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Get element from json array javascript [closed]

How do JavaScript closures work?What is the most efficient way to deep clone an object in JavaScript?How do I check if an element is hidden in jQuery?How do I remove a property from a JavaScript object?Can comments be used in JSON?How can I convert a string to boolean in JavaScript?What is the correct JSON content type?How to check whether a string contains a substring in JavaScript?How do I remove a particular element from an array in JavaScript?For-each over an array in JavaScript?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

I have a simple Json String

[
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

I want get field Name in Data in ValueInput by Javascript.

Please help me!

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Reproducible Example." – pirho, wscourge, Kristopher Ives, Bart

If this question can be reworded to fit the rules in the help center, please edit the question.

1

You can use JSON.parse to convert json to object.

– Eddie
Mar 25 at 8:44

2

Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask

– Denny
Mar 25 at 11:18

add a comment |

I have a simple Json String

[
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

I want get field Name in Data in ValueInput by Javascript.

Please help me!

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Reproducible Example." – pirho, wscourge, Kristopher Ives, Bart

If this question can be reworded to fit the rules in the help center, please edit the question.

1

You can use JSON.parse to convert json to object.

– Eddie
Mar 25 at 8:44

2

Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask

– Denny
Mar 25 at 11:18

add a comment |

I have a simple Json String

[
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

I want get field Name in Data in ValueInput by Javascript.

Please help me!

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

I have a simple Json String

[
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

I want get field Name in Data in ValueInput by Javascript.

Please help me!

javascript arrays json object

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

edited Mar 25 at 8:49

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

asked Mar 25 at 8:42

Java Dev Beginner

601 silver badge8 bronze badges

closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Reproducible Example." – pirho, wscourge, Kristopher Ives, Bart

If this question can be reworded to fit the rules in the help center, please edit the question.

closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Reproducible Example." – pirho, wscourge, Kristopher Ives, Bart

If this question can be reworded to fit the rules in the help center, please edit the question.

1

You can use JSON.parse to convert json to object.

– Eddie
Mar 25 at 8:44

2

Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask

– Denny
Mar 25 at 11:18

add a comment |

1

You can use JSON.parse to convert json to object.

– Eddie
Mar 25 at 8:44

2

Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask

– Denny
Mar 25 at 11:18

You can use JSON.parse to convert json to object.

– Eddie
Mar 25 at 8:44

Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask

– Denny
Mar 25 at 11:18

add a comment |

7 Answers
7

active

oldest

votes

You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

add a comment |

You could use JSON.parse

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

add a comment |

You can use JSON.parse

JSON.parse(o[0].valueInput).data[0].name

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

@Deepakgupta data[0] is not a string, the array is parsed before. See the live demo before post a comment

– R3tep
Mar 25 at 8:51

the input value is a string, not an object, and the string is not correctly stringified.

– AZ_
Mar 25 at 9:03

@AZ_ The input value is not a string. Jack make some bad edit

– R3tep
Mar 25 at 9:07

1

it says I have a simple Json String not sure maybe.

– AZ_
Mar 25 at 9:15

@AZ_ Yes he have a json string into the key valueInput

– R3tep
Mar 25 at 9:16

add a comment |

Use JSON.parse, and use map:

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

add a comment |

You can use an array variable and the callback function of JSON.parse to get the name key & val

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

add a comment |

Here is a way to do it.

let originalData = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
];

let valueInput = JSON.parse(originalData[0].valueInput);

let data = valueInput.data;

console.log(data);

for (var i = 0; i < data.length; i++)
 console.log(data[i].name);

See jsfiddle https://jsfiddle.net/3s1na4eL/3/

Let me know if there are any questions.

