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MySQL: UNION plus JOIN


What is the difference between “INNER JOIN” and “OUTER JOIN”?What is the difference between UNION and UNION ALL?Should I use the datetime or timestamp data type in MySQL?Python join: why is it string.join(list) instead of list.join(string)?Difference between JOIN and INNER JOININNER JOIN ON vs WHERE clauseWhat's the difference between INNER JOIN, LEFT JOIN, RIGHT JOIN and FULL JOIN?MySQL Limit LEFT JOIN Subquery after joiningmysql relation slowHow to optimize a select query with multiple left joins in a large database






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I'm trying to figure out how to use UNION with the same JOIN and not to fall into #2014 - Commands out of sync.



I have created four simple tables and wrote simplified code for them. The main idea is to get each sword, gun and hat which have 'best' in name + if the owner of these is cool.



SELECT pirate_id, sword, null AS gun, null AS hat, legs = 1 AS is_cool FROM swords as t1
LEFT JOIN
(SELECT legs, pirate_id as pid FROM body_parts) AS t2
ON t1.pirate_id = t2.pid
WHERE sword LIKE '%best%'

UNION
SELECT pirate_id, null AS sword, gun, null AS hat, legs = 1 AS is_cool FROM guns as t3
LEFT JOIN
(SELECT legs, pirate_id as pid FROM body_parts) AS t4
ON t3.pirate_id = t4.pid
WHERE gun LIKE '%best%'

UNION
SELECT pirate_id, null AS sword, null AS gun, hat, legs = 1 AS is_cool FROM hats as t5
LEFT JOIN
(SELECT legs, pirate_id as pid FROM body_parts) AS t6
ON t5.pirate_id = t6.pid
WHERE hat LIKE '%best%'

ORDER BY is_cool DESC, pirate_id ASC


Currently I have to repeat JOIN each time I have to UNION. I hope there is a better way...



TABLES CREATION:



CREATE TABLE IF NOT EXISTS `body_parts` (
`pirate_id` int(11) NOT NULL,
`legs` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `body_parts` (`pirate_id`, `legs`) VALUES
(1, 0),
(2, 1),
(3, 2);

CREATE TABLE IF NOT EXISTS `guns` (
`pirate_id` int(11) NOT NULL,
`gun` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `guns` (`pirate_id`, `gun`) VALUES
(1, 'best 1');

CREATE TABLE IF NOT EXISTS `hats` (
`pirate_id` int(11) NOT NULL,
`hat` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `hats` (`pirate_id`, `hat`) VALUES
(2, 'best 2');

CREATE TABLE IF NOT EXISTS `swords` (
`pirate_id` int(11) NOT NULL,
`sword` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `swords` (`pirate_id`, `sword`) VALUES
(3, 'best 3');










share|improve this question




























    1















    I'm trying to figure out how to use UNION with the same JOIN and not to fall into #2014 - Commands out of sync.



    I have created four simple tables and wrote simplified code for them. The main idea is to get each sword, gun and hat which have 'best' in name + if the owner of these is cool.



    SELECT pirate_id, sword, null AS gun, null AS hat, legs = 1 AS is_cool FROM swords as t1
    LEFT JOIN
    (SELECT legs, pirate_id as pid FROM body_parts) AS t2
    ON t1.pirate_id = t2.pid
    WHERE sword LIKE '%best%'

    UNION
    SELECT pirate_id, null AS sword, gun, null AS hat, legs = 1 AS is_cool FROM guns as t3
    LEFT JOIN
    (SELECT legs, pirate_id as pid FROM body_parts) AS t4
    ON t3.pirate_id = t4.pid
    WHERE gun LIKE '%best%'

    UNION
    SELECT pirate_id, null AS sword, null AS gun, hat, legs = 1 AS is_cool FROM hats as t5
    LEFT JOIN
    (SELECT legs, pirate_id as pid FROM body_parts) AS t6
    ON t5.pirate_id = t6.pid
    WHERE hat LIKE '%best%'

    ORDER BY is_cool DESC, pirate_id ASC


    Currently I have to repeat JOIN each time I have to UNION. I hope there is a better way...



