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Why do i get “invalid use of non-static data member” error when i try to create an array inside class? [duplicate]

Array initialization use const variable in C++error: request for member '..' in '..' which is of non-class typestatic constructors in C++? I need to initialize private static objectsDeclaring a non static const array as class memberStatic constant string (class member)C++11 allows in-class initialization of non-static and non-const members. What changed?invalid use of non-static data member (array)error: invalid in-class initialization of static data member of non-integral type 'const char[]'Replacing a 32-bit loop counter with 64-bit introduces crazy performance deviationsInvalid use of non static data memberStatic data member initialization in the class definition?

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-2

This question already has an answer here:

• 
  Array initialization use const variable in C++
  
  4 answers
  
  

I created an array with the length of x but I get the error

invalid use of non-static data member Test::x.

I tried to replace int newArray[x]; with int newArray = new int[x]; but still didn't work out.
When I declared the newArray[x] in the constructor or put static const before int x = 10, the code run successfully.
Why is that?

#include <iostream>
#include <vector>
using namespace std;

class Test

private:
 int x = 10;
 int newArray[x];
public:
 Test();
 ~Test();
;
int main()


 return 0;

c++

share|improve this question

edited Mar 25 at 11:35

Ayxan

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asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

marked as duplicate by Alan Birtles, P.W c++
Users with the  c++ badge can single-handedly close c++ questions as duplicates and reopen them as needed.

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Mar 25 at 11:22

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You may want to read this : stackoverflow.com/questions/18996258/…
  
  – Spinkoo
  Mar 25 at 11:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The size of arrays must be known at compile-time. Use vector if that cannot happen.
  
  – M.M
  Mar 25 at 11:21
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Don't edit question in a way to invalidate answers please
  
  – Ayxan
  Mar 25 at 11:35
  
  

  
  
  
  

add a comment | 

-2

This question already has an answer here:

• 
  Array initialization use const variable in C++
  
  4 answers
  
  

I created an array with the length of x but I get the error

invalid use of non-static data member Test::x.

I tried to replace int newArray[x]; with int newArray = new int[x]; but still didn't work out.
When I declared the newArray[x] in the constructor or put static const before int x = 10, the code run successfully.
Why is that?

#include <iostream>
#include <vector>
using namespace std;

class Test

private:
 int x = 10;
 int newArray[x];
public:
 Test();
 ~Test();
;
int main()


 return 0;

c++

share|improve this question

edited Mar 25 at 11:35

Ayxan

3,41477 silver badges2525 bronze badges

asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

marked as duplicate by Alan Birtles, P.W c++
Users with the  c++ badge can single-handedly close c++ questions as duplicates and reopen them as needed.

StackExchange.ready(function()
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Mar 25 at 11:22

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You may want to read this : stackoverflow.com/questions/18996258/…
  
  – Spinkoo
  Mar 25 at 11:19
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The size of arrays must be known at compile-time. Use vector if that cannot happen.
  
  – M.M
  Mar 25 at 11:21
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Don't edit question in a way to invalidate answers please
  
  – Ayxan
  Mar 25 at 11:35
  
  

  
  
  
  

add a comment | 

This question already has an answer here:

• 
  Array initialization use const variable in C++
  
  4 answers
  
  

I created an array with the length of x but I get the error

invalid use of non-static data member Test::x.

I tried to replace int newArray[x]; with int newArray = new int[x]; but still didn't work out.
When I declared the newArray[x] in the constructor or put static const before int x = 10, the code run successfully.
Why is that?

#include <iostream>
#include <vector>
using namespace std;

class Test

private:
 int x = 10;
 int newArray[x];
public:
 Test();
 ~Test();
;
int main()


 return 0;

c++

share|improve this question

edited Mar 25 at 11:35

Ayxan

3,41477 silver badges2525 bronze badges

asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

#include <iostream>
#include <vector>
using namespace std;

class Test

private:
 int x = 10;
 int newArray[x];
public:
 Test();
 ~Test();
;
int main()


 return 0;

share|improve this question

edited Mar 25 at 11:35

Ayxan

3,41477 silver badges2525 bronze badges

asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

share|improve this question

edited Mar 25 at 11:35

Ayxan

3,41477 silver badges2525 bronze badges

asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

edited Mar 25 at 11:35

Ayxan

3,41477 silver badges2525 bronze badges

edited Mar 25 at 11:35

Ayxan

3,41477 silver badges2525 bronze badges

asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

asked Mar 25 at 11:16

Minh MốcMinh Mốc

122 bronze badges

1 Answer
1

active

oldest

votes

1

int newArray[x]; won't work because size of a static array needs to be known at compile time. Adding static constexpr to the declaration of x makes it a compile time constant and that's why the code compiles.
int newArray = new int[x]; won't work either, because operator new returns a pointer, which cannot be assigned to an integer. Having said that, consider using std::vector instead.

share|improve this answer

edited Mar 25 at 11:44

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Downvoter Can anyone suggest improvements or corrections to this?
  
  – Ayxan
  Mar 25 at 11:48
  

  
  
  
  

add a comment | 

1

int newArray[x]; won't work because size of a static array needs to be known at compile time. Adding static constexpr to the declaration of x makes it a compile time constant and that's why the code compiles.
int newArray = new int[x]; won't work either, because operator new returns a pointer, which cannot be assigned to an integer. Having said that, consider using std::vector instead.

share|improve this answer

edited Mar 25 at 11:44

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Downvoter Can anyone suggest improvements or corrections to this?
  
  – Ayxan
  Mar 25 at 11:48
  

  
  
  
  

add a comment | 

1

int newArray[x]; won't work because size of a static array needs to be known at compile time. Adding static constexpr to the declaration of x makes it a compile time constant and that's why the code compiles.
int newArray = new int[x]; won't work either, because operator new returns a pointer, which cannot be assigned to an integer. Having said that, consider using std::vector instead.

share|improve this answer

edited Mar 25 at 11:44

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Downvoter Can anyone suggest improvements or corrections to this?
  
  – Ayxan
  Mar 25 at 11:48
  

  
  
  
  

add a comment | 

int newArray[x]; won't work because size of a static array needs to be known at compile time. Adding static constexpr to the declaration of x makes it a compile time constant and that's why the code compiles.
int newArray = new int[x]; won't work either, because operator new returns a pointer, which cannot be assigned to an integer. Having said that, consider using std::vector instead.

share|improve this answer

edited Mar 25 at 11:44

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges

share|improve this answer

edited Mar 25 at 11:44

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges

answered Mar 25 at 11:23

AyxanAyxan

3,41477 silver badges2525 bronze badges