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How to get swagger to use both, the @applicationPath and @path


How do I efficiently iterate over each entry in a Java Map?Does a finally block always get executed in Java?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?How do I generate random integers within a specific range in Java?How to get an enum value from a string value in Java?How do I determine whether an array contains a particular value in Java?How do I convert a String to an int in Java?How do I fix android.os.NetworkOnMainThreadException?PHP REST API with Swagger - LiveHelperChat






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1















Swagger version: 2.0.7



I have an application with @applicationPath("/rest") and various @path("/shop/fruits").



The real endpoint is /rest/shop/fruits.
But swagger is considering the endpoint as /shop/fruits.
Even after pointing the resourcepackage to the application paths file, it is not working.



 oas.info(info);
SwaggerConfiguration oasConfig = new SwaggerConfiguration()
.openAPI(oas).resourcePackages(Stream.of("com.shops.rest").collect(Collectors.toSet()));


try
new JaxrsOpenApiContextBuilder()
.openApiConfiguration(oasConfig)
.buildContext(true);
catch (OpenApiConfigurationException e)
throw new RuntimeException(e.getMessage(), e);



I don't want to update my application path for this. Any solution which I should try.
Swagger 2.0 has support for @applicatioPath but still it's not considering the complete path.










share|improve this question






























    1















    Swagger version: 2.0.7



    I have an application with @applicationPath("/rest") and various @path("/shop/fruits").



    The real endpoint is /rest/shop/fruits.
    But swagger is considering the endpoint as /shop/fruits.
    Even after pointing the resourcepackage to the application paths file, it is not working.



     oas.info(info);
    SwaggerConfiguration oasConfig = new SwaggerConfiguration()
    .openAPI(oas).resourcePackages(Stream.of("com.shops.rest").collect(Collectors.toSet()));


    try
    new JaxrsOpenApiContextBuilder()
    .openApiConfiguration(oasConfig)
    .buildContext(true);
    catch (OpenApiConfigurationException e)
    throw new RuntimeException(e.getMessage(), e);



    I don't want to update my application path for this. Any solution which I should try.
    Swagger 2.0 has support for @applicatioPath but still it's not considering the complete path.










    share|improve this question


























      1












      1








      1








      Swagger version: 2.0.7



      I have an application with @applicationPath("/rest") and various @path("/shop/fruits").



      The real endpoint is /rest/shop/fruits.
      But swagger is considering the endpoint as /shop/fruits.
      Even after pointing the resourcepackage to the application paths file, it is not working.



       oas.info(info);
      SwaggerConfiguration oasConfig = new SwaggerConfiguration()
      .openAPI(oas).resourcePackages(Stream.of("com.shops.rest").collect(Collectors.toSet()));


      try
      new JaxrsOpenApiContextBuilder()
      .openApiConfiguration(oasConfig)
      .buildContext(true);
      catch (OpenApiConfigurationException e)
      throw new RuntimeException(e.getMessage(), e);



      I don't want to update my application path for this. Any solution which I should try.
      Swagger 2.0 has support for @applicatioPath but still it's not considering the complete path.










      share|improve this question
















      Swagger version: 2.0.7



      I have an application with @applicationPath("/rest") and various @path("/shop/fruits").



      The real endpoint is /rest/shop/fruits.
      But swagger is considering the endpoint as /shop/fruits.
      Even after pointing the resourcepackage to the application paths file, it is not working.



       oas.info(info);
      SwaggerConfiguration oasConfig = new SwaggerConfiguration()
      .openAPI(oas).resourcePackages(Stream.of("com.shops.rest").collect(Collectors.toSet()));


      try
      new JaxrsOpenApiContextBuilder()
      .openApiConfiguration(oasConfig)
      .buildContext(true);
      catch (OpenApiConfigurationException e)
      throw new RuntimeException(e.getMessage(), e);



      I don't want to update my application path for this. Any solution which I should try.
      Swagger 2.0 has support for @applicatioPath but still it's not considering the complete path.







      java jax-rs swagger swagger-2.0






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 25 at 13:31







      Sanket

















      asked Mar 25 at 13:25









      SanketSanket

      187 bronze badges




      187 bronze badges






















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