Resolver in graphql on relationHow should I write a resolver while using apollo graphql server backed by neo4j database?Graphql-Access arguments in child resolversUnrecognized arguments in graphql mutationReact Apollo using Named VariablegraphQL query give me null object in responseGraphql: completely change field type in schemaApollo / GraphQl - Type must be Input typeBuilding GraphQL Resolver to Return List of Strings — Receiving [object Object] Instead of StringsQuery component integrated inside functional componentApollo Server, Graphql - Must provide query string
What's the explanation for this joke about a three-legged dog that walks into a bar?
Can't understand how static works exactly
Why did modems have speakers?
Other than a swing wing, what types of variable geometry have flown?
Is it possible to build or embed the SMILES representation of compounds in 3D?
What is the best word describing the nature of expiring in a short amount of time, connoting "losing public attention"?
How could an engineer advance human civilization by time traveling to the past?
Monty Hall Problem with a Fallible Monty
What the purpose of the fuel shutoff valve?
What would be the side effects on the life of a person becoming indestructible?
Grid/table with lots of buttons
How may I shorten this shell script?
Why can't a country print its own money to spend it only abroad?
how to add 1 milliseconds on a datetime string?
Can 々 stand for a duplicated kanji with a different reading?
Is there a way to shorten this while condition?
Are symplectomorphisms of Weil–Petersson symplectic form induced from surface diffeomorphisms?
Invert Some Switches on a Switchboard
What is the spanish equivalent of "the boys are sitting"?
Reference request: mod 2 cohomology of periodic KO theory
Impact of throwing away fruit waste on a peak > 3200 m above a glacier
What exactly makes a General Products hull nearly indestructible?
Why must API keys be kept private?
Issue with ContourPlot
Resolver in graphql on relation
How should I write a resolver while using apollo graphql server backed by neo4j database?Graphql-Access arguments in child resolversUnrecognized arguments in graphql mutationReact Apollo using Named VariablegraphQL query give me null object in responseGraphql: completely change field type in schemaApollo / GraphQl - Type must be Input typeBuilding GraphQL Resolver to Return List of Strings — Receiving [object Object] Instead of StringsQuery component integrated inside functional componentApollo Server, Graphql - Must provide query string
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I would like to execute this request, to have all buckets with specific language :
buckets
id,
code,
language(id:1)
code
But I have this response :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language": "FR" <= Real value "EN"
,
"id": 4,
"language": "FR" <= Real value "EN"
]
I would like to have only the bucket with language id selected :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
]
schema.js
import gql from 'apollo-server';
export const typeDefs = gql`
# Language
type Language
id: Int!
name: String
code: String
is_active: Boolean
# Bucket
type Bucket
id: Int!,
code: String
language(id: Int): Language
# query for types
type Query
buckets: [Bucket]
schema
query: Query
`;
export default typeDefs;
resolvers.js
import GraphQLDate from 'graphql-date';
import Bucket, Language from './connectors';
export const resolvers =
Date: GraphQLDate,
Query:
buckets(_, args)
return Bucket.findAll(
where: args,
order: [['created_at', 'DESC']],
);
,
Bucket:
language(bucket, id)
console.log('resolver id', id);
const where = id: bucket.fk_language_id ;
if (id)
where.id = id
return Language.findOne(
where: where,
);
,
;
export default resolvers;
connectors.js
...
// define language
const LanguageModel = db.define('language',
name : type: Sequelize.STRING,
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
// define bucket
const BucketModel = db.define('bucket',
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
BucketModel.belongsTo(LanguageModel,
foreignKey: 'fk_language_id'
);
LanguageModel.hasMany(BucketModel,
foreignKey: 'id'
);
...
My database is very simple, just two tables Language and Bucket.
Database
Language
id | name | code | is_active
Bucket
id | fk_language_id | code | created_at | updated_at
With this request :
buckets
id,
language
code
I have this result :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language":
"code": "EN"
,
"id": 4,
"language":
"code": "EN"
]
graphql sequelize.js apollo apollo-server
|
show 5 more comments
I would like to execute this request, to have all buckets with specific language :
buckets
id,
code,
language(id:1)
code
But I have this response :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language": "FR" <= Real value "EN"
,
"id": 4,
"language": "FR" <= Real value "EN"
]
I would like to have only the bucket with language id selected :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
]
schema.js
import gql from 'apollo-server';
export const typeDefs = gql`
# Language
type Language
id: Int!
name: String
code: String
is_active: Boolean
# Bucket
type Bucket
id: Int!,
code: String
language(id: Int): Language
# query for types
type Query
buckets: [Bucket]
schema
query: Query
`;
export default typeDefs;
resolvers.js
import GraphQLDate from 'graphql-date';
import Bucket, Language from './connectors';
export const resolvers =
Date: GraphQLDate,
Query:
buckets(_, args)
return Bucket.findAll(
where: args,
order: [['created_at', 'DESC']],
);
,
Bucket:
language(bucket, id)
console.log('resolver id', id);
const where = id: bucket.fk_language_id ;
if (id)
where.id = id
return Language.findOne(
where: where,
);
,
;
export default resolvers;
connectors.js
...
