unmarshall anonymous json field to “named” fieldFlattening marshalled JSON structs with anonymous members in GoJSON Unmarshall not working as expected with structsCustom JSON Unmarshalling for string-encoded numberJSON decode unknown objectAdding Arbitrary fields to json output of an unknown structJSON unmarshal integer field into a stringJSON Marshaling of composite structs which both implement MarshalJSON()Concatenate two values from a JSON object into a map[string]bool in GoAssign additional field when unmarshalling JSON object to GO structGo getting failed field from UnmarshalTypeError
what to say when a company asks you why someone (a friend) who was fired left?
In a script how can I signal who's winning the argument?
Found more old paper shares from broken up companies
Why are MEMS in QFN packages?
What was the rationale behind 36 bit computer architectures?
What is an Eternal Word™?
What's the 1 inch size square knob sticking out of wall?
Why are angular mometum and angular velocity not necessarily parallel, but linear momentum and linear velocity are always parallel?
Aging LEDs - does their output drop after turn-on?
how to add 1 milliseconds on a datetime string?
Can GPL and BSD licensed applications be used for government work?
What is the best word describing the nature of expiring in a short amount of time, connoting "losing public attention"?
What is the relationship between the theme songs in Sherlock Holmes (2009 movie) and Sherlock (BBC series)?
Bug in Lualatex: not printing characters from calculation
Can a character with a low Intelligence score take the Ritual Caster feat and choose the Wizard class?
The seven story archetypes. Are they truly all of them?
Why is a dedicated QA team member necessary?
Raw curve25519 public key points
How to Trust a Self-Signed Certificate
Is there a way to shorten this while condition?
Idioms: Should it be " the internet is a seemingly infinite well of information" or "the internet is a seemingly infinite wealth of information"
Can't understand how static works exactly
Alternative methods for solving a system of one linear one non linear simultaneous equations
Are irregular workouts through the day effective?
unmarshall anonymous json field to “named” field
Flattening marshalled JSON structs with anonymous members in GoJSON Unmarshall not working as expected with structsCustom JSON Unmarshalling for string-encoded numberJSON decode unknown objectAdding Arbitrary fields to json output of an unknown structJSON unmarshal integer field into a stringJSON Marshaling of composite structs which both implement MarshalJSON()Concatenate two values from a JSON object into a map[string]bool in GoAssign additional field when unmarshalling JSON object to GO structGo getting failed field from UnmarshalTypeError
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
Say I have the following json
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
And I have the following structs to represent this data
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property1"`
Otherproperty bool `json:"otherproperty"`
doing
var model Model
json.Unmarshal(content, &model)
Does not deserialize any of the json unfortunately.
How do I deserialize to my Model correctly?
How do I deserialize the json so that ObjectName = "unknown"?
Im not quite understanding the internals of encoding/json when it comes to anonymous json fields.
Ive also tried wrapping Model in a third "outer" Model, but still does not work with the anonymous json field.
go
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
add a comment |
Say I have the following json
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
And I have the following structs to represent this data
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property1"`
Otherproperty bool `json:"otherproperty"`
doing
var model Model
json.Unmarshal(content, &model)
Does not deserialize any of the json unfortunately.
How do I deserialize to my Model correctly?
How do I deserialize the json so that ObjectName = "unknown"?
Im not quite understanding the internals of encoding/json when it comes to anonymous json fields.
Ive also tried wrapping Model in a third "outer" Model, but still does not work with the anonymous json field.
go
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
2
Usemap[string]*Model, then range over the map and use the key to set the ObjectName.
– mkopriva
Mar 26 at 15:23
add a comment |
Say I have the following json
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
And I have the following structs to represent this data
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property1"`
Otherproperty bool `json:"otherproperty"`
doing
var model Model
json.Unmarshal(content, &model)
Does not deserialize any of the json unfortunately.
How do I deserialize to my Model correctly?
How do I deserialize the json so that ObjectName = "unknown"?
Im not quite understanding the internals of encoding/json when it comes to anonymous json fields.
Ive also tried wrapping Model in a third "outer" Model, but still does not work with the anonymous json field.
go
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
Say I have the following json
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
And I have the following structs to represent this data
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property1"`
Otherproperty bool `json:"otherproperty"`
doing
var model Model
json.Unmarshal(content, &model)
Does not deserialize any of the json unfortunately.
How do I deserialize to my Model correctly?
How do I deserialize the json so that ObjectName = "unknown"?
Im not quite understanding the internals of encoding/json when it comes to anonymous json fields.
