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Do dynamic libraries have the same virtual memory address in all programs?


When to use dynamic vs. static librariesHow to translate a virtual memory address to a physical address?Dynamic linking: offset value used to index relocation tableVirtual address space vs virtual memoryWhere virtual memory addresses reside?Understanding Virtual Address, Virtual Memory and PagingLLDB Terminal OutputVirtual Address to Physical addressFinding virtual memory address of variable on osxVirtual Memory, Virtual Address






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1















When a library is dynamically linked to a program does it have the same address in that program as in any other program?



I my head I imagined each process gets the whole of the address space and then everything in that process (inc. dynamic libraries that are already in memory) gets mapped to semi-random parts of it because of ASLR.



But I did a short experiment that seems to imply that the address of libraries that are in memory are fixed across different processes and thus reusable across programs? Is that correct?



I wrote two short c programs which used the "sleep" function. In one I printed out the address of the sleep function and in the second I assigned a function pointer to that address. I ran them both and the sleep function worked in both.



#include <stdio.h>
#include <unistd.h>

int main()

while(1)

printf("%sn", &"hi");
sleep(2);
printf("pointer to sleep: %pn", sleep);




#include <stdio.h>
#include <unistd.h>

#define sleepagain ((void (*)(int))0x7fff7652e669) //addr of sleep from first program

int main()

while(1)

printf("%sn", &"test");
sleepagain(2);




I wasn't sure what this would show but what it actually showed was a) the address was the same every time I ran the first program and b) that sleep still functioned when I ran the second.



I think I understand how this works but I am curious if it has to work the way it does and what are the reasons behind it?



Just to reference the answer I got already when I took a look with otool -IvV I got:



a.out:
Indirect symbols for (__TEXT,__stubs) 2 entries
address index name
0x0000000100000f62 2 _printf
0x0000000100000f68 3 _sleep
Indirect symbols for (__DATA,__nl_symbol_ptr) 2 entries
address index name
0x0000000100001000 4 dyld_stub_binder
0x0000000100001008 ABSOLUTE
Indirect symbols for (__DATA,__got) 1 entries
address index name
0x0000000100001010 3 _sleep
Indirect symbols for (__DATA,__la_symbol_ptr) 2 entries
address index name
0x0000000100001018 2 _printf
0x0000000100001020 3 _sleep


Which is also what the indirect address was in lldb. The address was the address of sleep itself:



Process 11209 launched: 'stuff/a.out' (x86_64)
hi
Process 11209 stopped
* thread #1, queue = 'com.apple.main-thread', stop reason = breakpoint 1.1
frame #0: 0x00007fff7652e669 libsystem_c.dylib`sleep
libsystem_c.dylib`sleep:
-> 0x7fff7652e669 <+0>: push rbp
0x7fff7652e66a <+1>: mov rbp, rsp
0x7fff7652e66d <+4>: push rbx
0x7fff7652e66e <+5>: sub rsp, 0x28
Target 0: (a.out) stopped.


For some additional info:



$ otool -hv a.out
Mach header
magic cputype cpusubtype caps filetype ncmds sizeofcmds flags
MH_MAGIC_64 X86_64 ALL LIB64 EXECUTE 15 1296 NOUNDEFS DYLDLINK TWOLEVEL PIE









share|improve this question






























    1















    When a library is dynamically linked to a program does it have the same address in that program as in any other program?



    I my head I imagined each process gets the whole of the address space and then everything in that process (inc. dynamic libraries that are already in memory) gets mapped to semi-random parts of it because of ASLR.



    But I did a short experiment that seems to imply that the address of libraries that are in memory are fixed across different processes and thus reusable across programs? Is that correct?



    I wrote two short c programs which used the "sleep" function. In one I printed out the address of the sleep function and in the second I assigned a function pointer to that address. I ran them both and the sleep function worked in both.



    #include <stdio.h>
    #include <unistd.h>

    int main()

    while(1)

    printf("%sn", &"hi");
    sleep(2);
    printf("pointer to sleep: %pn", sleep);




    #include <stdio.h>
    #include <unistd.h>

    #define sleepagain ((void (*)(int))0x7fff7652e669) //addr of sleep from first program

    int main()

    while(1)

    printf("%sn", &"test");
    sleepagain(2);




    I wasn't sure what this would show but what it actually showed was a) the address was the same every time I ran the first program and b) that sleep still functioned when I ran the second.



    I think I understand how this works but I am curious if it has to work the way it does and what are the reasons behind it?