// define language
const LanguageModel = db.define('language',
name : type: Sequelize.STRING,
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
// define bucket
const BucketModel = db.define('bucket',
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
BucketModel.belongsTo(LanguageModel,
foreignKey: 'fk_language_id'
);
LanguageModel.hasMany(BucketModel,
foreignKey: 'id'
);
...
My database is very simple, just two tables Language and Bucket.
Database
Language
id | name | code | is_active
Bucket
id | fk_language_id | code | created_at | updated_at
With this request :
buckets
id,
language
code
I have this result :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language":
"code": "EN"
,
"id": 4,
"language":
"code": "EN"
]
graphql sequelize.js apollo apollo-server
are you pretty sure this is happening when you include the ID in the query? ``` if (id) where.id = id ```
– masmerino
Mar 26 at 17:09
Are you getting "id" in your resolver ? Because i don't see any "input" in schema.
– Amit Bhoyar
Mar 26 at 17:10
@masmerino I updated my code with the simple request without specific id on language
– Jérémie Chazelle
Mar 26 at 17:12
let's do a quick test: could you change your query to it: buckets(filter: languaje: id: 1) id, language code
– masmerino
Mar 26 at 17:26
Prisma and grapql cool support filters by this way :)
– masmerino
Mar 26 at 17:27
|
show 5 more comments
I would like to execute this request, to have all buckets with specific language :
buckets
id,
code,
language(id:1)
code
But I have this response :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language": "FR" <= Real value "EN"
,
"id": 4,
"language": "FR" <= Real value "EN"
]
I would like to have only the bucket with language id selected :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
]
schema.js
import gql from 'apollo-server';
export const typeDefs = gql`
# Language
type Language
id: Int!
name: String
code: String
is_active: Boolean
# Bucket
type Bucket
id: Int!,
code: String
language(id: Int): Language
# query for types
type Query
buckets: [Bucket]
schema
query: Query
`;
export default typeDefs;
resolvers.js
import GraphQLDate from 'graphql-date';
import Bucket, Language from './connectors';
export const resolvers =
Date: GraphQLDate,
Query:
buckets(_, args)
return Bucket.findAll(
where: args,
order: [['created_at', 'DESC']],
);
,
Bucket:
language(bucket, id)
console.log('resolver id', id);
const where = id: bucket.fk_language_id ;
if (id)
where.id = id
return Language.findOne(
where: where,
);
,
;
export default resolvers;
connectors.js
...
// define language
const LanguageModel = db.define('language',
name : type: Sequelize.STRING,
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
// define bucket
const BucketModel = db.define('bucket',
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
BucketModel.belongsTo(LanguageModel,
foreignKey: 'fk_language_id'
);
LanguageModel.hasMany(BucketModel,
foreignKey: 'id'
);
...
My database is very simple, just two tables Language and Bucket.
Database
Language
id | name | code | is_active
Bucket
id | fk_language_id | code | created_at | updated_at
With this request :
buckets
id,
language
code
I have this result :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language":
"code": "EN"
,
"id": 4,
"language":
"code": "EN"
]
graphql sequelize.js apollo apollo-server
I would like to execute this request, to have all buckets with specific language :
buckets
id,
code,
language(id:1)
code
But I have this response :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language": "FR" <= Real value "EN"
,
"id": 4,
"language": "FR" <= Real value "EN"
]
I would like to have only the bucket with language id selected :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
]
schema.js
import gql from 'apollo-server';
export const typeDefs = gql`
# Language
type Language
id: Int!
name: String
code: String
is_active: Boolean
# Bucket
type Bucket
id: Int!,
code: String
language(id: Int): Language
# query for types
type Query
buckets: [Bucket]
schema
query: Query
`;
export default typeDefs;
resolvers.js
import GraphQLDate from 'graphql-date';
import Bucket, Language from './connectors';
export const resolvers =
Date: GraphQLDate,
Query:
buckets(_, args)
return Bucket.findAll(
where: args,
order: [['created_at', 'DESC']],
);
,
Bucket:
language(bucket, id)
console.log('resolver id', id);
const where = id: bucket.fk_language_id ;
if (id)
where.id = id
return Language.findOne(
where: where,
);
,
;
export default resolvers;
connectors.js
...
