/backup files anyway
  
  – nhed
  Nov 2 '16 at 20:37
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  These answers are generally correct and you could add awk 'sub(/r$/,"")1' windows.txt > unix.tx but be aware that the tr is deleting all rs from the input, not just those that occur at the end of each line as the perl, sed, and now awk scripts would do.
  
  – Ed Morton
  Aug 19 '17 at 13:42
  
  

  
  
  
  

add a comment | 

65

Doing this with POSIX is tricky:

• POSIX Sed does not support r or 15. Even if it did, the in place
  option -i is not POSIX




• POSIX Awk does support r and 15, however the -i inplace option
  is not POSIX




• d2u and dos2unix are not POSIX utilities, but ex is




• POSIX ex does not support r, 15, n or 12

To remove carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("r","");print>ARGV[1]' file

To add carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("n","r&");print>ARGV[1]' file

share|improve this answer

edited Jan 15 '17 at 20:06

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Those awk scripts are GNU awk only due to multi-character RS (more than 1 char in a RS invokes undefined behavior in POSIX so some POSIX awks will silently drop the $ and retain just the ^, others can do whatever else they like), they would produce unexpected results when the getline fails, they will only operate on the first line of the input, and they will corrupt the input file in some situations and if they were fixed to operate on all lines would cause an infinite loop in others by writing to the input file as it's being read. Do not execute those scripts.
  
  – Ed Morton
  Aug 19 '17 at 13:36
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  This work on the same file, ie. it replace line endings in-place. While the tr solutions require different file as an output.
  
  – PeterM
  Sep 7 '17 at 10:59
  
  

  
  
  
  

add a comment | 

84

Some options:

Using tr

tr -d '1532' < windows.txt > unix.txt

OR

tr -d 'r' < windows.txt > unix.txt 

Using perl

perl -p -e 's/r$//' < windows.txt > unix.txt

Using sed

sed 's/^M$//' windows.txt > unix.txt

OR

sed 's/r$//' windows.txt > unix.txt

To obtain ^M, you have to type CTRL-V and then CTRL-M.

share|improve this answer

edited Jun 7 '17 at 23:01

B T

29.2k26139169

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  
  on my mac only this works: tr -d 'r' < windows.txt > unix.txt
  
  – Davoud Taghawi-Nejad
  Sep 4 '15 at 21:22
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  I learned on mac you cannot use tr to open and write to the same file. That results in a blank file, but writing to a different name works great!
  
  – Loren
  Jul 28 '16 at 0:59
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Loren i think that should be your assumption with any redirection. The destination file is opened before the reading of the source. Some commands let you do "in-place" like sed's -i but use intermediate/backup files anyway
  
  – nhed
  Nov 2 '16 at 20:37
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  These answers are generally correct and you could add awk 'sub(/r$/,"")1' windows.txt > unix.tx but be aware that the tr is deleting all rs from the input, not just those that occur at the end of each line as the perl, sed, and now awk scripts would do.
  
  – Ed Morton
  Aug 19 '17 at 13:42
  
  

  
  
  
  

add a comment | 

84

Some options:

Using tr

tr -d '1532' < windows.txt > unix.txt

OR

tr -d 'r' < windows.txt > unix.txt 

Using perl

perl -p -e 's/r$//' < windows.txt > unix.txt

Using sed

sed 's/^M$//' windows.txt > unix.txt

OR

sed 's/r$//' windows.txt > unix.txt

To obtain ^M, you have to type CTRL-V and then CTRL-M.

share|improve this answer

edited Jun 7 '17 at 23:01

B T

29.2k26139169

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

• 
  
  
  

  
  8
  

  
  
  
  
  
  

  
  
  on my mac only this works: tr -d 'r' < windows.txt > unix.txt
  
  – Davoud Taghawi-Nejad
  Sep 4 '15 at 21:22
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  I learned on mac you cannot use tr to open and write to the same file. That results in a blank file, but writing to a different name works great!
  
  – Loren
  Jul 28 '16 at 0:59
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Loren i think that should be your assumption with any redirection. The destination file is opened before the reading of the source. Some commands let you do "in-place" like sed's -i but use intermediate/backup files anyway
  
  – nhed
  Nov 2 '16 at 20:37
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  These answers are generally correct and you could add awk 'sub(/r$/,"")1' windows.txt > unix.tx but be aware that the tr is deleting all rs from the input, not just those that occur at the end of each line as the perl, sed, and now awk scripts would do.
  