Ive also tried wrapping Model in a third "outer" Model, but still does not work with the anonymous json field.
go
go
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
edited Mar 26 at 15:40
VisualBean
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
asked Mar 26 at 15:19
VisualBeanVisualBean
3,2412 gold badges19 silver badges47 bronze badges
3,2412 gold badges19 silver badges47 bronze badges
2
Usemap[string]*Model, then range over the map and use the key to set the ObjectName.
– mkopriva
Mar 26 at 15:23
add a comment |
2
Usemap[string]*Model, then range over the map and use the key to set the ObjectName.
– mkopriva
Mar 26 at 15:23
2
2
Use
map[string]*Model, then range over the map and use the key to set the ObjectName.– mkopriva
Mar 26 at 15:23
Use
map[string]*Model, then range over the map and use the key to set the ObjectName.– mkopriva
Mar 26 at 15:23
add a comment |
1 Answer
1
active
oldest
votes
can use map[string]Model to encode. https://play.golang.org/p/QWXQZFjBgRB
package main
import (
"fmt"
"encoding/json"
)
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property"`
Otherproperty bool `json:"otherproperty"`
func main()
jsonstring := `
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
`
a := make(map[string]Model)
json.Unmarshal([]byte(jsonstring), &a)
var m Model
for k, v := range(a)
m = v
m.ObjectName = k
break
fmt.Println(m.ObjectName, m.KnownArray, m.OtherKnownArray)
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55360658%2funmarshall-anonymous-json-field-to-named-field%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
can use map[string]Model to encode. https://play.golang.org/p/QWXQZFjBgRB
package main
import (
"fmt"
"encoding/json"
)
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property"`
Otherproperty bool `json:"otherproperty"`
func main()
jsonstring := `
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
`
a := make(map[string]Model)
json.Unmarshal([]byte(jsonstring), &a)
var m Model
for k, v := range(a)
m = v
m.ObjectName = k
break
fmt.Println(m.ObjectName, m.KnownArray, m.OtherKnownArray)
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
add a comment |
can use map[string]Model to encode. https://play.golang.org/p/QWXQZFjBgRB
package main
import (
"fmt"
"encoding/json"
)
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property"`
Otherproperty bool `json:"otherproperty"`
func main()
jsonstring := `
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
`
a := make(map[string]Model)
json.Unmarshal([]byte(jsonstring), &a)
var m Model
for k, v := range(a)
m = v
m.ObjectName = k
break
fmt.Println(m.ObjectName, m.KnownArray, m.OtherKnownArray)
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
add a comment |
can use map[string]Model to encode. https://play.golang.org/p/QWXQZFjBgRB
package main
import (
"fmt"
"encoding/json"
)
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property"`
Otherproperty bool `json:"otherproperty"`
func main()
jsonstring := `
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
`
a := make(map[string]Model)
json.Unmarshal([]byte(jsonstring), &a)
var m Model
for k, v := range(a)
m = v
m.ObjectName = k
break
fmt.Println(m.ObjectName, m.KnownArray, m.OtherKnownArray)
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
can use map[string]Model to encode. https://play.golang.org/p/QWXQZFjBgRB
package main
import (
"fmt"
"encoding/json"
)
type Model struct
ObjectName string
KnownArray []KnownType `json:"knownArray"`
OtherKnownArray []string `json:"otherKnownArray"`
type KnownType struct
Property string `json:"property"`
Otherproperty bool `json:"otherproperty"`
func main()
jsonstring := `
"unknown":
"knownArray": [
"property": "somevalue", "otherproperty": false
],
"otherKnownArray": [""]
`
a := make(map[string]Model)
json.Unmarshal([]byte(jsonstring), &a)
var m Model
for k, v := range(a)
m = v
m.ObjectName = k
break
fmt.Println(m.ObjectName, m.KnownArray, m.OtherKnownArray)
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
edited Mar 26 at 15:44
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
answered Mar 26 at 15:33
Pan KePan Ke
5497 bronze badges
5497 bronze badges
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
add a comment |
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
This answers half the question, which is awesome! im am 100% further now. But what about the property "ObjectName"? or do I just assign it after the fact?
– VisualBean
Mar 26 at 15:40
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
@VisualBean, I updated the answer. Yes, you just assign it
– Pan Ke
Mar 26 at 15:44
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
Ooh because its the key.. ofcourse.. Thank you!
– VisualBean
Mar 26 at 15:45
add a comment |
Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.
Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55360658%2funmarshall-anonymous-json-field-to-named-field%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
Use
map[string]*Model, then range over the map and use the key to set the ObjectName.– mkopriva
Mar 26 at 15:23