    TABLES CREATION:



    CREATE TABLE IF NOT EXISTS `body_parts` (
    `pirate_id` int(11) NOT NULL,
    `legs` int(11) NOT NULL
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
    INSERT INTO `body_parts` (`pirate_id`, `legs`) VALUES
    (1, 0),
    (2, 1),
    (3, 2);

    CREATE TABLE IF NOT EXISTS `guns` (
    `pirate_id` int(11) NOT NULL,
    `gun` varchar(100) NOT NULL
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
    INSERT INTO `guns` (`pirate_id`, `gun`) VALUES
    (1, 'best 1');

    CREATE TABLE IF NOT EXISTS `hats` (
    `pirate_id` int(11) NOT NULL,
    `hat` varchar(100) NOT NULL
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
    INSERT INTO `hats` (`pirate_id`, `hat`) VALUES
    (2, 'best 2');

    CREATE TABLE IF NOT EXISTS `swords` (
    `pirate_id` int(11) NOT NULL,
    `sword` varchar(100) NOT NULL
    ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
    INSERT INTO `swords` (`pirate_id`, `sword`) VALUES
    (3, 'best 3');










    share|improve this question
























      1












      1








      1








      I'm trying to figure out how to use UNION with the same JOIN and not to fall into #2014 - Commands out of sync.



      I have created four simple tables and wrote simplified code for them. The main idea is to get each sword, gun and hat which have 'best' in name + if the owner of these is cool.



      SELECT pirate_id, sword, null AS gun, null AS hat, legs = 1 AS is_cool FROM swords as t1
      LEFT JOIN
      (SELECT legs, pirate_id as pid FROM body_parts) AS t2
      ON t1.pirate_id = t2.pid
      WHERE sword LIKE '%best%'

      UNION
      SELECT pirate_id, null AS sword, gun, null AS hat, legs = 1 AS is_cool FROM guns as t3
      LEFT JOIN
      (SELECT legs, pirate_id as pid FROM body_parts) AS t4
      ON t3.pirate_id = t4.pid
      WHERE gun LIKE '%best%'

      UNION
      SELECT pirate_id, null AS sword, null AS gun, hat, legs = 1 AS is_cool FROM hats as t5
      LEFT JOIN
      (SELECT legs, pirate_id as pid FROM body_parts) AS t6
      ON t5.pirate_id = t6.pid
      WHERE hat LIKE '%best%'

      ORDER BY is_cool DESC, pirate_id ASC


      Currently I have to repeat JOIN each time I have to UNION. I hope there is a better way...



      TABLES CREATION:



      CREATE TABLE IF NOT EXISTS `body_parts` (
      `pirate_id` int(11) NOT NULL,
      `legs` int(11) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `body_parts` (`pirate_id`, `legs`) VALUES
      (1, 0),
      (2, 1),
      (3, 2);

      CREATE TABLE IF NOT EXISTS `guns` (
      `pirate_id` int(11) NOT NULL,
      `gun` varchar(100) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `guns` (`pirate_id`, `gun`) VALUES
      (1, 'best 1');

      CREATE TABLE IF NOT EXISTS `hats` (
      `pirate_id` int(11) NOT NULL,
      `hat` varchar(100) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `hats` (`pirate_id`, `hat`) VALUES
      (2, 'best 2');

      CREATE TABLE IF NOT EXISTS `swords` (
      `pirate_id` int(11) NOT NULL,
      `sword` varchar(100) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `swords` (`pirate_id`, `sword`) VALUES
      (3, 'best 3');










      share|improve this question














      I'm trying to figure out how to use UNION with the same JOIN and not to fall into #2014 - Commands out of sync.



      I have created four simple tables and wrote simplified code for them. The main idea is to get each sword, gun and hat which have 'best' in name + if the owner of these is cool.



      SELECT pirate_id, sword, null AS gun, null AS hat, legs = 1 AS is_cool FROM swords as t1
      LEFT JOIN
      (SELECT legs, pirate_id as pid FROM body_parts) AS t2
      ON t1.pirate_id = t2.pid
      WHERE sword LIKE '%best%'

      UNION
      SELECT pirate_id, null AS sword, gun, null AS hat, legs = 1 AS is_cool FROM guns as t3
      LEFT JOIN
      (SELECT legs, pirate_id as pid FROM body_parts) AS t4
      ON t3.pirate_id = t4.pid
      WHERE gun LIKE '%best%'

      UNION
      SELECT pirate_id, null AS sword, null AS gun, hat, legs = 1 AS is_cool FROM hats as t5
      LEFT JOIN
      (SELECT legs, pirate_id as pid FROM body_parts) AS t6
      ON t5.pirate_id = t6.pid
      WHERE hat LIKE '%best%'

      ORDER BY is_cool DESC, pirate_id ASC


      Currently I have to repeat JOIN each time I have to UNION. I hope there is a better way...