// define language
const LanguageModel = db.define('language',
name : type: Sequelize.STRING,
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
// define bucket
const BucketModel = db.define('bucket',
code : type: Sequelize.STRING,
is_active: type: Sequelize.BOOLEAN
);
BucketModel.belongsTo(LanguageModel,
foreignKey: 'fk_language_id'
);
LanguageModel.hasMany(BucketModel,
foreignKey: 'id'
);
...
My database is very simple, just two tables Language and Bucket.
Database
Language
id | name | code | is_active
Bucket
id | fk_language_id | code | created_at | updated_at
With this request :
buckets
id,
language
code
I have this result :
"data":
"buckets": [
"id": 1,
"language":
"code": "FR"
,
"id": 2,
"language":
"code": "FR"
,
"id": 3,
"language":
"code": "EN"
,
"id": 4,
"language":
"code": "EN"
]
graphql sequelize.js apollo apollo-server
graphql sequelize.js apollo apollo-server
edited Mar 26 at 17:40
Jérémie Chazelle
asked Mar 26 at 15:04
Jérémie ChazelleJérémie Chazelle
1,02417 silver badges42 bronze badges
1,02417 silver badges42 bronze badges
are you pretty sure this is happening when you include the ID in the query? ``` if (id) where.id = id ```
– masmerino
Mar 26 at 17:09
Are you getting "id" in your resolver ? Because i don't see any "input" in schema.
– Amit Bhoyar
Mar 26 at 17:10
@masmerino I updated my code with the simple request without specific id on language
– Jérémie Chazelle
Mar 26 at 17:12
let's do a quick test: could you change your query to it: buckets(filter: languaje: id: 1) id, language code
– masmerino
Mar 26 at 17:26
Prisma and grapql cool support filters by this way :)
– masmerino
Mar 26 at 17:27
|
show 5 more comments
are you pretty sure this is happening when you include the ID in the query? ``` if (id) where.id = id ```
– masmerino
Mar 26 at 17:09
Are you getting "id" in your resolver ? Because i don't see any "input" in schema.
– Amit Bhoyar
Mar 26 at 17:10
@masmerino I updated my code with the simple request without specific id on language
– Jérémie Chazelle
Mar 26 at 17:12
let's do a quick test: could you change your query to it: buckets(filter: languaje: id: 1) id, language code
– masmerino
Mar 26 at 17:26
Prisma and grapql cool support filters by this way :)
– masmerino
Mar 26 at 17:27
are you pretty sure this is happening when you include the ID in the query? ``` if (id) where.id = id ```
– masmerino
Mar 26 at 17:09
are you pretty sure this is happening when you include the ID in the query? ``` if (id) where.id = id ```
– masmerino
Mar 26 at 17:09
Are you getting "id" in your resolver ? Because i don't see any "input" in schema.
– Amit Bhoyar
Mar 26 at 17:10
Are you getting "id" in your resolver ? Because i don't see any "input" in schema.
– Amit Bhoyar
Mar 26 at 17:10
@masmerino I updated my code with the simple request without specific id on language
– Jérémie Chazelle
Mar 26 at 17:12
@masmerino I updated my code with the simple request without specific id on language
– Jérémie Chazelle
Mar 26 at 17:12
let's do a quick test: could you change your query to it: buckets(filter: languaje: id: 1) id, language code
– masmerino
Mar 26 at 17:26
let's do a quick test: could you change your query to it: buckets(filter: languaje: id: 1) id, language code
– masmerino
Mar 26 at 17:26
Prisma and grapql cool support filters by this way :)
– masmerino
Mar 26 at 17:27
Prisma and grapql cool support filters by this way :)
– masmerino
Mar 26 at 17:27
|
show 5 more comments
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55360369%2fresolver-in-graphql-on-relation%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Is this question similar to what you get asked at work? Learn more about asking and sharing private information with your coworkers using Stack Overflow for Teams.
Is this question similar to what you get asked at work? Learn more about asking and sharing private information with your coworkers using Stack Overflow for Teams.
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55360369%2fresolver-in-graphql-on-relation%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
are you pretty sure this is happening when you include the ID in the query? ``` if (id) where.id = id ```
– masmerino
Mar 26 at 17:09
Are you getting "id" in your resolver ? Because i don't see any "input" in schema.
– Amit Bhoyar
Mar 26 at 17:10
@masmerino I updated my code with the simple request without specific id on language
– Jérémie Chazelle
Mar 26 at 17:12
let's do a quick test: could you change your query to it: buckets(filter: languaje: id: 1) id, language code
– masmerino
Mar 26 at 17:26
Prisma and grapql cool support filters by this way :)
– masmerino
Mar 26 at 17:27