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Iterating through lists with periodic boundary condition and computing distances between elements


How to iterate through two lists in parallel?Iterating over every two elements in a listProcessing a very very big data set in python - memory errorHistogram for data with periodic boundary conditionsnp.ndarray with Periodic Boundary conditionsEfficiently select random matrix indices with given probabilitiesEfficiently get permutation of 3 numpy arrays of differing sizes and typesDistance computation between (M,N) and (N,) arrayswindowed selection from a list in python






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I am trying to write a python function that takes an index of a list as an input n1, then in an interval of size w, selects [n1-w,n1+w] selects another index n2 with probability that decays as a function of the separation between n1 and n2 and returns the index n2 and the element of the list corresponding to n2.



In my current implementation ("Attempt 1"), first I compute all the probabilities using, then select an index with the weights.



This works fine (I think) given a list [0,1,2,3,4,5,6,7,8,9]
and if my n1 is somewhere in the middle say 5 and w=2, then an element is being chosen from the interval
[3 4 5 6 7]
with probability weights [0.16666667 0.33333333 0. 0.33333333 0.16666667].



The problem I am dealing with is if I am selecting an element from the ends, for example, choosing n2choice(8) gives



[6 7 8 9]#indices interval
[0.2 0.4 0. 0.4]#weights



Instead I would like an interval



[6 7 8 9 0]# indices interval
[0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



Or similarly, at the other end, n2choice(1) gives [0 1 2 3]#interval
[0.2 0.4 0. 0.4]#weights



Instead I would like to get



[9 0 1 2 3]# indices interval
[0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



Essentially, I would like to convert the current "absorbing" boundary conditions I have implemented to "periodic boundaries" wherein the 1D list is in fact treated as a 1D ring.



To do so i used i tried using the % operator (see attempt 2). However this throws an "IndexError: list index out of range". I could use some help troubleshooting this code, and also suggestion on a fast, pythonic way to do this. I would like to be able to do this for arrays of arbitrary length, and with arbitrary w, instead of this simple test case presented here.



#Attempt 1
import numpy as np
import random
a = [0,1,2,3,4,5,6,7,8,9]
w =2
mylist = np.array(a)
indices_list = np.arange(mylist.size)
def n2choice(n1):
prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[max(n1-w,0):n1+w+1].size)]
prob_wts = np.array(prob_wts)/sum(prob_wts)
#for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
#print(i, i+(n1-w))

print(prob_wts)
print(sum(prob_wts))
print(indices_list[max(n1-w,0):n1+w+1])
n2 = random.choices(indices_list[max(n1-w,0):n1+w+1], weights=prob_wts,k=1)
print(prob_wts[max(n1-w,0):n1+w+1])
n2_c = (n2[0], mylist[n2[0]])
return np.array(n2_c)
n2choice(5)


#Attempt 2
import numpy as np
import random
import itertools
a = [0,1,2,3,4,5,6,7,8,9]
w =2
mylist = np.array(a)
indices_list = np.arange(mylist.size)
def n2choice(n1):
prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)].size)]
prob_wts = np.array(prob_wts)/sum(prob_wts)
#for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
#print(i, i+(n1-w))

print(prob_wts)
print(sum(prob_wts))
print(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)])
n2 = random.choices(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)], weights=prob_wts,k=1)
#print(prob_wts[max(n1-w,0):n1+w+1])
n2_c = (n2[0], mylist[n2[0]])
return np.array(n2_c)
n2choice(1)









share|improve this question




























    0















    I am trying to write a python function that takes an index of a list as an input n1, then in an interval of size w, selects [n1-w,n1+w] selects another index n2 with probability that decays as a function of the separation between n1 and n2 and returns the index n2 and the element of the list corresponding to n2.



    In my current implementation ("Attempt 1"), first I compute all the probabilities using, then select an index with the weights.



    This works fine (I think) given a list [0,1,2,3,4,5,6,7,8,9]
    and if my n1 is somewhere in the middle say 5 and w=2, then an element is being chosen from the interval
    [3 4 5 6 7]
    with probability weights [0.16666667 0.33333333 0. 0.33333333 0.16666667].



