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PostgreSQL Foreign Table Error Relation Doesn't Exist


PostgreSQL “DESCRIBE TABLE”Show tables in PostgreSQLModify OWNER on all tables simultaneously in PostgreSQLHow to import CSV file data into a PostgreSQL table?How can I drop all the tables in a PostgreSQL database?Import SQL dump into PostgreSQL databasePostgreSQL error: Fatal: role “username” does not existPostgreSQL: Column Reference in Foreign Key Constraint Does Not ExistPostgresql and primary key, foreign key indexingCheck foreign table owner on Postgres






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0















I've created a foreign table urltrackerft



In my foreign server util it has table urltracker:



enter image description here



enter image description here



I've followed the steps in creating the foreign server and table here:
https://www.postgresql.org/docs/current/postgres-fdw.html



My create script looks something like this:



CREATE FOREIGN TABLE urltrackerft (
id numeric NOT NULL,
...
) SERVER util
OPTIONS (schema_name 'util', table_name 'urltracker');


But when I try to read the urltrackerft table I get this error message:
enter image description here



To me it looks like perhaps the Foreign server isn't exactly synced.



Checking the user mappings, the info looks correct, could it be the host isn't an IP and is a DNS?
enter image description here



Perhaps the firewall or the hba_conf is incorrect for one of the server. But I'm seeing the foreign server util in the primary server. I'm a bit lost on this one. Any help is appreciated, thanks!



The primary server is on PostgreSQL v10, and the foreign server is on PostgreSQL v11.










share|improve this question






























    0















    I've created a foreign table urltrackerft



    In my foreign server util it has table urltracker:



    enter image description here



    enter image description here



    I've followed the steps in creating the foreign server and table here:
    https://www.postgresql.org/docs/current/postgres-fdw.html



    My create script looks something like this:



    CREATE FOREIGN TABLE urltrackerft (
    id numeric NOT NULL,
    ...
    ) SERVER util
    OPTIONS (schema_name 'util', table_name 'urltracker');


    But when I try to read the urltrackerft table I get this error message:
    enter image description here



    To me it looks like perhaps the Foreign server isn't exactly synced.



    Checking the user mappings, the info looks correct, could it be the host isn't an IP and is a DNS?
    enter image description here



    Perhaps the firewall or the hba_conf is incorrect for one of the server. But I'm seeing the foreign server util in the primary server. I'm a bit lost on this one. Any help is appreciated, thanks!



    The primary server is on PostgreSQL v10, and the foreign server is on PostgreSQL v11.










    share|improve this question


























      0












      0








      0








      I've created a foreign table urltrackerft



      In my foreign server util it has table urltracker:



      enter image description here



      enter image description here



      I've followed the steps in creating the foreign server and table here:
      https://www.postgresql.org/docs/current/postgres-fdw.html



      My create script looks something like this:



      CREATE FOREIGN TABLE urltrackerft (
      id numeric NOT NULL,
      ...
      ) SERVER util
      OPTIONS (schema_name 'util', table_name 'urltracker');


      But when I try to read the urltrackerft table I get this error message:
      enter image description here



      To me it looks like perhaps the Foreign server isn't exactly synced.



      Checking the user mappings, the info looks correct, could it be the host isn't an IP and is a DNS?
      enter image description here



      Perhaps the firewall or the hba_conf is incorrect for one of the server. But I'm seeing the foreign server util in the primary server. I'm a bit lost on this one. Any help is appreciated, thanks!



      The primary server is on PostgreSQL v10, and the foreign server is on PostgreSQL v11.










      share|improve this question
















      I've created a foreign table urltrackerft



      In my foreign server util it has table urltracker:



      enter image description here



      enter image description here



      I've followed the steps in creating the foreign server and table here:
      https://www.postgresql.org/docs/current/postgres-fdw.html



      My create script looks something like this:



      CREATE FOREIGN TABLE urltrackerft (
      id numeric NOT NULL,
      ...
      ) SERVER util
      OPTIONS (schema_name 'util', table_name 'urltracker');


      But when I try to read the urltrackerft table I get this error message:
      enter image description here



      To me it looks like perhaps the Foreign server isn't exactly synced.



      Checking the user mappings, the info looks correct, could it be the host isn't an IP and is a DNS?
      enter image description here



      Perhaps the firewall or the hba_conf is incorrect for one of the server. But I'm seeing the foreign server util in the primary server. I'm a bit lost on this one. Any help is appreciated, thanks!



      The primary server is on PostgreSQL v10, and the foreign server is on PostgreSQL v11.







      postgresql postgres-fdw






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 26 at 8:44









      Laurenz Albe

      59.7k11 gold badges42 silver badges63 bronze badges




      59.7k11 gold badges42 silver badges63 bronze badges










      asked Mar 26 at 6:25









      sojim2sojim2

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          1 Answer
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          Your foreign table seems to be in the schema public of database util, if I read your colorful pictures right.



          Then it is unsurprising that the following foreign table definition will not work:



          OPTIONS (schema_name 'util', table_name 'urltracker')


          Use schema_name 'public' instead.






          share|improve this answer






















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            1 Answer
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            active

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            active

            oldest

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            Your foreign table seems to be in the schema public of database util, if I read your colorful pictures right.



            Then it is unsurprising that the following foreign table definition will not work:



            OPTIONS (schema_name 'util', table_name 'urltracker')


            Use schema_name 'public' instead.






            share|improve this answer



























              1














              Your foreign table seems to be in the schema public of database util, if I read your colorful pictures right.



              Then it is unsurprising that the following foreign table definition will not work:



              OPTIONS (schema_name 'util', table_name 'urltracker')


              Use schema_name 'public' instead.






              share|improve this answer

























                1












                1








                1







                Your foreign table seems to be in the schema public of database util, if I read your colorful pictures right.



                Then it is unsurprising that the following foreign table definition will not work:



                OPTIONS (schema_name 'util', table_name 'urltracker')


                Use schema_name 'public' instead.






                share|improve this answer













                Your foreign table seems to be in the schema public of database util, if I read your colorful pictures right.



                Then it is unsurprising that the following foreign table definition will not work:



                OPTIONS (schema_name 'util', table_name 'urltracker')


                Use schema_name 'public' instead.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 26 at 8:43









                Laurenz AlbeLaurenz Albe

                59.7k11 gold badges42 silver badges63 bronze badges




                59.7k11 gold badges42 silver badges63 bronze badges
















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