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Java stop variable from getting updated of a class


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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








-2















I am facing a problem as my class variable gets automatically updated with the latest value. But I want separate value for each of the object.



public class B 

public String state;

public B()
this.state = "new";


public void firstMethod()

this.state = "first";



public void secondMethod()

this.state = "second";





public abstract class C

public B b;

public C(B service)
this.b = service;


public abstract void execute();



public static void main(String[] args)
B b = new B();
C c = new C(b)
@Override
public void execute()
b.firstMethod();


;

C c1 = new C(b)
@Override
public void execute()
b.secondMethod();


;

c.execute();
c1.execute();
System.out.println(c.b.state);

System.out.println(c1.b.state);



I am getting c and c1 both state equal to "second". I know if I create two separate B object i.e. b1 and b2 and pass those in c and c1 while initializing then it would give me different result as I am expecting. But is there any way to get c.state as "first" and c1.state as "second" with passing the same object to both c and c1?










share|improve this question
























  • But probably it's a duplicate of this: stackoverflow.com/questions/55175471/…

    – markspace
    Mar 25 at 21:28











  • where are you calling execute() on your objects?

    – MFisherKDX
    Mar 25 at 21:28






  • 2





    Think what you are asking: "I have 3 people. I give person C the home address of person B, and I give person C1 the home address of person B. I then tell person C to go to the home address they have and paint the person living there red. I then tell person C1 to go to the home address they have and paint the person living there blue. After that I check what color person B is, and they are always painted blue. Can I somehow make that person B is both a red painted person and a blue painted person?" No, no you cannot.

    – Max Vollmer
    Mar 25 at 22:02











  • I agree. Suppose, I need to inject C and C1 to an array list. Then, is there any way to see the difference between the associated state of C and C1? May be adding some properties in any one of the class or variables that will allow me to store the associated state value with C and C1?

    – faysal
    Mar 25 at 22:19

















-2















I am facing a problem as my class variable gets automatically updated with the latest value. But I want separate value for each of the object.



public class B 

public String state;

public B()
this.state = "new";


public void firstMethod()

this.state = "first";



public void secondMethod()

this.state = "second";





public abstract class C

public B b;

public C(B service)
this.b = service;


public abstract void execute();



public static void main(String[] args)
B b = new B();
C c = new C(b)
@Override
public void execute()
b.firstMethod();


;

C c1 = new C(b)
@Override
public void execute()
b.secondMethod();


;

c.execute();
c1.execute();
System.out.println(c.b.state);

System.out.println(c1.b.state);



I am getting c and c1 both state equal to "second". I know if I create two separate B object i.e. b1 and b2 and pass those in c and c1 while initializing then it would give me different result as I am expecting. But is there any way to get c.state as "first" and c1.state as "second" with passing the same object to both c and c1?










share|improve this question
























  • But probably it's a duplicate of this: stackoverflow.com/questions/55175471/…

    – markspace
    Mar 25 at 21:28











  • where are you calling execute() on your objects?

    – MFisherKDX
    Mar 25 at 21:28






  • 2





    Think what you are asking: "I have 3 people. I give person C the home address of person B, and I give person C1 the home address of person B. I then tell person C to go to the home address they have and paint the person living there red. I then tell person C1 to go to the home address they have and paint the person living there blue. After that I check what color person B is, and they are always painted blue. Can I somehow make that person B is both a red painted person and a blue painted person?" No, no you cannot.

    – Max Vollmer
    Mar 25 at 22:02











  • I agree. Suppose, I need to inject C and C1 to an array list. Then, is there any way to see the difference between the associated state of C and C1? May be adding some properties in any one of the class or variables that will allow me to store the associated state value with C and C1?

