How to replace complementary SNP call to original reference/alternate SNP call?How do I replace NA values with zeros in an R dataframe?How do I remove duplicated SNPs using PLink?How to delete a row by reference in data.table?How to transform an SNP matrix in Tab-delimited format into numbers using python?How to map the segment boundaries to the closest position in reference file in RList of data.frame manipulation and combination generationFunction parameters - replace by referenceLD proxy in R - how to replace missing SNPs?How do I remove duplicated by position SNPs using PLink?how to remove error replacement has length zero in R

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How to replace complementary SNP call to original reference/alternate SNP call?


How do I replace NA values with zeros in an R dataframe?How do I remove duplicated SNPs using PLink?How to delete a row by reference in data.table?How to transform an SNP matrix in Tab-delimited format into numbers using python?How to map the segment boundaries to the closest position in reference file in RList of data.frame manipulation and combination generationFunction parameters - replace by referenceLD proxy in R - how to replace missing SNPs?How do I remove duplicated by position SNPs using PLink?how to remove error replacement has length zero in R






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2















I did sequencing on two genotypes and extracted the corresponding SNP chip SNPs to compare our genotypes to publicly available data on the exact same genotypes. I noticed that some SNPs must be of opposite strand polarity and need to be flipped. How can I use R to check if the sample calls match the reference or alternate SNP calls, and if they do not, to replace the sample calls with the complementary nucleotide?



I tried to incorporate ifelse and chartr, but I failed.



Example Data



test <- data.frame("pos" = 1:5, "ref" = c("A", "T", "C", "C","G"), "alt" = c("G","C", "A", "T", "A"), "sample" = c("A", "A", "C", "G", "G"))
View(test)

+---------+------+-------+----------+
| pos | ref | alt | sample1 |
+---------+------+-------+----------+
| 1 | A | G | A |
| 2 | T | C | A |
| 3 | C | A | C |
| 4 | C | T | G |
| 5 | G | A | G |
+---------+------+-------+----------+




Desired Output



+---------+------+-------+----------+
| pos | ref | alt | sample1 |
+---------+------+-------+----------+
| 1 | A | G | A |
| 2 | T | C | T |
| 3 | C | A | C |
| 4 | C | T | C |
| 5 | G | A | G |
+---------+------+-------+----------+









share|improve this question






























    2















    I did sequencing on two genotypes and extracted the corresponding SNP chip SNPs to compare our genotypes to publicly available data on the exact same genotypes. I noticed that some SNPs must be of opposite strand polarity and need to be flipped. How can I use R to check if the sample calls match the reference or alternate SNP calls, and if they do not, to replace the sample calls with the complementary nucleotide?



    I tried to incorporate ifelse and chartr, but I failed.



    Example Data



    test <- data.frame("pos" = 1:5, "ref" = c("A", "T", "C", "C","G"), "alt" = c("G","C", "A", "T", "A"), "sample" = c("A", "A", "C", "G", "G"))
    View(test)

    +---------+------+-------+----------+
    | pos | ref | alt | sample1 |
    +---------+------+-------+----------+
    | 1 | A | G | A |
    | 2 | T | C | A |
    | 3 | C | A | C |
    | 4 | C | T | G |
    | 5 | G | A | G |
    +---------+------+-------+----------+




    Desired Output



    +---------+------+-------+----------+
    | pos | ref | alt | sample1 |
    +---------+------+-------+----------+
    | 1 | A | G | A |
    | 2 | T | C | T |
    | 3 | C | A | C |
    | 4 | C | T | C |
    | 5 | G | A | G |
    +---------+------+-------+----------+









    share|improve this question


























      2












      2








      2








      I did sequencing on two genotypes and extracted the corresponding SNP chip SNPs to compare our genotypes to publicly available data on the exact same genotypes. I noticed that some SNPs must be of opposite strand polarity and need to be flipped. How can I use R to check if the sample calls match the reference or alternate SNP calls, and if they do not, to replace the sample calls with the complementary nucleotide?



      I tried to incorporate ifelse and chartr, but I failed.



