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How concat many attribute values for xml?

How do I parse XML in Python?XML to CSV using XSLT helpHow do you parse and process HTML/XML in PHP?Chrome, Firefox and Safari not applying XSLT? IE does!How to pass “Null” (a real surname!) to a SOAP web service in ActionScript 3?Read SOAP XML by ASMX web servcie functionC#+Magento API V2:The content type text/xml; charset=utf-8,text/xml; charset=UTF-8 of the response message does not matchSOAP response/Request then how to convert it in to PHPXSLT change value node based on the value of another nodehow to solve [org.xml.sax.SAXParseException; lineNumber: 2; columnNumber: 1; Content is not allowed in prolog.]

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

1

1

SOAP Message:

<?xml version='1.0' encoding='utf-8'?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
 <soapenv:Body> 
 <field_21>
 <row StartDate="2017-01-01" EndDate="2017-01-07" DaysCount="7" Diagnoz="A00.0"/>
 <row StartDate="2019-02-01" EndDate="2019-02-07" DaysCount="8" Diagnoz="A10.0"/>
 </field_21>
 </soapenv:Body>
</soapenv:Envelope>

My xslt:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
 xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" version="1.0">
 <xsl:template match="/">
 <result> 
 <xsl:value-of select="string-join(
 concat(//field_21/row/@StartDate, ' ', 
 //field_21/row/@EndDate, ' ', 
 //field_21/row/@DaysCount, ' ', 
 //field_21/row/@Diagnoz), ';')"/>
 </result> 
 </xsl:template>
</xsl:stylesheet>

Result:

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0</result>

The result that I need:

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0; 2019-02-01 2019-02-07 8 A10.0</result>

Tell me how to correct my conversion to get the required result

xml xslt soap wso2

share|improve this question

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can you use 2.0 or 1.0 only?
  
  – Amrendra Kumar
  Mar 27 at 11:09
  

  
  
  
  

add a comment | 

1

1

SOAP Message:

<?xml version='1.0' encoding='utf-8'?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
 <soapenv:Body> 
 <field_21>
 <row StartDate="2017-01-01" EndDate="2017-01-07" DaysCount="7" Diagnoz="A00.0"/>
 <row StartDate="2019-02-01" EndDate="2019-02-07" DaysCount="8" Diagnoz="A10.0"/>
 </field_21>
 </soapenv:Body>
</soapenv:Envelope>

My xslt:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
 xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" version="1.0">
 <xsl:template match="/">
 <result> 
 <xsl:value-of select="string-join(
 concat(//field_21/row/@StartDate, ' ', 
 //field_21/row/@EndDate, ' ', 
 //field_21/row/@DaysCount, ' ', 
 //field_21/row/@Diagnoz), ';')"/>
 </result> 
 </xsl:template>
</xsl:stylesheet>

Result:

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0</result>

The result that I need:

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0; 2019-02-01 2019-02-07 8 A10.0</result>

Tell me how to correct my conversion to get the required result

xml xslt soap wso2

share|improve this question

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can you use 2.0 or 1.0 only?
  
  – Amrendra Kumar
  Mar 27 at 11:09
  

  
  
  
  

add a comment | 

SOAP Message:

<?xml version='1.0' encoding='utf-8'?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
 <soapenv:Body> 
 <field_21>
 <row StartDate="2017-01-01" EndDate="2017-01-07" DaysCount="7" Diagnoz="A00.0"/>
 <row StartDate="2019-02-01" EndDate="2019-02-07" DaysCount="8" Diagnoz="A10.0"/>
 </field_21>
 </soapenv:Body>
</soapenv:Envelope>

My xslt:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
 xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" version="1.0">
 <xsl:template match="/">
 <result> 
 <xsl:value-of select="string-join(
 concat(//field_21/row/@StartDate, ' ', 
 //field_21/row/@EndDate, ' ', 
 //field_21/row/@DaysCount, ' ', 
 //field_21/row/@Diagnoz), ';')"/>
 </result> 
 </xsl:template>
</xsl:stylesheet>

Result:

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0</result>

The result that I need:

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0; 2019-02-01 2019-02-07 8 A10.0</result>

Tell me how to correct my conversion to get the required result

xml xslt soap wso2

share|improve this question

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

<?xml version='1.0' encoding='utf-8'?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
 <soapenv:Body> 
 <field_21>
 <row StartDate="2017-01-01" EndDate="2017-01-07" DaysCount="7" Diagnoz="A00.0"/>
 <row StartDate="2019-02-01" EndDate="2019-02-07" DaysCount="8" Diagnoz="A10.0"/>
 </field_21>
 </soapenv:Body>
</soapenv:Envelope>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
 xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" version="1.0">
 <xsl:template match="/">
 <result> 
 <xsl:value-of select="string-join(
 concat(//field_21/row/@StartDate, ' ', 
 //field_21/row/@EndDate, ' ', 
 //field_21/row/@DaysCount, ' ', 
 //field_21/row/@Diagnoz), ';')"/>
 </result> 
 </xsl:template>
</xsl:stylesheet>

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0</result>

<result xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">2017-01-01 2017-01-07 7 A00.0; 2019-02-01 2019-02-07 8 A10.0</result>

share|improve this question

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

share|improve this question

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

asked Mar 27 at 10:58

serjio_designserjio_design

844 bronze badges

1 Answer
1

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oldest

votes

2

This is slightly confusing because your stylesheet has version="1.0" in it, but string-join is only available in XSLT 2.0. However, if you were using XSLT 2.0, I would expect the concat to failure because //field_21/row/@StartDate returns multiple nodes, which would not be allowed in XSLT 2.0

But, if you are indeed using XSLT 2.0, you could write the expression like this:

<xsl:value-of select="string-join(//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz), ';')"/>

Or, like this, to take advantage of the separator attribute available in XSLT 2.0.