    – faysal
    Mar 25 at 22:19













-2












-2








-2








I am facing a problem as my class variable gets automatically updated with the latest value. But I want separate value for each of the object.



public class B 

public String state;

public B()
this.state = "new";


public void firstMethod()

this.state = "first";



public void secondMethod()

this.state = "second";





public abstract class C

public B b;

public C(B service)
this.b = service;


public abstract void execute();



public static void main(String[] args)
B b = new B();
C c = new C(b)
@Override
public void execute()
b.firstMethod();


;

C c1 = new C(b)
@Override
public void execute()
b.secondMethod();


;

c.execute();
c1.execute();
System.out.println(c.b.state);

System.out.println(c1.b.state);



I am getting c and c1 both state equal to "second". I know if I create two separate B object i.e. b1 and b2 and pass those in c and c1 while initializing then it would give me different result as I am expecting. But is there any way to get c.state as "first" and c1.state as "second" with passing the same object to both c and c1?










share|improve this question
















I am facing a problem as my class variable gets automatically updated with the latest value. But I want separate value for each of the object.



public class B 

public String state;

public B()
this.state = "new";


public void firstMethod()

this.state = "first";



public void secondMethod()

this.state = "second";





public abstract class C

public B b;

public C(B service)
this.b = service;


public abstract void execute();



public static void main(String[] args)
B b = new B();
C c = new C(b)
@Override
public void execute()
b.firstMethod();


;

C c1 = new C(b)
@Override
public void execute()
b.secondMethod();


;

c.execute();
c1.execute();
System.out.println(c.b.state);

System.out.println(c1.b.state);



I am getting c and c1 both state equal to "second". I know if I create two separate B object i.e. b1 and b2 and pass those in c and c1 while initializing then it would give me different result as I am expecting. But is there any way to get c.state as "first" and c1.state as "second" with passing the same object to both c and c1?







java class oop






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 25 at 21:51







faysal

















asked Mar 25 at 21:26









faysalfaysal

751 silver badge11 bronze badges




751 silver badge11 bronze badges












  • But probably it's a duplicate of this: stackoverflow.com/questions/55175471/…

    – markspace
    Mar 25 at 21:28











  • where are you calling execute() on your objects?

    – MFisherKDX
    Mar 25 at 21:28






  • 2





    Think what you are asking: "I have 3 people. I give person C the home address of person B, and I give person C1 the home address of person B. I then tell person C to go to the home address they have and paint the person living there red. I then tell person C1 to go to the home address they have and paint the person living there blue. After that I check what color person B is, and they are always painted blue. Can I somehow make that person B is both a red painted person and a blue painted person?" No, no you cannot.

    – Max Vollmer
    Mar 25 at 22:02











  • I agree. Suppose, I need to inject C and C1 to an array list. Then, is there any way to see the difference between the associated state of C and C1? May be adding some properties in any one of the class or variables that will allow me to store the associated state value with C and C1?

    – faysal
    Mar 25 at 22:19

















  • But probably it's a duplicate of this: stackoverflow.com/questions/55175471/…

    – markspace
    Mar 25 at 21:28











  • where are you calling execute() on your objects?

    – MFisherKDX
    Mar 25 at 21:28






  • 2





    Think what you are asking: "I have 3 people. I give person C the home address of person B, and I give person C1 the home address of person B. I then tell person C to go to the home address they have and paint the person living there red. I then tell person C1 to go to the home address they have and paint the person living there blue. After that I check what color person B is, and they are always painted blue. Can I somehow make that person B is both a red painted person and a blue painted person?" No, no you cannot.

    – Max Vollmer
    Mar 25 at 22:02











  • I agree. Suppose, I need to inject C and C1 to an array list. Then, is there any way to see the difference between the associated state of C and C1? May be adding some properties in any one of the class or variables that will allow me to store the associated state value with C and C1?

    – faysal
    Mar 25 at 22:19
















But probably it's a duplicate of this: stackoverflow.com/questions/55175471/…

– markspace
Mar 25 at 21:28





But probably it's a duplicate of this: stackoverflow.com/questions/55175471/…

– markspace
Mar 25 at 21:28













where are you calling execute() on your objects?

– MFisherKDX
Mar 25 at 21:28





where are you calling execute() on your objects?

– MFisherKDX
Mar 25 at 21:28




2




2





Think what you are asking: "I have 3 people. I give person C the home address of person B, and I give person C1 the home address of person B. I then tell person C to go to the home address they have and paint the person living there red. I then tell person C1 to go to the home address they have and paint the person living there blue. After that I check what color person B is, and they are always painted blue. Can I somehow make that person B is both a red painted person and a blue painted person?" No, no you cannot.

– Max Vollmer
Mar 25 at 22:02





Think what you are asking: "I have 3 people. I give person C the home address of person B, and I give person C1 the home address of person B. I then tell person C to go to the home address they have and paint the person living there red. I then tell person C1 to go to the home address they have and paint the person living there blue. After that I check what color person B is, and they are always painted blue. Can I somehow make that person B is both a red painted person and a blue painted person?" No, no you cannot.