      Example Data



      test <- data.frame("pos" = 1:5, "ref" = c("A", "T", "C", "C","G"), "alt" = c("G","C", "A", "T", "A"), "sample" = c("A", "A", "C", "G", "G"))
      View(test)

      +---------+------+-------+----------+
      | pos | ref | alt | sample1 |
      +---------+------+-------+----------+
      | 1 | A | G | A |
      | 2 | T | C | A |
      | 3 | C | A | C |
      | 4 | C | T | G |
      | 5 | G | A | G |
      +---------+------+-------+----------+




      Desired Output



      +---------+------+-------+----------+
      | pos | ref | alt | sample1 |
      +---------+------+-------+----------+
      | 1 | A | G | A |
      | 2 | T | C | T |
      | 3 | C | A | C |
      | 4 | C | T | C |
      | 5 | G | A | G |
      +---------+------+-------+----------+









      share|improve this question
















      I did sequencing on two genotypes and extracted the corresponding SNP chip SNPs to compare our genotypes to publicly available data on the exact same genotypes. I noticed that some SNPs must be of opposite strand polarity and need to be flipped. How can I use R to check if the sample calls match the reference or alternate SNP calls, and if they do not, to replace the sample calls with the complementary nucleotide?



      I tried to incorporate ifelse and chartr, but I failed.



      Example Data



      test <- data.frame("pos" = 1:5, "ref" = c("A", "T", "C", "C","G"), "alt" = c("G","C", "A", "T", "A"), "sample" = c("A", "A", "C", "G", "G"))
      View(test)

      +---------+------+-------+----------+
      | pos | ref | alt | sample1 |
      +---------+------+-------+----------+
      | 1 | A | G | A |
      | 2 | T | C | A |
      | 3 | C | A | C |
      | 4 | C | T | G |
      | 5 | G | A | G |
      +---------+------+-------+----------+




      Desired Output



      +---------+------+-------+----------+
      | pos | ref | alt | sample1 |
      +---------+------+-------+----------+
      | 1 | A | G | A |
      | 2 | T | C | T |
      | 3 | C | A | C |
      | 4 | C | T | C |
      | 5 | G | A | G |
      +---------+------+-------+----------+






      r bioinformatics






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 26 at 13:41









      Oka

      7782 silver badges9 bronze badges




      7782 silver badges9 bronze badges










      asked Mar 25 at 20:17









      sxdsxd

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      111 bronze badge






















          3 Answers
          3






          active

          oldest

          votes


















          0














          You can use the library dplyr to manipulate your dataset. With mutate() for instance, you can check if the sample call match the reference.
          Then, you can use ifelse() to make some changes.



          library(dplyr)


          test %>%
          mutate(TEST1 = (ref == sample)) %>%
          mutate(sample2 = ifelse(TEST1 == TRUE, ref, sample))

          # pos ref alt sample TEST1
          # 1 1 A G A TRUE
          # 2 2 T C A FALSE
          # 3 3 C A C TRUE
          # 4 4 C T G FALSE
          # 5 5 G A G TRUE





          share|improve this answer























          • Thank you! I am new to the ifelse/%>%.

            – sxd
            Mar 25 at 21:21











          • I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

            – sxd
            Mar 25 at 21:27







          • 1





            it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

            – demarsylvain
            Mar 25 at 21:33












          • test$TEST1 is already logical, no need to compare to TRUE.

            – zx8754
            Mar 26 at 7:19











          • you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

            – demarsylvain
            Mar 26 at 13:59


















          0














          Using ifelse and chartr:



          ifelse(test$sample == test$ref, test$sample, chartr("ATCG", "TAGC", test$sample))
          # [1] "A" "T" "C" "C" "G"





          share|improve this answer






























            0














            While you asked for solution in R, you still may want to consider other tools to flip strands especially if you need to do it on larger scale. You can do it with Plink and many other tools. Also I probably would seek to confirm the strand alignment in public data from their records/Method description. If only some of the SNPs in public datasets are/seems to be flipped, it is suspicious (one would expect that alignment would be uniform within the data from the same source).
            Also, if you use positional arguments, you should confirm the genome build/versions in your vs public data, because different versions can also be a source of confusion. Finally, I would probably also want to make sure that the SNPs in questions are not multiallelic, as it can also be a source of divergence..






            share|improve this answer

























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              3 Answers
              3






              active

              oldest

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              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0














              You can use the library dplyr to manipulate your dataset. With mutate() for instance, you can check if the sample call match the reference.
              Then, you can use ifelse() to make some changes.



              library(dplyr)


              test %>%
              mutate(TEST1 = (ref == sample)) %>%
              mutate(sample2 = ifelse(TEST1 == TRUE, ref, sample))

              # pos ref alt sample TEST1
              # 1 1 A G A TRUE
              # 2 2 T C A FALSE
              # 3 3 C A C TRUE
              # 4 4 C T G FALSE
              # 5 5 G A G TRUE





              share|improve this answer























              • Thank you! I am new to the ifelse/%>%.

