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How can I use PHP variables within a WP_Query array?

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0

I'm trying to pull variables into a WP_Query array, but the intended output isn't what I would expect.

Here's my code:

<?php
$country_name = the_title();
$populate_jhcarousel = new WP_Query( array(
 'post_type' => 'story',
 'tax_query' => array(
 array(
 'taxonomy' => 'location',
 'field' => 'name',
 'terms' => "'"$country_name"'"
 ),
 ),
 'posts_per_page' => 20,
 'order'=> 'DESC'
 ) );
?>

My intention is to bring in all posts whose location is the title of whatever country page their on. In my local setup, I'm testing with Tanzania. When I use the following 'terms' => 'Tanzania', my slider populates properly. But when I use the variable, it either throws a 500 error, or just outputs the word "Tanzania" in place of my slider. Below is what I've tried, and the results:

'terms' => "'"$country_name"'" = HTTP ERROR 500

'terms' => '$country_name' = "Tanzania"

'terms' => $country_name = "Tanzania"

'terms' => 'Tanzania' = Intended result

Any help on using variables within a WP_Query array would be welcomed. Many thanks in advance!!!!

php wordpress variables

share|improve this question

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you get a htrp 500 error because you need to add concatenation operator "." (dot).
  
  – Dexter0015
  Mar 27 at 16:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  more accurately, he needs to realize the quotes and concat are not necessary. just do 'terms' => $country_name
  
  – Kai Qing
  Mar 27 at 16:42
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Dexter0015 would you mind elaborating on your solution? I've tried 'terms' => .$country_name. and I've tried 'terms' => '.$country_name.' and finally 'terms' => "'".$country_name."'" all without my intended result. @KaiQing I've also tried your suggestion, as I stated above.
  
  – Alex Robinson
  Mar 27 at 18:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AlexRobinson In the op, you wrote that you used 'terms' => "'"$country_name"'", which is missing the concatenation dots between the double quotes and $country_name. As @KaiQing said, you don't need quotes. If $country_name is a string, it should work. Try outputting and checking that $country_name is correctly set before hand.
  
  – Daniel Foust
  Mar 27 at 20:03
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  It looks like the issue is that you are using the_title(), which has the default behavior of echoing out the title. Change that to get_the_title() and see if that works.
  
  – Daniel Foust
  Mar 27 at 20:07
  

  
  
  
  

 | 
show 2 more comments

0

I'm trying to pull variables into a WP_Query array, but the intended output isn't what I would expect.

Here's my code:

<?php
$country_name = the_title();
$populate_jhcarousel = new WP_Query( array(
 'post_type' => 'story',
 'tax_query' => array(
 array(
 'taxonomy' => 'location',
 'field' => 'name',
 'terms' => "'"$country_name"'"
 ),
 ),
 'posts_per_page' => 20,
 'order'=> 'DESC'
 ) );
?>

My intention is to bring in all posts whose location is the title of whatever country page their on. In my local setup, I'm testing with Tanzania. When I use the following 'terms' => 'Tanzania', my slider populates properly. But when I use the variable, it either throws a 500 error, or just outputs the word "Tanzania" in place of my slider. Below is what I've tried, and the results:

'terms' => "'"$country_name"'" = HTTP ERROR 500

'terms' => '$country_name' = "Tanzania"

'terms' => $country_name = "Tanzania"

'terms' => 'Tanzania' = Intended result

Any help on using variables within a WP_Query array would be welcomed. Many thanks in advance!!!!

php wordpress variables

share|improve this question

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you get a htrp 500 error because you need to add concatenation operator "." (dot).
  
  – Dexter0015
  Mar 27 at 16:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  more accurately, he needs to realize the quotes and concat are not necessary. just do 'terms' => $country_name
  
  – Kai Qing
  Mar 27 at 16:42
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Dexter0015 would you mind elaborating on your solution? I've tried 'terms' => .$country_name. and I've tried 'terms' => '.$country_name.' and finally 'terms' => "'".$country_name."'" all without my intended result. @KaiQing I've also tried your suggestion, as I stated above.
  
  – Alex Robinson
  Mar 27 at 18:05
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @AlexRobinson In the op, you wrote that you used 'terms' => "'"$country_name"'", which is missing the concatenation dots between the double quotes and $country_name. As @KaiQing said, you don't need quotes. If $country_name is a string, it should work. Try outputting and checking that $country_name is correctly set before hand.
  
  – Daniel Foust
  Mar 27 at 20:03
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  It looks like the issue is that you are using the_title(), which has the default behavior of echoing out the title. Change that to get_the_title() and see if that works.
  
  – Daniel Foust
  Mar 27 at 20:07
  

  
  
  
  

 | 
show 2 more comments

I'm trying to pull variables into a WP_Query array, but the intended output isn't what I would expect.

Here's my code:

<?php
$country_name = the_title();
$populate_jhcarousel = new WP_Query( array(
 'post_type' => 'story',
 'tax_query' => array(
 array(
 'taxonomy' => 'location',
 'field' => 'name',
 'terms' => "'"$country_name"'"
 ),
 ),
 'posts_per_page' => 20,
 'order'=> 'DESC'
 ) );
?>

My intention is to bring in all posts whose location is the title of whatever country page their on. In my local setup, I'm testing with Tanzania. When I use the following 'terms' => 'Tanzania', my slider populates properly. But when I use the variable, it either throws a 500 error, or just outputs the word "Tanzania" in place of my slider. Below is what I've tried, and the results:

'terms' => "'"$country_name"'" = HTTP ERROR 500

'terms' => '$country_name' = "Tanzania"

'terms' => $country_name = "Tanzania"

'terms' => 'Tanzania' = Intended result

Any help on using variables within a WP_Query array would be welcomed. Many thanks in advance!!!!

php wordpress variables

share|improve this question

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

<?php
$country_name = the_title();
$populate_jhcarousel = new WP_Query( array(
 'post_type' => 'story',
 'tax_query' => array(
 array(
 'taxonomy' => 'location',
 'field' => 'name',
 'terms' => "'"$country_name"'"
 ),
 ),
 'posts_per_page' => 20,
 'order'=> 'DESC'
 ) );
?>

share|improve this question

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

share|improve this question

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

asked Mar 27 at 16:26

Alex RobinsonAlex Robinson

2866 bronze badges

1 Answer
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1

The issue is that you are using the_title(), which has the default behavior of echoing out the title. Change that to get_the_title().

share|improve this answer

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges

add a comment | 

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1

The issue is that you are using the_title(), which has the default behavior of echoing out the title. Change that to get_the_title().

share|improve this answer

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges

add a comment | 

1

The issue is that you are using the_title(), which has the default behavior of echoing out the title. Change that to get_the_title().

share|improve this answer

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges

add a comment | 

The issue is that you are using the_title(), which has the default behavior of echoing out the title. Change that to get_the_title().

share|improve this answer

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges

share|improve this answer

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges

answered Mar 27 at 20:25

Daniel FoustDaniel Foust

37711 gold badge33 silver badges1616 bronze badges