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

add a comment |

You can do:

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

edited Mar 26 at 2:39

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

add a comment |

7 Answers
7

active

oldest

votes

7 Answers
7

active

oldest

votes

You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

add a comment |

You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

add a comment |

You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

var arr = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];

arr.forEach((arrObj) => 
 var jsonData = JSON.parse(arrObj.valueInput);
 jsonData.data.forEach((name) => console.log(name));
);

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

answered Mar 25 at 8:45

Ankit Agarwal

25k5 gold badges23 silver badges45 bronze badges

add a comment |

You could use JSON.parse

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

add a comment |

You could use JSON.parse

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

add a comment |

You could use JSON.parse

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

You could use JSON.parse

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

var jsonArray = [
 
 assetName: 'LCT',
 assetValue: '',
 typeValueInput: 'select',
 valueInputSelect: null,
 required: true,
 valueInput:
 '"data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]'
 
];

let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => 
 console.log(value.name, value.id);
);

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

answered Mar 25 at 8:47

Loc Mai

411 silver badge3 bronze badges

add a comment |

You can use JSON.parse

JSON.parse(o[0].valueInput).data[0].name

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

@Deepakgupta data[0] is not a string, the array is parsed before. See the live demo before post a comment

– R3tep
Mar 25 at 8:51

the input value is a string, not an object, and the string is not correctly stringified.

– AZ_
Mar 25 at 9:03

@AZ_ The input value is not a string. Jack make some bad edit

– R3tep
Mar 25 at 9:07

1

it says I have a simple Json String not sure maybe.

– AZ_
Mar 25 at 9:15

@AZ_ Yes he have a json string into the key valueInput

– R3tep
Mar 25 at 9:16

add a comment |

You can use JSON.parse

JSON.parse(o[0].valueInput).data[0].name

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

@Deepakgupta data[0] is not a string, the array is parsed before. See the live demo before post a comment

– R3tep
Mar 25 at 8:51

the input value is a string, not an object, and the string is not correctly stringified.

– AZ_
Mar 25 at 9:03

@AZ_ The input value is not a string. Jack make some bad edit

– R3tep
Mar 25 at 9:07

1

it says I have a simple Json String not sure maybe.

– AZ_
Mar 25 at 9:15

@AZ_ Yes he have a json string into the key valueInput

– R3tep
Mar 25 at 9:16

add a comment |

You can use JSON.parse

JSON.parse(o[0].valueInput).data[0].name

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

You can use JSON.parse

JSON.parse(o[0].valueInput).data[0].name

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

var o = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
]

console.log(JSON.parse(o[0].valueInput).data[0].name);

// To get all, use a loop

var arrO = JSON.parse(o[0].valueInput).data;

arrO.forEach((obj) => console.log(obj.name))

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

answered Mar 25 at 8:44

R3tep

8,7528 gold badges29 silver badges64 bronze badges

@Deepakgupta data[0] is not a string, the array is parsed before. See the live demo before post a comment

– R3tep
Mar 25 at 8:51

the input value is a string, not an object, and the string is not correctly stringified.

– AZ_
Mar 25 at 9:03

@AZ_ The input value is not a string. Jack make some bad edit

– R3tep
Mar 25 at 9:07

1

it says I have a simple Json String not sure maybe.

– AZ_
Mar 25 at 9:15

@AZ_ Yes he have a json string into the key valueInput

– R3tep
Mar 25 at 9:16

add a comment |

@Deepakgupta data[0] is not a string, the array is parsed before. See the live demo before post a comment

– R3tep
Mar 25 at 8:51

the input value is a string, not an object, and the string is not correctly stringified.

– AZ_
Mar 25 at 9:03

@AZ_ The input value is not a string. Jack make some bad edit

– R3tep
Mar 25 at 9:07

1

it says I have a simple Json String not sure maybe.

– AZ_
Mar 25 at 9:15

@AZ_ Yes he have a json string into the key valueInput

– R3tep
Mar 25 at 9:16

@Deepakgupta data[0] is not a string, the array is parsed before. See the live demo before post a comment

– R3tep
Mar 25 at 8:51

the input value is a string, not an object, and the string is not correctly stringified.