                – sxd
                Mar 25 at 21:21











              • I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

                – sxd
                Mar 25 at 21:27







              • 1





                it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

                – demarsylvain
                Mar 25 at 21:33












              • test$TEST1 is already logical, no need to compare to TRUE.

                – zx8754
                Mar 26 at 7:19











              • you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

                – demarsylvain
                Mar 26 at 13:59















              0














              You can use the library dplyr to manipulate your dataset. With mutate() for instance, you can check if the sample call match the reference.
              Then, you can use ifelse() to make some changes.



              library(dplyr)


              test %>%
              mutate(TEST1 = (ref == sample)) %>%
              mutate(sample2 = ifelse(TEST1 == TRUE, ref, sample))

              # pos ref alt sample TEST1
              # 1 1 A G A TRUE
              # 2 2 T C A FALSE
              # 3 3 C A C TRUE
              # 4 4 C T G FALSE
              # 5 5 G A G TRUE





              share|improve this answer























              • Thank you! I am new to the ifelse/%>%.

                – sxd
                Mar 25 at 21:21











              • I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

                – sxd
                Mar 25 at 21:27







              • 1





                it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

                – demarsylvain
                Mar 25 at 21:33












              • test$TEST1 is already logical, no need to compare to TRUE.

                – zx8754
                Mar 26 at 7:19











              • you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

                – demarsylvain
                Mar 26 at 13:59













              0












              0








              0







              You can use the library dplyr to manipulate your dataset. With mutate() for instance, you can check if the sample call match the reference.
              Then, you can use ifelse() to make some changes.



              library(dplyr)


              test %>%
              mutate(TEST1 = (ref == sample)) %>%
              mutate(sample2 = ifelse(TEST1 == TRUE, ref, sample))

              # pos ref alt sample TEST1
              # 1 1 A G A TRUE
              # 2 2 T C A FALSE
              # 3 3 C A C TRUE
              # 4 4 C T G FALSE
              # 5 5 G A G TRUE





              share|improve this answer













              You can use the library dplyr to manipulate your dataset. With mutate() for instance, you can check if the sample call match the reference.
              Then, you can use ifelse() to make some changes.



              library(dplyr)


              test %>%
              mutate(TEST1 = (ref == sample)) %>%
              mutate(sample2 = ifelse(TEST1 == TRUE, ref, sample))

              # pos ref alt sample TEST1
              # 1 1 A G A TRUE
              # 2 2 T C A FALSE
              # 3 3 C A C TRUE
              # 4 4 C T G FALSE
              # 5 5 G A G TRUE






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Mar 25 at 20:32









              demarsylvaindemarsylvain

              1,4912 gold badges7 silver badges21 bronze badges




              1,4912 gold badges7 silver badges21 bronze badges












              • Thank you! I am new to the ifelse/%>%.

                – sxd
                Mar 25 at 21:21











              • I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

                – sxd
                Mar 25 at 21:27







              • 1





                it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

                – demarsylvain
                Mar 25 at 21:33












              • test$TEST1 is already logical, no need to compare to TRUE.

                – zx8754
                Mar 26 at 7:19











              • you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

                – demarsylvain
                Mar 26 at 13:59

















              • Thank you! I am new to the ifelse/%>%.

                – sxd
                Mar 25 at 21:21











              • I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

                – sxd
                Mar 25 at 21:27







              • 1





                it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

                – demarsylvain
                Mar 25 at 21:33












              • test$TEST1 is already logical, no need to compare to TRUE.

                – zx8754
                Mar 26 at 7:19











              • you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

                – demarsylvain
                Mar 26 at 13:59
















              Thank you! I am new to the ifelse/%>%.

              – sxd
              Mar 25 at 21:21





              Thank you! I am new to the ifelse/%>%.

              – sxd
              Mar 25 at 21:21













              I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

              – sxd
              Mar 25 at 21:27






              I was able to do i <- sapply(test, is.factor) test[i] <- lapply(test[i], as.character) to make it work with your recommendation. Going to create more rows using chartr to pull the right complementary nucleotides when using ifelse.

