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Default dictionary value in Swift
How to call Objective-C code from Swift#pragma mark in Swift?Swift for loop: for index, element in array?Swift Beta performance: sorting arraysRemoving duplicate elements from an array in SwiftSorting Dictionaries containing more complex values in SwiftSwift Dictionary Multiple Key Value Pairs - IterationDoes assigning a property of a tuple contained in a Swift Dictionary change the Dictionary itself?Default value of uninitialized variable/object in SwiftConvert JSON String to Swift Dictionary
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I know I can have a default dictionary value in swift, but I am struggling to do this for a tuple
i.e.
var freq = [Int:(Int,Int,Int)]()
I want to make a default value
freq[num.element, default: (0, num.offset, num.offset) ] = (7, 0, 0 )
This produces the frequency table with 7,0,0 for every value when the key does not exist.
Can I use the default for a more complicated dictionary?
For an example if we have an array of numbers [1,2,2,3,3,3]
we can count the number of elements using a frequency table
var freq = [Int:Int]()
for num in nums
freq[num, default: 0] += 1
We want to store the initial position of each number, and the final position of each number in the frequency table so use
var freq = [Int:(Int,Int,Int)]()
for num in nums.enumerated()
if freq[num.element] == nil
freq[num.element] = (1,num.offset, num.offset)
else
freq[num.element] = (freq[num.element]!.0 + 1, freq[num.element]!.1, num.offset)
For this code I want to use a default value.
I am looking for a way of using a default value on a frequency list containing more than just a single value. It is not relevant that I am using a tuple rather than an array of values, for an example I want to find out how to use default with a tuple using arrays.
I tried to use the example above to make a default value, and on testing it does not work. I have looked at previous questions, a Google Search and looked at Apple's documentation.
Question: How to use default for a dictionary var freq = Int:(Int,Int,Int)
swift
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
|
show 1 more comment
I know I can have a default dictionary value in swift, but I am struggling to do this for a tuple
i.e.
var freq = [Int:(Int,Int,Int)]()
I want to make a default value
freq[num.element, default: (0, num.offset, num.offset) ] = (7, 0, 0 )
This produces the frequency table with 7,0,0 for every value when the key does not exist.
Can I use the default for a more complicated dictionary?
For an example if we have an array of numbers [1,2,2,3,3,3]
we can count the number of elements using a frequency table
var freq = [Int:Int]()
for num in nums
freq[num, default: 0] += 1
We want to store the initial position of each number, and the final position of each number in the frequency table so use
var freq = [Int:(Int,Int,Int)]()
for num in nums.enumerated()
if freq[num.element] == nil
freq[num.element] = (1,num.offset, num.offset)
else
freq[num.element] = (freq[num.element]!.0 + 1, freq[num.element]!.1, num.offset)
For this code I want to use a default value.
I am looking for a way of using a default value on a frequency list containing more than just a single value. It is not relevant that I am using a tuple rather than an array of values, for an example I want to find out how to use default with a tuple using arrays.
I tried to use the example above to make a default value, and on testing it does not work. I have looked at previous questions, a Google Search and looked at Apple's documentation.
Question: How to use default for a dictionary var freq = Int:(Int,Int,Int)
swift
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
The default value—which is(0, num.offset, num.offset)—is never used in the code in your questions. In other words: the code in your question could be written asfreq[num.element] = (7, 0, 0).
– David Rönnqvist
Mar 27 at 2:05
It's a frequency table. So traverse a String and count the number of each element. Whether this is used or not, the default is not set.
– WishIHadThreeGuns
Mar 27 at 2:11
1
Please show the rest of the code that calculates the frequencies. Currently I find it hard to understand what you're asking without the surrounding context.
– David Rönnqvist
Mar 27 at 2:16
It's hugely problematic here, as the minimum requirement is clearly stated. I've given an extended example, but frequently doing so on Stack Overflow gives accusations of "homework" (It isn't) or answering a different question unrelated to the one asked (use an array of values, not a tuple! etc.). This one is wholly about the use of defaults with dictionaries in Swift.
– WishIHadThreeGuns
Mar 27 at 2:24
For what it's worth it's easier to understand what you're asking and what you're trying to achieve after you edited your question to include additional information.
– David Rönnqvist
Mar 27 at 3:00
|
show 1 more comment
I know I can have a default dictionary value in swift, but I am struggling to do this for a tuple
i.e.
var freq = [Int:(Int,Int,Int)]()
I want to make a default value
freq[num.element, default: (0, num.offset, num.offset) ] = (7, 0, 0 )
This produces the frequency table with 7,0,0 for every value when the key does not exist.
Can I use the default for a more complicated dictionary?
For an example if we have an array of numbers [1,2,2,3,3,3]
we can count the number of elements using a frequency table
var freq = [Int:Int]()
for num in nums
freq[num, default: 0] += 1
We want to store the initial position of each number, and the final position of each number in the frequency table so use
var freq = [Int:(Int,Int,Int)]()
for num in nums.enumerated()
if freq[num.element] == nil
freq[num.element] = (1,num.offset, num.offset)
else
freq[num.element] = (freq[num.element]!.0 + 1, freq[num.element]!.1, num.offset)
For this code I want to use a default value.