    The problem I am dealing with is if I am selecting an element from the ends, for example, choosing n2choice(8) gives



    [6 7 8 9]#indices interval
    [0.2 0.4 0. 0.4]#weights



    Instead I would like an interval



    [6 7 8 9 0]# indices interval
    [0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



    Or similarly, at the other end, n2choice(1) gives [0 1 2 3]#interval
    [0.2 0.4 0. 0.4]#weights



    Instead I would like to get



    [9 0 1 2 3]# indices interval
    [0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



    Essentially, I would like to convert the current "absorbing" boundary conditions I have implemented to "periodic boundaries" wherein the 1D list is in fact treated as a 1D ring.



    To do so i used i tried using the % operator (see attempt 2). However this throws an "IndexError: list index out of range". I could use some help troubleshooting this code, and also suggestion on a fast, pythonic way to do this. I would like to be able to do this for arrays of arbitrary length, and with arbitrary w, instead of this simple test case presented here.



    #Attempt 1
    import numpy as np
    import random
    a = [0,1,2,3,4,5,6,7,8,9]
    w =2
    mylist = np.array(a)
    indices_list = np.arange(mylist.size)
    def n2choice(n1):
    prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[max(n1-w,0):n1+w+1].size)]
    prob_wts = np.array(prob_wts)/sum(prob_wts)
    #for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
    #print(i, i+(n1-w))

    print(prob_wts)
    print(sum(prob_wts))
    print(indices_list[max(n1-w,0):n1+w+1])
    n2 = random.choices(indices_list[max(n1-w,0):n1+w+1], weights=prob_wts,k=1)
    print(prob_wts[max(n1-w,0):n1+w+1])
    n2_c = (n2[0], mylist[n2[0]])
    return np.array(n2_c)
    n2choice(5)


    #Attempt 2
    import numpy as np
    import random
    import itertools
    a = [0,1,2,3,4,5,6,7,8,9]
    w =2
    mylist = np.array(a)
    indices_list = np.arange(mylist.size)
    def n2choice(n1):
    prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)].size)]
    prob_wts = np.array(prob_wts)/sum(prob_wts)
    #for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
    #print(i, i+(n1-w))

    print(prob_wts)
    print(sum(prob_wts))
    print(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)])
    n2 = random.choices(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)], weights=prob_wts,k=1)
    #print(prob_wts[max(n1-w,0):n1+w+1])
    n2_c = (n2[0], mylist[n2[0]])
    return np.array(n2_c)
    n2choice(1)









    share|improve this question
























      0












      0








      0


      0






      I am trying to write a python function that takes an index of a list as an input n1, then in an interval of size w, selects [n1-w,n1+w] selects another index n2 with probability that decays as a function of the separation between n1 and n2 and returns the index n2 and the element of the list corresponding to n2.



      In my current implementation ("Attempt 1"), first I compute all the probabilities using, then select an index with the weights.



      This works fine (I think) given a list [0,1,2,3,4,5,6,7,8,9]
      and if my n1 is somewhere in the middle say 5 and w=2, then an element is being chosen from the interval
      [3 4 5 6 7]
      with probability weights [0.16666667 0.33333333 0. 0.33333333 0.16666667].



      The problem I am dealing with is if I am selecting an element from the ends, for example, choosing n2choice(8) gives



      [6 7 8 9]#indices interval
      [0.2 0.4 0. 0.4]#weights



      Instead I would like an interval



      [6 7 8 9 0]# indices interval
      [0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



      Or similarly, at the other end, n2choice(1) gives [0 1 2 3]#interval
      [0.2 0.4 0. 0.4]#weights



      Instead I would like to get



      [9 0 1 2 3]# indices interval
      [0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



      Essentially, I would like to convert the current "absorbing" boundary conditions I have implemented to "periodic boundaries" wherein the 1D list is in fact treated as a 1D ring.



      To do so i used i tried using the % operator (see attempt 2). However this throws an "IndexError: list index out of range". I could use some help troubleshooting this code, and also suggestion on a fast, pythonic way to do this. I would like to be able to do this for arrays of arbitrary length, and with arbitrary w, instead of this simple test case presented here.