– Max Vollmer
Mar 25 at 22:02













I agree. Suppose, I need to inject C and C1 to an array list. Then, is there any way to see the difference between the associated state of C and C1? May be adding some properties in any one of the class or variables that will allow me to store the associated state value with C and C1?

– faysal
Mar 25 at 22:19





I agree. Suppose, I need to inject C and C1 to an array list. Then, is there any way to see the difference between the associated state of C and C1? May be adding some properties in any one of the class or variables that will allow me to store the associated state value with C and C1?

– faysal
Mar 25 at 22:19












2 Answers
2






active

oldest

votes


















0














Your c and c1 share the exact same B object, namely b.



Since the state we are discussing belongs to b, there is only one of them - called b.state.



If you want state to be different, you cannot use the same B object with both C objects.



This likely boils down to a misunderstanding of the reference semantics of assignment and parameter passing. Neither assignment nor parameter-passing makes a copy of an object.




But is there any way to get c.state as "first" and c1.state as
"second" with passing the same object to both c and c1?




This could not possibly work. Suppose a single B object could somehow have any number of values of state. Whenever you wrote b.state, how would the system know which one you meant?



Well, that's not entirely true as I wrote it. If the constructor of C only used its B object to make an entirely new copy, such that it kept the copy rather than the original, then you'd achieve the effect; there would be three B objects in the world, the original, the copy made by c, and the copy made by c1. But that has no advantage here over just passing in separate B instances to begin with.






share|improve this answer

























  • Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

    – faysal
    Mar 25 at 22:08











  • "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

    – another-dave
    Mar 25 at 22:10











  • Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

    – faysal
    Mar 25 at 22:16











  • I have solved the problem by cloning the object.

    – faysal
    Mar 25 at 22:53


















0














You used the same instance of B class into your 2 objects, so your state variable will always get updated by the last called method, you need to use another instance of B to have two separated state property.






share|improve this answer

























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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Your c and c1 share the exact same B object, namely b.



    Since the state we are discussing belongs to b, there is only one of them - called b.state.



    If you want state to be different, you cannot use the same B object with both C objects.



    This likely boils down to a misunderstanding of the reference semantics of assignment and parameter passing. Neither assignment nor parameter-passing makes a copy of an object.




    But is there any way to get c.state as "first" and c1.state as
    "second" with passing the same object to both c and c1?




    This could not possibly work. Suppose a single B object could somehow have any number of values of state. Whenever you wrote b.state, how would the system know which one you meant?



    Well, that's not entirely true as I wrote it. If the constructor of C only used its B object to make an entirely new copy, such that it kept the copy rather than the original, then you'd achieve the effect; there would be three B objects in the world, the original, the copy made by c, and the copy made by c1. But that has no advantage here over just passing in separate B instances to begin with.






    share|improve this answer

























    • Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

      – faysal
      Mar 25 at 22:08











    • "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

      – another-dave
      Mar 25 at 22:10











    • Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

      – faysal
      Mar 25 at 22:16











    • I have solved the problem by cloning the object.

      – faysal
      Mar 25 at 22:53















    0














    Your c and c1 share the exact same B object, namely b.



    Since the state we are discussing belongs to b, there is only one of them - called b.state.



    If you want state to be different, you cannot use the same B object with both C objects.



    This likely boils down to a misunderstanding of the reference semantics of assignment and parameter passing. Neither assignment nor parameter-passing makes a copy of an object.




    But is there any way to get c.state as "first" and c1.state as
    "second" with passing the same object to both c and c1?




    This could not possibly work. Suppose a single B object could somehow have any number of values of state. Whenever you wrote b.state, how would the system know which one you meant?



    Well, that's not entirely true as I wrote it. If the constructor of C only used its B object to make an entirely new copy, such that it kept the copy rather than the original, then you'd achieve the effect; there would be three B objects in the world, the original, the copy made by c, and the copy made by c1. But that has no advantage here over just passing in separate B instances to begin with.






    share|improve this answer

























    • Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

      – faysal
      Mar 25 at 22:08











    • "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

      – another-dave
      Mar 25 at 22:10











    • Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

      – faysal
      Mar 25 at 22:16











    • I have solved the problem by cloning the object.