    Just to reference the answer I got already when I took a look with otool -IvV I got:



    a.out:
    Indirect symbols for (__TEXT,__stubs) 2 entries
    address index name
    0x0000000100000f62 2 _printf
    0x0000000100000f68 3 _sleep
    Indirect symbols for (__DATA,__nl_symbol_ptr) 2 entries
    address index name
    0x0000000100001000 4 dyld_stub_binder
    0x0000000100001008 ABSOLUTE
    Indirect symbols for (__DATA,__got) 1 entries
    address index name
    0x0000000100001010 3 _sleep
    Indirect symbols for (__DATA,__la_symbol_ptr) 2 entries
    address index name
    0x0000000100001018 2 _printf
    0x0000000100001020 3 _sleep


    Which is also what the indirect address was in lldb. The address was the address of sleep itself:



    Process 11209 launched: 'stuff/a.out' (x86_64)
    hi
    Process 11209 stopped
    * thread #1, queue = 'com.apple.main-thread', stop reason = breakpoint 1.1
    frame #0: 0x00007fff7652e669 libsystem_c.dylib`sleep
    libsystem_c.dylib`sleep:
    -> 0x7fff7652e669 <+0>: push rbp
    0x7fff7652e66a <+1>: mov rbp, rsp
    0x7fff7652e66d <+4>: push rbx
    0x7fff7652e66e <+5>: sub rsp, 0x28
    Target 0: (a.out) stopped.


    For some additional info:



    $ otool -hv a.out
    Mach header
    magic cputype cpusubtype caps filetype ncmds sizeofcmds flags
    MH_MAGIC_64 X86_64 ALL LIB64 EXECUTE 15 1296 NOUNDEFS DYLDLINK TWOLEVEL PIE









    share|improve this question


























      1












      1








      1








      When a library is dynamically linked to a program does it have the same address in that program as in any other program?



      I my head I imagined each process gets the whole of the address space and then everything in that process (inc. dynamic libraries that are already in memory) gets mapped to semi-random parts of it because of ASLR.



      But I did a short experiment that seems to imply that the address of libraries that are in memory are fixed across different processes and thus reusable across programs? Is that correct?



      I wrote two short c programs which used the "sleep" function. In one I printed out the address of the sleep function and in the second I assigned a function pointer to that address. I ran them both and the sleep function worked in both.



      #include <stdio.h>
      #include <unistd.h>

      int main()

      while(1)

      printf("%sn", &"hi");
      sleep(2);
      printf("pointer to sleep: %pn", sleep);




      #include <stdio.h>
      #include <unistd.h>

      #define sleepagain ((void (*)(int))0x7fff7652e669) //addr of sleep from first program

      int main()

      while(1)

      printf("%sn", &"test");
      sleepagain(2);




      I wasn't sure what this would show but what it actually showed was a) the address was the same every time I ran the first program and b) that sleep still functioned when I ran the second.



      I think I understand how this works but I am curious if it has to work the way it does and what are the reasons behind it?



      Just to reference the answer I got already when I took a look with otool -IvV I got:



      a.out:
      Indirect symbols for (__TEXT,__stubs) 2 entries
      address index name
      0x0000000100000f62 2 _printf
      0x0000000100000f68 3 _sleep
      Indirect symbols for (__DATA,__nl_symbol_ptr) 2 entries
      address index name
      0x0000000100001000 4 dyld_stub_binder
      0x0000000100001008 ABSOLUTE
      Indirect symbols for (__DATA,__got) 1 entries
      address index name
      0x0000000100001010 3 _sleep
      Indirect symbols for (__DATA,__la_symbol_ptr) 2 entries
      address index name
      0x0000000100001018 2 _printf
      0x0000000100001020 3 _sleep


      Which is also what the indirect address was in lldb. The address was the address of sleep itself:



      Process 11209 launched: 'stuff/a.out' (x86_64)
      hi
      Process 11209 stopped
      * thread #1, queue = 'com.apple.main-thread', stop reason = breakpoint 1.1
      frame #0: 0x00007fff7652e669 libsystem_c.dylib`sleep
      libsystem_c.dylib`sleep:
      -> 0x7fff7652e669 <+0>: push rbp
      0x7fff7652e66a <+1>: mov rbp, rsp
      0x7fff7652e66d <+4>: push rbx
      0x7fff7652e66e <+5>: sub rsp, 0x28
      Target 0: (a.out) stopped.


      For some additional info:



      $ otool -hv a.out
      Mach header
      magic cputype cpusubtype caps filetype ncmds sizeofcmds flags
      MH_MAGIC_64 X86_64 ALL LIB64 EXECUTE 15 1296 NOUNDEFS DYLDLINK TWOLEVEL PIE









      share|improve this question
















      When a library is dynamically linked to a program does it have the same address in that program as in any other program?



