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Difference between -| and |- in TikZ
TikZ: What EXACTLY does the the |- notation for arrows do?Insertion of perpendicular symbol at intersection of two perpendicular linesHow to Mark Right Angle in TikzMatrices and TikZ : arrows inside the matrixOmit the same coordinate parameters in drawing line in tikzHow to add perpendicular symbol at desired locationHelp on LateX Diagram using TikZ packageHow to fix TikZ corners in 3DTikZ: how to find the intersection of two extended lines?Complicated Tikz logic drawingRight Angle Symbol Alignment with TikZ/CalcTikZ: Drawing an arc from an intersection to an intersectionA display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsTikZ calculate in/out-angle from nodesTwo parallel lines between nodes of arbitrary size and position
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
add a comment |
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
tikz-pgf
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
asked Mar 24 at 12:16
subham sonisubham soni
5,29383192
5,29383192
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
1
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
3 Answers
3
active
oldest
votes
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
add a comment |
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
add a comment |
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
edited Apr 20 at 14:24
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
answered Mar 24 at 13:55
The old JouleVThe old JouleV
19.5k43175
19.5k43175
add a comment |
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
edited Mar 25 at 5:54
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
36.9k558163
36.9k558163
add a comment |
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
answered Mar 24 at 18:31
Money Oriented ProgrammerMoney Oriented Programmer
5,96411346
5,96411346
add a comment |
add a comment |
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tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33