              – sxd
              Mar 25 at 21:27





              1




              1





              it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

              – demarsylvain
              Mar 25 at 21:33






              it is not necessary to use the pipe %>%. You can do test$sample2 = ifelse(test$TEST1 = TRUE, test$ref, test$sample) in order to create a new variable. The syntaxe is more elegant with dplyr.

              – demarsylvain
              Mar 25 at 21:33














              test$TEST1 is already logical, no need to compare to TRUE.

              – zx8754
              Mar 26 at 7:19





              test$TEST1 is already logical, no need to compare to TRUE.

              – zx8754
              Mar 26 at 7:19













              you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

              – demarsylvain
              Mar 26 at 13:59





              you're right. It's just to add more clarity, the code is easier to understand when the condition is fully "visible".

              – demarsylvain
              Mar 26 at 13:59













              0














              Using ifelse and chartr:



              ifelse(test$sample == test$ref, test$sample, chartr("ATCG", "TAGC", test$sample))
              # [1] "A" "T" "C" "C" "G"





              share|improve this answer



























                0














                Using ifelse and chartr:



                ifelse(test$sample == test$ref, test$sample, chartr("ATCG", "TAGC", test$sample))
                # [1] "A" "T" "C" "C" "G"





                share|improve this answer

























                  0












                  0








                  0







                  Using ifelse and chartr:



                  ifelse(test$sample == test$ref, test$sample, chartr("ATCG", "TAGC", test$sample))
                  # [1] "A" "T" "C" "C" "G"





                  share|improve this answer













                  Using ifelse and chartr:



                  ifelse(test$sample == test$ref, test$sample, chartr("ATCG", "TAGC", test$sample))
                  # [1] "A" "T" "C" "C" "G"






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 26 at 7:18









                  zx8754zx8754

                  32k7 gold badges70 silver badges109 bronze badges




                  32k7 gold badges70 silver badges109 bronze badges





















                      0














                      While you asked for solution in R, you still may want to consider other tools to flip strands especially if you need to do it on larger scale. You can do it with Plink and many other tools. Also I probably would seek to confirm the strand alignment in public data from their records/Method description. If only some of the SNPs in public datasets are/seems to be flipped, it is suspicious (one would expect that alignment would be uniform within the data from the same source).
                      Also, if you use positional arguments, you should confirm the genome build/versions in your vs public data, because different versions can also be a source of confusion. Finally, I would probably also want to make sure that the SNPs in questions are not multiallelic, as it can also be a source of divergence..






                      share|improve this answer



























                        0














                        While you asked for solution in R, you still may want to consider other tools to flip strands especially if you need to do it on larger scale. You can do it with Plink and many other tools. Also I probably would seek to confirm the strand alignment in public data from their records/Method description. If only some of the SNPs in public datasets are/seems to be flipped, it is suspicious (one would expect that alignment would be uniform within the data from the same source).
                        Also, if you use positional arguments, you should confirm the genome build/versions in your vs public data, because different versions can also be a source of confusion. Finally, I would probably also want to make sure that the SNPs in questions are not multiallelic, as it can also be a source of divergence..






                        share|improve this answer

























                          0












                          0








                          0







                          While you asked for solution in R, you still may want to consider other tools to flip strands especially if you need to do it on larger scale. You can do it with Plink and many other tools. Also I probably would seek to confirm the strand alignment in public data from their records/Method description. If only some of the SNPs in public datasets are/seems to be flipped, it is suspicious (one would expect that alignment would be uniform within the data from the same source).
                          Also, if you use positional arguments, you should confirm the genome build/versions in your vs public data, because different versions can also be a source of confusion. Finally, I would probably also want to make sure that the SNPs in questions are not multiallelic, as it can also be a source of divergence..






                          share|improve this answer













                          While you asked for solution in R, you still may want to consider other tools to flip strands especially if you need to do it on larger scale. You can do it with Plink and many other tools. Also I probably would seek to confirm the strand alignment in public data from their records/Method description. If only some of the SNPs in public datasets are/seems to be flipped, it is suspicious (one would expect that alignment would be uniform within the data from the same source).
                          Also, if you use positional arguments, you should confirm the genome build/versions in your vs public data, because different versions can also be a source of confusion. Finally, I would probably also want to make sure that the SNPs in questions are not multiallelic, as it can also be a source of divergence..







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Mar 26 at 13:28









                          OkaOka

                          7782 silver badges9 bronze badges




                          7782 silver badges9 bronze badges



























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