      TABLES CREATION:



      CREATE TABLE IF NOT EXISTS `body_parts` (
      `pirate_id` int(11) NOT NULL,
      `legs` int(11) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `body_parts` (`pirate_id`, `legs`) VALUES
      (1, 0),
      (2, 1),
      (3, 2);

      CREATE TABLE IF NOT EXISTS `guns` (
      `pirate_id` int(11) NOT NULL,
      `gun` varchar(100) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `guns` (`pirate_id`, `gun`) VALUES
      (1, 'best 1');

      CREATE TABLE IF NOT EXISTS `hats` (
      `pirate_id` int(11) NOT NULL,
      `hat` varchar(100) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `hats` (`pirate_id`, `hat`) VALUES
      (2, 'best 2');

      CREATE TABLE IF NOT EXISTS `swords` (
      `pirate_id` int(11) NOT NULL,
      `sword` varchar(100) NOT NULL
      ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
      INSERT INTO `swords` (`pirate_id`, `sword`) VALUES
      (3, 'best 3');







      mysql join union






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 26 at 6:54









      Alex ShiganovAlex Shiganov

      7211 bronze badges




      7211 bronze badges






















          1 Answer
          1






          active

          oldest

          votes


















          1














          You could use a single left join changing the using a subquery



           select t1.pirate_id, t1.sword, t1.gun, t1.hat, t2.legs=1 is_cool

          from (
          SELECT pirate_id, sword, null AS gun, null AS hat
          FROM swords
          WHERE sword LIKE '%best%'

          UNION

          SELECT pirate_id, null, gun, null
          FROM guns
          WHERE gun LIKE '%best%'

          UNION
          SELECT pirate_id, null, null, hat
          FROM hats
          WHERE hat LIKE '%best%'
          ) t1
          LEFT JOIN (
          SELECT legs, pirate_id
          FROM body_parts
          ) t2 ON t2.pirate_id = t1.pirate_id
          ORDER BY is_cool DESC, pirate_id ASC





          share|improve this answer

























          • #1054 - Unknown column 'legs' in 'field list'

            – Alex Shiganov
            Mar 28 at 13:16











          • answer updated ..

            – scaisEdge
            Mar 28 at 17:46











          • #1222 - The used SELECT statements have a different number of columns

            – Alex Shiganov
            Mar 29 at 13:39











          • answer updated .. with 4 columns in each select union

            – scaisEdge
            Mar 29 at 16:03











          • You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

            – Alex Shiganov
            Mar 29 at 18:46










          Your Answer






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          1 Answer
          1






          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You could use a single left join changing the using a subquery



           select t1.pirate_id, t1.sword, t1.gun, t1.hat, t2.legs=1 is_cool

          from (
          SELECT pirate_id, sword, null AS gun, null AS hat
          FROM swords
          WHERE sword LIKE '%best%'

          UNION

          SELECT pirate_id, null, gun, null
          FROM guns
          WHERE gun LIKE '%best%'

          UNION
          SELECT pirate_id, null, null, hat
          FROM hats
          WHERE hat LIKE '%best%'
          ) t1
          LEFT JOIN (
          SELECT legs, pirate_id
          FROM body_parts
          ) t2 ON t2.pirate_id = t1.pirate_id
          ORDER BY is_cool DESC, pirate_id ASC





          share|improve this answer

























          • #1054 - Unknown column 'legs' in 'field list'

            – Alex Shiganov
            Mar 28 at 13:16











          • answer updated ..

            – scaisEdge
            Mar 28 at 17:46











          • #1222 - The used SELECT statements have a different number of columns

            – Alex Shiganov
            Mar 29 at 13:39











          • answer updated .. with 4 columns in each select union

            – scaisEdge
            Mar 29 at 16:03











          • You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

            – Alex Shiganov
            Mar 29 at 18:46















          1














          You could use a single left join changing the using a subquery



           select t1.pirate_id, t1.sword, t1.gun, t1.hat, t2.legs=1 is_cool

          from (
          SELECT pirate_id, sword, null AS gun, null AS hat
          FROM swords
          WHERE sword LIKE '%best%'

          UNION

          SELECT pirate_id, null, gun, null
          FROM guns
          WHERE gun LIKE '%best%'

          UNION
          SELECT pirate_id, null, null, hat
          FROM hats
          WHERE hat LIKE '%best%'
          ) t1
          LEFT JOIN (
          SELECT legs, pirate_id
          FROM body_parts
          ) t2 ON t2.pirate_id = t1.pirate_id
          ORDER BY is_cool DESC, pirate_id ASC





          share|improve this answer

























          • #1054 - Unknown column 'legs' in 'field list'

            – Alex Shiganov
            Mar 28 at 13:16











          • answer updated ..