  – Ed Morton
  Aug 19 '17 at 13:42
  
  

  
  
  
  

add a comment | 

Some options:

Using tr

tr -d '1532' < windows.txt > unix.txt

OR

tr -d 'r' < windows.txt > unix.txt 

Using perl

perl -p -e 's/r$//' < windows.txt > unix.txt

Using sed

sed 's/^M$//' windows.txt > unix.txt

OR

sed 's/r$//' windows.txt > unix.txt

To obtain ^M, you have to type CTRL-V and then CTRL-M.

share|improve this answer

edited Jun 7 '17 at 23:01

B T

29.2k26139169

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

tr -d '1532' < windows.txt > unix.txt

tr -d 'r' < windows.txt > unix.txt 

perl -p -e 's/r$//' < windows.txt > unix.txt

sed 's/^M$//' windows.txt > unix.txt

sed 's/r$//' windows.txt > unix.txt

share|improve this answer

edited Jun 7 '17 at 23:01

B T

29.2k26139169

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

edited Jun 7 '17 at 23:01

B T

29.2k26139169

edited Jun 7 '17 at 23:01

B T

29.2k26139169

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

answered May 27 '13 at 8:07

jaypal singhjaypal singh

59.2k1586124

65

Doing this with POSIX is tricky:

• POSIX Sed does not support r or 15. Even if it did, the in place
  option -i is not POSIX




• POSIX Awk does support r and 15, however the -i inplace option
  is not POSIX




• d2u and dos2unix are not POSIX utilities, but ex is




• POSIX ex does not support r, 15, n or 12

To remove carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("r","");print>ARGV[1]' file

To add carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("n","r&");print>ARGV[1]' file

share|improve this answer

edited Jan 15 '17 at 20:06

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Those awk scripts are GNU awk only due to multi-character RS (more than 1 char in a RS invokes undefined behavior in POSIX so some POSIX awks will silently drop the $ and retain just the ^, others can do whatever else they like), they would produce unexpected results when the getline fails, they will only operate on the first line of the input, and they will corrupt the input file in some situations and if they were fixed to operate on all lines would cause an infinite loop in others by writing to the input file as it's being read. Do not execute those scripts.
  
  – Ed Morton
  Aug 19 '17 at 13:36
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  This work on the same file, ie. it replace line endings in-place. While the tr solutions require different file as an output.
  
  – PeterM
  Sep 7 '17 at 10:59
  
  

  
  
  
  

add a comment | 

65

Doing this with POSIX is tricky:

• POSIX Sed does not support r or 15. Even if it did, the in place
  option -i is not POSIX




• POSIX Awk does support r and 15, however the -i inplace option
  is not POSIX




• d2u and dos2unix are not POSIX utilities, but ex is




• POSIX ex does not support r, 15, n or 12

To remove carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("r","");print>ARGV[1]' file

To add carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("n","r&");print>ARGV[1]' file

share|improve this answer

edited Jan 15 '17 at 20:06

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Those awk scripts are GNU awk only due to multi-character RS (more than 1 char in a RS invokes undefined behavior in POSIX so some POSIX awks will silently drop the $ and retain just the ^, others can do whatever else they like), they would produce unexpected results when the getline fails, they will only operate on the first line of the input, and they will corrupt the input file in some situations and if they were fixed to operate on all lines would cause an infinite loop in others by writing to the input file as it's being read. Do not execute those scripts.
  
  – Ed Morton
  Aug 19 '17 at 13:36
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  This work on the same file, ie. it replace line endings in-place. While the tr solutions require different file as an output.
  
  – PeterM
  Sep 7 '17 at 10:59
  
  

  
  
  
  

add a comment | 

Doing this with POSIX is tricky:

• POSIX Sed does not support r or 15. Even if it did, the in place
  option -i is not POSIX




• POSIX Awk does support r and 15, however the -i inplace option
  is not POSIX




• d2u and dos2unix are not POSIX utilities, but ex is




• POSIX ex does not support r, 15, n or 12

To remove carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("r","");print>ARGV[1]' file

To add carriage returns:

awk 'BEGINRS="^$";ORS="";getline;gsub("n","r&");print>ARGV[1]' file

share|improve this answer

edited Jan 15 '17 at 20:06

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1

awk 'BEGINRS="^$";ORS="";getline;gsub("r","");print>ARGV[1]' file

awk 'BEGINRS="^$";ORS="";getline;gsub("n","r&");print>ARGV[1]' file

share|improve this answer

edited Jan 15 '17 at 20:06

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1

answered Jan 19 '14 at 16:53

Steven PennySteven Penny

1