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How to instantiate class (from array) inside the loop

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0

I want to instantiate class inside the loop, I've tried doing this:

<?php
 use AppCaves_demographic_info;
 use AppCaves_current_uses;
 use AppCaves_flora_outside;

 public function get_page4_contd_data($id) 
 $tables = [
 'Caves_demographic_info', 'Caves_current_uses', 'Caves_flora_outside',
 ];


 for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];
 

 
?>

It produces the error 'Class class_name not found', Is it possible to do that inside the loop?

php laravel

share|improve this question

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

add a comment | 

0

I want to instantiate class inside the loop, I've tried doing this:

<?php
 use AppCaves_demographic_info;
 use AppCaves_current_uses;
 use AppCaves_flora_outside;

 public function get_page4_contd_data($id) 
 $tables = [
 'Caves_demographic_info', 'Caves_current_uses', 'Caves_flora_outside',
 ];


 for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];
 

 
?>

It produces the error 'Class class_name not found', Is it possible to do that inside the loop?

php laravel

share|improve this question

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

add a comment | 

I want to instantiate class inside the loop, I've tried doing this:

<?php
 use AppCaves_demographic_info;
 use AppCaves_current_uses;
 use AppCaves_flora_outside;

 public function get_page4_contd_data($id) 
 $tables = [
 'Caves_demographic_info', 'Caves_current_uses', 'Caves_flora_outside',
 ];


 for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];
 

 
?>

It produces the error 'Class class_name not found', Is it possible to do that inside the loop?

php laravel

share|improve this question

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

<?php
 use AppCaves_demographic_info;
 use AppCaves_current_uses;
 use AppCaves_flora_outside;

 public function get_page4_contd_data($id) 
 $tables = [
 'Caves_demographic_info', 'Caves_current_uses', 'Caves_flora_outside',
 ];


 for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];
 

 
?>

share|improve this question

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

share|improve this question

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

asked Mar 26 at 2:22

JielJiel

341010 bronze badges

1 Answer
1

active

oldest

votes

1

Your approach seems right, can you try (with namespace)

$className = 'App' . $tables[$index];
$class = new $className;

So something like this in your example:

 $tables = [
 'AppCaves_demographic_info', 
 'AppCaves_current_uses', 
 'AppCaves_flora_outside',
 ];

for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];

share|improve this answer

edited Mar 26 at 2:34

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  still not working.. second approach produces same error. first approach produces unexpected error
  
  – Jiel
  Mar 26 at 2:27
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you try it with namespace? I just tried in my code, with full namespace it should work
  
  – senty
  Mar 26 at 2:30
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  how would you parse the backslash in the string though?
  
  – Jiel
  Mar 26 at 2:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As it is works for me, did you get an error?
  
  – senty
  Mar 26 at 2:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I've got it. It worked. Thanks!
  
  – Jiel
  Mar 26 at 2:37
  
  

  
  
  
  

 | 
show 3 more comments

Your Answer

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1

Your approach seems right, can you try (with namespace)

$className = 'App' . $tables[$index];
$class = new $className;

So something like this in your example:

 $tables = [
 'AppCaves_demographic_info', 
 'AppCaves_current_uses', 
 'AppCaves_flora_outside',
 ];

for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];

share|improve this answer

edited Mar 26 at 2:34

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  still not working.. second approach produces same error. first approach produces unexpected error
  
  – Jiel
  Mar 26 at 2:27
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you try it with namespace? I just tried in my code, with full namespace it should work
  
  – senty
  Mar 26 at 2:30
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  how would you parse the backslash in the string though?
  
  – Jiel
  Mar 26 at 2:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As it is works for me, did you get an error?
  
  – senty
  Mar 26 at 2:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I've got it. It worked. Thanks!
  
  – Jiel
  Mar 26 at 2:37
  
  

  
  
  
  

 | 
show 3 more comments

1

Your approach seems right, can you try (with namespace)

$className = 'App' . $tables[$index];
$class = new $className;

So something like this in your example:

 $tables = [
 'AppCaves_demographic_info', 
 'AppCaves_current_uses', 
 'AppCaves_flora_outside',
 ];

for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];

share|improve this answer

edited Mar 26 at 2:34

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  still not working.. second approach produces same error. first approach produces unexpected error
  
  – Jiel
  Mar 26 at 2:27
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you try it with namespace? I just tried in my code, with full namespace it should work
  
  – senty
  Mar 26 at 2:30
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  how would you parse the backslash in the string though?
  
  – Jiel
  Mar 26 at 2:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As it is works for me, did you get an error?
  
  – senty
  Mar 26 at 2:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I've got it. It worked. Thanks!
  
  – Jiel
  Mar 26 at 2:37
  
  

  
  
  
  

 | 
show 3 more comments

Your approach seems right, can you try (with namespace)

$className = 'App' . $tables[$index];
$class = new $className;

So something like this in your example:

 $tables = [
 'AppCaves_demographic_info', 
 'AppCaves_current_uses', 
 'AppCaves_flora_outside',
 ];

for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];

share|improve this answer

edited Mar 26 at 2:34

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges

$className = 'App' . $tables[$index];
$class = new $className;

 $tables = [
 'AppCaves_demographic_info', 
 'AppCaves_current_uses', 
 'AppCaves_flora_outside',
 ];

for($index = 0; $index < count($tables); $index++) 
 $$tables[$index]."_model" = new $tables[$index];

share|improve this answer

edited Mar 26 at 2:34

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges

answered Mar 26 at 2:25

sentysenty

4,27588 gold badges6060 silver badges142142 bronze badges