            – scaisEdge
            Mar 28 at 17:46











          • #1222 - The used SELECT statements have a different number of columns

            – Alex Shiganov
            Mar 29 at 13:39











          • answer updated .. with 4 columns in each select union

            – scaisEdge
            Mar 29 at 16:03











          • You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

            – Alex Shiganov
            Mar 29 at 18:46













          1












          1








          1







          You could use a single left join changing the using a subquery



           select t1.pirate_id, t1.sword, t1.gun, t1.hat, t2.legs=1 is_cool

          from (
          SELECT pirate_id, sword, null AS gun, null AS hat
          FROM swords
          WHERE sword LIKE '%best%'

          UNION

          SELECT pirate_id, null, gun, null
          FROM guns
          WHERE gun LIKE '%best%'

          UNION
          SELECT pirate_id, null, null, hat
          FROM hats
          WHERE hat LIKE '%best%'
          ) t1
          LEFT JOIN (
          SELECT legs, pirate_id
          FROM body_parts
          ) t2 ON t2.pirate_id = t1.pirate_id
          ORDER BY is_cool DESC, pirate_id ASC





          share|improve this answer















          You could use a single left join changing the using a subquery



           select t1.pirate_id, t1.sword, t1.gun, t1.hat, t2.legs=1 is_cool

          from (
          SELECT pirate_id, sword, null AS gun, null AS hat
          FROM swords
          WHERE sword LIKE '%best%'

          UNION

          SELECT pirate_id, null, gun, null
          FROM guns
          WHERE gun LIKE '%best%'

          UNION
          SELECT pirate_id, null, null, hat
          FROM hats
          WHERE hat LIKE '%best%'
          ) t1
          LEFT JOIN (
          SELECT legs, pirate_id
          FROM body_parts
          ) t2 ON t2.pirate_id = t1.pirate_id
          ORDER BY is_cool DESC, pirate_id ASC






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 30 at 6:31

























          answered Mar 26 at 7:24









          scaisEdgescaisEdge

          105k10 gold badges55 silver badges73 bronze badges




          105k10 gold badges55 silver badges73 bronze badges












          • #1054 - Unknown column 'legs' in 'field list'

            – Alex Shiganov
            Mar 28 at 13:16











          • answer updated ..

            – scaisEdge
            Mar 28 at 17:46











          • #1222 - The used SELECT statements have a different number of columns

            – Alex Shiganov
            Mar 29 at 13:39











          • answer updated .. with 4 columns in each select union

            – scaisEdge
            Mar 29 at 16:03











          • You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

            – Alex Shiganov
            Mar 29 at 18:46

















          • #1054 - Unknown column 'legs' in 'field list'

            – Alex Shiganov
            Mar 28 at 13:16











          • answer updated ..

            – scaisEdge
            Mar 28 at 17:46











          • #1222 - The used SELECT statements have a different number of columns

            – Alex Shiganov
            Mar 29 at 13:39











          • answer updated .. with 4 columns in each select union

            – scaisEdge
            Mar 29 at 16:03











          • You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

            – Alex Shiganov
            Mar 29 at 18:46
















          #1054 - Unknown column 'legs' in 'field list'

          – Alex Shiganov
          Mar 28 at 13:16





          #1054 - Unknown column 'legs' in 'field list'

          – Alex Shiganov
          Mar 28 at 13:16













          answer updated ..

          – scaisEdge
          Mar 28 at 17:46





          answer updated ..

          – scaisEdge
          Mar 28 at 17:46













          #1222 - The used SELECT statements have a different number of columns

          – Alex Shiganov
          Mar 29 at 13:39





          #1222 - The used SELECT statements have a different number of columns

          – Alex Shiganov
          Mar 29 at 13:39













          answer updated .. with 4 columns in each select union

          – scaisEdge
          Mar 29 at 16:03





          answer updated .. with 4 columns in each select union

          – scaisEdge
          Mar 29 at 16:03













          You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

          – Alex Shiganov
          Mar 29 at 18:46





          You've missed one char. Anyway, thank you for the answer! Why not write 'select pirate_id, sword, gun, hat, legs = 1 AS is_cool', without table name?

          – Alex Shiganov
          Mar 29 at 18:46








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