– AZ_
Mar 25 at 9:03

@AZ_ The input value is not a string. Jack make some bad edit

– R3tep
Mar 25 at 9:07

it says I have a simple Json String not sure maybe.

– AZ_
Mar 25 at 9:15

@AZ_ Yes he have a json string into the key valueInput

– R3tep
Mar 25 at 9:16

add a comment |

Use JSON.parse, and use map:

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

add a comment |

Use JSON.parse, and use map:

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

add a comment |

Use JSON.parse, and use map:

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

Use JSON.parse, and use map:

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

const data = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
]
const names = JSON.parse(data[0].valueInput).data.map(( name ) => name);
console.log(names);

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

answered Mar 25 at 8:51

Jack Bashford

26.7k6 gold badges24 silver badges51 bronze badges

add a comment |

You can use an array variable and the callback function of JSON.parse to get the name key & val

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

add a comment |

You can use an array variable and the callback function of JSON.parse to get the name key & val

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

add a comment |

You can use an array variable and the callback function of JSON.parse to get the name key & val

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

You can use an array variable and the callback function of JSON.parse to get the name key & val

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

let dt = [
 "assetName": "LCT",
 "assetValue": "",
 "typeValueInput": "select",
 "valueInputSelect": null,
 "required": true,
 "valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
];
let nameArray = [];

let dlt = JSON.parse(dt[0].valueInput, function(key, val) 
 if (key === 'name') 
 nameArray.push(val);
 
)

console.log(nameArray)

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

answered Mar 25 at 8:56

brk

32.1k3 gold badges24 silver badges47 bronze badges

add a comment |

Here is a way to do it.

let originalData = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
];

let valueInput = JSON.parse(originalData[0].valueInput);

let data = valueInput.data;

console.log(data);

for (var i = 0; i < data.length; i++)
 console.log(data[i].name);

See jsfiddle https://jsfiddle.net/3s1na4eL/3/

Let me know if there are any questions.

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

add a comment |

Here is a way to do it.

let originalData = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
];

let valueInput = JSON.parse(originalData[0].valueInput);

let data = valueInput.data;

console.log(data);

for (var i = 0; i < data.length; i++)
 console.log(data[i].name);

See jsfiddle https://jsfiddle.net/3s1na4eL/3/

Let me know if there are any questions.

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

add a comment |

Here is a way to do it.

let originalData = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
];

let valueInput = JSON.parse(originalData[0].valueInput);

let data = valueInput.data;

console.log(data);

for (var i = 0; i < data.length; i++)
 console.log(data[i].name);

See jsfiddle https://jsfiddle.net/3s1na4eL/3/

Let me know if there are any questions.

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

Here is a way to do it.

let originalData = [
 
 "assetName":"LCT",
 "assetValue":"",
 "typeValueInput":"select",
 "valueInputSelect":null,
 "required":true,
 "valueInput":""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"
 
];

let valueInput = JSON.parse(originalData[0].valueInput);

let data = valueInput.data;

console.log(data);

for (var i = 0; i < data.length; i++)
 console.log(data[i].name);

See jsfiddle https://jsfiddle.net/3s1na4eL/3/

Let me know if there are any questions.

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

answered Mar 25 at 8:59

Kabelo Tooka

1841 silver badge10 bronze badges

add a comment |

You can do:

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

edited Mar 26 at 2:39

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

add a comment |

You can do:

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

edited Mar 26 at 2:39

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

add a comment |

You can do:

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

edited Mar 26 at 2:39

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

You can do:

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

const arr = ["assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": ""data":["name":"name1","id":"12","name":"name2","id":"13","name":"name3","id":"14"]"];

arr.forEach(o => JSON.parse(o.valueInput).data.forEach((id, name) => console.log(id, name)));

edited Mar 26 at 2:39

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

edited Mar 26 at 2:39

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

answered Mar 25 at 8:53

Yosvel Quintero

12.5k4 gold badges27 silver badges31 bronze badges

add a comment |

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