      – faysal
      Mar 25 at 22:53













    0












    0








    0







    Your c and c1 share the exact same B object, namely b.



    Since the state we are discussing belongs to b, there is only one of them - called b.state.



    If you want state to be different, you cannot use the same B object with both C objects.



    This likely boils down to a misunderstanding of the reference semantics of assignment and parameter passing. Neither assignment nor parameter-passing makes a copy of an object.




    But is there any way to get c.state as "first" and c1.state as
    "second" with passing the same object to both c and c1?




    This could not possibly work. Suppose a single B object could somehow have any number of values of state. Whenever you wrote b.state, how would the system know which one you meant?



    Well, that's not entirely true as I wrote it. If the constructor of C only used its B object to make an entirely new copy, such that it kept the copy rather than the original, then you'd achieve the effect; there would be three B objects in the world, the original, the copy made by c, and the copy made by c1. But that has no advantage here over just passing in separate B instances to begin with.






    share|improve this answer















    Your c and c1 share the exact same B object, namely b.



    Since the state we are discussing belongs to b, there is only one of them - called b.state.



    If you want state to be different, you cannot use the same B object with both C objects.



    This likely boils down to a misunderstanding of the reference semantics of assignment and parameter passing. Neither assignment nor parameter-passing makes a copy of an object.




    But is there any way to get c.state as "first" and c1.state as
    "second" with passing the same object to both c and c1?




    This could not possibly work. Suppose a single B object could somehow have any number of values of state. Whenever you wrote b.state, how would the system know which one you meant?



    Well, that's not entirely true as I wrote it. If the constructor of C only used its B object to make an entirely new copy, such that it kept the copy rather than the original, then you'd achieve the effect; there would be three B objects in the world, the original, the copy made by c, and the copy made by c1. But that has no advantage here over just passing in separate B instances to begin with.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 25 at 22:07

























    answered Mar 25 at 21:59









    another-daveanother-dave

    1,6632 silver badges10 bronze badges




    1,6632 silver badges10 bronze badges












    • Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

      – faysal
      Mar 25 at 22:08











    • "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

      – another-dave
      Mar 25 at 22:10











    • Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

      – faysal
      Mar 25 at 22:16











    • I have solved the problem by cloning the object.

      – faysal
      Mar 25 at 22:53

















    • Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

      – faysal
      Mar 25 at 22:08











    • "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

      – another-dave
      Mar 25 at 22:10











    • Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

      – faysal
      Mar 25 at 22:16











    • I have solved the problem by cloning the object.

      – faysal
      Mar 25 at 22:53
















    Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

    – faysal
    Mar 25 at 22:08





    Yes I got your point. Actually I was thinking whether it will be a good idea to create a new object or there is another way of dealing this situation. So I think I need to create two separte b object when create c and c1.

    – faysal
    Mar 25 at 22:08













    "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

    – another-dave
    Mar 25 at 22:10





    "separate B" seems the simple approach, unless this is just an illustration of some actual situation that would make it more complicated.

    – another-dave
    Mar 25 at 22:10













    Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

    – faysal
    Mar 25 at 22:16





    Actually in my context, I am highly restricted to create a separate B. Can you tell me if there is another class A. And B extends A. in that case, how would I tackle this problem with copy constrcutor or may adopt any other approach?

    – faysal
    Mar 25 at 22:16













    I have solved the problem by cloning the object.

    – faysal
    Mar 25 at 22:53





    I have solved the problem by cloning the object.

    – faysal
    Mar 25 at 22:53













    0














    You used the same instance of B class into your 2 objects, so your state variable will always get updated by the last called method, you need to use another instance of B to have two separated state property.






    share|improve this answer



























      0














      You used the same instance of B class into your 2 objects, so your state variable will always get updated by the last called method, you need to use another instance of B to have two separated state property.






      share|improve this answer

























        0












        0








        0







        You used the same instance of B class into your 2 objects, so your state variable will always get updated by the last called method, you need to use another instance of B to have two separated state property.






        share|improve this answer













        You used the same instance of B class into your 2 objects, so your state variable will always get updated by the last called method, you need to use another instance of B to have two separated state property.







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        answered Mar 25 at 22:07









        AYOUB_MAAYOUB_MA

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