I am looking for a way of using a default value on a frequency list containing more than just a single value. It is not relevant that I am using a tuple rather than an array of values, for an example I want to find out how to use default with a tuple using arrays.
I tried to use the example above to make a default value, and on testing it does not work. I have looked at previous questions, a Google Search and looked at Apple's documentation.
Question: How to use default for a dictionary var freq = Int:(Int,Int,Int)
swift
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
I know I can have a default dictionary value in swift, but I am struggling to do this for a tuple
i.e.
var freq = [Int:(Int,Int,Int)]()
I want to make a default value
freq[num.element, default: (0, num.offset, num.offset) ] = (7, 0, 0 )
This produces the frequency table with 7,0,0 for every value when the key does not exist.
Can I use the default for a more complicated dictionary?
For an example if we have an array of numbers [1,2,2,3,3,3]
we can count the number of elements using a frequency table
var freq = [Int:Int]()
for num in nums
freq[num, default: 0] += 1
We want to store the initial position of each number, and the final position of each number in the frequency table so use
var freq = [Int:(Int,Int,Int)]()
for num in nums.enumerated()
if freq[num.element] == nil
freq[num.element] = (1,num.offset, num.offset)
else
freq[num.element] = (freq[num.element]!.0 + 1, freq[num.element]!.1, num.offset)
For this code I want to use a default value.
I am looking for a way of using a default value on a frequency list containing more than just a single value. It is not relevant that I am using a tuple rather than an array of values, for an example I want to find out how to use default with a tuple using arrays.
I tried to use the example above to make a default value, and on testing it does not work. I have looked at previous questions, a Google Search and looked at Apple's documentation.
Question: How to use default for a dictionary var freq = Int:(Int,Int,Int)
swift
swift
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
edited Mar 27 at 3:09
WishIHadThreeGuns
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
asked Mar 27 at 1:31
WishIHadThreeGunsWishIHadThreeGuns
9711 bronze badges
9711 bronze badges
The default value—which is(0, num.offset, num.offset)—is never used in the code in your questions. In other words: the code in your question could be written asfreq[num.element] = (7, 0, 0).
– David Rönnqvist
Mar 27 at 2:05
It's a frequency table. So traverse a String and count the number of each element. Whether this is used or not, the default is not set.
– WishIHadThreeGuns
Mar 27 at 2:11
1
Please show the rest of the code that calculates the frequencies. Currently I find it hard to understand what you're asking without the surrounding context.
– David Rönnqvist
Mar 27 at 2:16
It's hugely problematic here, as the minimum requirement is clearly stated. I've given an extended example, but frequently doing so on Stack Overflow gives accusations of "homework" (It isn't) or answering a different question unrelated to the one asked (use an array of values, not a tuple! etc.). This one is wholly about the use of defaults with dictionaries in Swift.
– WishIHadThreeGuns
Mar 27 at 2:24
For what it's worth it's easier to understand what you're asking and what you're trying to achieve after you edited your question to include additional information.
– David Rönnqvist
Mar 27 at 3:00
|
show 1 more comment
The default value—which is(0, num.offset, num.offset)—is never used in the code in your questions. In other words: the code in your question could be written asfreq[num.element] = (7, 0, 0).
– David Rönnqvist
Mar 27 at 2:05
It's a frequency table. So traverse a String and count the number of each element. Whether this is used or not, the default is not set.
– WishIHadThreeGuns
Mar 27 at 2:11
1
Please show the rest of the code that calculates the frequencies. Currently I find it hard to understand what you're asking without the surrounding context.
– David Rönnqvist
Mar 27 at 2:16
It's hugely problematic here, as the minimum requirement is clearly stated. I've given an extended example, but frequently doing so on Stack Overflow gives accusations of "homework" (It isn't) or answering a different question unrelated to the one asked (use an array of values, not a tuple! etc.). This one is wholly about the use of defaults with dictionaries in Swift.
– WishIHadThreeGuns
Mar 27 at 2:24
For what it's worth it's easier to understand what you're asking and what you're trying to achieve after you edited your question to include additional information.
– David Rönnqvist
Mar 27 at 3:00
The default value—which is
(0, num.offset, num.offset)—is never used in the code in your questions. In other words: the code in your question could be written as freq[num.element] = (7, 0, 0).– David Rönnqvist
Mar 27 at 2:05
The default value—which is
(0, num.offset, num.offset)—is never used in the code in your questions. In other words: the code in your question could be written as freq[num.element] = (7, 0, 0).– David Rönnqvist
Mar 27 at 2:05
It's a frequency table. So traverse a String and count the number of each element. Whether this is used or not, the default is not set.
– WishIHadThreeGuns
Mar 27 at 2:11
It's a frequency table. So traverse a String and count the number of each element. Whether this is used or not, the default is not set.
– WishIHadThreeGuns
Mar 27 at 2:11
1
1
Please show the rest of the code that calculates the frequencies. Currently I find it hard to understand what you're asking without the surrounding context.