<xsl:value-of select="//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" separator="; " />

If, however, you can only use XSLT 1.0, you would have to use xsl:for-each (or xsl:apply-templates

<xsl:for-each select="//field_21/row">
 <xsl:if test="position() > 1">; </xsl:if>
 <xsl:value-of select="concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" />
</xsl:for-each>

share|improve this answer

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  For 2.0 you can use like <xsl:value-of select="string-join(for $val in /*:Envelope/*:Body/field_21/row return concat($val/@StartDate, ' ', $val/@EndDate, ' ',$val/@DaysCount, ' ',$val/@Diagnoz),', ')"/>
  
  – Amrendra Kumar
  Mar 27 at 11:17
  

  
  
  
  

add a comment | 

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2

This is slightly confusing because your stylesheet has version="1.0" in it, but string-join is only available in XSLT 2.0. However, if you were using XSLT 2.0, I would expect the concat to failure because //field_21/row/@StartDate returns multiple nodes, which would not be allowed in XSLT 2.0

But, if you are indeed using XSLT 2.0, you could write the expression like this:

<xsl:value-of select="string-join(//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz), ';')"/>

Or, like this, to take advantage of the separator attribute available in XSLT 2.0.

<xsl:value-of select="//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" separator="; " />

If, however, you can only use XSLT 1.0, you would have to use xsl:for-each (or xsl:apply-templates

<xsl:for-each select="//field_21/row">
 <xsl:if test="position() > 1">; </xsl:if>
 <xsl:value-of select="concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" />
</xsl:for-each>

share|improve this answer

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  For 2.0 you can use like <xsl:value-of select="string-join(for $val in /*:Envelope/*:Body/field_21/row return concat($val/@StartDate, ' ', $val/@EndDate, ' ',$val/@DaysCount, ' ',$val/@Diagnoz),', ')"/>
  
  – Amrendra Kumar
  Mar 27 at 11:17
  

  
  
  
  

add a comment | 

2

This is slightly confusing because your stylesheet has version="1.0" in it, but string-join is only available in XSLT 2.0. However, if you were using XSLT 2.0, I would expect the concat to failure because //field_21/row/@StartDate returns multiple nodes, which would not be allowed in XSLT 2.0

But, if you are indeed using XSLT 2.0, you could write the expression like this:

<xsl:value-of select="string-join(//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz), ';')"/>

Or, like this, to take advantage of the separator attribute available in XSLT 2.0.

<xsl:value-of select="//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" separator="; " />

If, however, you can only use XSLT 1.0, you would have to use xsl:for-each (or xsl:apply-templates

<xsl:for-each select="//field_21/row">
 <xsl:if test="position() > 1">; </xsl:if>
 <xsl:value-of select="concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" />
</xsl:for-each>

share|improve this answer

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  For 2.0 you can use like <xsl:value-of select="string-join(for $val in /*:Envelope/*:Body/field_21/row return concat($val/@StartDate, ' ', $val/@EndDate, ' ',$val/@DaysCount, ' ',$val/@Diagnoz),', ')"/>
  
  – Amrendra Kumar
  Mar 27 at 11:17
  

  
  
  
  

add a comment | 

This is slightly confusing because your stylesheet has version="1.0" in it, but string-join is only available in XSLT 2.0. However, if you were using XSLT 2.0, I would expect the concat to failure because //field_21/row/@StartDate returns multiple nodes, which would not be allowed in XSLT 2.0

But, if you are indeed using XSLT 2.0, you could write the expression like this:

<xsl:value-of select="string-join(//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz), ';')"/>

Or, like this, to take advantage of the separator attribute available in XSLT 2.0.

<xsl:value-of select="//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" separator="; " />

If, however, you can only use XSLT 1.0, you would have to use xsl:for-each (or xsl:apply-templates

<xsl:for-each select="//field_21/row">
 <xsl:if test="position() > 1">; </xsl:if>
 <xsl:value-of select="concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" />
</xsl:for-each>

share|improve this answer

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges

<xsl:value-of select="string-join(//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz), ';')"/>

<xsl:value-of select="//field_21/row/concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" separator="; " />

<xsl:for-each select="//field_21/row">
 <xsl:if test="position() > 1">; </xsl:if>
 <xsl:value-of select="concat(@StartDate, ' ', @EndDate, ' ', @DaysCount, ' ', @Diagnoz)" />
</xsl:for-each>

share|improve this answer

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges

answered Mar 27 at 11:13

Tim CTim C

64.2k1313 gold badges6262 silver badges8585 bronze badges