      I my head I imagined each process gets the whole of the address space and then everything in that process (inc. dynamic libraries that are already in memory) gets mapped to semi-random parts of it because of ASLR.



      But I did a short experiment that seems to imply that the address of libraries that are in memory are fixed across different processes and thus reusable across programs? Is that correct?



      I wrote two short c programs which used the "sleep" function. In one I printed out the address of the sleep function and in the second I assigned a function pointer to that address. I ran them both and the sleep function worked in both.



      #include <stdio.h>
      #include <unistd.h>

      int main()

      while(1)

      printf("%sn", &"hi");
      sleep(2);
      printf("pointer to sleep: %pn", sleep);




      #include <stdio.h>
      #include <unistd.h>

      #define sleepagain ((void (*)(int))0x7fff7652e669) //addr of sleep from first program

      int main()

      while(1)

      printf("%sn", &"test");
      sleepagain(2);




      I wasn't sure what this would show but what it actually showed was a) the address was the same every time I ran the first program and b) that sleep still functioned when I ran the second.



      I think I understand how this works but I am curious if it has to work the way it does and what are the reasons behind it?



      Just to reference the answer I got already when I took a look with otool -IvV I got:



      a.out:
      Indirect symbols for (__TEXT,__stubs) 2 entries
      address index name
      0x0000000100000f62 2 _printf
      0x0000000100000f68 3 _sleep
      Indirect symbols for (__DATA,__nl_symbol_ptr) 2 entries
      address index name
      0x0000000100001000 4 dyld_stub_binder
      0x0000000100001008 ABSOLUTE
      Indirect symbols for (__DATA,__got) 1 entries
      address index name
      0x0000000100001010 3 _sleep
      Indirect symbols for (__DATA,__la_symbol_ptr) 2 entries
      address index name
      0x0000000100001018 2 _printf
      0x0000000100001020 3 _sleep


      Which is also what the indirect address was in lldb. The address was the address of sleep itself:



      Process 11209 launched: 'stuff/a.out' (x86_64)
      hi
      Process 11209 stopped
      * thread #1, queue = 'com.apple.main-thread', stop reason = breakpoint 1.1
      frame #0: 0x00007fff7652e669 libsystem_c.dylib`sleep
      libsystem_c.dylib`sleep:
      -> 0x7fff7652e669 <+0>: push rbp
      0x7fff7652e66a <+1>: mov rbp, rsp
      0x7fff7652e66d <+4>: push rbx
      0x7fff7652e66e <+5>: sub rsp, 0x28
      Target 0: (a.out) stopped.


      For some additional info:



      $ otool -hv a.out
      Mach header
      magic cputype cpusubtype caps filetype ncmds sizeofcmds flags
      MH_MAGIC_64 X86_64 ALL LIB64 EXECUTE 15 1296 NOUNDEFS DYLDLINK TWOLEVEL PIE






      macos dynamic-linking virtual-address-space






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 25 at 13:04







      AsksStupidQuestions

















      asked Mar 25 at 11:12









      AsksStupidQuestionsAsksStupidQuestions

      642 silver badges7 bronze badges




      642 silver badges7 bronze badges






















          1 Answer
          1






          active

          oldest

          votes


















          2














          On macOS, many system libraries are part of the dyld shared cache. There's a machine-wide mapping. So, those libraries end up at the same address in all processes of the same architecture (32- or 64-bit).



          The location of the dyld shared cache is randomized at system boot. So, library addresses will be the same from process to process until you reboot.



          Not all system libraries are part of the cache, only the ones that Apple deems to be commonly loaded.



          Libraries of your own or from third parties will be loaded at random locations each time they're loaded, assuming they are position-independent.



          Try looking at the output from vmmap -v <pid>. Look for the line with "machine-wide VM submap" and those that follow.






          share|improve this answer























          • I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

            – AsksStupidQuestions
            Mar 25 at 15:15







          • 1





            I would not expect keeping one process with it loaded would affect subsequent processes that load it.

            – Ken Thomases
            Mar 25 at 19:20











          • Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

            – AsksStupidQuestions
            Mar 25 at 19:53






          • 1





            Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

            – Ken Thomases
            Mar 25 at 20:03













          Your Answer






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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          On macOS, many system libraries are part of the dyld shared cache. There's a machine-wide mapping. So, those libraries end up at the same address in all processes of the same architecture (32- or 64-bit).



          The location of the dyld shared cache is randomized at system boot. So, library addresses will be the same from process to process until you reboot.



          Not all system libraries are part of the cache, only the ones that Apple deems to be commonly loaded.



          Libraries of your own or from third parties will be loaded at random locations each time they're loaded, assuming they are position-independent.