– David Rönnqvist
Mar 27 at 2:16
Please show the rest of the code that calculates the frequencies. Currently I find it hard to understand what you're asking without the surrounding context.
– David Rönnqvist
Mar 27 at 2:16
It's hugely problematic here, as the minimum requirement is clearly stated. I've given an extended example, but frequently doing so on Stack Overflow gives accusations of "homework" (It isn't) or answering a different question unrelated to the one asked (use an array of values, not a tuple! etc.). This one is wholly about the use of defaults with dictionaries in Swift.
– WishIHadThreeGuns
Mar 27 at 2:24
It's hugely problematic here, as the minimum requirement is clearly stated. I've given an extended example, but frequently doing so on Stack Overflow gives accusations of "homework" (It isn't) or answering a different question unrelated to the one asked (use an array of values, not a tuple! etc.). This one is wholly about the use of defaults with dictionaries in Swift.
– WishIHadThreeGuns
Mar 27 at 2:24
For what it's worth it's easier to understand what you're asking and what you're trying to achieve after you edited your question to include additional information.
– David Rönnqvist
Mar 27 at 3:00
For what it's worth it's easier to understand what you're asking and what you're trying to achieve after you edited your question to include additional information.
– David Rönnqvist
Mar 27 at 3:00
|
show 1 more comment
1 Answer
1
active
oldest
votes
Is this what you looking for? Just get the current value with default value and store it in a variable first makes life easier.
var freq = [Int:(Int,Int,Int)]()
var nums = [1,2,2,3,3,3]
for num in nums.enumerated()
let currentTuple = freq[num.element, default: (0,num.offset,num.offset)]
freq[num.element] = (currentTuple.0 + 1, currentTuple.1,num.offset)
print(freq) //output: [1: (1, 0, 0), 2: (2, 1, 2), 3: (3, 3, 5)]
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
add a comment |
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1 Answer
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Is this what you looking for? Just get the current value with default value and store it in a variable first makes life easier.
var freq = [Int:(Int,Int,Int)]()
var nums = [1,2,2,3,3,3]
for num in nums.enumerated()
let currentTuple = freq[num.element, default: (0,num.offset,num.offset)]
freq[num.element] = (currentTuple.0 + 1, currentTuple.1,num.offset)
print(freq) //output: [1: (1, 0, 0), 2: (2, 1, 2), 3: (3, 3, 5)]
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
add a comment |
Is this what you looking for? Just get the current value with default value and store it in a variable first makes life easier.
var freq = [Int:(Int,Int,Int)]()
var nums = [1,2,2,3,3,3]
for num in nums.enumerated()
let currentTuple = freq[num.element, default: (0,num.offset,num.offset)]
freq[num.element] = (currentTuple.0 + 1, currentTuple.1,num.offset)
print(freq) //output: [1: (1, 0, 0), 2: (2, 1, 2), 3: (3, 3, 5)]
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
add a comment |
Is this what you looking for? Just get the current value with default value and store it in a variable first makes life easier.
var freq = [Int:(Int,Int,Int)]()
var nums = [1,2,2,3,3,3]
for num in nums.enumerated()
let currentTuple = freq[num.element, default: (0,num.offset,num.offset)]
freq[num.element] = (currentTuple.0 + 1, currentTuple.1,num.offset)
print(freq) //output: [1: (1, 0, 0), 2: (2, 1, 2), 3: (3, 3, 5)]
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
Is this what you looking for? Just get the current value with default value and store it in a variable first makes life easier.
var freq = [Int:(Int,Int,Int)]()
var nums = [1,2,2,3,3,3]
for num in nums.enumerated()
let currentTuple = freq[num.element, default: (0,num.offset,num.offset)]
freq[num.element] = (currentTuple.0 + 1, currentTuple.1,num.offset)
print(freq) //output: [1: (1, 0, 0), 2: (2, 1, 2), 3: (3, 3, 5)]
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
answered Mar 27 at 2:35
Ricky MoRicky Mo
2,4721 gold badge2 silver badges13 bronze badges
2,4721 gold badge2 silver badges13 bronze badges
add a comment |
add a comment |
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The default value—which is
(0, num.offset, num.offset)—is never used in the code in your questions. In other words: the code in your question could be written asfreq[num.element] = (7, 0, 0).– David Rönnqvist
Mar 27 at 2:05
It's a frequency table. So traverse a String and count the number of each element. Whether this is used or not, the default is not set.
– WishIHadThreeGuns
Mar 27 at 2:11
1
Please show the rest of the code that calculates the frequencies. Currently I find it hard to understand what you're asking without the surrounding context.
– David Rönnqvist
Mar 27 at 2:16
It's hugely problematic here, as the minimum requirement is clearly stated. I've given an extended example, but frequently doing so on Stack Overflow gives accusations of "homework" (It isn't) or answering a different question unrelated to the one asked (use an array of values, not a tuple! etc.). This one is wholly about the use of defaults with dictionaries in Swift.
– WishIHadThreeGuns
Mar 27 at 2:24
For what it's worth it's easier to understand what you're asking and what you're trying to achieve after you edited your question to include additional information.
– David Rönnqvist
Mar 27 at 3:00