      #Attempt 1
      import numpy as np
      import random
      a = [0,1,2,3,4,5,6,7,8,9]
      w =2
      mylist = np.array(a)
      indices_list = np.arange(mylist.size)
      def n2choice(n1):
      prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[max(n1-w,0):n1+w+1].size)]
      prob_wts = np.array(prob_wts)/sum(prob_wts)
      #for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
      #print(i, i+(n1-w))

      print(prob_wts)
      print(sum(prob_wts))
      print(indices_list[max(n1-w,0):n1+w+1])
      n2 = random.choices(indices_list[max(n1-w,0):n1+w+1], weights=prob_wts,k=1)
      print(prob_wts[max(n1-w,0):n1+w+1])
      n2_c = (n2[0], mylist[n2[0]])
      return np.array(n2_c)
      n2choice(5)


      #Attempt 2
      import numpy as np
      import random
      import itertools
      a = [0,1,2,3,4,5,6,7,8,9]
      w =2
      mylist = np.array(a)
      indices_list = np.arange(mylist.size)
      def n2choice(n1):
      prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)].size)]
      prob_wts = np.array(prob_wts)/sum(prob_wts)
      #for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
      #print(i, i+(n1-w))

      print(prob_wts)
      print(sum(prob_wts))
      print(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)])
      n2 = random.choices(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)], weights=prob_wts,k=1)
      #print(prob_wts[max(n1-w,0):n1+w+1])
      n2_c = (n2[0], mylist[n2[0]])
      return np.array(n2_c)
      n2choice(1)









      share|improve this question














      I am trying to write a python function that takes an index of a list as an input n1, then in an interval of size w, selects [n1-w,n1+w] selects another index n2 with probability that decays as a function of the separation between n1 and n2 and returns the index n2 and the element of the list corresponding to n2.



      In my current implementation ("Attempt 1"), first I compute all the probabilities using, then select an index with the weights.



      This works fine (I think) given a list [0,1,2,3,4,5,6,7,8,9]
      and if my n1 is somewhere in the middle say 5 and w=2, then an element is being chosen from the interval
      [3 4 5 6 7]
      with probability weights [0.16666667 0.33333333 0. 0.33333333 0.16666667].



      The problem I am dealing with is if I am selecting an element from the ends, for example, choosing n2choice(8) gives



      [6 7 8 9]#indices interval
      [0.2 0.4 0. 0.4]#weights



      Instead I would like an interval



      [6 7 8 9 0]# indices interval
      [0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



      Or similarly, at the other end, n2choice(1) gives [0 1 2 3]#interval
      [0.2 0.4 0. 0.4]#weights



      Instead I would like to get



      [9 0 1 2 3]# indices interval
      [0.16666667 0.33333333 0. 0.33333333 0.16666667]#weights



      Essentially, I would like to convert the current "absorbing" boundary conditions I have implemented to "periodic boundaries" wherein the 1D list is in fact treated as a 1D ring.



      To do so i used i tried using the % operator (see attempt 2). However this throws an "IndexError: list index out of range". I could use some help troubleshooting this code, and also suggestion on a fast, pythonic way to do this. I would like to be able to do this for arrays of arbitrary length, and with arbitrary w, instead of this simple test case presented here.



      #Attempt 1
      import numpy as np
      import random
      a = [0,1,2,3,4,5,6,7,8,9]
      w =2
      mylist = np.array(a)
      indices_list = np.arange(mylist.size)
      def n2choice(n1):
      prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[max(n1-w,0):n1+w+1].size)]
      prob_wts = np.array(prob_wts)/sum(prob_wts)
      #for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
      #print(i, i+(n1-w))

      print(prob_wts)
      print(sum(prob_wts))
      print(indices_list[max(n1-w,0):n1+w+1])
      n2 = random.choices(indices_list[max(n1-w,0):n1+w+1], weights=prob_wts,k=1)
      print(prob_wts[max(n1-w,0):n1+w+1])
      n2_c = (n2[0], mylist[n2[0]])
      return np.array(n2_c)
      n2choice(5)


      #Attempt 2
      import numpy as np
      import random
      import itertools
      a = [0,1,2,3,4,5,6,7,8,9]
      w =2
      mylist = np.array(a)
      indices_list = np.arange(mylist.size)
      def n2choice(n1):
      prob_wts = [0 if i+(n1-w) == n1 else 1/(abs(i+(n1-w)-n1))**(1.) for i in np.arange(mylist[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)].size)]
      prob_wts = np.array(prob_wts)/sum(prob_wts)
      #for i in np.arange(mylist[max(n1-w,0):n1+w+1].size):
      #print(i, i+(n1-w))

      print(prob_wts)
      print(sum(prob_wts))
      print(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)])
      n2 = random.choices(indices_list[(n1 - w)%len(mylist):(n1+w+1)%len(mylist)], weights=prob_wts,k=1)
      #print(prob_wts[max(n1-w,0):n1+w+1])
      n2_c = (n2[0], mylist[n2[0]])
      return np.array(n2_c)
      n2choice(1)






      python python-3.x numpy






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