          Try looking at the output from vmmap -v <pid>. Look for the line with "machine-wide VM submap" and those that follow.






          share|improve this answer























          • I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

            – AsksStupidQuestions
            Mar 25 at 15:15







          • 1





            I would not expect keeping one process with it loaded would affect subsequent processes that load it.

            – Ken Thomases
            Mar 25 at 19:20











          • Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

            – AsksStupidQuestions
            Mar 25 at 19:53






          • 1





            Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

            – Ken Thomases
            Mar 25 at 20:03















          2














          On macOS, many system libraries are part of the dyld shared cache. There's a machine-wide mapping. So, those libraries end up at the same address in all processes of the same architecture (32- or 64-bit).



          The location of the dyld shared cache is randomized at system boot. So, library addresses will be the same from process to process until you reboot.



          Not all system libraries are part of the cache, only the ones that Apple deems to be commonly loaded.



          Libraries of your own or from third parties will be loaded at random locations each time they're loaded, assuming they are position-independent.



          Try looking at the output from vmmap -v <pid>. Look for the line with "machine-wide VM submap" and those that follow.






          share|improve this answer























          • I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

            – AsksStupidQuestions
            Mar 25 at 15:15







          • 1





            I would not expect keeping one process with it loaded would affect subsequent processes that load it.

            – Ken Thomases
            Mar 25 at 19:20











          • Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

            – AsksStupidQuestions
            Mar 25 at 19:53






          • 1





            Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

            – Ken Thomases
            Mar 25 at 20:03













          2












          2








          2







          On macOS, many system libraries are part of the dyld shared cache. There's a machine-wide mapping. So, those libraries end up at the same address in all processes of the same architecture (32- or 64-bit).



          The location of the dyld shared cache is randomized at system boot. So, library addresses will be the same from process to process until you reboot.



          Not all system libraries are part of the cache, only the ones that Apple deems to be commonly loaded.



          Libraries of your own or from third parties will be loaded at random locations each time they're loaded, assuming they are position-independent.



          Try looking at the output from vmmap -v <pid>. Look for the line with "machine-wide VM submap" and those that follow.






          share|improve this answer













          On macOS, many system libraries are part of the dyld shared cache. There's a machine-wide mapping. So, those libraries end up at the same address in all processes of the same architecture (32- or 64-bit).



          The location of the dyld shared cache is randomized at system boot. So, library addresses will be the same from process to process until you reboot.



          Not all system libraries are part of the cache, only the ones that Apple deems to be commonly loaded.



          Libraries of your own or from third parties will be loaded at random locations each time they're loaded, assuming they are position-independent.



          Try looking at the output from vmmap -v <pid>. Look for the line with "machine-wide VM submap" and those that follow.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 25 at 15:13









          Ken ThomasesKen Thomases

          73.8k6 gold badges77 silver badges116 bronze badges




          73.8k6 gold badges77 silver badges116 bronze badges












          • I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

            – AsksStupidQuestions
            Mar 25 at 15:15







          • 1





            I would not expect keeping one process with it loaded would affect subsequent processes that load it.

            – Ken Thomases
            Mar 25 at 19:20











          • Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

            – AsksStupidQuestions
            Mar 25 at 19:53






          • 1





            Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

            – Ken Thomases
            Mar 25 at 20:03

















          • I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

            – AsksStupidQuestions
            Mar 25 at 15:15







          • 1





            I would not expect keeping one process with it loaded would affect subsequent processes that load it.

            – Ken Thomases
            Mar 25 at 19:20











          • Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

            – AsksStupidQuestions
            Mar 25 at 19:53






          • 1





            Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

            – Ken Thomases
            Mar 25 at 20:03
















          I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

          – AsksStupidQuestions
          Mar 25 at 15:15






          I had a go with my own dylib and yeah, each time it was loaded it was at a new location, if I kept it loaded (by running a program using it in an infinite loop) the addresses were the same and I could get it from other programs. Enjoying learning how this stuff works.

          – AsksStupidQuestions
          Mar 25 at 15:15





          1




          1





          I would not expect keeping one process with it loaded would affect subsequent processes that load it.

          – Ken Thomases
          Mar 25 at 19:20





          I would not expect keeping one process with it loaded would affect subsequent processes that load it.

          – Ken Thomases
          Mar 25 at 19:20













          Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

          – AsksStupidQuestions
          Mar 25 at 19:53





          Hm, you're right, I guess I got fooled because the lowest two bytes of the address were the same.

          – AsksStupidQuestions
          Mar 25 at 19:53




          1




          1





          Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

          – Ken Thomases
          Mar 25 at 20:03





          Yeah, ASLR should only move stuff by increments of a page size (4096 a.k.a. 0x1000). So, it will never change the low three hex digits.

          – Ken Thomases
          Mar 25 at 20:03



















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